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Python and Powers Math
(3 answers)
How do I do exponentiation in python? [duplicate]
(3 answers)
Closed last year.
Is it possible to type a squared number in python?
Or how to type for example 5 to the power of 2
number**power
As Joran Beasley said you only type **2 next to the number to take it to the power of 2.
In python we multiply with * so ** is multiplying two times, which is square. however *** is an error and **3 is cubic.
however you can also define a method
def power(number,n):
x=1
for n in range(n):
x=number*x
return x
print(power(5,8))
Related
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solution to power of the numbers in python3
(3 answers)
Exponentials in python: x**y vs math.pow(x, y)
(5 answers)
Closed 6 months ago.
In the formula for calculating the volume of a sphere, the radius is raised to the power of 3. So, if I assign a variable such as sphere_radius to the radius, how would I raise that variable to the power of 3 (in shorthand form without having to multiply the radius three times) in my python statement to calculate the volume?
In python, a**b will raise a to the power of b.
For example:
cubed = radius ** 3
This question already has answers here:
Why is exponentiation applied right to left?
(4 answers)
Closed 2 years ago.
Am New to python trying out some basic python function. Came across exponential
In python
2 ** 2 ** 3 is 256
But while in mathematics getting as 64.
Use parentheses. This will give the correct answer.
(2 ** 2) ** 3
Use parentheses
x = (2**2)**3
or:
pow(2,2*3)
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Is integer division always equal to the floor of regular division?
(4 answers)
Closed 3 years ago.
I was making an integer to Boolean program and was dealing with some large numbers
The test case was - 15921396743627894741911
When I used
r/2 the output was 7.960698371813948e+21
int(r/2) gave me 7960698371813947736064
and r//2 gave me 7960698371813947370955
Why is the value for the last two cases so vastly different. Thank you
In Python 3, / does "true division", which returns a float, but floats have limited precision.
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Complex numbers in python
(3 answers)
Closed 4 years ago.
I want to find the absolute value of something like 'i' but when I type 'abs(1)' it says 'i' is not defined. What do I do?
In python to find the absolute value of a complex function you use j instead of i.
abs(a+bj) # General Format
abs(0+1j)
>> 1
Or you could define i as the square root of -1 and use it instead
i = (-1) ** 0.5
abs(i)
>> 1
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How does the modulo (%) operator work on negative numbers in Python?
(12 answers)
Closed 5 years ago.
How come -20 % 3 = 1?
Just confused with the formulae used for negative number % positive number.
(I have seen many question related in quora but still not clear with formula used)
I am not sure about the formula but you can add x to the negative number such that (x+ negative number)>=0 and x is a multiple of mod value . This is right because
x % k = (x+ y*k) % k