I need a way to reformat the date and time from 2021-01-27T12:00:17Z as a separate date and time variable in the format as shown below:
Date: 27/01/2021
Time: 12:00
import pandas as pd
values = {'dates': ['2021-01-27T12:00:17Z']}
df = pd.DataFrame(values)
df['dates'] = pd.to_datetime(df['dates'], format='%Y-%m-%dT%H:%M:%SZ')
formatted_date = pd.to_datetime(df['dates']).dt.date
print('Formatted Date:',formatted_date)
formatted_time = pd.to_datetime(df['dates']).dt.time
print('Formatted Time:',formatted_time)
print ('df value:', df)
print (df.dtypes)
When I change the syntax from format='%Y-%m-%dT%H:%M:%SZ' to format='%d-%m-%YT%H:%M:%SZ' it produces an error.
Any help would be much appreciated.
I am using these, hope it helps;
from datetime import datetime, timedelta, timezone
utc_time = datetime.fromtimestamp(date_time).astimezone(timezone.utc)
local_time = datetime.fromtimestamp(date_time).astimezone(local_tz)
date = datetime.fromisoformat(date_time).astimezone(local_tz).date
time = datetime.fromisoformat(date_time).astimezone(local_tz).time
for datetime calculation, we can use timedelta
local_time = datetime.fromtimestamp(date_time).astimezone(local_tz) + deltatime(hours=5)
local_time = datetime.fromtimestamp(date_time).astimezone(local_tz) + deltatime(minutes=60)
<built-in method date of datetime.datetime object at 0x000002BF40795DA0>
<built-in method time of datetime.datetime object at 0x000002BF40795DA0>
the date and time are datetime.datetime objects.
Related
i have an dataframe with dates and would like to get the time between the first date and the last date, when i run the code below
df.sort_values('timestamp', inplace=True)
firstDay = df.iloc[0]['timestamp']
lastDay = df.iloc[len(df)-1]['timestamp']
print(firstDay)
print(lastDay)
it provides the following formate of the dates :
2016-09-24 17:42:27.839496
2017-01-18 10:24:08.629327
and I'm trying to get the different between them but they're in the str format, and I've been having trouble converting them to a form where i can get the difference
here you go :o)
import datetime
from datetime import date
from datetime import datetime
import pandas as pd
date_format_str = '%Y-%m-%d %H:%M:%S.%f'
date_1 = '2016-09-24 17:42:27.839496'
date_2 = '2017-01-18 10:24:08.629327'
start = datetime.strptime(date_1, date_format_str)
end = datetime.strptime(date_2, date_format_str)
diff = end - start
# Get interval between two timstamps as timedelta object
diff_in_hours = diff.total_seconds() / 3600
print(diff_in_hours)
# get the difference between two dates as timedelta object
diff = end.date() - start.date()
print(diff.days)
Pandas
import datetime
from datetime import date
from datetime import datetime
import pandas as pd
date_1 = '2016-09-24 17:42:27.839496'
date_2 = '2017-01-18 10:24:08.629327'
start = pd.to_datetime(date_1, format='%Y-%m-%d %H:%M:%S.%f')
end = pd.to_datetime(date_2, format='%Y-%m-%d %H:%M:%S.%f')
# get the difference between two datetimes as timedelta object
diff = end - start
print(diff.days)
So, Basically, I got this 2 df columns with data content. The initial content is in the dd/mm/YYYY format, and I want to subtract them. But I can't really subtract string, so I converted it to datetime, but when I do such thing for some reason the format changes to YYYY-dd-mm, so when I try to subtract them, I got a wrong result. For example:
Initial Content:
a: 05/09/2022
b: 30/09/2021
result expected: 25 days.
Converted to DateTime:
a: 2022-05-09
b: 2021-09-30 (For some reason this date stills the same)
result: 144 days.
I'm using pandas and datetime to make this project.
So, I wanted to know a way I can subtract this 2 columns with the proper result.
--- Answer
When I used
pd.to_datetime(date, format="%d/%m/%Y")
It worked. Thank you all for your time. This is my first project in pandas. :)
df = pd.DataFrame({'Date1': ['05/09/2021'], 'Date2': ['30/09/2021']})
df = df.apply(lambda x:pd.to_datetime(x,format=r'%d/%m/%Y')).assign(Delta=lambda x: (x.Date2-x.Date1).dt.days)
print(df)
Date1 Date2 Delta
0 2021-09-05 2021-09-30 25
I just answered a similar query here subtracting dates in python
import datetime
from datetime import date
from datetime import datetime
import pandas as pd
date_format_str = '%Y-%m-%d %H:%M:%S.%f'
date_1 = '2016-09-24 17:42:27.839496'
date_2 = '2017-01-18 10:24:08.629327'
start = datetime.strptime(date_1, date_format_str)
end = datetime.strptime(date_2, date_format_str)
diff = end - start
# Get interval between two timstamps as timedelta object
diff_in_hours = diff.total_seconds() / 3600
print(diff_in_hours)
# get the difference between two dates as timedelta object
diff = end.date() - start.date()
print(diff.days)
Pandas
import datetime
from datetime import date
from datetime import datetime
import pandas as pd
date_1 = '2016-09-24 17:42:27.839496'
date_2 = '2017-01-18 10:24:08.629327'
start = pd.to_datetime(date_1, format='%Y-%m-%d %H:%M:%S.%f')
end = pd.to_datetime(date_2, format='%Y-%m-%d %H:%M:%S.%f')
# get the difference between two datetimes as timedelta object
diff = end - start
print(diff.days)
With python, How can I check if a date stored in a string has already passed?
My current code:
from datetime import date, datetime
date1 = date.today()
data2_str = '2018-06-25'
data2_obj = datetime.strptime(data2_str, '%Y-%m-%d')
print(date1<=data2_obj)
The code above gives me the following error:
TypeError: can't compare datetime.datetime to datetime.date
Note that I would not want to work with any time - just the date (this case the treated in 32287708)
Use the .date() method to get the date component like this:
from datetime import date, datetime
date1 = date.today()
date2_str = '2018-06-25'
date2 = datetime.strptime(date2_str, '%Y-%m-%d').date()
print(date1<=date2)
Output:
False
I'm trying to subtract a day from this date 06-30-2019 in order to make it 06-29-2019 but can't figure out any way to achive that.
I've tried with:
import datetime
date = "06-30-2019"
date = datetime.datetime.strptime(date,'%m-%d-%Y').strftime('%m-%d-%Y')
print(date)
It surely gives me back the date I used above.
How can I subtract a day from a date in the above format?
try this
import datetime
date = "06/30/19"
date = datetime.datetime.strptime(date, "%m/%d/%y")
NewDate = date + datetime.timedelta(days=-1)
print(NewDate) # 2019-06-29 00:00:00
Your code:
date = "06-30-2019"
date = datetime.datetime.strptime(date,'%m-%d-%Y').strftime('%m-%d-%Y')
Check type of date variable.
type(date)
Out[]: str
It is in string format. To perform subtraction operation you must convert it into date format first. You can use pd.to_datetime()
# Import packages
import pandas as pd
from datetime import timedelta
# input date
date = "06-30-2019"
# Convert it into pd.to_datetime format
date = pd.to_datetime(date)
print(date)
# Substracting days
number_of_days = 1
new_date = date - timedelta(number_of_days)
print(new_date)
output:
2019-06-29 00:00:00
If you want to get rid of timestamp you can use:
str(new_date.date())
Out[]: '2019-06-29'
use timedelta
import datetime
date = datetime.datetime.strptime("06/30/19" ,"%m/%d/%y")
print( date - datetime.timedelta(days=1))
I have data with the date format as follows:
date_format = 190410
year = 19
month = 04
date = 10
I want to change the date format, to be like this:
date_format = 10-04-2019
How do I solve this problem?
>>> import datetime
>>> date = 190410
>>> datetime.datetime.strptime(str(date), "%y%m%d").strftime("%d-%m-%Y")
'10-04-2019'
datetime.strptime() takes a data string and a format, and turns that into datetime object, and datetime objects have a method called strftime that turns datetime objects to string with given format. You can look what %y %m %d %Y are from here.
This is what you want(Notice that you have to change your format)
import datetime
date_format = '2019-04-10'
date_time_obj = datetime.datetime.strptime(date_format, '%Y-%m-%d')
print(date_time_obj)
Here is an other example
import datetime
date_time_str = '2018-06-29 08:15:27.243860'
date_time_obj = datetime.datetime.strptime(date_time_str, '%Y-%m-%d %H:%M:%S.%f')
print('Date:', date_time_obj.date())
print('Time:', date_time_obj.time())
print('Date-time:', date_time_obj)
You can also do this
from datetime import datetime, timedelta
s = "20120213"
# you could also import date instead of datetime and use that.
date = datetime(year=int(s[0:4]), month=int(s[4:6]), day=int(s[6:8]))
print(date)
There are many ways to achieve what you want.