Hey so i have started with python recently and im facing a syntax error when im trying to activate this code with python 3.1
This code is from the Automate the Boring Stuff and it's exactly the same as the author used and mine is facing an Error, any idea ?
btw the Error is with the elif condition
import random
print('Hello. What is your name?')
name = input()
print('Well, ' + name + ', I am thinking of a number between 1 to 20 ')
secretNumber = random.randint(1, 20)
for guessesTaken in range(1, 7):
print('Take a guess.')
guess = int(input())
if guess < secretNumber:
print('Your guess is too low.')
elif guess > secretNumber:
print ('Your guess is too high.')
else:
break
if guess == secretNumber:
print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses')
else:
print(' Nope, that number i was thinking of was ' + str(secretNumber))
code with identation fixed which ran on my machine
import random
print('Hello. What is your name?')
name = input()
print('Well, ' + name + ', I am thinking of a number between 1 to 20 ')
secretNumber = random.randint(1, 20)
for guessesTaken in range(1, 7):
print('Take a guess.')
guess = int(input())
if guess < secretNumber:
print('Your guess is too low.')
elif guess > secretNumber:
print ('Your guess is too high.')
else:
break
if guess == secretNumber:
print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses')
else:
print(' Nope, that number i was thinking of was ' + str(secretNumber))
Here is the correct indentation:
import random
print('Hello. What is your name?')
name = input()
print('Well, ' + name + ', I am thinking of a number between 1 to 20 ')
secretNumber = random.randint(1, 20)
for guessesTaken in range(1, 7):
print('Take a guess.')
guess = int(input())
if guess < secretNumber:
print('Your guess is too low.')
elif guess > secretNumber:
print ('Your guess is too high.')
else:
break
if guess == secretNumber:
print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses')
else:
print(' Nope, that number i was thinking of was ' + str(secretNumber))
Indentation is a very important concept of Python!
You have indentation errors on your code, elif and else should be indented at the same level of if. Same for the second 'else'.
import random
print('Hello. What is your name?')
name = input()
print('Well, ' + name + ', I am thinking of a number between 1 to 20 ')
secretNumber = random.randint(1, 20)
for guessesTaken in range(1, 7):
print('Take a guess.')
guess = int(input())
if guess < secretNumber:
print('Your guess is too low.')
elif guess > secretNumber:
print ('Your guess is too high.')
else:
break
if guess == secretNumber:
print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses')
else:
print(' Nope, that number i was thinking of was ' + str(secretNumber))
I think you are looking for this. Note the indentation of the if/else statements.
import random
print('Hello. What is your name?')
name = input()
print('Well, ' + name + ', I am thinking of a number between 1 to 20 ')
secretNumber = random.randint(1, 20)
for guessesTaken in range(1, 7):
print('Take a guess.')
guess = int(input())
if guess < secretNumber:
print('Your guess is too low.')
elif guess > secretNumber:
print ('Your guess is too high.')
else:
break
if guess == secretNumber:
print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken)
+' guesses')
else:
print(' Nope, that number i was thinking of was ' + str(secretNumber))
Disclaimer:
I'm a bit of a newb myself so there could be better answers out there.
Python is all about indentation. The indentations of the if/elif/else should be all on the same level. See below:
if guess < secretNumber:
print('Your guess is too low.')
elif guess > secretNumber:
print ('Your guess is too high.')
else:
break
Related
I'm going through the Automate the Boring Stuff with Python videos on youtube. I finished the one about random number guessing game and am now adding some stuff to it to make it more complete.
I added some code that makes it so that if you don't enter an integer (which creates a ValueError) the program tells you that you didn't enter an integer. However, the point of the game is that you only get 6 guesses, but when the error comes up it, it resets the number of guesses.
How can I make it so that the error doesn't reset the number of cases?
Here's the code:
# This is a guess the number game.
import random
print ('Hello, what is your name?')
name = input ()
name = name.strip()
print ('Well, ' + name + ' I am thinking of a number between 1 and 20.')
secretNumber = random.randint (1, 20)
print ('DEBUG: Secret number is ' + str(secretNumber))
while True:
try:
for guessesTaken in range (1, 7):
print ('Take a guess.')
guess = int (input ())
if guess < secretNumber:
print ('Your guess is too low.')
elif guess > secretNumber:
print ('Your guess is too high.')
else:
break # This condition is for the correct guess
if (guess == secretNumber and guessesTaken == 1):
print ('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guess.')
break
elif (guess == secretNumber and guessesTaken > 1):
print ('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses.')
break
else:
print ('Nope. The number I was thinkig of was ' + str(secretNumber))
break
except ValueError:
print ('You did not enter a number.') # This condition is for if a non-integer is entered.
I feel like I've tried every combination of where I can but the try and for loop, but can't seem to figure it out.
The outer while loop seems unnecessary because it allows you to try even after 6 attempts.
Therefore the break in the last three conditions will also be deleted.
You should put the try into the for loop so that if an exception is raised, the program will continue to count the number of attempts.
I would do something like:
# This is a guess the number game.
import random
print('Hello, what is your name?')
name = input()
name = name.strip()
print('Well, ' + name + ' I am thinking of a number between 1 and 20.')
secretNumber = random.randint(1, 20)
print('DEBUG: Secret number is ' + str(secretNumber))
for guessesTaken in range(1, 7):
try:
print('Take a guess.')
guess = int(input())
if guess < secretNumber:
print('Your guess is too low.')
elif guess > secretNumber:
print('Your guess is too high.')
else:
break # This condition is for the correct guess
except ValueError:
print('You did not enter a number.') # This condition is for if a non-integer is entered.
if (guess == secretNumber and guessesTaken == 1):
print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guess.')
elif (guess == secretNumber and guessesTaken > 1):
print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses.')
else:
print('Nope. The number I was thinkig of was ' + str(secretNumber))
The except block also should be moved, to be related to the try block, under the block of the loop because we don't want to stop the for loop as I mentioned before.
This is a guess the number game.
import random
print ('Hello, what is your name?')
name = input ()
guess = 0
name = name.strip()
print ('Well, ' + name + ' I am thinking of a number between 1 and 20.')
secretNumber = random.randint (1, 20)
print ('DEBUG: Secret number is ' + str(secretNumber))
while True:
for guessesTaken in range (1, 7):
try:
print ('Take a guess.')
guess = int (input ())
if guess < secretNumber:
print ('Your guess is too low.')
elif guess > secretNumber:
print ('Your guess is too high.')
else:
break # This condition is for the correct guess
except ValueError:
print ('You did not enter a number.') # This condition is for if a non-integer is entered.
if (guess == secretNumber and guessesTaken == 1):
print ('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guess.')
break
elif (guess == secretNumber and guessesTaken > 1):
print ('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses.')
break
else:
print ('Nope. The number I was thinkig of was ' + str(secretNumber))
break
This question already has answers here:
Why does code like `str = str(...)` cause a TypeError, but only the second time?
(20 answers)
Closed 2 years ago.
I am trying to learn Python. I am currently writing my first program and following Automate the Boring Stuff. I have run into an error that I cannot understand. I am running python 3.9.1. The lines in question run perfectly fine on their own, but give me the following error:
line 11, in <module>
print ('Pick a number.')
TypeError: 'str' object is not callable
Here is the total code:
import random
print ('Hello! What is your name?')
name = input()
print = ('Hi, ' + name + '. I am thinking of a number between -99 and 99.')
secretNumber = random.randint(-99,99)
for guessesTaken in range(1,7):
print ('Pick a number.')
guess = int(input())
if guess < secretNumber:
print ('Your guess is too low. Guess again.')
elif guess > secretNumber:
print('Your guess is too high. Guess again.')
else:
break # This means the guess was correct
if guess == secretNumber:
print ('Good job, ' + name + '. You guessed the value in ' + str(guessesTaken) + ' guesses.')
else:
print ('You did not guess the number. The correct number was ' + str(secretNumber) + '.')
The problem is in the line 6 actually, where you try to assign an value to the print:
print = ('Hi, ' + name + '. I am thinking of a number between -99 and 99.')
You should delete that = and the code will work :)
import random
print('Hello! What is your name?')
name = input()
print('Hi, ' + name + '. I am thinking of a number between -99 and 99.')
secretNumber = random.randint(-99,99)
for guessesTaken in range(1,7):
print ('Pick a number.')
guess = int(input())
if guess < secretNumber:
print ('Your guess is too low. Guess again.')
elif guess > secretNumber:
print('Your guess is too high. Guess again.')
else:
break # This means the guess was correct
if guess == secretNumber:
print ('Good job, ' + name + '. You guessed the value in ' + str(guessesTaken) + ' guesses.')
else:
print ('You did not guess the number. The correct number was ' + str(secretNumber) + '.')
Because of your line
print = ('Hi, ' + name + '. I am thinking of a number between -99 and 99.')
where your redefined the built-in function print to be a string.
Remove = from that command:
print('Hi, ' + name + '. I am thinking of a number between -99 and 99.')
I am new to Python, so this is probably a dumb question to many here, but in the following code, how would I go about adding an exception, so that should someone enter say a word for instance, that would handle the invalid input and continue to ask, 'Take a guess.'?
import random
secretNumber = random.randint(1, 100)
print('I am thinking of a number between 1 and 100.')
for guessesTaken in range(1, 11):
print('Take a guess.')
guess = int(input())
if guess < secretNumber:
print('Your guess is too low.')
elif guess > secretNumber:
print('Your guess is too high.')
else:
break # This condition is the correct guess!
if guess == secretNumber:
print('Good job! You guessed mu number in ' + str(guessesTaken) + ' guesses!')
else:
print('Nope. The number I was thinking of was ' + str(secretNumber))
I believe what you are trying to do can be accomplished with the input as follows:
guess = None
while guess is None:
try:
print('Take a guess.')
guess = int(input())
except ValueError:
pass
The code I have:
import random
guessesTaken = 0
print('Hello! What is your name?')
myName = input()
number = random.randint(1, 20)
print('Well, ' + myName + ', I am thinking of a number between 1 and 20.')
while guessesTaken < 5:
print('Take a guess.')
guess = input()
guess = int(guess)
guessesTaken = guessesTaken + 1
guessesTaken = print('Thats a guess gone.')
if guess < number:
print('Your guess is too low.')
if guess > number:
print('Your guess is too high.')
if guess == number:
print('You won at life!')
break
if guess == number:
print('idk, ' + myName + '! You guessed my number in ' + guessesTaken + ' guesses!')
print('Again? Again.')
Need help with:
1.This error - Traceback (most recent call last):
File "\\wbs-fs01\2013$\13CDyke\Guessing game.py", line 12, in <module>
while guessesTaken < 5:
TypeError: unorderable types: NoneType() < int()
2.Need to fix it and display how many guesses you got the answer in.
The problem is this line:
guessesTaken = print('Thats a guess gone.')
print returns None, so that's the value your variable gets. Remove the assignment and it'll work:
print('Thats a guess gone.')
def main():
import random
guesslist = []
ErrorTol = 5
guessesTaken = 0
print("|--------------------------------------------------------------------|")
print("| |")
print("|--------------------------------------------------------------------|")
print("| WELCOME! Please enter your name to begin this guessing game |")
print("|--------------------------------------------------------------------|")
print("| |")
print("|--------------------------------------------------------------------|")
myName = input()
again = ""
while again != "q":
number = random.uniform(-300, 300)
print('Well, ' + myName + ', I am thinking of a number between -300 and 300.')
while guessesTaken < 3:
print("Take a guess.")
guess = input()
guess = int(guess)
guesslist.append(guess)
guessesTaken = guessesTaken + 1
if guess < number:
print('Your guess is too low.')
if guess > number:
print('Your guess is too high.')
if guess == number or (abs(number - guess) <= ErrorTol):
break
if guess == number or (abs(number - guess) <= ErrorTol):
guessesTaken = guessesTaken
print('Good job, ' + myName + '! You guessed my number in ' + str(guessesTaken) + ' guesses!')
print("numbers you guessed:", guesslist)
else:
number = int(number)
print('Nope. The number I was thinking of was ' + str(number))
again = input("Hit 'q' to quit the program or any other keys to play the game again.").lower()[0]
main()
I can't get the program to loop properly, I have no clue what I did wrong! When I do not guess the number correctly, I should be able to hit any keys to try again and hit 'q' to try again, but when I hit any other keys it will not loop properly. Again, I have no clue what is wrong with this code.
You do not reset guessesTaken to zero so your program acts as if the user has already made there three guesses. Try something like this:
again = input("Hit 'q' to quit the program or any other keys to play the game again.").lower()[0]
guessesTaken = 0
You have to reset the amount of guesses when you check to see if the key is not equal to q. I put your code into another method, just better design!
Good luck!
import random
def main():
print("|--------------------------------------------------------------------|")
print("| |")
print("|--------------------------------------------------------------------|")
print("| WELCOME! Please enter your name to begin this guessing game |")
print("|--------------------------------------------------------------------|")
print("| |")
print("|--------------------------------------------------------------------|")
guess()
def guess():
guesslist = []
ErrorTol = 5
guessesTaken = 0
myName = input()
again = ""
while again != "q":
guessesTaken = 0
number = random.uniform(-300, 300)
print('Well, ' + myName + ', I am thinking of a number between -300 and 300.')
while guessesTaken < 3:
print("Take a guess.")
guess = input()
guess = int(guess)
guesslist.append(guess)
guessesTaken = guessesTaken + 1
if guess < number:
print('Your guess is too low.')
if guess > number:
print('Your guess is too high.')
if guess == number or (abs(number - guess) <= ErrorTol):
break
if guess == number or (abs(number - guess) <= ErrorTol):
guessesTaken = guessesTaken
print('Good job, ' + myName + '! You guessed my number in ' + str(guessesTaken) + ' guesses!')
print("numbers you guessed:", guesslist)
else:
number = int(number)
print('Nope. The number I was thinking of was ' + str(number))
again = input("Hit 'q' to quit the program or any other keys to play the game again.")