I am trying create a Python dashboard in which a user uploads an image and then the image is analyzed. The uploaded image is received as a base64 string and it needs to be converted to an image. I have tried
decoded = BytesIO(base64.b64decode(base64_string))
image = Image.open(decoded)
but I received this error:
cannot identify image file <_io.BytesIO object at 0x00000268954E9888>
Image needs a file-like object, the sort of thing returned by an open. The easiest way to do this is using a with statement:
decoded = base64.b64decode(base64)
with BytesIO(decoded) as fh:
image = Image.open(fh)
# do stuff with image here: when the with block ends
# it's very likely the image will no longer be usable
See if that works better for you. :)
In order to remove sensitive content from a PDF, I am converting it to image and back to PDF again.
I am able to do this while saving the jpeg image, however I would eventually like to adapt my code so that the file is in memory the whole time. PDF in memory -> JPEG in memory -> PDF in memory. I'm having trouble with the intermediary step.
from pdf2image import convert_from_path, convert_from_bytes
import img2pdf
images = convert_from_path('testing.pdf', fmt='jpeg')
image = images[0]
# opening from filename
with open("output/output.pdf","wb") as f:
f.write(img2pdf.convert(image.tobytes()))
On the last line, I am getting the error:
ImageOpenError: cannot read input image (not jpeg2000). PIL: error reading image: cannot identify image file <_io.BytesIO object at 0x1040cc8f0>
I'm not sure how to be converting this image to the string that img2pdf is looking for.
The pdf2image module will extract the images as Pillow images. And according the Pillow tobytes() documention: "This method returns the raw image data from the internal storage." Which is some bitmap representation.
To get your code working use BytesIO module like so:
# opening from filename
import io
with open("output/output.pdf","wb") as f, io.BytesIO() as output:
image.save(output, format='jpg')
f.write(img2pdf.convert(output.getvalue()))
I am trying to convert, what I think is a bytearray pulled from a database to an image using python PIL.
I have access to the imagetype(jpg, png,..), the image height/width, and the bytearray. The bytearray is of the format
0xffd8ffe000104a46494600010101006000600000ffe111164578.....
I have tried many of the PIL options such as .fromstring and .frombuffer. I've also tried converting the bytearray into other forms (Base64,etc..) and then converting it to an image from there. None of these have worked and the image file is always corrupted.
If i follow the advice from this question:
image = Image.open(io.BytesIO(imagestring))
image.save(imageToSave.jpg)
I get this error: IOError: cannot identify image file
type(imagestring) returns type 'bytearray'
Thanks for reading and for any answers, let me know if I should edit this post with more info.
I can't explain why the 0x is there and if it will be a problem other people run into, but I had to trim off the 0x from the start of the string:
0xffd8ffe000104a46494600010101006000600000ffe111164578....
The code:
image = Image.open(io.BytesIO(imagestring))
image.save(imageToSave.jpg)
worked fine after that
This is a code of a JPG/PNG(I don't know exactly)
Here's on google docs
I need to decode it in Python to complete image and show it using Pillow or something like that. Do you know any libraries or ways how to decode it? Thanks!
(for Python 3)
If the image is stored as a binary file, open it directly:
import PIL
# Create Image object
picture = PIL.Image.open('picture_code.dat')
#display image
picture.show()
# print whether JPEG, PNG, etc.
print(picture.format)
If the image is stored as hex in a plaintext file picture_code.dat similar to your Google Docs link, it needs to first be converted to binary data:
import binascii
import PIL
import io
# Open plaintext file with hex
picture_hex = open('picture_code.dat').read()
# Convert hex to binary data
picture_bytes = binascii.unhexlify(picture_hex)
# Convert bytes to stream (file-like object in memory)
picture_stream = io.BytesIO(picture_bytes)
# Create Image object
picture = PIL.Image.open(picture_stream)
#display image
picture.show()
# print whether JPEG, PNG, etc.
print(picture.format)
I am creating image that I would like to embed in the e-mail. I cannot figure out how to create image as binary and pass into MIMEImage. Below is the code I have and I have error when I try to read image object - the error is "AttributeError: 'NoneType' object has no attribute 'read'".
image=Image.new("RGBA",(300,400),(255,255,255))
image_base=ImageDraw.Draw(image)
emailed_password_pic=image_base.text((150,200),emailed_password,(0,0,0))
imgObj=emailed_password_pic.read()
msg=MIMEMultipart()
html="""<p>Please finish registration <br/><img src="cid:image.jpg"></p>"""
img_file='image.jpg'
msgText = MIMEText(html,'html')
msgImg=MIMEImage(imgObj)
msgImg.add_header('Content-ID',img_file)
msg.attach(msgImg)
msg.attach(msgText)
If you look at line 4 - I am trying to read image so that I can pass it into MIMEImage. Apparently, image needs to be read as binary. However, I don't know how to convert it to binary so that .read() can process it.
FOLLOW-UP
I edited code per suggestions from jsbueno - thank you very much!!!:
emailed_password=os.urandom(16)
image=Image.new("RGBA",(300,400),(255,255,255))
image_base=ImageDraw.Draw(image)
emailed_password_pic=image_base.text((150,200),emailed_password,(0,0,0))
stream_bytes=BytesIO()
image.save(stream_bytes,format='png')
stream_bytes.seek(0)
#in_memory_file=stream_bytes.getvalue()
#imgObj=in_memory_file.read()
imgObj=stream_bytes.read()
msg=MIMEMultipart()
sender='xxx#abc.com'
receiver='jjjj#gmail.com'
subject_header='Please use code provided in this e-mail to confirm your subscription.'
msg["To"]=receiver
msg["From"]=sender
msg["Subject"]=subject_header
html="""<p>Please finish registration by loging into your account and typing in code from this e-mail.<br/><img src="cid:image.png"></p>"""
img_file='image.png'
msgText=MIMEText(html,'html')
msgImg=MIMEImage(imgObj) #Is mistake here?
msgImg.add_header('Content-ID',img_file)
msg.attach(msgImg)
msg.attach(msgText)
smtpObj=smtplib.SMTP('smtp.mandrillapp.com', 587)
smtpObj.login(userName,userPassword)
smtpObj.sendmail(sender,receiver,msg.as_string())
I am not getting errors now but e-mail does not have image in it. I am confused about the way image gets attached and related to in html/email part. Any help is appreciated!
UPDATE:
This code actually works - I just had minor typo in the code on my PC.
There are a couple of conceptual errors there, both in using PIL and on what format an image should be in order to be incorporated into an e-mail.
In PIL: the ImageDraw class operates inplace, not like the Image class calls, which usually return a new image after each operation. In your code, it means that the call to image_base.text is actually changing the pixel data of the object that lies in your image variable. This call actually returns None and the code above should raise an error like "AttributeError: None object does not have attribute 'read'" on the following line.
Past that (that is, you should fetch the data from your image variable to attach it to the e-mail) comes the second issue: PIL, for obvious reasons, have images in an uncompressed, raw pixel data format in memory. When attaching images in e-mails we usually want images neatly packaged inside a file - PNG or JPG formats are usually better depending on the intent - let's just stay with .PNG. So, you have to create the file data using PIL, and them attach the file data (i.e. the data comprising a PNG file, including headers, metadata, and the actual pixel data in a compressed form). Otherwise you'd be putting in your e-mail a bunch of (uncompressed) pixel data that the receiving party would have no way to assemble back into an image (even if he would treat the data as pixels, raw pixel data does not contain the image shape so-)
You have two options: either generate the file-bytes in memory, or write them to an actual file in disk, and re-read that file for attaching. The second form is easier to follow. The first is both more efficient and "the right thing to do" - so let's keep it:
from io import BytesIO
# In Python 2.x:
# from StringIO import StringIO.StringIO as BytesIO
image=Image.new("RGBA",(300,400),(255,255,255))
image_base=ImageDraw.Draw(image)
# this actually modifies "image"
emailed_password_pic=image_base.text((150,200),emailed_password,(0,0,0))
stream = BytesIO()
image.save(stream, format="png")
stream.seek(0)
imgObj=stream.read()
...
(NB: I have not checked the part dealing with mail and mime proper in your code - if you are using it correctly, it should work now)