How to access files in multiple sub-directories using glob - python

I have several files stored in a folder called Originals. Originals is stored in a folder called B_Substrate, B_Substrate is stored in a folder called Substrate_Training and Substrate_Training is stored in a folder called Jacob_Images.
I am trying to access the files in the folder Originals using glob but unable to access them.
Can anyone help me understand how to access files in multiple sub directories
This is my code but it doesn't work
import glob
file = '/content/drive/My Drive/Jacob_Images/Substrate_Training/B_Substrate/Originals/*.jpg'
for f in glob.glob(file):
print(f)

Instead of specifying .jpg within the path itself, specify it in glob() function. So, you can try this:
import glob
file = '/content/drive/My Drive/Jacob_Images/Substrate_Training/B_Substrate/Originals'
for f in glob.glob(file + "/*.jpg"):
print(f)
Or you can use this code below borrowing code from this post.
for i in glob.glob('/home/studio-lab-user/sagemaker-studiolab-notebooks/Misc/tsv/**/*.csv', recursive=True):
print(i)
Your code also works. I am certain the issue is with the path you are providing.
Using your way:
Using my way:

Related

How can i have multiple loop to reach list of all files from multiple determined folders?

I have multiple folders. I will read some of them; each folder includes various files (images) that I want access to their paths. I used the below code:
[os.path.join(folder,fname) for fname in os.listdir(folder) for folder in selected_train]
previously I had a list of folders in folders.
but I get the below error:
name 'folder' is not defined
How can I correct it?
You can use os.walk function to navigate through the folder.
import os
subfiles=[x[2] for x in os.walk(".")]
print(subfiles)
And also, if you want to just one list you can do this;
import os
subfiles=[]
for x in os.walk("."):
subfiles.extend(x[2])#x[2] represent the all files in one directory
print(subfiles)

Move files one by one to newly created directories for each file with Python 3

What I have is an initial directory with a file inside D:\BBS\file.x and multiple .txt files in the work directory D:\
What I am trying to do is to copy the folder BBS with its content and incrementing it's name by number, then copy/move each existing .txt file to the newly created directory to make it \BBS1, \BBS2, ..., BBSn (depends on number of the txt).
Visual example of the Before and After:
Initial view of the \WorkFolder
Desired view of the \WorkFolder
Right now I have reached only creating of a new directory and moving txt in it but all at once, not as I would like to. Here's my code:
from pathlib import Path
from shutil import copy
import shutil
import os
wkDir = Path.cwd()
src = wkDir.joinpath('BBS')
count = 0
for content in src.iterdir():
addname = src.name.split('_')[0]
out_folder = wkDir.joinpath(f'!{addname}')
out_folder.mkdir(exist_ok=True)
out_path = out_folder.joinpath(content.name)
copy(content, out_path)
files = os.listdir(wkDir)
for f in files:
if f.endswith(".txt"):
shutil.move(f, out_folder)
I kindly request for assistance with incrementing and copying files one by one to the newly created directory for each as mentioned.
Not much skills with python in general. Python3 OS Windows
Thanks in advance
Now, I understand what you want to accomplish. I think you can do it quite easily by only iterating over the text files and for each one you copy the BBS folder. After that you move the file you are currently at. In order to get the folder_num, you may be able to just access the file name's characters at the particular indexes (e.g. f[4:6]) if the name is always of the pattern TextXX.txt. If the prefix "Text" may vary, it is more stable to use regular expressions like in the following sample.
Also, the function shutil.copytree copies a directory with its children.
import re
import shutil
from pathlib import Path
wkDir = Path.cwd()
src = wkDir.joinpath('BBS')
for f in os.listdir(wkDir):
if f.endswith(".txt"):
folder_num = re.findall(r"\d+", f)[0]
target = wkDir.joinpath(f"{src.name}{folder_num}")
# copy BBS
shutil.copytree(src, target)
# move .txt file
shutil.move(f, target)

Rename files within a folder - Python

How can I rename files inside a folder without knowing their original name? For example I have a file.jpg and without knowing what it's called I want to call it test.jpg, this with all the files inside a folder.
Try this:
import os
import glob
# Getting all files in a folder (including hidden files)
files = os.listdir(os.path.expanduser("~/Downloads"))
# Getting all .jpg files in a directory
jpeg_files = glob.glob(os.path.expanduser("~/Downloads/*.jpeg"))
print(jpeg_files)
os.rename(jpeg_files[0], os.path.expanduser("~/Downloads/test.jpeg"))
If you want to rename all of the .jpeg files, then replace the last line with:
for file in jpeg_files:
os.rename(file, os.path.expanduser("~/Downloads/test.jpeg"))
Right now I'm using os.expanduser() just so that it's easier for people to test

How can I read files with similar names on python, rename them and then work with them?

I've already posted here with the same question but I sadly I couldn't come up with a solution (even though some of you guys gave me awesome answers but most of them weren't what I was looking for), so I'll try again and this time giving more information about what I'm trying to do.
So, I'm using a program called GMAT to get some outputs (.txt files with numerical values). These outputs have different names, but because I'm using them to more than one thing I'm getting something like this:
GMATd_1.txt
GMATd_2.txt
GMATf_1.txt
GMATf_2.txt
Now, what I need to do is to use these outputs as inputs in my code. I need to work with them in other functions of my script, and since I will have a lot of these .txt files I want to rename them as I don't want to use them like './path/etc'.
So what I wanted was to write a loop that could get these files and rename them inside the script so I can use these files with the new name in other functions (outside the loop).
So instead of having to this individually:
GMATds1= './path/GMATd_1.txt'
GMATds2= './path/GMATd_2.txt'
I wanted to write a loop that would do that for me.
I've already tried using a dictionary:
import os
import fnmatch
dict = {}
for filename in os.listdir('.'):
if fnmatch.fnmatch(filename, 'thing*.txt'):
examples[filename[:6]] = filename
This does work but I can't use the dictionary key outside the loop.
If I understand correctly, you try to fetch files with similar names (at least a re-occurring pattern) and rename them. This can be accomplished with the following code:
import glob
import os
all_files = glob.glob('path/to/directory/with/files/GMAT*.txt')
for file in files:
new_path = create_new_path(file) # possibly split the file name, change directory and/or filename
os.rename(file, new_path)
The glob library allows for searching files with * wildcards and makes it hence possible to search for files with a specific pattern. It lists all the files in a certain directory (or multiple directories if you include a * wildcard as a directory). When you iterate over the files, you could either directly work with the input of the files (as you apparently intend to do) or rename them as shown in this snippet. To rename them, you would need to generate a new path - so you would have to write the create_new_path function that takes the old path and creates a new one.
Since python 3.4 you should be using the built-in pathlib package instead of os or glob.
from pathlib import Path
import shutil
for file_src in Path("path/to/files").glob("GMAT*.txt"):
file_dest = str(file_src.resolve()).replace("ds", "d_")
shutil.move(file_src, file_dest)
you can use
import os
path='.....' # path where these files are located
path1='.....' ## path where you want these files to store
i=1
for file in os.listdir(path):
if file.endswith(end='.txt'):
os.rename(path + "/" + file, path1 + "/"+str(i) + ".txt")
i+=1
it will rename all the txt file in the source folder to 1,2,3,....n.txt

Zipped files have extra unwanted folders

I have been having an issue with using the zipfile.Zipfile() function. It zips my files properly, but then has extra folders that I do not want in the output zip file. It does put all my desired files in the .zip but it seems to add the last few directories from the files being written in the .zip file by default. Is there any way to exclude these folders? Here is my code:
import arcpy, os
from os import path as p
import zipfile
arcpy.overwriteOutput = True
def ZipShapes(path, out_path):
arcpy.env.workspace = path
shapes = arcpy.ListFeatureClasses()
# iterate through list of shapefiles
for shape in shapes:
name = p.splitext(shape)[0]
print name
zip_path = p.join(out_path, name + '.zip')
zip = zipfile.ZipFile(zip_path, 'w')
zip.write(p.join(path,shape))
for f in arcpy.ListFiles('%s*' %name):
if not f.endswith('.shp'):
zip.write(p.join(path,f))
print 'All files written to %s' %zip_path
zip.close()
if __name__ == '__main__':
path = r'C:\Shape_test\Census_CedarCo'
out_path = r'C:\Shape_outputs'
ZipShapes(path, out_path)
I tried to post some pictures but I do not have enough reputation points. Basically it is adding 2 extra folders (empty) inside the zip file. So instead of the files being inside the zip like this:
C:\Shape_outputs\Public_Buildings.zip\Public_Buildings.shp
They are showing up like this:
C:\Shape_outputs\Public_Buildings.zip\Shape_test\Census_CedarCo\Public_Buildings.shp
The "Shape_test" and "Census_CedarCo" folders are the directories that the shapefiles I am trying to copy come from, but if I am just writing these files why are the sub directories also being copied into the zip file? I suppose it is not a huge deal since I am getting the files zipped, but it is more of an annoyance than anything.
I assumed that when creating a zip file it would just write the files I specify themselves. Why does it add these extra directories inside the zip file? Is there a way around it? Am I missing something here? I appreciate any input! Thanks
The optional second parameter in ZipFile.write(filename[, arcname[, compress_type]]) is that name used in the archive file. You can strip the offending folders from the front of the path and use the remainder for the archive path name. I'm not sure exactly how arcpy gives you the paths, but something like zip.write(p.join(path,shape), shape) should do it.

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