Develop Reference

How to click on the first matching element having a specific background-url using Selenium Python

HTML:
<div class="__section-image" style="background-image: url("/img/all/05_element/continentImg/1.png");"></div>
The website have a lot of this html. I want to click the first of them.

To click on the first matching element you can use either of the following locator strategies:
Using css_selector:
driver.find_elements(By.CSS_SELECTOR, "div[class='__section-image']")[0].click()
Using xpath:
driver.find_elements(By.XPATH, "//div[#class='__section-image']")[0].click()
Ideally to click on the first matching element you need to induce WebDriverWait for the visibility_of_all_elements_located() and you can use either of the following locator strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "div[class='__section-image']")))[0].click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//div[#class='__section-image']")))[0].click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

How to click on an element by title with Selenium Python

I'm trying to check a checkbox with selenium and the only available info is the title.
Is a dynamic element, so I need to select by the title.
I tried all the methods without success (contains #title, etc).
Can someone please help? I'm beginning to code.
The xpath is:
/html/body/div[7]/div[2]/div/div[2]/div/div[2]/div/div/div[1]/form/div/span[1]/input
The CSS Selector is:
#selectCommon > span:nth-child(1) > input:nth-child(1)
The HTML looks like:
<input type="checkbox" title="AM - AMERICAS">

To click() on the element with title as AM - AMERICAS you can use either of the following locator strategies:
Using css_selector:
driver.find_element(By.CSS_SELECTOR, "input[title^='AM'][title$='AMERICAS']").click()
Using xpath:
driver.find_element(By.XPATH, "//input[starts-with(#title, 'AM') and contains(#title, 'AMERICAS')]").click()
Ideally to click() on the clickable element you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following locator strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input[title^='AM'][title$='AMERICAS']"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[starts-with(#title, 'AM') and contains(#title, 'AMERICAS')]"))).click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Can't find and click element using selenium

This is the HTML:
<li class="Y8-fY "><a class="-nal3 " href="/example/" tabindex="0"><span class="g47SY ">1.692</span> abonniert</a></li>
I tried using XPATH with the href to find it but i just get the nosuchelement error.

To click() on the desired element you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:
Using PARTIAL_LINK_TEXT:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.PARTIAL_LINK_TEXT, "abonniert"))).click()
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "li > a[href='/example/'] > span"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//li/a[#href='/example/']/span"))).click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

How to click an element using Selenium Python

So I have this element in HTML...
<span style="font-size:11pt">Security</span>
... and I want to click it using Selenium in python. How can I do it? (Maybe I can identify it using onclick, but how?)
Also, here is what I've tried:
security = driver.find_element_by_xpath("//button[#onclick=\"on_catolog(2);\"]")
security.click()

You used wrong tag name in your XPath "//button[#onclick=\"on_catolog(2);\"]". It's not a button, but anchor tag. Try
"//a[#onclick='on_catolog(2);']"
Or click by link text:
security = driver.find_element_by_link_text("Security")
security.click()

To click on the element with text as Security you can use either of the following Locator Strategies:
Using css_selector:
driver.find_element_by_css_selector("a[onclick^='on_catolog'] > span[style='font-size:11pt']").click()
Using xpath:
driver.find_element_by_xpath("//a[starts-with(#onclick, 'on_catolog')]/span[text()='Security']").click()
Ideally, to click on the element you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "a[onclick^='on_catolog'] > span[style='font-size:11pt']"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//a[starts-with(#onclick, 'on_catolog')]/span[text()='Security']"))).click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

How to extract the text from the HTML using Selenium and Python

I have this HTML:
And I want get this text "rataoriginal". (This text changes, I need this part of the code as text)
I've tried
xpath = "//span[#class='_5h6Y_ _3Whw5 selectable-text invisible-space copyable-text']"
auxa = driver.find_element_by_xpath(xpath).text
print(auxa)
But it prints the same as print("\n"). I don't want to use beaultifulsoup for a while.
This HTML is from 'https://web.whatsapp.com'

The WebElement is a dynamic element, so to print the values you have to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "span.selectable-text.invisible-space.copyable-text[dir='auto']"))).text)
Using XPATH:
print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//span[contains(#class, '') and contains(#class, 'invisible-space')][contains(#class, '') and #dir='auto']"))).text)
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
References
You can find a relevant discussion in:
How to retrieve the text of a WebElement using Selenium - Python

//*[contains(text(),"rataoriginal")] please use this xpath