I have a device that do some calculations and then i want to send it with help of request to my site:
import requests
params = {'data1': '47237582'}
r =requests.get("http://127.0.0.1:8000/", data = params)
print(r)
I have a django site. How can i save the value of my request for later display?
def read(request):
if request.method == 'GET':
msg = request.GET['data1']
And how can i save it to database?
First, create a model called Message, fields maybe: msg and from, it actually depends on how you want to store the msg,
Then after getting the msg with msg = request.GET['data1'] store the msg with msg_obj = Message.objects.create(msg=msg, ...other-fields if any)
If you are gonna have different keys (i.e columns) for each request, then I say you use MongoDB, which will allow you save different set of key-values in a single document.
Related
I am launching REST API build in python.
I am inputting a list as input and getting the required data.
example:
your.api.com/birth?name=James&date=2015-02-01&name=Robert&date=2020-01-01
from flask import request
#app.route('/birth')
def birth():
names = request.form.getlist('name')
dates = request.form.getlist('date')
As the number of inputs I have is huge, the end point URL is becoming huge. Is there any way to do the same using PUT or POST where I dump a doc in some format (say json) as my input?
Sure, put the request fields in a JSON and go through the dictionary
#app.route('/birth', methods=['POST'])
def birth():
data = request.get_json()
names = data["names"]
# etc.
When the input grows it is suggested to use a POST call rather than GET call.
from flask import request
#app.route('/birth')
def birth():
names = request.form.getlist('name')
dates = request.form.getlist('date')
Convert /birth to the following
from flask import request
#app.route('/birth', methods=['POST'])
def birth():
input = request.get_json()
# <Do the processing>
And in the POST call from client-side use a JSON like the following
{
name: [<array of values>],
date: [<array of values>]
}
I am working in Angular and I am using Http Request and Response.
Is it possible to send multiple arguments in 'Response'.
Angular file:
this.http.get("api/agent/applicationaware").subscribe((data:any)...
python file:
def get(request):
...
return Response(serializer.data)
I want to send multiple arguments in the Response.
Like
return Response(serializer.data,obj.someothervalue)
can you help me with this?
Thanks in advance :)
You can return a dictionary
return Response({'serializer_data': serializer.data, 'some_other_value': obj.someothervalue})
Or you can append someothervalue to serializer.data
data = serializer.data
data['someothervalue'] = obj.someothervalue
return Response(data)
If obj.someothervalue is a dictionary as well, then you can merge two dictionaries:
data = serializer.data.copy()
data.update(obj.someothervalue)
return Response(data)
add a dictionary
dict = {}
dict['details'] = serializer.data
dict['other'] = someotherdata
return Response(dict)
hope this helps
You need to decide a protocol for API response first and then you can plan accordingly.
To answer your question, YES you can send multiple args in response.
You can create a dictionary/list and put all the values you want to send inside it. Now send that dictionary/list as your response.
I would recommend something kind of this :
response = dict()
response["data"] = dict()
response["data"]["serializer_data"] = serializer.data
response["data"]["some_other_value"] = obj.someothervalue
return Response(response)
On the receiving end of the response you will have to read the response data in similar way you sent it.
I want to call a generate() function and send a user a message, but then continue executing a function.
#application.route("/api/v1.0/gen", methods=['POST'])
def generate():
return "Your id for getting the generated data is 'hgF8_dh4kdsRjdr'"
main() #generate a data
return "Successfully generated something. Use your id to get the data"
I understand that this is not a correct way of returning, but I hope you get the idea of what I am trying to accomplish. Maybe Flask has some build-in method to return multiple times from one api call?
Basically, what are you describing is called Server-Sent Events (aka SSE)
The difference of this format, that they returned an 'eventstream' Response type instead of usual JSON/plaintext
And if you want to use it with python/flask, you need generators.
Small code example (with GET request):
#application.route("/api/v1.0/gen", methods=['GET'])
def stream():
def eventStream():
text = "Your id for getting the generated data is 'hgF8_dh4kdsRjdr'"
yield str(Message(data = text, type="message"))
main()
text = "Successfully generated something. Use your id to get the data"
yield str(Message(data = text, type="message"))
resp.headers['Content-Type'] = 'text/event-stream'
resp.headers['Cache-Control'] = 'no-cache'
resp.headers['Connection'] = 'keep-alive'
return resp
Message class you can find here: https://gist.github.com/Alveona/b79c6583561a1d8c260de7ba944757a7
And of course, you need specific client that can properly read such responses.
postwoman.io supports SSE at Real-Time tab
I'm getting a POST request inside a Flask app from Slack. The request is sent when a user presses on an interactive message button. According to Slack docs I must extract the body of the request to verify the signature.
My computed signature doesn't match the one sent by Slack, though.
In fact, the body of the request comes as some encoded string. The string is actually an encoded dictionary instead of a query str parameters, as expected.
Here's the beginning of my view:
#app.route('/register', methods=['POST'])
def register_visit():
data = request.get_data()
signature = request.headers.get('X-Slack-Signature', None)
timestamp = request.headers.get('X-Slack-Request-Timestamp', None)
signing_secret = b'aaaaaaaaaaaaaaaa'
# old message, ignore
if round(actual_time.time() - float(timestamp)) > 60 * 5:
return
concatenated = ("v0:%s:%s" % (timestamp, data)).encode('utf-8')
computed_signature = 'v0=' + hmac.new(signing_secret, msg=concatenated, digestmod=hashlib.sha256).hexdigest()
if hmac.compare_digest(computed_signature, signature):
...
I've tried to format the received data to make it look like:
token=fdjkgjl&user_id=1234... but I am not aware of all of the necessary parameters that have to be present in the data.
Any ideas are highly appreciated.
The body of the message is following - after being URL decoded (note I've modified possibly sensitive data):
b'payload={"type":"interactive_message","actions":
[{"name":"yes_button","type":"button","value":"236"}],"callback_id":"visit_button","team":{"id":"fffff","domain":"ffff"},"channel":{"id":"ffff","name":"directmessage"},"user":{"id":"ffffff","name":"fffft"},"action_ts":"1540403943.419120","message_ts":"1541403949.000100","attachment_id":"1","token":"8LpjBuv13J7xAjhl2lEajoBU","is_app_unfurl":false,"original_message":{"text":"Test","bot_id":"DDDDDDDDD","attachments":[{"callback_id":"visit_button","text":"Register","id":1,"color":"3AA3E3","actions":[{"id":"1","name":"yes_button","text":"Yes","type":"button","value":"236","style":""}],"fallback":"Register"}],"type":"message","subtype":"bot_message","ts":"1540413949.000100"},"response_url":"https://hooks.slack.com/actions/ffffff/ffffff/tXJjx1XInaUhrikj6oEzK08e","trigger_id":"464662548327.425084163429.dda35a299eedb940ab98dbb9386b56f0"}'
The reason you are getting the "garbled" data is that you are using request.get_data(). That method will return the raw data of a request, but not do any decoding for you.
Much more convenient is to use request.form.get('payload'), which will directly give you the JSON string of the request object. You can then convert that into a dict object with json.loads() to process it further in your app.
Note that the format you received is the correct format for interactive messages. You will not get a query string (e.g. "token=abc;user_id?def...") as you suggested (like for slash command requests). Interactive message request will always contain the request as JSON string in a payload form property. See here for reference.
Here is a simple working example, which will reply a greeting to the user that pressed the button. It will work directly with Slack, but I recommend using Postman to test it.
#app.py
from flask import Flask, request #import main Flask class and request object
import json
app = Flask(__name__) #create the Flask app
#app.route('/register', methods=['POST'])
def register_visit():
slack_req = json.loads(request.form.get('payload'))
response = '{"text": "Hi, <#' + slack_req["user"]["id"] + '>"}'
return response, 200, {'content-type': 'application/json'}
if __name__ == '__main__':
app.run(debug=True, port=5000) #run app in debug mode on port 5000
OK, the issue wasn't related to how Slack sends me the message. It was about misunderstanding which data comes as bytes and which data is unicode. The culprit was string formatting in my case - the line concatenated = ("v0:%s:%s" % (timestamp, data)).encode('utf-8') should have been concatenated = (b"v0:%b:%b" % (timestamp.encode("utf-8"), data)). Data is already bytes, timestamp meanwhile is unicode.
Cannot believe I've banged my head on this for hours -_-
#app.route('/register', methods=['POST'])
def register_visit():
data = request.get_data()
signature = request.headers.get('X-Slack-Signature', None)
timestamp = request.headers.get('X-Slack-Request-Timestamp', None)
signing_secret = b'aaaaaaaaaaaaaaaa'
# old message, ignore
if round(actual_time.time() - float(timestamp)) > 60 * 5:
return
concatenated = (b"v0:%b:%b" % (timestamp.encode("utf-8"), data))
computed_signature = 'v0=' + hmac.new(signing_secret, msg=concatenated,
digestmod=hashlib.sha256).hexdigest()
if hmac.compare_digest(computed_signature, signature):
...
This worked for me
from urllib import parse
parsed_text = parse.unquote('your bytes text here')
I'm in the process of writing a very simple Python application for a friend that will query a service and get some data in return. I can manage the GET requests easily enough, but I'm having trouble with the POST requests. Just to get my feet wet, I've only slightly modified their example JSON data, but when I send it, I get an error. Here's the code (with identifying information changed):
import urllib.request
import json
def WebServiceClass(Object):
def __init__(self, user, password, host):
self.user = user
self.password = password
self.host = host
self.url = "https://{}/urldata/".format(self.host)
mgr = urllib.request.HTTPPasswordMgrWithDefaultRealm()
mgr.add_password(None, "https://{}".format(self.host), self.user, self.password)
self.opener = urllib.request.build_opener(urllib.request.HTTPDigestAuthHandler(mgr))
username = "myusername"
password = "mypassword"
service_host = "thisisthehostinfo"
web_service_object = WebServiceClass(username, password, service_host)
user_query = {"searchFields":
{
"First Name": "firstname",
"Last Name": "lastname"
},
"returnFields":["Entity ID","First Name","Last Name"]
}
user_query = json.dumps(user_query)
user_query = user_query.encode("ascii")
the_url = web_service_object.url + "modules/Users/search"
try:
user_data = web_service_object.opener.open(the_url, user_query)
user_data.read()
except urllib.error.HTTPError as e:
print(e.code)
print(e.read())
I got the class data from their API documentation.
As I said, I can do GET requests fine, but this POST request gives me a 500 error with the following text:
Content type 'application/x-www-form-urlencoded;charset=UTF-8' not supported
In researching this error, my assumption has become that the above error means I need to submit the data as multipart/form-data. Whether or not that assumption is correct is something I would like to test, but stock Python doesn't appear to have any easy way to create multipart/form-data - there are modules out there, but all of them appear to take a file and convert it to multipart/form-data, whereas I just want to convert this simple JSON data to test.
This leads me to two questions: does it seem as though I'm correct in my assumption that I need multipart/form-data to get this to work correctly? And if so, do I need to put my JSON data into a text file and use one of those modules out there to turn it into multipart, or is there some way to do it without creating a file?
Maybe you want to try the requests lib, You can pass a files param, then requests will send a multipart/form-data POST instead of an application/x-www-form-urlencoded POST. You are not limited to using actual files in that dictionary, however:
import requests
response = requests.post('http://httpbin.org/post', files=dict(foo='bar'))
print response.status_code
If you want to know more about the requests lib, and specially in sending multipart forms take a look at this:
http://docs.python-requests.org/en/master/
and
http://docs.python-requests.org/en/master/user/advanced/?highlight=Multipart-Encoded%20Files