Is each Thespian actor running on a single thread? - python

I am hitting a roadblock in my thespian implementation. I have an infinite while loop that will break if a condition is met, but I want to stay in the while loop until the condition is met. I understand that it is blocking and I am fine with not being able to receive any messages while in the infinite loop, however, it seems like other actors are not entering the loop until the previous actor has exited their infinite loop. This makes me believe that all actors are on a single thread. Any idea on workarounds?
class Actor(ActorTypeDispatcher):
def logic(self):
should_break = False
while True:
print(self.id)
if should_break:
break
**insert logic to determine if should_break is True or False**
I have instantiated 100 actors (the id is incremented from 1-100). Actors 1-5 immediately enter the break statement after an iteration, however when I print the id it is stuck on 6. The logic to break the loop for Actor where id = 6 is dependent on other Actors actions simultaneously.

Per Thespian's docs:
By default, the "simpleSystemBase" is used, which runs all Actors synchronously in the current process. While this base is very useful for debugging (see the Debugging section), it does not provide the level of concurrency usually desired at production time.
Which suggests that by default Thespian effectively runs all actors in the same thread.
Alternative bases (e.g. the multiprocTCPBase, which the docs elsewhere cite as the base to choose unless you're sure you want multiprocUDPBase or multiprocQueueBase) can be passed to the ActorSystem at startup. The default simpleSystemBase has no parallelism.

Related

Duration calculation and control in ROS - furthermore why does this script keep running even after pressing Ctrl-C?

I have written some code to make the turtlebot turn around. The code is working. What I want to know is how fast the turtlebot is running and how I can control it. Forexample, how can I ensure that the turtlebot turns 5 degrees in one minute?
Last part of the question. After pressing Ctrl-C, the turtlebot stops but the script keeps running. Why? and how can I stop that?
this post does not really help.
went through this post .Does that mean that the while loop below runs 5 times a second regardless of the values I put in the for loops? Or does it mean ROS tries its best to make sure that the loop runs 5 times a second to the best of my machine's ability?
Thank you very much.
# 5 HZ
angle = 5
r = rospy.Rate(5);
while not rospy.is_shutdown():
# code to turn
for x in range(0,100):
rospy.loginfo("turn")
turn_cmd.angular.z = radians(angle)
new_angle = (angle + new_angle) % 360
self.cmd_vel.publish(turn_cmd)
r.sleep()
# code to pause
for x in range(0,100):
rospy.loginfo("stop")
turn_cmd.angular.z = radians(0)
self.cmd_vel.publish(turn_cmd)
r.sleep()
def shutdown(self):
# stop turtlebot
rospy.loginfo("Stop turning")
self.cmd_vel.publish(Twist())
rospy.sleep(1)
According to ROS Wiki, the rospy.Rate convenience class makes a best effort to maintain the loop running at the specified frequency by considering the execution time of the loop since the last successful r.sleep(). This means in your case: as long as the code execution time within the loop does not exceed 1/5 seconds, rospy.Rate will make sure the loop runs at 5Hz.
Regarding the script not stopping when pressing Ctrl-C:
KeyboardInterrupt will be handled differently than in normal Python scripts when using rospy.
rospy catches the KeyboardInterrupt signal to set the rospy.is_shutdown() flag to true. This flag is only checked at the end of each loop, therefore if pressing Ctrl-C during the for-loop executions, the script cannot be stopped because the flag is not checked immediately.
A manual way to signal a shutdown of the node is to use rospy.signal_shutdown(). For this, the disable_signals option needs to be set to true when initializing the ROS node (see Section 2.3 here). Note that you will additionally have to manually invoke the correct shutdown routines to ensure a proper cleanup.

python How to while loop while true , run multiple functions together

def function():
while True:
...omission...(this function is repeated permanently)
i =0
while i < 4:
driver.execute_script("""window.open("URL")""")
driver.switch_to.window(driver.window_handles[-1])
time.sleep(1)
function()
time.sleep(1)
i += 1 #open new tab and run function.
it doesn't work because while true loop is repeated permanently. Is there any ways to run multiple functions together?
https://imgur.com/a/4SIVekS This picture shows what I want
According to your picture, what you want is to launch the function a set number of times (4?), and run those in parrallel.
On a single core, as is the normal behavior, straight up parallel processing is impossible. You need to access other cores and manage a decentralized processing. while is useless there. I'm worried the level of difficulty is over your current skills, but here we go.
The overall flow that you (probably, depends on the actual memory safety of your functions) need is:
- to create a thread pool with the set number of threads for the number of runs you want.
- indicate the function you need to run
- start them, making sure the start itself is non-blocking.
- ensure one functions's processing doesn't impact another's results. race conditions are a common problem.
- gather results, again, in a non-blocking way.
You can use several methods. I highly recommend you read up a lot on the following documentations.
Threading:
https://docs.python.org/3/library/threading.html
Multiprocessing:
https://docs.python.org/3/library/multiprocessing.html
I don't understand your question because I don't understand what your function is supposed to do.
while True:
will always create an infinite loop. "while" is a command that tells python to loop through the following block so long as the expression following it evaluates to True. True always evaluates to True.
It seems like you want to use a conditional, like you do in "while x < 4".
x < 4
...is an expression that evaluates to true when x is less than 4, and false if x is not less than 4. Everything below the line:
while x < 4:
will then run if x is less than 4, and when it's done running that code, it will go back and evaluate if x is less than 4 again, and if it is, run the code again. To include another while loop inside of that loop, that new loop also needs an expression to evaluate. If you want to evaluate the same expression, write it out:
while x < 4:
# do something
while x < 4:
#do more things
# do even more things
# change x at some point, or else you're in an infinite loop.
However, there's no reason to do that specifically, because you're already doing it. All of the code is only running when x < 4, so checking that condition again right there is redundant, and doing it in another loop doesn't make sense. If the inside loop is also incrementing x, then the outside loop won't loop and doesn't need to increment x.
Also, if you want a function to check a condition based on a variable outside the function, you'll want to pass things to that function.

Add time delay between every statement of python code

Is there an easy way to execute time delay (like time.sleep(3)) between every statement of Python code without having to explicitly write between every statement?
Like in the below Python Script which performs certain action on SAP GUI window. Sometimes, the script continues to the next statement before the previous statement is complete. So, I had to add a time delay between every statement so that it executes correctly. It is working with time delay, but I end up adding time.sleep(3) between every line. Just wondering if there is a better way?
import win32com.client
import time
sapgui = win32com.client.GetObject("SAPGUI").GetScriptingEngine
session = sapgui.FindById("ses[0]")
def add_record(employee_num, start_date, comp_code):
try:
time.sleep(3)
session.findById("wnd[0]/tbar[0]/okcd").text = "/npa40"
time.sleep(3)
session.findById("wnd[0]").sendVKey(0)
time.sleep(3)
session.findById("wnd[0]/usr/ctxtRP50G-PERNR").text = employee_num
time.sleep(3)
session.findById("wnd[0]").sendVKey(0)
time.sleep(3)
session.findById("wnd[0]/usr/ctxtRP50G-EINDA").text = start_date
time.sleep(3)
session.findById("wnd[0]/usr/tblSAPMP50ATC_MENU_EVENT/ctxtRP50G-WERKS[1,0]").text = comp_code
time.sleep(3)
session.findById("wnd[0]/usr/tblSAPMP50ATC_MENU_EVENT/ctxtRP50G-PERSG[2,0]").text = "1"
time.sleep(3)
session.findById("wnd[0]/usr/tblSAPMP50ATC_MENU_EVENT/ctxtRP50G-PERSK[3,0]").text = "U1"
time.sleep(3)
session.findById("wnd[0]/usr/tblSAPMP50ATC_MENU_EVENT").getAbsoluteRow(0).selected = True
time.sleep(3)
return "Pass"
except:
return "failed"
The right way to do what you asked for is almost certainly to use the debugger, pdb.
The right way to do what you want is probably something completely different: find some signal that tells you that the step is done, and wait for that signal. With problems like this, almost any time you pick will be way, way too long 99% of the time, but still too short 1% of the time. That signal may be joining a thread, or waiting on a (threading or multiprocessing) Condition, or getting from a queue, or awaiting a coroutine or future, or setting the sync flag on an AppleEvent, or… It really depends on what you're doing.
But if you really want to do this, you can use settrace:
def sleeper(frame, event, arg):
if event == 'line':
time.sleep(2)
return sleeper
sys.settrace(sleeper)
One small problem is that the notion of line used by the interpreter may well not be what you want. Briefly, a 'line' trace event is triggered whenever the ceval loop jumps to a different lnotab entry (see lnotab_notes.txt in the source to understand what that means—and you'll probably need at least a passing understanding of how bytecode is interpreted, at least from reading over the dis docs, to understand that). So, for example, a multiline expression is a single line; the line of a with statement may appear twice, etc.1
And there's probably an even bigger problem.
Sometimes, the script continues to next step before the previous step is fully complete.
I don't know what those steps are, but if you put the whole thread to sleep for 2 seconds, there's a good chance the step you're waiting for won't make any progress, because the thread is asleep. (For example, you're not looping through any async or GUI event loops, because you're doing nothing at all.) If so, then after 2 seconds, it'll still be just as incomplete as it was before, and you'll have wasted 2 seconds for nothing.
1. If your notion of "line" is closer to what's described in the reference docs on lexing and parsing Python, you could create an import hook that walks the AST and adds an expression statement with a Call to time.sleep(2) after each list element in each body with a module, definition, or compound statement (and then compiles and execs the result as usual).
Anything you want to happen in a program has to be explicitly stated - this is the nature of programming. This is like asking if you can print hello world without calling print("hello world").
I think the best advice to give you here is: don't think in terms of "lines", but think in term of functions.
use debugging mode and watch each and every line executing line by line.

possible django race condition

#receiver(post_save, sender=MyRequestLog)
def steptwo_launcher(sender, instance, **kwargs):
GeneralLogging(calledBy='MyRequestLog', logmsg='enter steptwo_launcher').save() # remember to remove this line
if instance.stepCode == 100:
GeneralLogging(calledBy='MyRequestLog', logmsg='step code 100 found. launch next step').save()
nextStep.delay(instance.requestId,False)
I think I just witness my code losing a race condition. The backend of my application updates the status of task one, and it writes a stepCode of 100 to the log when the next task should be started. The front end of the application polls to report the current step back to the end user.
It appears that after the backend created an entry with stepCode 100, the front request came in so soon after, that the if instance.stepCode == 100: was never found to be True. The GeneralLogging only reports one entry at the time of the suspected collision and does not launch the nextstep.
My question is to 1) Confirm this is possible, which I already suspect. and 2) A way to fix this so nextStep is not skipped due to the race condition.
This question lacks a bunch of potentially useful information (e.g. missing code, missing output), but any code of the form
if state == x:
change_state
has a potential race condition when multiple control paths hit this code.
Two of the most common ways to handle this problem are (1) locks:
with some_lock:
if state:
change_state
i.e. stop everyone else from hitting this code until we're done, and (2) queues:
queue.push(item_to_be_processed)
# somewhere else
item_to_be_processed = queue.pop()
A queue/lock implementation in a db could use select_for_update and use an extra processed field, i.e. let the "writer" process save the model with processed = False and have the "reader" process do:
from django.db import transaction
...
with transaction.atomic():
items = MyRequestLog.objects.select_for_update(skip_locked=True).filter(
stepCode=100,
processed=False
)
for item in items:
do_something_useful(item) # you might want to pull this outside of the atomic block if your application allows (so you don't keep rows locked for an extended period)
item.processed = True
item.save()
ps: check your database for support (https://docs.djangoproject.com/en/2.0/ref/models/querysets/#select-for-update)

Django 1.6 transactions to avoid race conditions

I'm trying to use Django 1.6 transactions to avoid race conditions on a game I'm developing. The game server has one simple goal: to pair two players.
My current approach is:
User wants to play
The server checks if there is anyone else waiting to play.
If there is not, it creates a GameConnection object (that has a unique identifier - uuid4).
If there is, it gets the GameConnection identifier and deletes the GameConnection.
This is the code:
# data['nickname'] = user's choice
games = GameConnection.objects.all()
if not games:
game = GameConnection.objects.create(connection=unicode(uuid.uuid4()))
game.nick1 = data["nickname"]
game.save()
response = HttpResponse(json.dumps({'connectionId': game.connection, 'whoAmI': 1, 'nick1': game.nick1, 'nick2': ""}))
else:
game = games[0]
conn = game.connection
nick1 = game.nick1
nick2 = data["nickname"]
game.delete()
response = HttpResponse(json.dumps({'connectionId': conn, 'whoAmI': 2, 'nick1': nick1, 'nick2': nick2}))
return response
Obviously there is a race condition on the code above. As this code is not atomic, it can happen that:
A checks for game connections. Finds none.
A creates a game connection.
B checks for game connections. Finds one (A).
C checks for game connections. Finds one (A).
B gets A's connection identifier and starts a game.
C gets A's connection identifier and starts a game.
I tried do but this whole block under with transaction.atomic():, or to use the #transaction.atomic decorator. But still, I am able to reproduce the race condition.
I am sure there is something about the transaction dynamics I am missing here. Can anyone shed a light?
#Sai is on track... the key is that the lock/mutex won't occur until a write (or delete). As coded, there will always be a time between "discovery" (read) of the pending connection and "claim" (write/lock) of the pending connection, with no way to know that a connection is in the process of being claimed.
If you are using PostgreSQL (pretty sure MySQL supports it, too), you can force the lock with "select for update", which will prevent another request from getting the same row until the transaction completes:
game = GameConnection.objects.all()[:1].select_for_update()
if game:
#do something, update, delete, etc.
else:
#create
Final note - consider something other than all() to be explicit about which game might be picked up (e.g., order by a "created" timestamp or something). Hope that helps.

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