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How do I make two functions share a variable?

My assignment is to make a secret number, which is 26, and make a guessing game saying the guess is either "too low" or "too high". I made two functions, int_guess for if the input is an integer and not_int_guess for when the input is not an integer. The problem that i have though is when im counting the amount of guesses, i dont know how to make both functions share a count of how many guesses they inputted.
print("Guess the secret number! Hint: it's an integer between 1 and 100...")
secret_num = 26
guess = int(input("What is your guess? "))
def int_guess(guess):
count = 0
while guess != 26:
if guess > secret_num:
print("Too high!")
guess = int(input("What is your guess? "))
count += 1
elif guess < secret_num:
print("Too low!")
guess = int(input("What is your guess? "))
count += 1
else:
print("You guessed it! It took you", count, "guesses.")
def not_int_guess(guess,count):
print("Bad input! Try again: ")
guess = int(input("What is your guess? "))
while guess != 26:
if guess > secret_num:
print("Too high!")
guess = int(input("What is your guess? "))
elif guess < secret_num:
print("Too low!")
guess = int(input("What is your guess? "))
else:
print("You guessed it! It took you", count, "guesses.")
try:
int_guess(guess)
except:
not_int_guess(guess,count)
One part of the assignment that i need to have is a try and except, the problem is that the count will reset to zero if the except is used, but i need the count to carry over to the exception case. I tried carrying the "count" variable over to the not_int_guess by placing it like not_int_guess(guess,count) but that doesnt work for a reason i dont understand.

Instead of using two functions, use the try and except within the while loop. That way everything is much neater and more efficient (also good to define functions before any main code):
def int_guess(secret_num):
count = 0
guess = 0 #Just defining it here so everything in the function knows about it
while guess != secret_num:
try:
guess = int(input("What is your guess? "))
except ValueError as err:
print("Not a number! Error:", err)
continue #This will make the program skip anything underneath here!
if guess > secret_num:
print("Too high!")
elif guess < secret_num:
print("Too low!")
count += 1 #Adds to count
#This will run after the while loop finishes:
print("You guessed it! It took you", count, "guesses.")
#Main code:
print("Guess the secret number! Hint: it's an integer between 1 and 100...")
int_guess(26)
Like this, the function will run until the user has guessed the number no matter what they input, while also keeping count through any errors

You can use the count variable outside the functions to use it in both the variables globally.
I have also made some changes to the code to make it work properly
print("Guess the secret number! Hint: it's an integer between 1 and 100...")
secret_num = 26
count = 0
guess = 0
def int_guess(guess):
count = 0
while guess != 26:
guess = int(input("What is your guess? "))
if guess > secret_num:
print("Too high!")
count += 1
elif guess < secret_num:
print("Too low!")
count += 1
else:
print("You guessed it! It took you", count, "guesses.")
def not_int_guess(guess):
print("Bad input! Try again: ")
int_guess(guess)
try:
int_guess(guess)
except:
not_int_guess(guess)

How to fix guessing game

The objective is to create a simple program that generates a number between 1 and 100, it will then ask the user to guess this, if they guess outside of the number range it should tell them to guess again, if not it should tell them whether their guess was too high or too low, prompting them to guess again. Once they do guess the correct number it should tell them they've won and the number of tries it took for them to guess it correctly.
Here is what I have so far
import random
def play_game():
number = random.randint(1, 100)
print("Guess a number between 1 and 100 inclusive.")
count = 1
while True:
guess = int(input("Your guess: "))
if guess > 0 and guess <= 100:
#the age is valid
return play_game
else:
print("Invalid number.")
return play_game()
if guess < number:
print("Too low.")
elif guess > number:
print("Too high.")
elif guess == number:
print("You won! You guessed it in " + str(count) + " tries.\n")
return
count+=1
play_game()
The issue I'm currently running into is when it checks to see if their guess was between 1-100 instead of moving on to weather or not their number was too how or to low, it stays and loops.
If anyone could help me with this issue and review the code in general I'd appreciate it.

I think the problem is with some indentation and some logical problems in the flow.
When you call play_game() from inside the game, it starts a completely different game
with different random_number.
A good code that satisfies your condition might look like the following
import random
def play_game():
number = random.randint(1, 100)
print("Guess a number between 1 and 100 inclusive.")
count = 1
while True:
guess = int(input("Your guess: "))
if guess > 0 and guess <= 100:
if guess < number:
print("Too low.")
elif guess > number:
print("Too high.")
elif guess == number:
print("You won! You guessed it in " + str(count) + " tries.\n")
return
count+=1
else:
print("Invalid number.")
play_game()

You could re-adjust your code:
1. if no. within range, run your high, low, match checks
2. break if guess matches the no
import random
def play_game():
number = random.randint(1, 100)
print("Guess a number between 1 and 100 inclusive.")
count = 0
while True:
count += 1
guess = int(input("Your guess: "))
if guess > 0 and guess <= 100:
#the age is valid
if guess < number:
print("Too low.")
elif guess > number:
print("Too high.")
elif guess == number:
print("You won! You guessed it in " + str(count) + " tries.\n")
break
else:
print("Invalid number, try again")
play_game()

The issue you are running into is because of incorrect indentation. The if-else statements that check whether the number is within the valid range are at the same indentation level as the while loop and thus are not executed within it. Simply indenting should fix the problem.
Furthermore, you have called play_game without parenthesis, making it incorrect syntax for a function call. However, rather than checking if the number is greater than 0 and lesser than 100, it would more optimal to check whether number is lesser than 0 or greater than 100, and if that is the case, print invalid number and call play_game().
It would look something like this:
while True:
if guess < 0 and guess > 100:
print ("Invalid number.")
return play_game()
The rest of your code looks good. I've also attached the link on the section of indentations of the Python documentation here.

While loops, if-else statements: Guess my number game

I'm a beginner using python, and am writing a "guess my number game". So far I have everything working fine. The computer picks a random number between 1 and 3 and asks the player to guess the number. If the guess is higher than the random number, the program prints "Lower", and vice versa. The player only has 5 tries, and when they run out, the player gets a message and the game ends. If the player guesses correctly, they are congratulated and the game ends. However, sometimes when the number is guessed correctly, the program doesn't print the congratulatory message and I can't figure out why...
import random
print("\tWelcome to 'Guess My Number'!:")
print("\nI'm thinking of a numer between 1 and 100.")
print("Guess carefully, you only have 5 tries!.\n")
#sets initial values
the_number = random.randint(1,3)
guess = int(input("Take a guess: "))
tries = 1
guesses = 4
#guessing loop
while guess != the_number:
if guess > the_number:
print("Lower...")
elif guesses <= 0:
print("Sorry, you're out of guesses! Try again...")
break
elif guess < the_number:
print("Higher...")
guess = int(input("Take a guess: "))
tries += 1
guesses -= 1
if guess == the_number:
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")

To answer your original question about the lack of congratulatory message for correct number, end the code with input(), to ensure it does not terminate before displaying the last message.
Order of calculation:
give input guess
reduce guesses (starting at 5), increase tries (starting at 1)
immediate break if guesses == 0
evaluate guess (lower, higher or equal, which would end while loop)
import random
print("\tWelcome to 'Guess My Number'!:")
print("\nI'm thinking of a numer between 1 and 3.")
print("Guess carefully, you only have 5 tries!.\n")
#sets initial values
the_number = random.randint(1,3)
guess = int(input("Take a guess: "))
tries = 1
guesses = 5
#guessing loop
while guess != the_number:
tries += 1
guesses -= 1
if guesses == 0:
print("Sorry, you're out of guesses! Try again...")
break
elif guess > the_number:
print("Lower...")
elif guess < the_number:
print("Higher...")
guess = int(input("Take a guess: "))
if guess == the_number:
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")
input()

Assuming everything else works, un-indent the final check. You can't check guess == the_number while it isn't equal
#guessing loop
while guess != the_number:
# do logic
# outside guessing loop
if guesses > 0:
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")

If you guess the number in your first try, the program will require another guess nevertheless since
guess = int(input("Take a guess: "))
tries += 1
guesses -= 1
comes before
if guess == the_number:
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")
when you already asked for a guess outside the loop. You should only ask for input inside the loop:
the_number = random.randint(1,3)
tries = 0
guesses = 5
#guessing loop
guess = None
while guess != the_number:
guess = int(input("Take a guess: "))
tries += 1
guesses -= 1
if guess > the_number:
print("Lower...")
elif guess < the_number:
print("Higher...")
if guess == the_number:
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")
if guesses <= 0:
print("Sorry, you're out of guesses! Try again...")
break

Python Number Guessing Game Need Help Avoiding Counting Duplicates in "Number of Guesses"

I am brand new to learning Python and am building a very simple number guessing game. The user guesses a number between 1-100, and are given feedback on whether their guess is too low or too high. When they guess the number correctly, the program tells them how many guesses they took. What I need help with: telling the user when they guessed a duplicate number if they have entered it already. I also want to exclude any duplicate guesses from the final guess count. What is the easiest way to do this?
Here is my game so far:
import random
print("Guess a number between 1-100")
the_number = random.randint(1, 100)
guess = int(input(""))
tries = 0
while guess != the_number:
if guess > the_number:
print("Lower")
if guess < the_number:
print("Higher")
guess = int(input("Guess again: "))
tries += 1
if guess == the_number:
print("You win! The number was", the_number)
print("And it only took you", tries, "tries!\n")

Keep track of the numbers guessed, only increasing if the user has not guessed a number already in our guessed set:
import random
print("Guess a number between 1-100")
the_number = random.randint(1, 100)
tries = 0
# store all the user guesses
guessed = set()
while True:
guess = int(input("Guess a number: "))
# if the guess is in our guesses set, the user has guessed before
if guess in guessed:
print("You already guessed that number!")
continue
# will only increment for unique guessed
tries += 1
if guess == the_number:
print("You win! The number was", the_number)
print("And it only took you", tries, "tries!\n")
break
elif guess > the_number:
print("Lower")
# if it's not == or >, it has to be <
else:
print("Higher")
# add guess each time
guessed.add(guess)
You also had some logic in regard to your ordering like taking a guess outside the loop which could have meant you never entered the loop if the user guessed first time.

this is how you should write the code.
import random
debug = True
def number_guessing():
previous_guesses = set()
tries = 0
print("Guess a number between 1-100")
random_number = random.randint(1, 100)
while True:
guess = int(input())
if guess in previous_guesses:
print("You already tried that number")
continue
previous_guesses.add(guess)
tries += 1
if random_number < guess:
print(f"Lower => previous attempts [{previous_guesses}] tries [{tries}]") if debug is True else None
elif random_number > guess:
print(f"Higher => previous attempts [{previous_guesses}] tries [{tries}]") if debug is True else None
elif guess == random_number:
print("You win! The number was", random_number)
print(f"And it only took you {tries} attempt{'s' if tries>1 else ''}!\n")
break
number_guessing()

Accumulators in python [closed]

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Closed 10 years ago.
I have to make an accumulator that counts the number of entries a user uses to guess a random number. I have all the while statements figured out but I can't get the piece that counts how many entries it took. Thanks for any help!
import random
secretNumber = random.randint(1,100)
secretNumber = int(secretNumber)
print("Guess a number between 1 and 100!")
number = input("Your guess: ")
number = int(number)
tries = 1
while number != secretNumber:
if number > secretNumber:
print("Too high!")
number = input("Your guess: ")
number = int(number)
if number < secretNumber:
print("Too low!")
number = input("Your guess: ")
number = int(number)
while number == secretNumber:
print("You got it in",tries,"tries")
break
the part I need help with is implementing the tries accumulator after the break

The first thing you want to ask is when you print tries, what are you getting?
Effectively, you will see you are always getting 1.
Because, you didn't increment. You didn't add as user keeps guessing.
Generally, you can write tries = tries + 1 for each guess.
tries = 1
while number != secretNumber:
if number > secretNumber:
print("Too high!")
tries = tries + 1 # here is the addition
number = input("Your guess: ")
number = int(number)
if number < secretNumber:
print("Too low!")
tries = tries + 1 # here is the addition
number = input("Your guess: ")
number = int(number)
while number == secretNumber:
print("You got it in",tries,"tries")
break
This code still has some problem. The 2nd loop doesn't make sense. A loop sounds like loop. It keeps running until a condition is met or someone (you) interrupts it and tells it to exit.
If user found the number, then while number !- secretNumber will become False right?
It will exit the first loop. Hence, you can skip the second loop and congratulate the user.
Another minor thing is the double if statements.
if statements are expensive. Computer has to test to guess right. But either way, there is a different way to do multiple conditions.
if condition1 met:
do this
elif condition2 met:
do this
elif condition3 met:
do this
elif more....
else: # optional, but encourage, this is a default fallback case
do this
If number > secretNumber is True, then you don't need to test number < secretNumber in theory. It makes the code cleaner and logically sound by adapting if .. elif .. else
import random
secretNumber = random.randint(1,100)
secretNumber = int(secretNumber)
print("Guess a number between 1 and 100!")
number = input("Your guess: ")
number = int(number)
tries = 1
while number != secretNumber:
if number > secretNumber:
print("Too high!")
tries = tries + 1 # here is the addition
number = input("Your guess: ")
number = int(number)
elif number < secretNumber:
print("Too low!")
tries = tries + 1 # here is the addition
number = input("Your guess: ")
number = int(number)
print("You got it in",tries,"tries")
# another way to print is
# print("You got it in %s tries" % tries)
# print("You got it in {t} tries".format(t=tries))
For beginners, use print to help debug your code.

Just put the line
tries += 1
in the loop- this line increases the tries variable by 1.
I also took the liberty of shortening it by removing part of it from the if statement, and removed the second while loop (since the loop always occurs exactly once there's no reason to put a loop there):
while number != secretNumber:
tries += 1
if number > secretNumber:
print("Too high!")
if number < secretNumber:
print("Too low!")
number = input("Your guess: ")
number = int(number)
print("You got it in",tries,"tries")

you can just add to the number of tries if you get it wrong:
...
while number != secretNumber:
tries += 1
if number > secretNumber:
print("Too high!")
...
Also, at the end instead of this:
while number == secretNumber:
print("You got it in",tries,"tries")
break
you can just use this:
print("You got it in",tries,"tries")
because it would only get to this point if you get the number right.
Another thing, tries should initially be equal to 0, no one, because at the beginning you tried 0 times, not 1.

import random
i = 0
rand_num = random.randint(1, 100)
while True:
i += 1
try:
guess = int(input('Guess the number: ')
except ValueError:
print('Invalid input, try again')
continue
if guess < rand_num:
print('Too low, try again')
elif guess > rand_num:
print('Too high, try again')
else:
print('You got it in ', tries, ' tries!')
break

You want to add the extra line tries += 1 in the while loop. What this does is add 1 to tries every guess. So then your code would be:
import random
secretNumber = random.randint(1,100)
secretNumber = int(secretNumber)
print("Guess a number between 1 and 100!")
number = input("Your guess: ")
number = int(number)
tries = 1
while number != secretNumber:
if number > secretNumber:
print("Too high!")
number = input("Your guess: ")
number = int(number)
if number < secretNumber:
print("Too low!")
number = input("Your guess: ")
number = int(number)
while number == secretNumber:
print("You got it in",tries,"tries")
break