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Check if string follow a strict format via Regex Python [closed]

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I have a string that might have any of the following format (example) :
1111__1111
1111__1111_11
111_11A_11
I have added the following check :
import re
print(bool(re.match("\d__\d","1111_1111"))
print(bool(re.match("\d__\d_\d","1111_1111_11"))
print(bool(re.match("\d_\d[A-Za-z]_\d","111_11A_11"))
I don't think the regex is correct because when I introduce a character in the first regex for example it returns me True Always.
can you please point me to a solution?
Thank you

It returns True because the pattern is trying to find matches based on each one of the characters inside the pattern string.
The following regular expression finds exact matches for the three scenarios:
print(bool(re.match("(^\d{4}__\d{4}$)","1111__1111")))
print(bool(re.match("(^\d{4}\_\d{4}\_\d{2}$)","1111_1111_11")))
print(bool(re.match("(^\d{3}_\d{2}[A-Z]_\d{2}$)","111_11A_11")))

how can I solve this in python? [closed]

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Id codes at a company come in the form x-y-zzzzzz, where x is a digit and y is a letter and zzzzzz represents a string of 6 letters. Write a function which takes in a code as an input (e.g. 3-a-abaabb) and returns the zzzzzz part (e.g. abaabb).
I have no idea how to start and solve this question. any help would be much appreciated. My IDE is pycharm (solving python coding problems) I basically need to create a function which takes the code as an input and will return the last 6 letters

You can use str.spit('-') then search count in code with repeat is equal or not, like below:
def fnd_code(code):
repeat, char, search = code.split('-')
return search.count(char) == int(repeat)
print(fnd_code('3-a-abaabb'))
print(fnd_code('4-a-abaabb'))
Output:
True
False

Associating the second word of a sentence to a variable. (Python) [closed]

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I'm currently trying to perform this, but my book for class doesn't show anything in relation to Boolean variables or anything related to this problem. I've been looking online for a while and everything is way too complicated for something that should be simple according the unit. If the solution is posted here, what was typed in to find it? Maybe I need to rephrase my question.
https://i.stack.imgur.com/RMSEx.png

def getSecondWord(sentence):
res = sentence.split(' ')[1]
if res.endswith('.'):
return res[:-1]
else:
return res
inputSentence = 'broccoli is delicious'
secondWord = getSecondWord(inputSentence)
print("second word is:", secondWord)

How can I eliminate typos from being logged in a keylogger? [closed]

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Ideally, I'd like the program to erase/un-log any and all erroneous character(s) when the Backspace key is pressed and replace them with the correct characters.
After searching for solutions to no avail, I'm wondering if it's even possible? If it is, my guess is that the code needed to do this might involve the modules: 're', 'readchar', 'msvcrt', 'getch' or some combination of those, in addition to using 'string.replace', 'x.remove', 'r/R', 'raw_input' 'x.translate', or the like. But I don't have the knowledge or skills yet to figure out how to apply them.

This code may be what you are looking for:
import re
text = "Helll[Back Space]o how are yoo[Back Space]u"
result = list(text)
for (start, end) in [(m.start(), m.end()) for m in re.finditer('\[Back Space\]', text)]:
text = text.replace(''.join(result[start-1:end]), '')
print text
Output:
Hello how are you

Matching strings and extracting parts [closed]

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I've an issue here. I have a string and I want to extract parts of it using regex. Here is the string
{{name}} I love me some work {{hero}}
I want to extract
[{{name}}, {{hero}}]
also in a case where the string exist as
{{name} I love me some work {{hero, come in {here, this is right}
I still want to get
[{{name}, {{name, {here, right}]
I hope this makes sense. I am working with Python.

If you want ['{{name}}', '{{hero}}', '{{hero, come in {here, this is right}'] use #Avinash's regex.
If you want ['{{name}}', '{{hero}}', '{{hero', {here', 'right}'] use the following:
re.findall(r'{+\w+}*|{*\w+}+', s)
RegEX DEMO

Have you tried the following?
import re
s = '{{name} I love me some work {{hero, come in {here, this is right}'
print re.findall(r'\{.*?\}', s)