Develop Reference

Python having problem with reading mp3 file [duplicate]

This question already has answers here:
Python speech recognition error converting mp3 file
(2 answers)
Closed 2 years ago.
import speech_recognition as sr
print(sr.__version__)
r = sr.Recognizer()
file_audio = sr.AudioFile('damn1.mp3')
with file_audio as source:
audio_text = r.record(source)
print(type(audio_text))
print(r.recognize_google(audio_text))
I have a problem running this program. The output I get is as following:
Traceback (most recent call last):
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\site-packages\speech_recognition\__init__.py", line 203, in __enter__
self.audio_reader = wave.open(self.filename_or_fileobject, "rb")
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\wave.py", line 510, in open
return Wave_read(f)
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\wave.py", line 164, in __init__
self.initfp(f)
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\wave.py", line 131, in initfp
raise Error('file does not start with RIFF id')
wave.Error: file does not start with RIFF id
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\site-packages\speech_recognition\__init__.py", line 208, in __enter__
self.audio_reader = aifc.open(self.filename_or_fileobject, "rb")
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\aifc.py", line 917, in open
return Aifc_read(f)
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\aifc.py", line 352, in __init__
self.initfp(file_object)
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\aifc.py", line 316, in initfp
raise Error('file does not start with FORM id')
aifc.Error: file does not start with FORM id
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\site-packages\speech_recognition\__init__.py", line 234, in __enter__
self.audio_reader = aifc.open(aiff_file, "rb")
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\aifc.py", line 917, in open
return Aifc_read(f)
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\aifc.py", line 358, in __init__
self.initfp(f)
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\aifc.py", line 314, in initfp
chunk = Chunk(file)
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\chunk.py", line 63, in __init__
raise EOFError
EOFError
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\Users\kubar\OneDrive\Pulpit\men.py", line 7, in <module>
with file_audio as source:
File "C:\Users\kubar\AppData\Local\Programs\Python\Python38-32\lib\site-packages\speech_recognition\__init__.py", line 236, in __enter__
raise ValueError("Audio file could not be read as PCM WAV, AIFF/AIFF-C, or Native FLAC; check if file is corrupted or in another format")
ValueError: Audio file could not be read as PCM WAV, AIFF/AIFF-C, or Native FLAC; check if file is corrupted or in another format

MP3 is a compressed format. Never use it when you manipulate audio since the large majority of tools handling audio does it on non compressed audio streams. So, even when such tool accepts your file, it probably starts by converting it, which consumes time and spaces. Moreover, MP3 is never used by professionals working on audio (musician, engineers, etc.) : avoid using it with audio materials having some importance for your work (even for archiving because the compression is not reversible), always prefer using non compressed formats as WAV or AIF instead (here the library seems to expect AIF).

How can read Minecraft .mca files so that in python I can extract individual blocks?

I can't find a way of reading the Minecraft world files in a way that i could use in python
I've looked around the internet but can find no tutorials and only a few libraries that claim that they can do this but never actually work
from nbt import *
nbtfile = nbt.NBTFile("r.0.0.mca",'rb')
I expected this to work but instead I got errors about the file not being compressed or something of the sort
Full error:
Traceback (most recent call last):
File "C:\Users\rober\Desktop\MinePy\MinecraftWorldReader.py", line 2, in <module>
nbtfile = nbt.NBTFile("r.0.0.mca",'rb')
File "C:\Users\rober\AppData\Local\Programs\Python\Python36-32\lib\site-packages\nbt\nbt.py", line 628, in __init__
self.parse_file()
File "C:\Users\rober\AppData\Local\Programs\Python\Python36-32\lib\site-packages\nbt\nbt.py", line 652, in parse_file
type = TAG_Byte(buffer=self.file)
File "C:\Users\rober\AppData\Local\Programs\Python\Python36-32\lib\site-packages\nbt\nbt.py", line 99, in __init__
self._parse_buffer(buffer)
File "C:\Users\rober\AppData\Local\Programs\Python\Python36-32\lib\site-packages\nbt\nbt.py", line 105, in _parse_buffer
self.value = self.fmt.unpack(buffer.read(self.fmt.size))[0]
File "C:\Users\rober\AppData\Local\Programs\Python\Python36-32\lib\gzip.py", line 276, in read
return self._buffer.read(size)
File "C:\Users\rober\AppData\Local\Programs\Python\Python36-32\lib\_compression.py", line 68, in readinto
data = self.read(len(byte_view))
File "C:\Users\rober\AppData\Local\Programs\Python\Python36-32\lib\gzip.py", line 463, in read
if not self._read_gzip_header():
File "C:\Users\rober\AppData\Local\Programs\Python\Python36-32\lib\gzip.py", line 411, in _read_gzip_header
raise OSError('Not a gzipped file (%r)' % magic)
OSError: Not a gzipped file (b'\x00\x00')

Use anvil parser. (Install with pip install anvil-parser)
Reading
import anvil
region = anvil.Region.from_file('r.0.0.mca')
# You can also provide the region file name instead of the object
chunk = anvil.Chunk.from_region(region, 0, 0)
# If `section` is not provided, will get it from the y coords
# and assume it's global
block = chunk.get_block(0, 0, 0)
print(block) # <Block(minecraft:air)>
print(block.id) # air
print(block.properties) # {}
https://pypi.org/project/anvil-parser/

According to this page, the .mca files is not totally kind of of NBT file. It begins with an 8KiB header which includes the offsets of chunks in the region file itself and the timestamps for the last updates of those chunks.
I recommend you to see the offical announcement and this page for more information.

How do I write an image to Dropbox directly?

I'm trying to reduce read/write on my sd card by writing image files to DropBox directly. I captured the image into stream, but I don't know how to write it to Dropbox. This is with the raspberry pi.
dbx = dropbox.Dropbox('token')
stream = io.BytesIO()
with picamera.PiCamera() as camera:
camera.resolution = (1280,960)
camera.capture(stream,format='jpeg')
stream.seek(0)
im = Image.open(stream)
dbx.files_upload(im,"/test.jpg",mute=True)
i get the following error, but not sure what it means or how to fix it.
Traceback (most recent call last):
File "./camera.py", line 25, in <module>
dbx.files_upload(im,"/test.jpg",mute=True)
File "/usr/local/lib/python2.7/dist-packages/dropbox/base.py", line 1225, in files_upload
f,
File "/usr/local/lib/python2.7/dist-packages/dropbox/dropbox.py", line 249, in request
timeout=timeout)
File "/usr/local/lib/python2.7/dist-packages/dropbox/dropbox.py", line 341, in request_json_string_with_retry
timeout=timeout)
File "/usr/local/lib/python2.7/dist-packages/dropbox/dropbox.py", line 385, in request_json_string
type(request_binary))
TypeError: expected request_binary as binary type, got <type 'instance'>

SimpleIDML How to convert IDML to PDF?

I am new to INDD CC Server. I have Implemented Indesign server running on Windows. I need to convert IDML to PDF but having issues.
I have used SimpleIDML Python library to manipulate Adobe(r) IDML(r) files.
My sample script is
I2P.py
from simple_idml.indesign import indesign
idml_file = "/home/user/Project/EPS/media/test/2-idml/test001.idml"
indd_file = "/home/user/Project/EPS/media/test/InDesigndocument/test001.indd"
url_path = "http://192.168.1.1:12345/"
client_dir = "/home/user/Project/EPS/media/source"
server_dir = "/home/user/Project/EPS/media/server"
response = indesign.save_as(indd_file, [{
"fmt": "pdf",
"params": {"colorSpace": "CMYK"},
}],
url_path,
client_dir,
server_dir)[0]
with open("my_file.pdf", "w+") as f:
f.write(response)
In documentation :
response = indesign.save_as("/path_to_file.indd", [{
"fmt": "pdf",
"params": {"colorSpace": "CMYK"},
}],
"http://url-to-indesign-server:port",
"/path/to/client/workdir",
"/path/to/indesign-server/workdir")[0]
When i run I2P script throws me error as :
Traceback (most recent call last):
File "ItoP.py", line 12, in <module>
server_path)[0]
File "/home/user/eps2_env/local/lib/python2.7/site-packages/simple_idml/indesign/indesign.py", line 71, in new_func
logger, logger_extra)
File "/home/user/eps2_env/local/lib/python2.7/site-packages/simple_idml/indesign/indesign.py", line 180, in save_as
responses = map(lambda fmt: _save_as(fmt), dst_formats_params)
File "/home/user/eps2_env/local/lib/python2.7/site-packages/simple_idml/indesign/indesign.py", line 180, in <lambda>
responses = map(lambda fmt: _save_as(fmt), dst_formats_params)
File "/home/user/eps2_env/local/lib/python2.7/site-packages/simple_idml/indesign/indesign.py", line 149, in _save_as
response = cl.service.RunScript(params)
File "/home/user/eps2_env/local/lib/python2.7/site-packages/suds/client.py", line 542, in __call__
return client.invoke(args, kwargs)
File "/home/user/eps2_env/local/lib/python2.7/site-packages/suds/client.py", line 602, in invoke
result = self.send(soapenv)
File "/home/user/eps2_env/local/lib/python2.7/site-packages/suds/client.py", line 649, in send
result = self.failed(binding, e)
File "/home/user/eps2_env/local/lib/python2.7/site-packages/suds/client.py", line 702, in failed
r, p = binding.get_fault(reply)
File "/home/user/eps2_env/local/lib/python2.7/site-packages/suds/bindings/binding.py", line 265, in get_fault
raise WebFault(p, faultroot)
suds.WebFault: Server raised fault: 'The specified script file can not be found: /home/user/Project/EPS/media/server/tmp9LVUWj/save_as.jsx'
Manually i can see dynamically created dir tmp9LVUWj inside server dir. Server path expecting on same time.
Not able to figure out how to set indesign-server/workdir and access in code and how to solve ? I have spend much time on this and not able find help or example code.
Or is there other python package to convert from IDML to PDF.
Thanks in advance

You wrote,
Manually I can see dynamically created dir tmp9LVUWj inside server
dir.
That is true, but that is not the error. It is stating that it cannot find a JSX file named save_as.jsx within that directory. Is that in fact the name of the JSX file that you were intending to place there, or the file that is residing there now?

Dropbox Python API: File size detection may have failed

I'm attempting to upload a text file to Dropbox using this code:
def uploadFile(file):
f = open('logs/%s.txt' % file)
response = client.put_file('/%s.txt' % file, f)
print "Uploaded log file %s" % file
Connecting to dropbox works perfectly fine, it's just when I upload files I recieve this error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Python27\lib\site-packages\dropbox_python_sdk-1.5.1-py2.7.egg\dropbox
\client.py", line 352, in put_file
return self.rest_client.PUT(url, file_obj, headers)
File "C:\Python27\lib\site-packages\dropbox_python_sdk-1.5.1-py2.7.egg\dropbox
\rest.py", line 265, in PUT
return cls.IMPL.PUT(*n, **kw)
File "C:\Python27\lib\site-packages\dropbox_python_sdk-1.5.1-py2.7.egg\dropbox
\rest.py", line 211, in PUT
return self.request("PUT", url, body=body, headers=headers, raw_response=raw
_response)
File "C:\Python27\lib\site-packages\dropbox_python_sdk-1.5.1-py2.7.egg\dropbox
\rest.py", line 174, in request
raise util.AnalyzeFileObjBug(clen, bytes_read)
dropbox.util.AnalyzeFileObjBug:
Expected file object to have 18 bytes, instead we read 17 bytes.
File size detection may have failed (see dropbox.util.AnalyzeFileObj)
Google has given me no help with this one.

Sounds like you are a victim of newline unification. The file object reports a file size of 18 bytes ("abcdefghijklmnop\r\n") but you read only 17 bytes ("abcdefghijklmnop\n").
Open the file in binary mode to avoid this:
f = open('logs/%s.txt' % file, 'rb')
The default is to use text mode, which may convert '\n' characters to a platform-specific representation on writing and back on reading.