I'm working in PyCharm. I haven't been programming for a few months and when I came back I saw a problem.
There are 2 user-input-taking variables, input is converted to int.
height = int(input())
width = int(input())
(it's literally entire code, there's nothing more)
When I run the program and give the 1st integer value, it's still fine, but the 2nd integer causes the following error:
ValueError: invalid literal for int() with base 10: ''
For some reason, it is "ValueError", though I just give it integer value (see screen at the end) and it seems to indicate that I gave it an empty string which is untrue (again, see the screen - I even marked the values I had given; in this case it was 4 and 5).
If I put some code between the 2 variables, like below, the problem doesn't appear:
height = int(input())
print(height)
width = int(input())
Also note that if it's just one variable, the problem doesn't appear.
And the problem appears only in PyCharm, I did the same in VSCode and everything worked properly. I also reinstalled PyCharm to check if it helps, but it didn't.
I suppose the problem is related to PyCharm, but since hard reinstall (deleting all that Revo Uninstaller found being related to PyCharm) didn't help I have no more ideas...
Visualization:
error
Please, check your python --version in virtual environment (it should be python 3.x)
I just ran the code myself (with a few amendments just to see the prompts) and it runs completely fine in my vs code even before my prompt amendments.
height = int(input("Input Height: "))
width = int(input("Input Width: "))# Write your code here :-)
area = height * width
print(area)
I would suggest checking you have the most update version of python and that everything is configured correctly on your machine.
Also it might help to re-save the file and re run.
It seems to be a known issue which will be fixed in the next PyCharm version.
See: https://youtrack.jetbrains.com/issue/PY-54238/STDIN-is-lost-for-a-second-input-call
As suggested by the support current workaround is to enable the "Emulate terminal in output console".
Related
If I run
python -m manimlib scene.py ket_bra
My scene renders fine into the interactive viewer, but I don't get any output file, the terminal prints the following
ManimGL v1.6.1
[13:55:48] INFO Using the default configuration file, which you can modify in `c:\users\miika\manim\manimlib\default_config.yml` config.py:323
INFO If you want to create a local configuration file, you can create a file named `custom_config.yml`, or run `manimgl --config` config.py:324
WARNING You may be using Windows platform and have not specified the path of `temporary_storage`, which may cause OSError. So it is recommended to specify the `temporary_storage` in the config file config.py:290
(.yml)
(process:3548): GLib-GIO-WARNING **: 13:55:49.613: Unexpectedly, UWP app `Clipchamp.Clipchamp_2.3.0.0_neutral__yxz26nhyzhsrt' (AUMId `Clipchamp.Clipchamp_yxz26nhyzhsrt!App') supports 46 extensions but has no verbs
If I add the parameter -p to the command then the interactive window remains blank and doesn't render the scene and in no case do I get an output file which is what I'm looking for and the terminal output is the same as before. Also if it's of note the background is grey, even tho it appears to be black in all samples that I can find. I have absolutely no idea what's going on as I can't find anybody else with a similar issue. I'm using windows 10 and v1.6.1 of 3b1b manim. The scene in this case is as follows (though this issue appears regardless of what the scene is)
from manimlib import *
class ket_bra(Scene):
def construct(self):
ket_q0 = Tex(r"|q_0\rangle")
ket_0 = Tex(r"|0\rangle")
ket_1 = Tex(r"|1\rangle")
ket_0_v2 = Tex(r"|0\rangle")
ket_1_v2 = Tex(r"|1\rangle")
ket_0_v3 = Tex(r"""|0\rangle=\begin{pmatrix}
1\\
0
\end{pmatrix}""")
ket_1_v3 = Tex(r"""|1\rangle=\begin{pmatrix}
0\\
1
\end{pmatrix}""")
bra_kets = VGroup(ket_q0, ket_0, ket_1).arrange(RIGHT, buff=1)
v_bra_kets = VGroup(ket_0_v2, ket_1_v2).arrange(RIGHT, buff=1.5)
bra_kets_def = VGroup(ket_0_v3, ket_1_v3).arrange(RIGHT, buff=1.5)
self.play(Write(ket_q0), Write(ket_0), Write(ket_1))
self.wait(0.5)
self.play(FadeOut(ket_q0))
self.play(Transform(ket_0, ket_0_v2), Transform(ket_1, ket_1_v2))
self.wait(1)
self.play(Transform(ket_0, ket_0_v3), Transform(ket_1, ket_1_v3))
Well I fixed the problem, without fixing the problem, I just switched to the community edition of manim and it works exactly as intended, so if you encounter the same problem and you're using 3b1b manim version, I reccomend just switching to the community version of manim, they are mostly functionally equivalent, but the community edition appears to be less buggy at least for me. Here's a super easy installation guide for it https://docs.manim.community/en/stable/installation/windows.html
However, I won't mark this as the best answer, because I didn't really solve the problem, and I still get the following warning and have no idea what it is. However, it appears to not affect functionality so it's fine, lol.
Windows Solution
Create TempLatex directory in C drive
Find manimlib/default_config.yml in the manim (manimgl version) directory and open it with a text editor
Modify line 18: before: temporary_storage: "" after: temporary_storage: "C:/TempLatex "
Save
From:
https://github.com/3b1b/manim/issues/1661#issuecomment-996575974
The following code works fine on both the jupiter notebook and the pycharm but its showing runtime error on codechef. The code is to check whether the permutation is ambiguous or not.
for i in range(int(input())):
n=int(input())
l=list(map(int,input().split()))
p=l[:]
for j in range(n):
p[l[j]-1]=j+1
if(p==l):
print("ambiguous")
else:
print("not ambiguous")
Welcome to Stack Overflow!
When posting, it usually helps to add more information, such as the error message itself. Regardless, I pasted your code into Python and I've deduced that the problem arises from the input() statement- I'm not sure what 'code chef' is, but it probably doesn't know that the user should input an integer into the input() prompt.
Therefore, a workaround is to hardcode your inputs as variables:
input1 = "5"
input2 = ...
for i in range(int(input1)):
n=int(input2)
...
I am 12 years old and working on my science fair project. 1000s of packages are stolen everyday so for my science fair project I am building a thing that goes on peoples porches. It detects a package and when the package is taken off without verification it beeps very loudly and takes a picture of the thief. I am writing the code in python 3 on my raspberry pi. I have never coded in python before but I know c and html and css. I haven't added the verification part yet but that will be somewhere in the code eventually and it will change the pin value to 0 or 1 if PIN is entered. **My code is giving me this error:
if pin == 1
^
SyntaxError: invalid syntax**
from Bluetin_Echo import Echo
import RPi.GPIO as GPIO
import time
import nexmo
import picamera
GPIO.setup(40,GPIO.OUT)
pin = 1
TRIGGER_PIN = 38
ECHO_PIN = 36
result = echo.read('in')
alarm = 40
speed_of_sound = 315
echo = Echo(TRIGGER_PIN, ECHO_PIN, speed_of_sound)
if pin == 1
if result < '5'
if result >= '10'
GPIO.output(14, 1)
<code>
In Python, since there are no brackets when declaring a block, we rely on indentation and punctuation. The : symbol is used to start an indent suite of statements in case of if, while, for, def and class statements.
if expression:
# something
pass
while expression:
# something
pass
for x in sequence:
# something
pass
def fct():
# something
pass
(pass is a null operation, it does nothing; useful in places where your code will eventually go, but has not been written yet)
So, your code should actually be:
if pin == 1:
if result < '5':
if result >= '10':
GPIO.output(14, 1)
Also, take care that:
You are comparing result with '5' and '10' as strings, not as numbers; I'm not saying this is really a mistake, but are you sure these should't be numbers?
You'll never reach the line with GPIO.output(14, 1). You check the result to be less than 5, but later, bigger than 10, which is impossible.
Since you are a beginner with Python, I recommend you to search in the documentation the things you struggle with. There are also nice tutorials on Python on different websites such CodeAcademy or w3schools.
I also recommend you to use an IDE for your projects, one that supports Python. Most of the time, they will point out the syntax errors you make before executing the code. I'm using Pycharm for my projects (you can download the Community version for free). You can also set up Sublime Text 3, Atom, Visual Code or Notepad++ with the appropriate plugins to help you.
Good luck with your project!
I'm getting started with Codechef. I submitted following code in python to solve this question.
The code below works fine with codechef's online (python) IDE as well as my local IDE. But, when I submit it on codechef, it results in Runtime Error (NZEC). Can someone explain to me the reason behind this?
withdrawCash = int(input())
totalCash = int(input())
if withdrawCash < totalCash and withdrawCash % 5 is 0:
totalCash = (totalCash - withdrawCash) - 0.5
print(totalCash)
The problem supplies both the inputs in a single line. Your code waits for input in 2 lines. Change it to:
withdrawCash,totalCash = map(int,raw_input.split())
NZEC (Non Zero Exit Code) occurs when your code doesn't return zero on exit. It can happen due to a number of reasons, but if splitting the input doesn't solve the problem, add an exception for EOFerror. Just write:
try:
withdrawCash = int(input().split()) # raw_input in the case of Python 2
except EOFerror:
print ("exit") # this is jst a pseudo statement `
Use indentation properly. I am currently using an android app of stack exchange in which writing code is not so easy. codechef is pretty poor when it comes to Python. Switch to any other lang for CP.
Try directly submitting the code without running it on Codechef ide because it with me also it showed the same but when I submitted directly I got submitted successfully. so Directly submit your code.
Running this code a few times presents no issues. Upon attempting to show a friend, it doesn't work. It just hangs after the input. It's worked quite a few times before but never again unfortunately.
I've tried rewriting the code in brackets, rewriting the code to a local directory instead of the Google Drive folder I have and I've even tried rewriting from scratch in regular notepad. All this was tried in case some sort of encoding issue had occured. No such luck. I figure something is wrong with the interpreter but I'm not sure how to remedy the situation.
def bin2dec():
bin = []
a = int(input("What number are you converting to binary?: "))
while a > 0:
if a % 2 == 0:
bin.insert(0, 0)
a = a/2
elif a % 2 == 1:
bin.insert(0, 1)
a = a/2-0.5
else:
#repetition
print("Your binary equivalent is:", bin)
repeat = input("Would you like to convert another binary number?: ")
if repeat == "yes":
bin2dec()
bin2dec()
Oh....welp. It seems the problem was actually that I somehow installed two versions of pythons and I guess they had been interfering with each other. Reason I'm not deleting this Q is because I'm sure I'm not the only one who's made this mistake. However, others have probably made this mistake in an effort to ensure compatibility between versions. Bad idea.