Develop Reference

Website not returning data that I want using beautifulsoup, but it shows up fine in my browser

I'm trying to scrape some data from this website but getting a 403 error. When I open it in my browser its not giving me the error. Help would be appreciated. This is my first time trying any web scraping. I think I need something different in my header? not sure. thanks
import requests
from bs4 import BeautifulSoup as bs
import pandas as pd
pp_props_url = 'https://api.prizepicks.com/projections?league_id=7&per_page=250&single_stat=true'
headers = {
'Connection': 'keep-alive',
'Accept': 'application/json; charset=UTF-8',
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/106.0.0.0 Safari/537.36',
'Access-Control-Allow-Credentials': 'true',
'Sec-Fetch-Site': 'same-origin',
'Sec-Fetch-Mode': 'cors',
'Referer': 'https://app.prizepicks.com/',
'Accept-Encoding': 'gzip, deflate, br',
'Accept-Language': 'en-US,en;q=0.9'
}
url = 'https://api.prizepicks.com/projections'
r = requests.get(url, headers=headers)
print(r)
df = pd.json_normalize(r.json()['data'])
print(df)
I get a 403 error and its not returning the data I want.

The following code should work:
import requests
from bs4 import BeautifulSoup as bs
import pandas as pd
pp_props_url = 'https://api.prizepicks.com/projections?league_id=7&per_page=250&single_stat=true'
headers = {
'Connection': 'keep-alive',
'Accept': 'application/json; charset=UTF-8',
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/106.0.0.0 Safari/537.36',
'Access-Control-Allow-Credentials': 'true',
'Sec-Fetch-Site': 'same-origin',
'Sec-Fetch-Mode': 'cors',
'Referer': 'https://app.prizepicks.com/',
'Accept-Encoding': 'gzip, deflate, br',
'Accept-Language': 'en-US,en;q=0.9'
}
r = requests.get(pp_props_url, headers=headers)
print(r)
df = pd.json_normalize(r.json()['data'])
print(df)

How do I send a HTTP/2 pseudo-headers with requests?

This code is to post a form data
headers = {
'authority': 'ec.ef.com.cn',
'user-agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.106 Safari/537.36',
'accept': '*/*',
'accept-language': 'en-US,en;q=0.9,ru-RU;q=0.8,ru;q=0.7,uk;q=0.6,en-GB;q=0.5',
}
s = requests.Session()
response = s.post(url, headers = headers)
which seems different to what Chrome does
I understand :authority is a kind of HTTP/2 Headers. How do I send it with Python requests?

You could use hyper.contrib.HTTP20Adapter, and set the mount(),like:
from hyper.contrib import HTTP20Adapter
import requests
def getHeaders():
headers = {
":authority": "xxx",
":method": "POST",
":path": "/login/secure.ashx",
":scheme": "https",
"User-Agent": "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_3) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36",
"X-Requested-With": "XMLHttpRequest"
}
return headers
sessions=requests.session()
sessions.mount('https://xxxx.com', HTTP20Adapter())
r=sessions.post(url_search,data=playload,headers=getHeaders())
Refer to a Chinese blog

Loop through Dataframe column of URLs and parse out html tag

This shouldn't be too hard, although I can't figure it, i'm betting i'm making a dumb mistake.
Here's the code that works on an individual link and returns the zestimate (the req_headers variable prevents throwing a captcha):
req_headers = {
'accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'accept-encoding': 'gzip, deflate, br',
'accept-language': 'en-US,en;q=0.8',
'upgrade-insecure-requests': '1',
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36'
}
link = 'https://www.zillow.com/homedetails/1404-Clearwing-Cir-Georgetown-TX-78626/121721750_zpid/'
test_soup = BeautifulSoup(requests.get(link, headers=req_headers).content, 'html.parser')
results = test_soup.select_one('h4:contains("Home value")').find_next('p').get_text(strip=True)
print(results)
Here's the code i'm trying to get to work and return the zestimate for each link and add to a new dataframe column, but I get AttributeError: 'NoneType' object has no attribute 'find_next' (Also, imagine i have a dataframe column of different zillow house links):
req_headers = {
'accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'accept-encoding': 'gzip, deflate, br',
'accept-language': 'en-US,en;q=0.8',
'upgrade-insecure-requests': '1',
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36'
}
for link in df['links']:
test_soup = BeautifulSoup(requests.get(link, headers=req_headers).content, 'html.parser')
results = test_soup.select_one('h4:contains("Home value")').find_next('p').get_text(strip=True)
df['zestimate'] = results
Any help is appreciated.

I had a space before and after the links in my dataframe column :/. That was it. The code works fine. just an oversight on my part. Thanks all

Can someone tell me how to read that file in python?

This is the result of using scrapy-splash in Python after browsing a LinkedIn page. Here is its beginning.
b'<html><head></head><body>\x1f\xef\xbf\xbd\x08\x03\xef\xbf\xbd\xef\xbf\xbdko+I\xef\xbf\xbd \xef\xbf\xbd\xef\xbf\xbd\xef\xbf\xbd\xef\xbf\xbd\x0f1\x1cT]]\xef\xbf[...]
I have no clue how to read this? Thanks.

So looks like it was coming from the line which I commented ... No idea why.
lua_script = """
function main(splash)
splash.private_mode_enabled = false
assert(splash:go{
splash.args.url,
headers=splash.args.headers,
})
assert(splash:wait(5))
return {html=splash:html()}
end
"""
yield SplashRequest(url=self.url, callback=self.parse,
endpoint='render.html',
args={'lua_source': lua_script,
'wait': 5,
'private_mode_enabled': 'false',
},
headers={
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/77.0.3865.90 Safari/537.36',
'accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3',
'accept-language': 'en-US,en;q=0.9,fr;q=0.8',
#'accept-encoding': 'gzip, deflate, br', # if used then file looks like shit
'referer': 'https://www.google.com/',
'upgrade-insecure-requests': 1,
},
)

Changing the referer URL in python requests

How do I change the referer if I'm using the requests library to make a GET request to a web page. I went through the entire manual but couldn't find it.

According to http://docs.python-requests.org/en/latest/user/advanced/#session-objects , you should be able to do:
s = requests.Session()
s.headers.update({'referer': my_referer})
s.get(url)
Or just:
requests.get(url, headers={'referer': my_referer})
Your headers dict will be merged with the default/session headers. From the docs:
Any dictionaries that you pass to a request method will be merged with
the session-level values that are set. The method-level parameters
override session parameters.

here we are rotating the user_agent with referer
user_agent_list = [
"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/77.0.3865.90 Safari/537.36",
"Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/79.0.3945.130 Safari/537.36",
"Mozilla/5.0 (iPad; CPU OS 15_6 like Mac OS X) AppleWebKit/605.1.15 (KHTML, like Gecko) CriOS/104.0.5112.99 Mobile/15E148 Safari/604.1"
]
reffer_list=[
'https://stackoverflow.com/',
'https://twitter.com/',
'https://www.google.co.in/',
'https://gem.gov.in/'
]
headers = {
'Connection': 'keep-alive',
'Cache-Control': 'max-age=0',
'Upgrade-Insecure-Requests': '1',
'User-Agent': random.choice(user_agent_list),
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'Accept-Encoding': 'gzip, deflate',
'Accept-Language': 'en-US,en;q=0.9,fr;q=0.8',
'referer': random.choice(reffer_list)
}