i am trying to import a file containing an image in python but i am getting an error writing the directory name while importing.
this is my directory:
my code is :
path = 'file_dir/dir_pict'
rd = []
label[]
Size = 32
for folder in os.listdir(path):
for file in os.listdir(os.path.join(path, folder)):
if file.endswith("png"):
label.append(folder)
pict = cv.imread(os.path.join(path, folder, file))
imgRGB = cv.cvtColor(pict, cv.COLORBGR2RGB)
there is an error: The system cannot find the path specified
maybe the file I entered was wrong name : path = 'file_dir/dir_pict'
i've try : path = 'r"C:\Users\riandra putra\OneDrive\Documents\file_dir"
but get an error :
NotADirectoryError: [WinError 267] The directory name is invalid: 'C:\\Users\\riandra putra\\OneDrive\\Documents\\file_dir\\program01.py'
i need your opinion about this
IIUC
path = 'dir_pict'
rd = []
label = []
Size = 32
for folder in os.listdir(path):
for file in os.listdir(path):
if file.endswith("png"):
label.append(folder)
pict = cv.imread(os.path.join(path, file))
imgRGB = cv.cvtColor(pict, cv.COLORBGR2RGB)
This should do what you want.
The path is correct. However, to make it works smoothly, you should add a 'r' before the path itself as per the following.
path = r'file_dir/dir_pict'
rd = []
label = []
Size = 32
for folder in os.listdir(path):
for file in os.listdir(os.path.join(path, folder)):
if file.endswith("png"):
label.append(folder)
pict = cv.imread(os.path.join(path, folder, file))
imgRGB = cv.cvtColor(pict, cv.COLORBGR2RGB)
In this way, it should work as expected. I noticed that you also missed the "=" while defining the label array, but it happens :D
For more info, look the docs https://docs.python.org/3/reference/lexical_analysis.html#string-and-bytes-literals
Related
I'm trying to read the folder name at the specific place from the file path. My current code:
import os
# search for and input multiple files
def get_files(source):
matches = []
for root, dirnames, filenames in os.walk(source):
for filename in filenames:
matches.append(os.path.join(root, filename))
return matches
def parse(files):
for file in files:
xml_information = {}
metadata = []
# Get the file path
filepath = os.path.dirname(file)
xml_information['file_path'] = '%s' % filepath
# Get customer name
customer = filepath.split("\\")[5]
xml_information['customer_name'] = '%s' % customer
metadata.append(xml_information)
print(metadata)
path = 'C:\\Users\\quan.nguyen\\SAGE\\Lania Thompson - Searching Project Files'
parse(get_files(path))
My program searches through folders and find the files and report back their folder path. However, I would like to read the folder path as well as the folder name at the sixth place which is customer name. When I run customer = filepath.split("\\")[5] it report an error:
Traceback (most recent call last):
File "*hidden*", line 33, in <module>
parse(get_files(path))
File "*hidden*", line 26, in parse
customer = filepath.split("\\")[5]
~~~~~~~~~~~~~~~~~~~~^^^
IndexError: list index out of range
However, when I run with customer = filepath.split("\\")[4], the program works and reads the last folder specified in path which is Lania Thompson - Searching Project Files. The result is as follows:
[{'file_path': 'C:\\Users\\quan.nguyen\\SAGE\\Lania Thompson - Searching Project Files\\Hazor Ltd\\PCS Mah\\Machine', 'customer_name': 'Lania Thompson - Searching Project Files'}]
My expecting result is Hazor Ltd:
[{'file_path': 'C:\\Users\\quan.nguyen\\SAGE\\Lania Thompson - Searching Project Files\\Hazor Ltd\\PCS Mah\\Machine', 'customer_name': 'Hazor Ltd'}]
The names are made up except from my name
So I have worked out the code using the pathlib library. The code is:
import os
from pathlib import Path
# search for and input multiple files
def get_files(source):
matches = []
for root, dirnames, filenames in os.walk(source):
for filename in filenames:
matches.append(os.path.join(root, filename))
return matches
def parse(files):
for file in files:
xml_information = {}
metadata = []
# Get the file path
filepath = os.path.dirname(file)
# Get customer name
p = Path(filepath)
files = [f for f in p.rglob('*') if f.is_file()]
for f in files:
xml_information['Customer'] = f.parts[5]
metadata.append(xml_information)
print(metadata)
path = 'C:\\Users\\quan.nguyen\\SAGE\\Lania Thompson - Searching Project Files'
parse(get_files(path))
change the number [5] in xml_information['Customer'] = f.parts[5] for the place you want to get the folder's name from.
I am trying to change file names like below:
the 000000 are the same number.
000000_ABC.png --->000000+1_ABC.png
000000_DEF.png --->000000+2_DEF.png
000000_GHI.png --->000000+3_GHI.png
000000_JKL.png --->000000+4_JKL.png
In order to do so, I wrote code like below.
img_files = os.listdir(PATH_TO_PNG_FILES)
for img_file, i in zip(img_files, range(len(img_files))):
new_img_file = img_file.replace("_", "+"+str(i)+"_")
os.rename(path + img_file, path + new_img_file)
There are more than just four files and more of similar lines.
The problem is that immediately after running pycharm, it successfully produces the desired results, but after I run another page related to the result directories, the results continue to be changed like below even after the process finished. I do not understand why.
000000+1+1_ABC.png
000000+2+2_DEF.png
000000+3+3_GHI.png
000000+4+4_JKL.png
or
otherwise "+unexpected number"
This is because the other directory may already contain file in the format of "000000+1_ABC.png" and your script is changing _ to "+1_" resulting in "000000+1+1_ABC.png". To solve this you can add a if statement to check it should not contain "+" symbol.
img_files = os.listdir(path inside of which the png files are saved)
for img_file, i in zip(img_files, range(len(img_files))):
if not ("+" in img_file):
new_img_file = img_file.replace("_", "+"+str(i)+"_")
os.rename(path + img_file, path + new_img_file)
A simple and naive way would be to add a verification to check whether there is a '+' in the filename. If you have other files which may contain a +, you may have to check for a stricter pattern.
I made a YouTube video https://youtu.be/K9jhAPZLZLc on how to rename multiple files like the one you have assuming all your files are in the same directory.
To answer your question. assuming all image files are in the same folder.
path = 'C:\\Users\\USER\\Desktop\\rename_images\\images\\' # path to your images
files = os.listdir(path)
for count, filename in enumerate(files):
# Get the file extension
file, file_extension = os.path.splitext(filename)
# check if the current file is a folder or not
full_path = f'{path}{filename}'
if os.path.isdir(full_path):
print('This is a directory')
elif os.path.isfile(full_path):
print('This is a normal file')
# Rename
if not '+' in file:
try:
file_split = file.split('_')
zeros = file_split[0]
alpha = file_split[-1]
current_file_name = os.path.join(path, filename)
new_file_name = os.path.join(path, ''.join([f'{zeros}+{count}_{alpha}', file_extension]))
os.rename(current_file_name, new_file_name)
except:
pass
else:
pass
else:
print('This is a special file')
I would imagine that the problem comes from modifying the name insted of overwriting.
import os
DIR_PATH = 'files'
def rename_files(dir_name):
img_files = os.listdir(dir_name)
for i in range(len(img_files)):
file_name = img_files[i].split('_')[-1]
file_name = '000000+{0}_{1}'.format(i, file_name)
os.rename(
os.path.join(dir_name, img_files[i]),
os.path.join(dir_name, file_name)
)
if __name__ == '__main__':
rename_files(DIR_PATH)
I have a bunch of jpgs in one folder (images) that I want to copy across to another folder (destination_folder). When they are copied across, I want the jpg files to be renamed as follows: filename1_red.jpg, filename2_red.jpg (i.e. adding on the suffix _red at the end)
I have the following so far:
import os
images = os.listdir('C:/Users/Admin-dsc/Documents/.../buses and motorcycles')
destination_folder = 'C:/Users/Admin-dsc/Documents/.../Buses'
for img in images:
filename = os.path.basename(img)
copyfile(img, os.path.join(destination_folder, filename))
Question 1: I get this error that I don't understand - how do I resolve it:
FileNotFoundError: [Errno 2] No such file or directory: 'RWG074059_2_o.jpg'
Question 2: I am unsure how to get the suffix.
Can anyone help?
os.listdir returns just the file names of the files in the specified folder, it doesn't return the complete path to the file. So, you need to join the source folder path with img:
import os
from shutil import copyfile
source_folder = 'C:/Users/Admin-dsc/Documents/.../buses and motorcycles'
destination_folder = 'C:/Users/Admin-dsc/Documents/.../Buses'
images = os.listdir(source_folder)
for img in images:
filename, ext = os.path.splitext(img)
filename = filename + '_red' + ext
copyfile(os.path.join(source_folder, img), os.path.join(destination_folder, filename))
How to debug this error:
import os
directory = 'C:/Users/Admin-dsc/Documents/.../buses and motorcycles'
images = os.listdir(directory)
for img in images:
print(img)
filename = os.path.basename(img)
print(filename)
Output:
main.py
main.py
What you can see:
You see that listdir() only returns filenames. You need to prepend the source folder again.
How to fix:
import os
directory = './'
destination_folder = 'C:/Users/Admin-dsc/Documents/.../Buses'
images = os.listdir(directory)
for img in images:
print(img)
filename = os.path.basename(img)
print(filename)
# prepend path again
source = os.path.join(directory,img)
target = os.path.join(destination_folder,img)
print(source, "=>", target)
# copyfile(source, target)
Output:
./main.py => C:/Users/Admin-dsc/Documents/.../Buses/main.py
img only contains the name of the image, not the complete path information.
Build an aboslute path instead when you specify the source image:
import os
source_folder = 'C:/Users/Admin-dsc/Documents/.../buses and motorcycles'
images = os.listdir(source_folder)
destination_folder = 'C:/Users/Admin-dsc/Documents/.../Buses'
for img in images:
filename = os.path.basename(img)
copyfile(os.path.join(source_folder, img), os.path.join(destination_folder, filename))
So I'm trying to iterate through a list of files that are within a subfolder named eachjpgfile and change the file from doc to the subfolder eachjpgfile mantaining the file's name but when I do this it adds the file to directory before eachjpgfile rather than keeping it in it. Looking at the code below, can you see why is it doing this and how can I keep it in the eachjpgfile directory?
Here is the code:
for eachjpgfile in filelist:
os.chdir(eachjpgfile)
newdirectorypath = os.curdir
list_of_files = os.listdir(newdirectorypath)
for eachfile in list_of_files:
onlyfilename = os.path.splitext(eachfile)[0]
if onlyfilename == 'doc':
newjpgfilename = eachfile.replace(onlyfilename,eachjpgfile)
os.rename(eachfile, newjpgfilename)
There is a lot of weird stuff going on in here, but I think the one that's causing your particular issue is using 'eachjpgfile' in 'eachfile.replace'.
From what I can tell, the 'eachjpgfile' you're passing in is a full-path, so you're replacing 'doc' in the filename with '/full/path/to/eachjpgfile', which puts it parallel to the 'eachjpgfile' directory regardless of your current working directory.
You could add a line to split the path/file names prior to the replace:
for eachjpgfile in filelist:
os.chdir(eachjpgfile)
newdirectorypath = os.curdir
list_of_files = os.listdir(newdirectorypath)
for eachfile in list_of_files:
onlyfilename = os.path.splitext(eachfile)[0]
if onlyfilename == 'doc':
root, pathName= os.path.split(eachjpgfile) #split out dir name
newjpgfilename = eachfile.replace(onlyfilename,pathName)
os.rename(eachfile, newjpgfilename)
which is a very dirty fix for a very dirty script. :)
try this:
import os
path = '.'
recursive = False # do not descent into subdirs
for root,dirs,files in os.walk( path ) :
for name in files :
new_name = name.replace( 'aaa', 'bbb' )
if name != new_name :
print name, "->", new_name
os.rename( os.path.join( root, name),
os.path.join( root, new_name ) )
if not recursive :
break
I am writing a Python function to change the extension of a list of files into another extension, like txt into rar, that's just an idle example. But I'm getting an error. The code is:
import os
def dTask():
#Get a file name list
file_list = os.listdir('C:\Users\B\Desktop\sil\sil2')
#Change the extensions
for file_name in file_list:
entry_pos = 0;
#Filter the file name first for '.'
for position in range(0, len(file_name)):
if file_name[position] == '.':
break
new_file_name = file_name[0:position]
#Filtering done !
#Using the name filtered, add extension to that name
new_file_name = new_file_name + '.rar'
#rename the entry in the file list, using new file name
print 'Expected change from: ', file_list[entry_pos]
print 'into File name: ', new_file_name
os.rename(file_list[entry_pos], new_file_name)
++entry_pos
Error:
>>> dTask()
Expected change from: New Text Document (2).txt
into File name: New Text Document (2).rar
Traceback (most recent call last):
File "<pyshell#10>", line 1, in <module>
dTask()
File "C:\Users\B\Desktop\dTask.py", line 19, in dTask
os.rename(file_list[entry_pos], new_file_name)
WindowsError: [Error 2] The system cannot find the file specified
I can succeed in getting the file name with another extension in variable level as you can see in the print-out, but not in reality because I can not end this process in OS level. The error is coming from os.rename(...). Any idea how to fix this ?
As the others have already stated, you either need to provide the path to those files or switch the current working directory so the os can find the files.
++entry_pos doesn't do anything. There is no increment operator in Python. Prefix + is just there fore symmetry with prefix -. Prefixing something with two + is just two no-ops. So you're not actually doing anything (and after you change it to entry_pos += 1, you're still resetting it to zero in each iteration.
Also, your code is very inelegant - for example, you are using a separate index to file_list and fail to keep that in synch with the iteration variable file_name, even though you could just use that one! To show how this can be done better.
-
def rename_by_ext(to_ext, path):
if to_ext[0] != '.':
to_ext = '.'+to_ext
print "Renaming files in", path
for file_name in os.listdir(path):
root, ext = os.path.splitext(file_name)
print "Renaming", file_name, "to", root+ext
os.rename(os.path.join(path, file_name), os.path.join(path, root+to_ext))
rename_by_ext('.rar', '...')
os.rename really doesn't like variables. Use shutil. Example taken from How to copy and move files with Shutil.
import shutil
import os
source = os.listdir("/tmp/")
destination = "/tmp/newfolder/"
for files in source:
if files.endswith(".txt"):
shutil.move(files,destination)
In your case:
import shutil
shutil.move(file_list[entry_pos], new_file_name)
You also want to double backslashes to escape them in Python strings, so instead of
file_list = os.listdir('C:\Users\B\Desktop\sil\sil2')
you want
file_list = os.listdir('C:\\Users\\B\\Desktop\\sil\\sil2')
Or use forward slashes - Python magically treats them as path separators on Windows.
You must use the full path for the rename.
import os
def dTask():
#Get a file name list
dir = 'C:\Users\B\Desktop\sil\sil2'
file_list = os.listdir(dir)
#Change the extensions
for file_name in file_list:
entry_pos = 0;
#Filter the file name first for '.'
for position in range(0, len(file_name)):
if file_name[position] == '.':
break
new_file_name = file_name[0:position]
#Filtering done !
#Using the name filtered, add extension to that name
new_file_name = new_file_name + '.rar'
#rename the entry in the file list, using new file name
print 'Expected change from: ', file_list[entry_pos]
print 'into File name: ', new_file_name
os.rename( os.path.join(dir, file_list[entry_pos]), os.path.join(dir,new_file_name))
++entry_pos
If you aren't in the directory C:\Users\B\Desktop\sil\sil2, then Python certainly won't be able to find those files.
import os
def extChange(path,newExt,oldExt=""):
if path.endswith != "\\" and path.endswith != "/":
myPath = path + "\\"
directory = os.listdir(myPath)
for i in directory:
x = myPath + i[:-4] + "." + newExt
y = myPath + i
if oldExt == "":
os.rename(y,x)
else:
if i[-4:] == "." + oldExt:
os.rename(y,x)
now call it:
extChange("C:/testfolder/","txt","lua") #this will change all .txt files in C:/testfolder to .lua files
extChange("C:/testfolder/","txt") #leaving the last parameter out will change all files in C:/testfolder to .txt