I've written a Python script to solve the Time Difference of Arrival (TDoA) angular reconstruction problem in 3-dimensions. To do so, I'm using SciPy's scipy.optimize.root root finding algorithm to solve a system of nonlinear equations. I find that the Levenberg-Marquardt method is the only supported method capable of reliably producing accurate results (most others simply fail).
I'd like to assess the uncertainty in the resulting solution. For most methods (including the default hybr method), SciPy returns the inverse Hessian of the objective function (i.e. the covariance matrix), from which one may begin to calculate the uncertainty(ies) in the found roots. Unfortunately this is not the case for the Levenberg-Marquardt method (which I'm admittedly much less familiar with on a mathematical method than the other methods... it just seems to work).
How (in general) can I estimate the uncertainties in the solution returned by scipy.optimize.root when using the lm method?
Related
I'm trying to fit my data and have so far used sp.optimize.leastsq. I changed to sp.optimize.least_squares to add bounds to the parameters, but both when I use bounds and when I don't the search doesn't converge, even in data sets sp.optimize.leastsq fitted just fine.
Shouldn't these functions work the same?
What could be the difference between them that makes the newer one not to find solutions the older one did?
leastsq
is a wrapper around MINPACK’s lmdif and lmder algorithms.
least_squares implements other methods in addition to the MINPACK algorithm.
method{‘trf’, ‘dogbox’, ‘lm’}, optional
Algorithm to perform minimization.
‘trf’ : Trust Region Reflective algorithm, particularly suitable for large sparse problems with bounds. Generally robust method.
‘dogbox’ : dogleg algorithm with rectangular trust regions, typical use case is small problems with bounds. Not recommended for problems with rank-deficient Jacobian.
‘lm’ : Levenberg-Marquardt algorithm as implemented in MINPACK. Doesn’t handle bounds and sparse Jacobians. Usually the most efficient method for small unconstrained problems.
Default is ‘trf’. See Notes for more information.
It is possible for some problems that lm method does not converge while trf converges.
Is there any way to force 'hybr' method of scipy.optimize 'root' to keep working even after it finds that convergence its too slow? In my problem, the solver nearly reaches desired precision, but right before it, the algorithm terminates because of slow convergence... Is it possible to make 'hybr' more 'self-confident'?
I use the root-finding algorithm root from scipy.optimize module to solve a system of two algebraic, non-linear equations. Since the equations have to be solved many times for various parameter values it is important to find a numerical method that would be most stable for this problem.
I have compared the performance of all the methods provided by scipy.optimize module. To visualize their performance I have used the following procedure:
The algebraic equations were rearranged so that they have zero on the R.H.S.
Then, at each step made by the algorithm, the sum of the L.H.S. squared of all the equations was computed and printed.
In my case, the most efficient method is the default "hybr". Other build-in methods either do not converge at all or are significantly slower. Unfortunately, in some cases the desired method gives up too fast. Lowering the precision and/or providing additional options to the functions did not help.
I am trying to solve a large-scale nonlinear system using the exact Newton method in SciPy. In my application, the Jacobian is easy to assemble (and factorize) as a sparse matrix.
It seems that all methods available in scipy.optimize.root approximate the Jacobian in one way or another, and I can't find a way to use Newton's method using the API that is discussed in SciPy's documentation.
Nonetheless, using the internal API, I have managed to use Newton's method with the following code:
from scipy.optimize.nonlin import nonlin_solve
x, info = nonlin_solve(f, x0, jac, line_search=False)
where f(x) is the residual and jac(x) is a callable that returns the Jacobian at x as a sparse matrix.
However, I am not sure whether this function is meant to be used outside SciPy and is subject to changes without notice.
Would this be recommended approach?
It is meant to be used.
Scipy's private functions that are not meant to be used from the outside start with a _.
This was confirmed by the scipy's team in an issue I raised recently: cf https://github.com/scipy/scipy/issues/17510
I have a relatively complicated function and I have calculated the analytical form of the Jacobian of this function. However, sometimes, I mess up this Jacobian.
MATLAB has a nice way to check for the accuracy of the Jacobian when using some optimization technique as described here.
The problem though is that it looks like MATLAB solves the optimization problem and then returns if the Jacobian was correct or not. This is extremely time consuming, especially considering that some of my optimization problems take hours or even days to compute.
Python has a somewhat similar function in scipy as described here which just compares the analytical gradient with a finite difference approximation of the gradient for some user provided input.
Is there anything I can do to check the accuracy of the Jacobian in MATLAB without having to solve the entire optimization problem?
A laborious but useful method I've used for this sort of thing is to check that the (numerical) integral of the purported derivative is the difference of the function at the end points. I have found this more convenient than comparing fractions like (f(x+h)-f(x))/h with f'(x) because of the difficulty of choosing h so that on the one hand h is not so small that the fraction is not dominated by rounding error and on the other h is small enough that the fraction should be close to f'(x)
In the case of a function F of a single variable, the assumption is that you have code f to evaluate F and fd say to evaluate F'. Then the test is, for various intervals [a,b] to look at the differences, which the fundamental theorem of calculus says should be 0,
Integral{ 0<=x<=b | fd(x)} - (f(b)-f(a))
with the integral being computed numerically. There is no need for the intervals to be small.
Part of the error will, of course, be due to the error in the numerical approximation to the integral. For this reason I tend to use, for example, and order 40 Gausss Legendre integrator.
For functions of several variables, you can test one variable at a time. For several functions, these can be tested one at a time.
I've found that these tests, which are of course by no means exhaustive, show up the kinds of mistakes that occur in computing derivatives quire readily.
Have you considered the usage of Complex step differentiation to check your gradient? See this description
Consider for the sake of simplicity the following equation (Burgers equation):
Let's solve it using scipy (in my case scipy.integrate.ode.set_integrator("zvode", ..).integrate(T)) with a variable time-step solver.
The issue is the following: if we use the naïve implementation in Fourier space
then the viscosity term nu * d2x(u[t]) can cause an overshoot if the time step is too big. This can lead to a fair amount of noise in the solutions, or even to (fake) diverging solutions (even with stiff solvers, on slightly more complex version of this equation).
One way to regularize this is to evaluate the viscosity term at step t+dt, and the update step becomes
This solution works well when programmed explicitly. How can I use scipy's variable-step ode solver to implement it ? To my surprise I haven't found any documentation on this fairly elementary thorny issue...
You actually can't, or on the other extreme, odeint or ode->zvode already does that to any given problem.
To the first, you would need to give the two parts of the equation separately. Obviously, that is not part of the solver interface. Look at DDE and SDE solvers where such a partition of the equation is actually required.
To the second, odeint and ode->zvode use implicit multi-step methods, which means that the values of u(t+dt) and the right side there enter the computation and the underlying local approximation.
You could still try to hack your original approach into the solver by providing a Jacobian function that only contains the second derivative term, but quite probably you will not achieve an improvement.
You could operator-partition the ODE and solve the linear part separately introducing
vhat(k,t) = exp(nu*k^2*t)*uhat(k,t)
so that
d/dt vhat(k,t) = -i*k*exp(nu*k^2*t)*conv(uhat(.,t),uhat(.,t))(k)