Develop Reference

How to create date timestamp logs like git log

Using datetime.datetime.now(), I receive some badly formatted timestamps.
Is there an intuitive way of creating a date timestamp in this format?
Wed Aug 7 13:38:59 2019 -0500
This is seen in git log.

You can use datetime.datetime.strftime() to format dates as shown below:
from datetime import datetime
d = '2019-08-07 13:38:59-0500'
d2 = datetime.strptime(d, '%Y-%m-%d %H:%M:%S%z')
d3 = d2.strftime('%a %b %d %H:%M:%S %Y %z')
print(d3)
This returns:
Wed Aug 07 13:38:59 2019 -050000
This website is a great resource for strftime formatting.

You can still use the datetime library. Using strftime, you can rewrite the datetime object into a nicely formatted string.
In your case, you are going for Wed Aug 7 13:38:59 2019 -0500, which translated to strftime formatting is "%a %b %d %H:%M:%S %Y %z".
Overall, it'd be
datetime.datetime.now().strftime("%a %b %d %H:%M:%S %Y %z")
Which will give a string that looks like 'Wed Aug 7 13:38:59 2019 -0500'.

I would do the following:
from time import gmtime, strftime
if __name__ == "__main__":
time = strftime("%a, %d %b %Y %H:%M:%S +0000", gmtime())
print(time)
This was found on the documentation page of the time module. There are also a lot of additional features you might be interested in using outlined here: https://docs.python.org/3/library/time.html#time.strftime

Python Given a date, time, hour... how can i get it's formated ISO ZULU

I have been using python IMAP protocol and I read email headers and retrieve the Date which looks like
myDate --> Fri, 22 Feb 2019 17:00:06 +0000
I need to find the equivalent UTC ISO8601 with zulu formatting how can I do that?
I tried:
dateInUTCIso= datetime.datetime.strptime(myDate, '%a, %d %b %Y %H:%M:%S +%f').date().isoformat()
but I am only getting year/month/date
dateInUTCIso= 2019-02-22

Remove the .date() method call
myDate = "Fri, 22 Feb 2019 17:00:06 +0000"
dateInUTCIso= datetime.datetime.strptime(myDate, '%a, %d %b %Y %H:%M:%S +%f').isoformat() + 'Z'
# 2019-02-22T17:00:06Z

You're calling .date().isoformat(). Without .date() you would get the ISO format.
However, if you want Z instead of +00:00 at the end, you'll have to swap out that part after the fact with .replace('+00:00', 'Z') on the string output

Python 3.7: converting a string with different timezone into date

I am trying to convert a string into date format in Python.
I am using following statement
datetime_obj = datetime.datetime.strptime("Sun Aug 19 16:24:31 PDT 2018", "%a %b %d %H:%M:%S %Z %Y")
However, I get an error -
ValueError: time data 'Sun Aug 19 16:24:31 PDT 2018' does not match format '%a %b %d %H:%M:%S %Z %Y'
If I remove the timezone from the date string and the format string, the code works perfect. Which leads me to believe that the issue is related to the timezone but I am not sure what actions should be taken.
I am in eastern timezone and the time zone in the string is in Pacific timezone.
Appreciate any help on this.

As mentioned in this answer you can use python-dateutil for this:
>>> from dateutil import parser
>>> datetime_obj = parser.parse("Sun Aug 19 16:24:31 PDT 2018")
datetime.datetime(2018, 8, 19, 16, 24, 31)
Standard datetime module behaves very strangely with parsing timezones, as I see reading this answer in question related to similar problem.

Convert string to DateTime for mysql in python

I want to convert my date into DateTime object for MySQL.
My string format is: Mon Aug 27 04:47:45 +0000 2018
Expected Output: 'YYYY-M-D H:mm:ss'

from datetime import datetime
t = datetime.strptime('Mon Aug 27 04:47:45 +0000 2008', '%a %b %d %H:%M:%S % z %Y')
t.strftime('%Y-%m-%d %H:%M:%S')
Refer section 8.1.8
here

If you are using python 3, this solution would work -
from datetime import datetime
x = 'Mon Aug 27 04:47:45 +0000 2018'
x = datetime.strftime(datetime.strptime(x, '%a %b %d %I:%M:%S %z %Y'), '%Y-%m-%d %H:%M:%S')
# OP '2018-08-27 04:47:45'
But for python 2, you might get a ValueError: 'z' is a bad directive.... In that case, you'll either have to use something like pytz or dateutil. The table that you need to look for all these conversions can be found here
Edit: You can't have Expected Output: 'YYYY-M-D H:mm:ss' if you convert your datetime string to datetime object. Datetime object has it's own format. Above gives you a string of the format that you want

from datetime import datetime
date_as_dt_object = datetime.strptime(dt, '%a %b %d %H:%M:%S %z %Y')
You can use date_as_dt_object in a raw query or an ORM. If used in a raw query pass it as a string like:
query = "select * from table where date >" + str(date_as_dt_object)
Check out this list for Python's strftime directives.
http://strftime.org/

How to convert GMT time to string time

How to convert GMT time to string time? it's quite strange, when I print the time in back-end, the time is in string time format, but when I transfer it to the front-end via JSON file, the time has changed to GMT format. Why? Could someone help me?
Input: Wed, 25 Jul 2018 19:19:42 GMT
Output: 2018-07-25 19:19:42

When you convert the original time to JSON Format, it will be changed to GMT Time format. To solve this problem, you can change the time to string before converting it to JSON.

You could do something like -
from datetime import datetime
ip = 'Wed, 25 Jul 2018 19:19:42 GMT'
op = datetime.strftime(datetime.strptime(ip,'%a, %d %b %Y %H:%M:%S %Z'), '%Y-%m-%d %H:%M:%S')
# op 2018-07-25 19:19:42
Refer to this beautiful table here to get the formats right and then look into strftime and strptime

You can find resources here on strptime
from datetime import datetime
t = 'Wed, 25 Jul 2018 19:19:42 GMT'
datetime.strptime(t,'%a, %d %b %Y %H:%M:%S %Z')
datetime.datetime(2018, 7, 25, 19, 19, 42)