This question already has answers here:
How can I format a float with given precision and zero padding?
(2 answers)
Closed 9 months ago.
How can I get a float number with leading zeros and decimal precision?
For example:
number = 1.8315454
and I want to print "01.83"
print(f"{number:05.2f}")
the 0 indicates to fill with leading 0, the ยด5"teh total of characters in the output: digitis + decimal point, the "." indicates that decimal places should be printed, the "2" indicates that 2 decimal digits are wanted, the 'f' indicates it is a floating point number.
use string formating (f-string):
number = 1.8315454
print(f"{number:05.2f}")
output:
>> 01.83
Related
This question already has answers here:
Limiting floats to two decimal points
(35 answers)
Closed 2 years ago.
so i had this problem where i generated numbers from 0-1 with a step of 0.01 but the numbers have so many decimals like 0.010101010101.I only need it in the form 0.01 with two decimals.
How do i remove the rest of decimals ?
You can format the decimal like
your_value = 0.1010101010
desired_value = '%.2f' % your_value
Now desired_value will have the decimal upto 2 places.
Or you could use decimal.
Look at the documentation in the link:
https://docs.python.org/3/library/decimal.html
Round num to digits places. round(num, digits)
This question already has answers here:
Limiting floats to two decimal points
(35 answers)
Closed 3 years ago.
I have a random number generated, then I use round to get it to 2 decimal places.
Occasionally I get an integer such as "2" i would like this to be displayed as "2.00"
Or when I get "3.1" to be displayed as "3.10"
I have tried rounding to 2 d.p using round()
import random
#this creates a number between 2 and 5.99 by adding a decimal to an integer then rounds the sum to 2 d.p
def second_question():
temp_var_4 = random.randint(2,5) + round(random.random(),2)
print(temp_var_4)
second_question()
No error messages just returning some numbers to integers or to one d.p
You can control the output formatting explicitly by using a format string:
print('%.2f' % temp_var_4)
This question already has answers here:
Truncate to three decimals in Python
(21 answers)
Closed 3 years ago.
I would like to truncate a floating point number at the third decimal place. However, I don't want to round the number.
float("{0:.3f}".format(132.32579))
The code above produces 132.326 but I want it to produce 132.325. Any help is appreciated
You can round to 1 digit more, slice the string for ignoring the last digit and convert back to float:
print( float("{0:.4f}".format(132.32579) [:-1]))
You can avoid the string conversion/rounding by multiplying by 1000, converting to int and dividing by 1000.0 again:
print( float(int(132.32579*1000)/1000.0))
Output (both):
132.325
This question already has answers here:
How do I pad a string with zeroes?
(19 answers)
Closed 6 years ago.
i'd like to convert a decimal to a string, where zeros at the end are preserved.
Using str method erases the last zeros.
Example:
number=0.20
Goal: "0.20"
e.g. using: str(number)="0.2" doesn't seem to work.
If you want 2 decimal places use:
number = 0.20
str_number = '%.2f' % number
Number before f indicates the desired number of places.
This can be done using string formatting.
"{0:.2f}".format(number)
Will return 0.20.
Doing your chosen method won't work because upon declaring number = 0.20 it omits the last zero right away. If you put that into your idle:
number = 0.20
number
0.2
So declaring number as str(number) is doing str(0.2).
Use the % operator with an appropriate format string:
'%1.2f' % number
=> '0.20'
This question already has answers here:
Python rounding error with float numbers [duplicate]
(2 answers)
Closed 6 years ago.
Can someone tell me what I'm missing here? This is using Python 2.7.11:
print float(148.95)
print float(148.95)*100
print int(float(148.95)*100)
Why does this print:
148.95
14895.0
14894 <--- Shouldn't this be 14895?
148.95 is not a number that can be exactly represented using floating point. The number internally stored is actually 148.94999999999998863131622783839702606201171875. When you multiply by a hundred, you get 14894.999999999998181010596454143524169921875. When you convert that to integer, it cuts off the .999... and you're left with 14894.
If you want a data type that can exactly represent numbers with at least two decimal places of precision, consider using Decimal.
>>> from decimal import Decimal
>>> x = Decimal("148.95")
>>> print x
148.95
>>> print x*100
14895.00
>>> print int(x*100)
14895