The title is actually clear what I expect.
I expect if the stored image is saved in variable instead of disk because I'm using it for jpeg compression at its paramater and I'm doing it repeteadly for streaming usage.
So it will be disk consuming if I open and reopen to read that saved image.
Here what was I doing:
import pyautogui as pag
im =pag.screenshot()
im.save('hoho.jpg', optimize=True, quality=10) #I'm using compression parameter.
I expect that function return the binary format of saved image.
import pyautogui as pag
im =pag.screenshot()
binary_image = im.save('hoho.jpg', optimize=True, quality=10) #I'm using compression parameter.
Related
I have an image in memory (downloaded from an online source) and I want to convert it to a different format before sending it on to a different online location.
The conversion is .webp to .jpg but that's not really relevant.
With Pillow I can easily convert local images and save them back to disc, but I can't get it to work with an image in memory.
I don't necessarily need to use Pillow. Any way to convert the image without having to save anything to disc is fine.
I am new to BytesIO with PIL, so just check my code attempt, with my test image it works, let me know
from PIL import Image
from io import BytesIO
img = Image.open('test.webp')
print('image : ', img.format)
img.show()
# Write PIL Image to in-memory PNG
membuf = BytesIO()
img.save(membuf, format="png")
img = Image.open(membuf)
print('image : ', img.format)
img.show()
I have a set of many songs, some of which have png images in metadata, and I need to convert these to jpg.
I know how to convert png images to jpg in general, but I am currently accessing metadata using eyed3, which returns ImageFrame objects, and I don't know how to manipulate these. I can, for instance, access the image type with
print(img.mime_type)
which returns
image/png
but I don't know how to progress from here. Very naively I tried loading the image with OpenCV, but it is either not a compatible format or I didn't do it properly. And anyway I wouldn't know how to update the old image with the new one either!
Note: While I am currently working with eyed3, it is perfectly fine if I can solve this any other way.
I was finally able to solve this, although in a not very elegant way.
The first step is to load the image. For some reason I could not make this work with eyed3, but TinyTag does the job:
from PIL import Image
from tinytag import TinyTag
tag = TinyTag.get(mp3_path, image=True)
image_data = tag.get_image()
img_bites = io.BytesIO(image_data)
photo = Image.open(im)
Then I manipulate it. For example we may resize it and save it as jpg. Because we are using Pillow (PIL) for these operations, we actually need to save the image and finally load it back to get the binary data (this detail is probably what should be improved in the process).
photo = photo.resize((500, 500)) # suppose we want 500 x 500 pixels
rgb_photo = photo.convert("RGB")
rgb_photo.save(temp_file_path, format="JPEG")
The last step is thus to load the image and set it as metadata. You have more details about this step in this answer.:
audio_file = eyed3.load(mp3_path) # this has been loaded before
audio_file.tag.images.set(
3, open(temp_file_path, "rb").read(), "image/jpeg"
)
audio_file.tag.save()
I am using tinytags module in python to get the cover art of a mp3 file and want to display or store it. The return type of the variable is showing to be bytes. I have tried fumbling around with PIL using frombytes but to no avail. Is there any method to convert the bytes to image?
from tinytag import TinyTag
tag = TinyTag.get("03. Me, Myself & I.mp3", image=True)
img = tag.get_image()
I actually got a PNG image when I called tag.get_image() but I guess you might get a JPEG. Either way, you can wrap it in a BytesIO and open it with PIL/Pillow or display it. Carrying on from your code:
from PIL import Image
import io
...
im = tag.get_image()
# Make a PIL Image
pi = Image.open(io.BytesIO(im))
# Save as PNG, or JPEG
pi.save('cover.png')
# Display
pi.show()
Note that you don't have to use PIL/Pillow. You could look at the first few bytes and if they are a PNG signature (\x89PNG) save data as binary with PNG extension. If the signature is JPEG (\xff \xd8) save data as binary with JPEG extension.
In order to remove sensitive content from a PDF, I am converting it to image and back to PDF again.
I am able to do this while saving the jpeg image, however I would eventually like to adapt my code so that the file is in memory the whole time. PDF in memory -> JPEG in memory -> PDF in memory. I'm having trouble with the intermediary step.
from pdf2image import convert_from_path, convert_from_bytes
import img2pdf
images = convert_from_path('testing.pdf', fmt='jpeg')
image = images[0]
# opening from filename
with open("output/output.pdf","wb") as f:
f.write(img2pdf.convert(image.tobytes()))
On the last line, I am getting the error:
ImageOpenError: cannot read input image (not jpeg2000). PIL: error reading image: cannot identify image file <_io.BytesIO object at 0x1040cc8f0>
I'm not sure how to be converting this image to the string that img2pdf is looking for.
The pdf2image module will extract the images as Pillow images. And according the Pillow tobytes() documention: "This method returns the raw image data from the internal storage." Which is some bitmap representation.
To get your code working use BytesIO module like so:
# opening from filename
import io
with open("output/output.pdf","wb") as f, io.BytesIO() as output:
image.save(output, format='jpg')
f.write(img2pdf.convert(output.getvalue()))
I want to serve matplotlib generated images with django.
If the image is a static png file, the following code works great:
from django.http import HttpResponse
def static_image_view(request):
response = HttpResponse(mimetype='image/png')
with open('test.png', 'rb') as f:
response.write(f.read())
return response
However, if the image is dynamically generated:
import numpy as np
import matplotlib
matplotlib.use('Agg')
from matplotlib import pyplot as plt
def dynamic_image_view(request):
response = HttpResponse(mimetype='image/png')
fig = plt.figure()
plt.plot(np.random.rand(100))
plt.savefig(response, format='png')
plt.close(fig)
return response
When accessing the url in Chrome (v36.0), the image will show up for a few seconds, then disappear and turn to the alt text. It seems that the browser doesn't know the image has already finished loading and waits until timeout. Checking with Chrome > Tools > Developer tools > Network supports this hypothesis: although the image appears after only about 1 sec, the status of the corresponding http request becomes "failed" after about 5 sec.
Note again, this strange phenomenon occurs only with the dynamically generated image, so it shouldn't be Chrome's problem (though it doesn't happen with IE or FireFox, presumably due to different rules in dealing with timeout requests).
To make it more tricky (i.e., hard to reproduce), it seems to be network speed dependent. It happens if I access the url from an IP in China, but not if via a proxy in the US (which seems to be faster visiting the host on which django is running)...
According to #HSquirrel, I tested writing the png into temporary disk file. Strangely, saving file with matplotlib didn't work,
plt.savefig('MPL.png', format='png')
with open('MPL.png', 'rb') as f:
response.write(f.read())
while saving file with PIL worked:
import io
from PIL import Image
f = io.BytesIO()
plt.savefig(f, format='png')
f.seek(0)
im = Image.open(f)
im.save('PIL.png', 'PNG')
Attempt of getting rid of temp file failed:
im.save(response, 'PNG')
However, if I generate the image data stream with PIL rather than matplotlib, temporary disk file would be unnecessary. The following code works:
from PIL import Image, ImageDraw
im = Image.new('RGBA', (256,256), (0,255,0,255))
draw = ImageDraw.Draw(im)
draw.line((100,100, 150,200), fill=128, width=3)
im.save(response, 'PNG')
Finally, savefig(response, 'jepg') has no problem at all.
Have you tried saving the image to disk and then returning that? (you can periodically clear your disk of such generated images based on their time of creation)
If that gives the same problem, it might be a problem with the way the png is generated. Than you could use some kind of image library (like PIL) to make sure all your png's are (re)generated in a way that works with all browsers.
EDIT:
I've checked the png you've linked and I've played around with it a bit, opening and saving it with different programs and with PIL. I get different binary data every time. It seems each program decides which chunks to keep and which to remove. They all encode the png image data differently as well (as far as I can see, I am by no means a specialist in this, I just looked at the binary data based on the specs).
There are a few different paths you can take:
1.The quick and dirty one:
import io
from PIL import Image
f = io.BytesIO()
plt.savefig(f, format='png')
f.seek(0)
im = Image.open(f)
tempfilename = generatetempfilename()
im.save(tempfilename, 'PNG')
with open(tempfilename, 'rb') as f:
response.write(f.read())
2.Adapt how matplotlib makes PNG files (possibly by just using PIL for
it as well). See
http://matplotlib.org/users/customizing.html#customizing-matplotlib
3.If it's an option for you, use jpeg.
4.Figure out what's wrong with the PNG generated by matplotlib and fix
it binary (I don't recommend this). You can use xxd (linux command: xxd test.png) to figure out how the files look in binary and then see how things go using the png spec: overview chunk spec