How can i auto increment and shorten a string as textfield? - python

im currently trying to do a project management app and i need to autoincrement project count and add shortened string from department. For example if Product Development add a project to site i need to show in table like this PD_1

The easiest way is to pass a function to a field default and use it to generate an incremental text value:
def create_project_reference():
projects = Project.objects.filter(# some filter)
return f'PD_{projects.count()+1}'
class Project(models.Model):
project_reference = models.CharField(...,
default=create_project_reference,
editable=False
)
The problem with this is that the default callable doesn't get self from the model that has been created, so you can't create dynamic filters. An alternative is to override the save() function of your model and you can then access self, pass it into your function, and use its info to set your filters:
def create_project_reference(project):
projects = Project.objects.filter(department=project.department)
return f'PD_{projects.count()+1}'
class Project(models.Model):
...
def save(self, *args, **kwargs):
self.project_reference = create_project_reference(self)
super(Project, self).save(*args, **kwargs)
There are limitations of overriding the save() function as it doesn't work with the bulk update() function - but that should be fine for a value that is set once when the object is created.

Related

on_save() is not triggered when model is created

I got the two following models:
class Stuff(models.Model):
...
def custom_function(self):
...
class MyModel(models.Model):
name = models.CharField(max_length=200)
many_stuff = models.ManyToManyField(Stuff, related_name="many_stuff+")
many_other_stuff = models.ManyToManyField(Stuff, related_name="many_other_stuff+")
def __init__(self, *args, **kwargs):
super(MyModel, self).__init__(*args, **kwargs)
for stuff in self.many_stuff.all():
many_stuff.custom_function()
def on_save(self, *args, **kwargs):
for stuff in self.many_stuff.all():
many_stuff.custom_function()
super(MyModel, self).save(*args, **kwargs)
When I create a new instance of MyModel through the Django Admin, I want to execute for each Stuff object, a function. It works on_save but I cannot make it work on __init__ for some reason. If I create the new instance, the functions don't get executed. If I save the newly created instance, the functions do get executed.
To be more specific, when I use this __init__ method, the model breaks on instance creation with the error:
MyModel needs to have a value for field "id" before this many-to-many relationship can be used.
I also attempted doing the same thing with the post_save signal, instead of using __init__ and on_save but I had the same problem. On object creation, the function custom_function did not get executed, but it did when I saved the object after it has been created by clicking on the save button.
Any ideas?
You simply cant create M2M join while creating object.
Because M2M model fields don't have real db fields, but have intermediary table that stores id from both model. When you create relation between two objects, both objects must have an id value ready to use.
First create MyModel instance without M2M fields, than set M2M fields. Something like that;
newModel = MyModel.objects.create(name=someting)
newStuff = Stuff.objects.create(..)
newModel.many_stuff.add(newStuff)

How and why I can't override related manager method on django?

I have this manager:
class ConfigValueManager(models.Manager):
def get(self, key):
config_value = self.filter(key=key).first()
if config_value:
type_caster = locate(config_value.type)
return type_caster(config_value.value)
return config_value
def set(self, key, value):
self.filter(key=key).update(value=value)
def set2(self, key, value):
qs = self.filter(key=key)
if qs:
qs.update(value=value, type=type(value).__name__, company=self.instance)
else:
self.create(key=key, value=value, type=type(value).__name__, company=self.instance)
the problem is that I can't overwrite set. The method is still coming from the parent, even though I've created set on the child. Funny thing is that get and set2 are fine. Even add which isn't in my example can't be overridden.
My question is how can I overwrite set and why this happens?
I add some details on why it's not easily possible, because I struggled on the same issue.
set, like add or create, are overridden in the dynamically created RelatedManager, as we can see in the django source code. This RelatedManager actually uses our manager as a super class that's why your get and set2 methods can used, but it does not help for overridden methods.
This manager is created in the ReverseManyToOneDescriptor.related_manager_cls cached property. In the example on your github snippet, Company.config_values is an instance of this ReverseManyToOneDescriptor.
I'll show an example on how to override the set method, by making some assumptions on your code, because it misses some definitions (like the Company model, the ForeignKey field inside FooConfigValue.)
I don't advise to use it, as it's absolutely not robust against django changes, and I didn't do any test, it just serves as a proof on how RelatedManager instances are created
Add this at the end of the example code and it should work
def modify_related_manager_set(model_cls):
# model_cls = Company here, and config_values is the related field name
reverse_descriptor = model_cls.config_values
base_set = reverse_descriptor.related_manager_cls.set
def custom_set(*args, **kwargs):
print("in my custom set")
return base_set(*args, **kwargs)
reverse_descriptor.related_manager_cls.set = custom_set
# do this call after all the models have been created
# e.g. after defining FooConfigValue
modify_related_manager_set(Company)
And you should now see the in my custom set being printed.
I know this doesn't help much, but at least it helped understand how related fields work
models.py
from django.db import models
from django.db.models.query import QuerySet
class PersonQuerySet(QuerySet):
def set(self, slug, **kwargs):
return self.filter(slug=slug).update(**kwargs)
class Person(models.Model):
name = models.CharField(max_length=100, null=True)
slug = models.CharField(max_length=10, null=True)
objects = PersonQuerySet.as_manager()
tests.py
from django.test import TestCase
from core.models import Person
class TestSet(TestCase):
def test_just_update_records_with_the_same_slug(self):
Person.objects.create(slug='batman', name='John')
Person.objects.create(slug='batman', name='Connor')
Person.objects.create(slug='bruce', name='Ill be back')
Person.objects.set('batman', name='###')
expected_value = 2
result = Person.objects.filter(name='###').count()
self.assertEqual(result, expected_value)
github example
https://github.com/luivilella/django-test-manager

In a Django serializer, take default field value from context (or request data)

I'm using Django with the REST Framework. In a serializer, I would like to assign a field value based on a view or request (request.data['type']) parameter, so I need the view/request in the context.
I succeeded, but only in a cumbersome way, and I am looking into ways to simplify the code. Here's the successful approach (omitting irrelevant fields):
class TypeDefault(object):
def set_context(self, serializer_field):
view = serializer_field.context['view'] # or context['request']
self.type = view.kwargs['type'].upper()
def __call__(self):
return self.type
class RRsetSerializer(serializers.ModelSerializer):
type = serializers.CharField(read_only=True, default=serializers.CreateOnlyDefault(TypeDefault()))
class Meta:
model = RRset
fields = ('type',)
read_only_fields = ('type',)
To simplify things, I tried removing the TypeDefault class, and replacing the type serializer field by
type = serializers.SerializerMethodField()
def get_type(self, obj):
return self.context.get('view').kwargs['type'].upper() # also tried self._context
However, context.get('view') returns None. I am unsure why the view context is not available here. My impression is that it should be possible to get the desired functionality without resorting to an extra class.
As a bonus, it would be nice to specify the default in the field declaration itself, like
type = serializers.CharField(default=self.context.get('view').kwargs['type'].upper())
However, self is not defined here, and I'm not sure what the right approach would be.
Also, I am interested if there is any difference in retrieving information from the view or from the request data. While the context approach should work for both, maybe there's a simpler way to get the CreateOnlyDefault functionality when the value is obtained from request data, as the serializers deals with the request data anyways.
Edit: Per Geotob's request, here is the code of the view that calls the serializer:
class RRsetsDetail(generics.ListCreateAPIView):
serializer_class = RRsetSerializer
# permission_classes = ... # some permission constraints
def get_queryset(self):
name = self.kwargs['name']
type = self.kwargs.get('type')
# Note in the following that the RRset model has a `domain` foreign-key field which is referenced here. It is irrelevant for the current problem though.
if type is not None:
return RRset.objects.filter(domain__name=name, domain__owner=self.request.user.pk, type=type)
else:
return RRset.objects.filter(domain__name=name, domain__owner=self.request.user.pk)
In urls.py, I have (among others):
url(r'^domains/(?P<name>[a-zA-Z\.\-_0-9]+)/rrsets/$', RRsetsDetail.as_view(), name='rrsets'),
url(r'^domains/(?P<name>[a-zA-Z\.\-_0-9]+)/rrsets/(?P<type>[A-Z]+)/$', RRsetsDetail.as_view(), name='rrsets-type'),
SerializerMethodField is a read-only field so I do not think it will work unless you set a default value... and you are back to the same problem as with CharField.
To simply things you could get rid of serializers.CreateOnlyDefault:
class RRsetSerializer(serializers.ModelSerializer):
type = serializers.CharField(read_only=True, default=TypeDefault())
If you want something more dynamic, I can only think of something like this:
class FromContext(object):
def __init__(self, value_fn):
self.value_fn = value_fn
def set_context(self, serializer_field):
self.value = self.value_fn(serializer_field.context)
def __call__(self):
return self.value
class RRsetSerializer(serializers.ModelSerializer):
type = serializers.CharField(read_only=True,
default=FromContext(lambda context: context.get('view').kwargs['type'].upper()))
FromContext takes a function during instantiation that will be used to retrieve the value you want from context.
All in all, your second approach above is the correct one:
Use serializers.SerializerMethodField and access self.context from the serializer method:
class SomeSerializer(serializers.ModelSerializer):
type = serializers.SerializerMethodField()
def get_type(self, obj):
return self.context['view'].kwargs['type'].upper()
The view, request and format keys are automatically added to your serializer context by all of the DRF generic views (http://www.django-rest-framework.org/api-guide/generic-views/#methods at the end of the section). This works just fine.
If you are creating a serializer instance manually, you will have to pass context=contextDict as an argument, where contextDict is whatever you need it to be (http://www.django-rest-framework.org/api-guide/serializers/#including-extra-context).
As #Michael has pointed out in another answer, the SerializerMethodField will be read only. But going by your first example (type = serializers.CharField(read_only=True.....) this seems to be what you want.

Django: Auto Instantiation of custom primary key?

I have a class with a custom pk field, and a classmethod to generate this special pk:
class Card(models.Model):
custom_pk = models.BigIntegerField(primary_key=True)
other_attr = ...
#classmethod
def gen_id(cls):
# ...
return the_id
Now, I suppose I can create object (in a view for example) doing this:
Card.objects.create(custom_pk=Card.gen_id(), other_attr="foo")
But I'd like to have the same result using the classic way to do it:
Card.objects.create(other_attr="foo")
Thanks!
You can use pre_save signal to supply your primary key is missing. This signal handler will be called before each call to Card.save() method, therefore we need to make sure that we won't override custom_pk if already set:
#receiver(pre_save, sender=Card)
def add_auto_pk(sender, instance, **kwargs):
if not instance.custom_pk:
instance.custom_pk = Card.get_id()
See Django signal documentation for more details.

django form custom widget for a "ListField" and displaying a list [duplicate]

I'm experimenting with django-nonrel on appengine and trying to use a djangotoolbox.fields.ListField to implement a many-to-many relation. As I read in the documentation a ListField is something that you can use to make a workaround for djamgo-nonrel not supporting many-to-many relations.
This is an excerpt from my model:
class MyClass(models.Model):
field = ListField(models.ForeignKey(AnotherClass))
So if I am getting this right I am creating a list of foreign keys to another class to show a relationship with multiple instances of another class
With this approach everything works fine ... No Exceptions. I can create `MyClass' objects in code and views. But when I try to use the admin interface I get the following error
No form field implemented for <class 'djangotoolbox.fields.ListField'>
So I though I would try something that I haven't done before. Create my own field. Well actually my own form for editing MyClass instances in the admin interface. Here is what I did:
class MyClassForm(ModelForm):
field = fields.MultipleChoiceField(choices=AnotherClass.objects.all(), widget=FilteredSelectMultiple("verbose_name", is_stacked=False))
class Meta:
model = MyClass
then I pass MyClassForm as the form to use to the admin interface
class MyClassAdmin(admin.ModelAdmin):
form = MyClassForm
admin.site.register(MyClass, MyClassAdmin)
I though that this would work but It doesn't. When I go to the admin interface I get the same error as before. Can anyone tell what I am doing wrong here ... or if you have any other suggestions or success stories of using the ListField, SetField, etc. from djangotoolbox.fields in the admin interface it would be very much appreciated.
OK, here is what I did to get this all working ...
I'll start from the beginning
This is what what my model looked like
class MyClass(models.Model):
field = ListField(models.ForeignKey(AnotherClass))
I wanted to be able to use the admin interface to create/edit instances of this model using a multiple select widget for the list field. Therefore, I created some custom classes as follows
class ModelListField(ListField):
def formfield(self, **kwargs):
return FormListField(**kwargs)
class ListFieldWidget(SelectMultiple):
pass
class FormListField(MultipleChoiceField):
"""
This is a custom form field that can display a ModelListField as a Multiple Select GUI element.
"""
widget = ListFieldWidget
def clean(self, value):
#TODO: clean your data in whatever way is correct in your case and return cleaned data instead of just the value
return value
These classes allow the listfield to be used in the admin. Then I created a form to use in the admin site
class MyClassForm(ModelForm):
def __init__(self, *args, **kwargs):
super(MyClasstForm,self).__init__(*args, **kwargs)
self.fields['field'].widget.choices = [(i.pk, i) for i in AnotherClass.objects.all()]
if self.instance.pk:
self.fields['field'].initial = self.instance.field
class Meta:
model = MyClass
After having done this I created a admin model and registered it with the admin site
class MyClassAdmin(admin.ModelAdmin):
form = MyClassForm
def __init__(self, model, admin_site):
super(MyClassAdmin,self).__init__(model, admin_site)
admin.site.register(MyClass, MyClassAdmin)
This is now working in my code. Keep in mind that this approach might not at all be well suited for google_appengine as I am not very adept at how it works and it might create inefficient queries an such.
As far as I understand, you're trying to have a M2M relationship in django-nonrel, which is not an out-of-the-box functionality. For starters, if you want a quick hack, you can go with this simple class and use a CharField to enter foreign keys manually:
class ListFormField(forms.Field):
""" A form field for being able to display a djangotoolbox.fields.ListField. """
widget = ListWidget
def clean(self, value):
return [v.strip() for v in value.split(',') if len(v.strip()) > 0]
But if you want to have a multiple selection from a list of models normally you'd have to use ModelMultipleChoiceField, which is also not functional in django-nonrel. Here's what I've done to emulate a M2M relationship using a MultipleSelectField:
Let's say you have a M2M relationship between 2 classes, SomeClass and AnotherClass respectively. You want to select the relationship on the form for SomeClass. Also I assume you want to hold the references as a ListField in SomeClass. (Naturally you want to create M2M relationships as they're explained here, to prevent exploding indexes if you're working on App Engine).
So you have your models like:
class SomeClass(models.Model):
another_class_ids = ListField(models.PositiveIntegerField(), null=True, blank=True)
#fields go here
class AnotherClass(models.Model):
#fields go here
And in your form:
class SomeClassForm(forms.ModelForm):
#Empty field, will be populated after form is initialized
#Otherwise selection list is not refreshed after new entities are created.
another_class = forms.MultipleChoiceField(required=False)
def __init__(self, *args, **kwargs):
super(SomeClassForm,self).__init__(*args, **kwargs)
self.fields['another_class'].choices = [(item.pk,item) for item in AnotherClass.objects.all()]
if self.instance.pk: #If class is saved, highlight the instances that are related
self.fields['another_class'].initial = self.instance.another_class_ids
def save(self, *args, **kwargs):
self.instance.another_class_ids = self.cleaned_data['another_class']
return super(SomeClassForm, self).save()
class Meta:
model = SomeClass
Hopefully this should get you going for the start, I implemented this functionality for normal forms, adjust it for admin panel shouldn't be that hard.
This could be unrelated but for the admin interface, be sure you have djangotoolbox listed after django.contrib.admin in the settings.. INSTALLED_APPS
You could avoid a custom form class for such usage by inquiring for the model object
class ModelListField(ListField):
def __init__(self, embedded_model=None, *args, **kwargs):
super(ModelListField, self).__init__(*args, **kwargs)
self._model = embedded_model.embedded_model
def formfield(self, **kwargs):
return FormListField(model=self._model, **kwargs)
class ListFieldWidget(SelectMultiple):
pass
class FormListField(MultipleChoiceField):
widget = ListFieldWidget
def __init__(self, model=None, *args, **kwargs):
self._model = model
super(FormListField, self).__init__(*args, **kwargs)
self.widget.choices = [(unicode(i.pk), i) for i in self._model.objects.all()]
def to_python(self, value):
return [self._model.objects.get(pk=key) for key in value]
def clean(self, value):
return value

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