Develop Reference

How can i fix my problem with pyautogui.click?

Need to mention that im new with Python and i decided to create a bot for multiplayer game, to autobuy items on auctionhouse, using opencv and pyautogui, so far everything was going pretty well, the cursor was heading to the right point on the screen (reload auction), but
pyautogui.click(clicks=1) isnt working in game window.
IDE (PyCharm) is running with admin rights, googled alot about the topic, but nothing works so far. Will be pleased if anyone could help me, this is my first big project i really want to work with, so hopefully you guys can help me :D
additional info: game uses Battle Eye anticheat, engine Java (probably... Game is called Stalcraft, you can find it on steam, looks like its something Minecraft-based, but im not sure about it)
OS: Win 10 x64
Python:3.11
What i tried:
pyautogui library (tried pyautogui.MoveTo(x,y) and the method with pyautogui.locateCenterOnScreen("whatever.png",confidence=0.85 Need to mention that first method works only in IDE, the second one based on img recognition also works with browser. Tried this in other apps, but no results. It's just hovering cursor on the right place, but no clicks at all)
pydirectinput library
Here's what i got so far
import cv2
import random
import pyautogui
from time import sleep
import imutils
import numpy as np
import pydirectinput
pyautogui.FAILSAFE=True
rng=random.uniform(0.87, 1.3)
sleep(5)
pyautogui.size()
print(pyautogui.size())
pyautogui.position()
print(pyautogui.position())
pyautogui.moveTo(x=1344, y=342, duration=rng)
pyautogui.click(1344, 342, clicks=5)```

This might be very silly. But I had no luck with .click. In my sample I used .moveTo as you did, but then .mouseDown() and .mouseUp() to simulate a click. Also sometimes it required a delay between the two. I wonder if that combo would help instead?
pyautogui.mouseDown()
sleep(1)
pyautogui.mouseUp()

Click on specific area of the Screen using Python

Is it possible to make Python click on a specific area of the screen? For example, I want it to move the cursor and click near the upper right corner of the screen on a specific place by itself, maybe with PyAutoGUI.

using pyautogui this can be easily done.
you can get pyautogui using pip install pyautogui in the terminal.
if that didn't work use pip install PyAutoGUI.
than using the code bellow you can click anywhere on the screen
import pyautogui
pyautogui.click(100,200)
#x , y
read more about pyautogui here
Try searching things in googles more often before asking question in stack overflow or other places, this could result in learning python and other thing way faster, for example when I searched your questions title the first thing that came up instantly gave me the answer.

import pyautogui
pyautogui.click(100, 100)
Where x and y coordinates go in .click(x, y)
You can read the docs here

Just to make it easier for use in code.
import pyautogui
def click(a, b):
pyautogui.click(a, b)
click(100, 200)

Take a screenshot that includes the cursor

I am trying to make a program with pyautogui that does different things depending on how the cursor looks (for example the cursor looks different when you are resizing a window or something like that), however when taking a screenshot with pyautogui.screenshot() the cursor itself isn't included in the image. Is there any way to take a screenshot with python that will include the cursor? photo of what I mean

There is no way (that I know of, anyway) you can include the cursor in the screenshot using pyautogui.
But there are 2 hacky work-arounds :-
You could press the hotkeys for taking the screenshot, i.e., just make the system take the screenshot, and get the image that way. For windows, it is win + prtscn, as far as I remember.
You could get the position of the mouse at the time of taking the screenshot, get an image of a cursor from the net, and overlay the cursor over the screenshot taken by pyautogui using PIL or any other library as you wish.

pyautogui and pywinauto combine to click application in background

what i am trying to do:
i trying to use the code below to locate and give me a X and Y position of the image
pyautogui.locateCenterOnScreen('accept.png')
after locating the image, i am trying to use pywinauto* to click on the image location in the background.
form.click(button='left', pressed='', coords=(pyautogui.locateCenterOnScreen('accept.png')), double=False, absolute=False)
problem:
nothing seems to happen.. i dont understand why. i checked on the pywinauto* and pyautogui "cheat sheets" it seems okay
someone please enlighten me

The correct spelling is "pywinauto". Method .click_input(...) with the same params is what you need as it moves the cursor and performs realistic click.
Method .click(...) silently sends window messages like WM_LBUTTONDOWN and WM_LBUTTONUP which may not work for some UI elements if they don't handle it.

pyautogui.locateOnScreen() Returns... Nothing?

I'm trying to use PyAutoGui's image recognition functions. (OS X)
Needless to say, I'm running into some slight issues that I can't seem to solve myself no matter where I look or what I do. I'm attempting to have PyAutoGui click on the Chrome shortcut based off a .png screenshot saved to my desktop.
Here's my code in terminal:
>>>import pyautogui
>>>chrome = pyautogui.locateOnScreen('/Users/ianscalzo/Desktop/chrome.png")
>>>
I get no backfire on my filepath, but it causes my shell/terminal to return nothing but go to a new line. (As shown in the code example above - Just causes terminal to go to a blank ">>>")
I don't really understand why it doesn't do anything but go to a new line, so any insight would be greatly appreciated.
Thank you so much!

After struggling with this forever also, finally figured out that you either use command line to take the screenshot or using the screenshot button with windows key. It doesn't work with the snipping tool.
so try:
image = pyautogui.screenshot()
image.save('testing.png')
Go and crop testing.png as small as possible so that locateOnScreen works faster. Then go back to the terminal and type:
pyautogui.locateOnScreen('testing.png')