I have a relatively simple nested dictionary as below:
emp_details = {
'Employee': {
'jim': {'ID':'001', 'Sales':'75000', 'Title': 'Lead'},
'eva': {'ID':'002', 'Sales': '50000', 'Title': 'Associate'},
'tony': {'ID':'003', 'Sales': '150000', 'Title': 'Manager'}
}
}
I can get the sales info of 'eva' easily by:
print(emp_details['Employee']['eva']['Sales'])
but I'm having difficulty writing a statement to extract information on all employees whose sales are over 50000.
You can't use one statement because the list initializer expression can't have an if without an else.
Use a for loop:
result = {} # dict expression
result_list = [] # list expression using (key, value)
for key, value in list(emp_details['Employee'].items())): # iterate from all items in dictionary
if int(value['Sales']) > 50000: # your judgement
result[key] = value # add to dict
result_list.append((key, value)) # add to list
print(result)
print(result_list)
# should say:
'''
{'jim': {'ID':'001', 'Sales':'75000', 'Title': 'Lead'}, 'tony': {'ID':'003', 'Sales': '150000', 'Title': 'Manager'}}
[('jim', {'ID':'001', 'Sales':'75000', 'Title': 'Lead'}), ('tony', {'ID':'003', 'Sales': '150000', 'Title': 'Manager'})]
'''
Your Sales is of String type.
Therefore, we can do something like this to get the information of employees whose sales are over 50000 : -
Method1 :
If you just want to get the information : -
emp_details={'Employee':{'jim':{'ID':'001', 'Sales':'75000', 'Title': 'Lead'}, \
'eva':{'ID':'002', 'Sales': '50000', 'Title': 'Associate'}, \
'tony':{'ID':'003', 'Sales': '150000', 'Title': 'Manager'}
}}
for emp in emp_details['Employee']:
if int(emp_details['Employee'][emp]['Sales']) > 50000:
print(emp_details['Employee'][emp])
It print outs to -:
{'ID': '001', 'Sales': '75000', 'Title': 'Lead'}
{'ID': '003', 'Sales': '150000', 'Title': 'Manager'}
Method2 : You can use Dict and List comprehension to get complete information : -
emp_details={'Employee':{'jim':{'ID':'001', 'Sales':'75000', 'Title': 'Lead'}, \
'eva':{'ID':'002', 'Sales': '50000', 'Title': 'Associate'}, \
'tony':{'ID':'003', 'Sales': '150000', 'Title': 'Manager'}
}}
emp_details_dictComp = {k:v for k,v in list(emp_details['Employee'].items()) if int(v['Sales']) > 50000}
print(emp_details_dictComp)
emp_details_listComp = [(k,v) for k,v in list(emp_details['Employee'].items()) if int(v['Sales']) > 50000]
print(emp_details_listComp)
Result : -
{'jim': {'ID': '001', 'Sales': '75000', 'Title': 'Lead'}, 'tony': {'ID': '003', 'Sales': '150000', 'Title': 'Manager'}}
[('jim', {'ID': '001', 'Sales': '75000', 'Title': 'Lead'}), ('tony', {'ID': '003', 'Sales': '150000', 'Title': 'Manager'})]
Related
I was tasked to create a CRUD program using Python dictionaries. I need to write code to check if the inputted key and value already exists in the dictionary, so here is the code of dictionary plus the input that prompt the user to search for ID:
products = [
{'id': 1, 'name': 'Light bulb', 'price': 100, 'stock': 16},
{'id': 2, 'name': 'Measuring tape', 'price': 200, 'stock': 34},
{'id': 3, 'name': 'Fan', 'price': 120, 'stock': 79},
{'id': 4, 'name': 'Flat shoes', 'price': 260, 'stock': 47},
{'id': 5, 'name': 'Swiss Army knife', 'price': 80, 'stock': 12},
{'id': 6, 'name': 'Guitar', 'price': 193, 'stock': 25},
{'id': 7, 'name': 'Marble', 'price': 30, 'stock': 45},
{'id': 8, 'name': 'Stapler', 'price': 220, 'stock': 78},
{'id': 9, 'name': 'Wrench and hammer', 'price': 65, 'stock': 12}
]
id_search = int(input("Enter ID product you want to search: ")
I wanted to make the if-else statement to see if the ID exists in the products dictionary, otherwise display the message that the ID is not found. I tried the following
if id_search in products:
print("Product ID found")
else:
print("Product ID not found")
But the result is always "Product ID not found".
You have a list of dicts not just a dict. You have to search through list of dicts:
found = False
for product in products:
if product.get("id") == id_search:
found = True
break
print(found)
Note that if your dicts are sorted, you probably can use binary search.
if len([[*my_dict.values()][0] for my_dict in products if [*my_dict.values()][0] == id_search]) > 0:
print("Product ID found")
else:
print("Product ID not found")
I want to convert input json to nested json defined, I am not able to think of any json library which help me achieve this
Input json
[{'Name': 'John', 'state': 'Boston', 'currency': 'USD', 'marks': 100},
{'Name': 'Rohan', 'state': 'Paris', 'currency': 'EUR', 'marks': 20},
{'Name': 'Rohan', 'state': 'Lyon', 'currency': 'EUR', 'marks': 11.4},
{'Name': 'Messi', 'state': 'Madrid', 'currency': 'EUR', 'marks': 9.9},
{'Name': 'Lampard', 'state': 'London', 'currency': 'GBP', 'marks': 12.2},
{'Name': 'Lampard', 'state': 'London', 'currency': 'FBP', 'marks': 10.9}]
output json
{
"USD": {
"John": {
"Boston": [
{
"Marks": 100
}
]
},
Current scenario based on value Currency,Name,state,marks
The nested json can be put upto n level if required such as Name and state and marks or it can be Name , curreny , state and marks or Name,curreny and marks
So you want currency > name > state > list of marks.
One solution would be to create the structure using defaultdicts, and then just add to it.
from collections import defaultdict
from functools import wraps
data = [...]
def ddmaker(type_):
#wraps(dict)
def caller():
return defaultdict(type_)
return caller
# create the structure of the output
output = defaultdict(ddmaker(ddmaker(list)))
# add to it
for item in data:
currency = item["currency"]
name = item["Name"]
state = item["state"]
mark = item["marks"]
output[currency][name][state].append({'Marks': mark})
I am trying to figure out how to filter for the dictionaries that have a status of "awaiting_delivery". I am not sure how to do this (or if it is impossible). I am new to python and programming. I am using Python 3.8.5 on VS Code on Ubuntu 20.04. The data below is sample data that I created that resembles json data from an API. Any help on how to filter for "status" would be great. Thank you.
nested_dict = {
'list_data': [
{
'id': 189530,
'total': 40.05,
'user_data': {
'id': 1001,
'first_name': 'jane',
'last_name': 'doe'
},
'status': 'future_delivery'
},
{
'id': 286524,
'total': 264.89,
'user_data': {
'id': 1002,
'first_name': 'john',
'last_name': 'doe'
},
'status': 'awaiting_delivery'
},
{
'id': 368725,
'total': 1054.98,
'user_data': {
'id': 1003,
'first_name': 'chris',
'last_name': 'nobody'
},
'status': 'awaiting_delivery'
},
{
'id': 422955,
'total': 4892.78,
'user_data': {
'id': 1004,
'first_name': 'mary',
'last_name': 'madeup'
},
'status': 'future_delivery'
}
],
'current_page': 1,
'total': 2,
'first': 1,
'last': 5,
'per_page': 20
}
#confirm that nested_dict is a dictionary
print(type(nested_dict))
#create a list(int_list) from the nested_dict dictionary
int_list = nested_dict['list_data']
#confirm that int_list is a list
print(type(int_list))
#create the int_dict dictionary from the int_list list
for int_dict in int_list:
print(int_dict)
#this is my attempt at filtering the int_dict dictionar for all orders with a status of awaiting_delivery
for order in int_dict:
int_dict.get('status')
print(order)
Output from Terminal Follows:
<class 'dict'>
<class 'list'>
{'id': 189530, 'total': 40.05, 'user_data': {'id': 1001, 'first_name': 'jane', 'last_name': 'doe'}, 'status': 'future_delivery'}
{'id': 286524, 'total': 264.89, 'user_data': {'id': 1002, 'first_name': 'john', 'last_name': 'doe'}, 'status': 'awaiting_delivery'}
{'id': 368725, 'total': 1054.98, 'user_data': {'id': 1003, 'first_name': 'chris', 'last_name': 'nobody'}, 'status': 'awaiting_delivery'}
{'id': 422955, 'total': 4892.78, 'user_data': {'id': 1004, 'first_name': 'mary', 'last_name': 'madeup'}, 'status': 'future_delivery'}
id
total
user_data
status
You can obtain a filtered list of dicts by doing conditional list comprehension on your list of dicts:
# filter the data
list_data_filtered = [entry for entry in nested_dict['list_data']
if entry['status'] == 'awaiting_delivery']
# print out the results
for entry in list_data_filtered:
print(entry)
# results
# {'id': 286524, 'total': 264.89, 'user_data': {'id': 1002, 'first_name': 'john', 'last_name': 'doe'}, 'status': 'awaiting_delivery'}
# {'id': 368725, 'total': 1054.98, 'user_data': {'id': 1003, 'first_name': 'chris', 'last_name': 'nobody'}, 'status': 'awaiting_delivery'}
I have a complex situation which I hope to solve and which might profit us all. I collected data from my API, added a pagination and inserted the complete data package in a tuple named q1 and finally I have made a dictionary named dict_1of that tuple which looks like this:
dict_1 = {100: {'ID': 100, 'DKSTGFase': None, 'DK': False, 'KM': None,
'Country: {'Name': GE', 'City': {'Name': 'Berlin'}},
'Type': {'Name': '219'}, 'DKObject': {'Name': '8555', 'Object': {'Name': 'Car'}},
'Order': {'OrderId': 101, 'CreatedOn': '2018-07-06T16:54:36.783+02:00',
'ModifiedOn': '2018-07-06T16:54:36.783+02:00',
'Name': Audi, 'Client': {‘1’ }}, 'DKComponent': {'Name': ‘John’}},
{200: {'ID': 200, 'DKSTGFase': None, 'DK': False, ' KM ': None,
'Country: {'Name': ES', 'City': {'Name': 'Madrid'}}, 'Type': {'Name': '220'},
'DKObject': {'Name': '8556', 'Object': {'Name': 'Car'}},
'Order': {'OrderId': 102, 'CreatedOn': '2018-07-06T16:54:36.783+02:00',
'ModifiedOn': '2018-07-06T16:54:36.783+02:00',
'Name': Mercedes, 'Client': {‘2’ }}, 'DKComponent': {'Name': ‘Sergio’}},
Please note that in the above dictionary I have just stated 2 records. The actual dictionary has 1400 records till it reaches ID 1500.
Now I want to 2 things:
I want to change some keys for all the records. key DK has to become DK1. Key Name in Country has to become Name1 and Name in Object has to become 'Name2'
The second thing I want is to make a dataFrame of the whole bunch of data. My expected outcome is:
This is my code:
q1 = response_2.json()
next_link = q1['#odata.nextLink']
q1 = [tuple(q1.values())]
while next_link:
new_response = requests.get(next_link, headers=headers, proxies=proxies)
new_data = new_response.json()
q1.append(tuple(new_data.values()))
next_link = new_data.get('#odata.nextLink', None)
dict_1 = {
record['ID']: record
for tup in q1
for record in tup[2]
}
#print(dict_1)
for x in dict_1.values():
x['DK1'] = x['DK']
x['Country']['Name1'] = x['Country']['Name']
x['Object']['Name2'] = x['Object']['Name']
df = pd.DataFrame(dict_1)
When i run this I receive the following Error:
Traceback (most recent call last):
File "c:\data\FF\Desktop\Python\PythongMySQL\Talky.py", line 57, in <module>
x['Country']['Name1'] = x['Country']['Name']
TypeError: 'NoneType' object is not subscriptable
working code
lists=[]
alldict=[{100: {'ID': 100, 'DKSTGFase': None, 'DK': False, 'KM': None,
'Country': {'Name': 'GE', 'City': {'Name': 'Berlin'}},
'Type': {'Name': '219'}, 'DKObject': {'Name': '8555', 'Object': {'Name': 'Car'}},
'Order': {'OrderId': 101, 'CreatedOn': '2018-07-06T16:54:36.783+02:00',
'ModifiedOn': '2018-07-06T16:54:36.783+02:00',
'Name': 'Audi', 'Client': {'1' }}, 'DKComponent': {'Name': 'John'}}}]
for eachdict in alldict:
key=list(eachdict.keys())[0]
eachdict[key]['DK1']=eachdict[key]['DK']
del eachdict[key]['DK']
eachdict[key]['Country']['Name1']=eachdict[key]['Country']['Name']
del eachdict[key]['Country']['Name']
eachdict[key]['DKObject']['Object']['Name2']=eachdict[key]['DKObject']['Object']['Name']
del eachdict[key]['DKObject']['Object']['Name']
lists.append([key, eachdict[key]['DK1'], eachdict[key]['KM'], eachdict[key]['Country']['Name1'],
eachdict[key]['Country']['City']['Name'], eachdict[key]['DKObject']['Object']['Name2'], eachdict[key]['Order']['Client']])
pd.DataFrame(lists, columns=[<columnNamesHere>])
Output:
{100: {'ID': 100,
'DKSTGFase': None,
'KM': None,
'Country': {'City': {'Name': 'Berlin'}, 'Name1': 'GE'},
'Type': {'Name': '219'},
'DKObject': {'Name': '8555', 'Object': {'Name2': 'Car'}},
'Order': {'OrderId': 101,
'CreatedOn': '2018-07-06T16:54:36.783+02:00',
'ModifiedOn': '2018-07-06T16:54:36.783+02:00',
'Name': 'Audi',
'Client': {'1'}},
'DKComponent': {'Name': 'John'},
'DK1': False}}
I've been stuck on this for hours.. I want to retrieve only ONE individuals keys and values from a dictionary that is nested inside of a list.
GAMERS = [{
'name': 'Fatboi',
'parent': 'Dick Van Dyke',
'game': 'Dark Souls 3',
'weight': '420 lbs'
},
{
'name': 'Justin',
'parent': 'Heather Blueberry',
'game': 'Tetris',
'weight': '180 lbs'
},
{
'name': 'jerkhead',
'parent': 'none',
'games': 'Hello Kitty',
'weight': '240 lbs'
},{
'name': 'Tumor',
'parent': 'Jack Black',
'games': 'Trying to live',
'weight': '150 lbs'
}]
So for instance I want to get Justins information printed only, nobody elses. Any insights?
You can pass the key which you want and push it to separate list.
GAMERS = [{
'name': 'Fatboi',
'parent': 'Dick Van Dyke',
'game': 'Dark Souls 3',
'weight': '420 lbs'
},
{
'name': 'Justin',
'parent': 'Heather Blueberry',
'game': 'Tetris',
'weight': '180 lbs'
},{
'name': 'jerkhead',
'parent': 'none',
'games': 'Hello Kitty',
'weight': '240 lbs'
}]
def get_key_pair_list(input_dict, key):
new_list = []
for item in input_dict:
my_dict = {}
if key in item.keys():
my_dict[key] = item[key]
new_list.append(my_dict)
return new_list
print(get_key_pair_list(GAMERS, 'name'))
Output:
[{'name': 'Fatboi'}, {'name': 'Justin'}, {'name': 'jerkhead'}]
Comprehensive way:
key = 'name'
my_list = [{key, item[key]} for item in GAMERS if key in item.keys() ]
print(my_list)
output:
[{'name', 'Fatboi'}, {'name', 'Justin'}, {'name', 'jerkhead'}]
You want to filter the list and grab the first value that matches a predicate. Make sure to handle the case where the item doesnt exist!
filtered_info = (
item for item in GAMERS if item['name'] == 'Justin'
)
justin_info = next(filtered_info, None)
if justin_info is not None:
print(justin_info)