I'm building a Django project in which I need to take a picture from webcam, and then store it in my database and as a file. I'm saving the source in the database, but I'm having some trouble saving it as a file.
Here is my code:
html:
<form method="POST" action="{% url 'takePhoto' %}" enctype="multipart/form-data">
{% csrf_token %}
<video id="video" autoplay ></video>
<canvas id="canvas"></canvas>
<input type="hidden" name="photo" id="photo" value=""/>
<button id="startbutton1" class="btn btn-outline-secondary btn-sm">Take Photo</button>
<button id="submit" type="submit">submit</button>
<script src="{% static 'scripts/script.js' %}"></script>
javascript:
(function() {
var width = 320;
var height = 0;
var streaming = false;
var video = null;
var canvas = null;
var photo = null;
var startbutton1 = null;
function startup() {
video = document.getElementById('video');
canvas = document.getElementById('canvas');
photo = document.getElementById('photo');
startbutton1 = document.getElementById('startbutton1');
navigator.mediaDevices.getUserMedia({video: true, audio: false})
.then(function(stream) {
video.srcObject = stream;
video.play();
})
.catch(function(err) {
console.log("An error occurred: " + err);
});
video.addEventListener('canplay', function(ev){
if (!streaming) {
height = video.videoHeight / (video.videoWidth/width);
if (isNaN(height)) {
height = width / (4/3);
}
video.setAttribute('width', width);
video.setAttribute('height', height);
canvas.setAttribute('width', width);
canvas.setAttribute('height', height);
streaming = true;
}
}, false);
startbutton1.addEventListener('click', function(ev){
takepicture();
ev.preventDefault();
}, false);
clearphoto();
}
function clearphoto() {
var context = canvas.getContext('2d');
context.fillStyle = "#AAA";
context.fillRect(0, 0, canvas.width, canvas.height);
var data = canvas.toDataURL('image/png');
photo.setAttribute('src', data);
}
function takepicture() {
var context = canvas.getContext('2d');
if (width && height) {
canvas.width = width;
canvas.height = height;
context.drawImage(video, 0, 0, width, height);
var data = canvas.toDataURL('image/png');
photo.value=data;
} else {
clearphoto();
}
}
window.addEventListener('load', startup, false);
})();
views:
def takePhoto(request):
print("works")
if not request.session.get('logged_in'):
return redirect('/appChallenge/login')
if request.method== 'POST':
user = User.objects.get(username=request.session["username"])
img = request.POST.get("photo")
image = img
imagePath="/media"
a=str(img)
image = image.save(f"{imagePath}/{a}.png")
imgInfo= Image(user=user, img=img)
imgInfo.save()
print("works")
return render(request, 'page.html')
When I click submit, it says "'str' object has no attribute 'save'"
Please help. Thanks.
If your js/html code works, you will receive a raw image data encoded to base64 in your view 'takePhoto'. Try
print(img) to see something like "data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAUAAAADwCAYAA...."
Maybe you will see just "iVBORw0KGgoAAAANSUhEUgAAAUAAAADwCAYAA...." without meta data.
So your 'img' is just a string with base64 encoded value, that hasn't method 'save'.
First, you need to get rid of "data:image/png;base64," in your raw image data, if your image string contains it. It is meta data and base64 could not decode it. You can do it at front end side:
var data = canvas.toDataURL('image/png').replace(/^data:image\/png;base64,/, "")
Or back end:
img = request.POST.get("photo").replace('data:image/png;base64,', '')
Next you need to use django ContentFile to create a file-like object. You need to simulate file with its method .read(). Also you need to decode base64 encoded image data:
import base64
from django.core.files.base import ContentFile
def takePhoto(request):
print("works")
if not request.session.get('logged_in'):
return redirect('/appChallenge/login')
if request.method== 'POST':
user = request.user
# remove meta data from base64 encoded data, you can also
# use 'split(',')[1]' to remove all before ','
img = request.POST.get("photo").replace('data:image/png;base64,', '')
# create a file-like object with your image data
image_file_like = ContentFile(base64.b64decode(img))
# first you need to create object
image = Image(user=user)
# and then save image into your model object
# note: only if your 'img' field is 'ImageField' or similar
image.img.save("filename.png", image_file_like)
image.save()
print("works")
return render(request, 'page.html')
P.S:
You don't need to add 'media' prefix in your image file name while saving it.
You should add MEDIA_ROOT variable in your settings.py like this:
BASE_DIR = Path(__file__).resolve().parent.parent # or manually set the path of your project
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
And all files automatically will be saved in your project media directory.
Related
I am new in Flask. My goal is to generate dynamic div containers every time I upload a dxf file and next submit happens. For example: one file uploaded- one div shown; two files uploaded- two divs shown and so on.
I can convert uploaded dxf files to .png images and I would like to show these images in div elements displayed after every upload.
I use input tag to upload files (type='file') and Java Script to generate dynamic elements (divs and their child tags).
The problem is that every time I upload file, the template is loading again and no new content is shown except the image of the last uploaded dxf. Please, give me a piece of advice to solve it.
HTML
...
<form enctype="multipart/form-data" id="uploadForm" action="/upload_files" name="uploadForm" method="post">
DXF file: <input type="file" id="dxfUpload" onchange="form.submit(); createConfigure();" name="dxfUpload" />
<div id="calcHolder" name="calcHolder">
<script type="text/javascript">
function createConfigure() {
var div = document.createElement("div");
div.id = "dxf-"+Math.random() * 100000000000000000 + "-"
+ window.performance.now() * 100000000000000000;
id_div=div.id;
div.className = 'border pad';
div.style.width = "640px";
div.style.height = "200px";
document.getElementById("calcHolder").appendChild(div);
var img = document.createElement("img");
img.setAttribute("src", "{{url_for('static', filename=dxfName+'.png')}}");
img.setAttribute("alt", "no image");
img.setAttribute("height", "120px");
img.setAttribute("width", "120px");
document.getElementById(id_div).appendChild(img);
var array = ["Carbon Steel","Stainless Steel","Aluminium"];
var selectMaterial = document.createElement("select");
document.getElementById(id_div).appendChild(selectMaterial);
for (var i = 0; i < array.length; i++) {
var option = document.createElement("option");
option.value = array[i];
option.text = array[i];
selectMaterial.appendChild(option);
}
var selectThickness = document.createElement("select");
document.getElementById(id_div).appendChild(selectThickness);
for (i = 1; i <= 16; i++) {
var opt = document.createElement('option');
//opt.value = i;
opt.innerHTML = i + ' mm';
selectThickness.appendChild(opt);
}
var quantity = document.createElement("input")
quantity.type="number";
quantity.value="1";
quantity.name="quantity";
quantity.min="1";
quantity.max="50";
quantity.onkeyup= function maxReach(){if(quantity.value > 50) quantity.value=50;};
document.getElementById(id_div).appendChild(quantity);
var btn = document.createElement("button");
btn.innerHTML = "Delete";
btn.type = "button";
document.getElementById(id_div).appendChild(btn);
btn.onclick = function() {div.remove();};
}
</script>
{{ html | safe }}
</div>
</form>
...
Python
#app.route('/upload_files', methods=['POST'])
def upload_files():
try:
if request.method == 'POST':
dxf_file = request.files['dxfUpload']
full_filename = os.path.join(app.config['UPLOAD_FOLDER'],dxf_file.filename)
dxf_file.save(full_filename)
first = DXF2IMG()
first.convert_dxf2img([full_filename],img_format='.png')
html="<img src="+url_for('static', filename=dxf_file.filename+'.png' )+" width='120' height='120' />"
return render_template('upload_files.html',dxfName=dxf_file.filename, html=html)
except:
...
#something happens
The result now
Desired result
Once the form.submit() function is executed, the form will be sent as a regular post request. For this reason, the following function is no longer executed and the entire page is reloaded.
In order to submit the form and change the content of the existing page, it is necessary to use AJAX.
This example shows you how to submit the form to the server and receive a JSON response containing the URLs of the received file and the generated image.
As soon as the submit button is pressed, the form data is packed into a FormData object and sent via AJAX using the fetch function. The browser's default behavior for a submit event is suppressed and the form is reset. The received file is processed by the server and the associated URLs are sent back to the client in JSON format. Now the document can be changed with the received data.
Remember this is just a minimal example to help you achieve your goals and implement your concept.
Flask (app.py)
import os
import ezdxf
from ezdxf.addons.drawing import matplotlib
from flask import Flask
from flask import (
jsonify,
make_response,
render_template,
url_for
)
from werkzeug.utils import secure_filename
app = Flask(__name__)
#app.route('/')
def index():
return render_template('index.html')
def dxf2png(source, target):
doc = ezdxf.readfile(source)
msp = doc.modelspace()
auditor = doc.audit()
if auditor.has_errors:
raise Exception('Conversion failed.')
matplotlib.qsave(doc.modelspace(), target)
#app.route('/upload', methods=['POST'])
def upload():
if 'dxf-file' in request.files:
file = request.files['dxf-file']
if file.filename != '':
filename = secure_filename(file.filename)
filepath = os.path.join(app.static_folder, filename)
destname, _ = os.path.splitext(filename)
destname = f'{destname}.png'
destpath = os.path.join(app.static_folder, destname)
file.save(filepath)
try:
dxf2png(filepath, destpath)
except:
os.remove(filepath)
return make_response('', 400)
return make_response(
jsonify(
target=url_for('static', filename=filename),
preview=url_for('static', filename=destname)
),
200
)
return make_response('', 400)
HTML (templates/index.html)
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Index</title>
<style media="screen">
.preview {
width: 120px;
height: auto;
}
</style>
</head>
<body>
<form name="dxf-upload" method="post" enctype="multipart/form-data">
<input type="file" name="dxf-file" />
<input type="submit" />
</form>
<div id="dxf-files"></div>
<script type="text/javascript">
((uri) => {
function createPreview(target, preview) {
const divElem = document.createElement('div');
divElem.innerHTML = `<img src="${preview}" class="preview" />`;
const outElem = document.getElementById('dxf-files');
outElem.append(divElem);
}
const form = document.querySelector('form[name="dxf-upload"]');
form.addEventListener('submit', evt => {
evt.preventDefault();
const formData = new FormData(evt.target);
fetch(uri, {
method: 'POST',
body: formData
}).then(resp => resp.json())
.then(data => {
const { target, preview } = data;
createPreview(target, preview);
});
evt.target.reset();
});
})({{ url_for('.upload') | tojson }});
</script>
</body>
</html>
I'm trying to run this website that takes using flask that takes a picture when u press next but it only works on the first time I go to that URL. When I get redirected to the same url then it no longer works.
Please help I've been stuck on this for months now and don't know what to do anymore.
from camera import VideoCamera
import cv2
import time
app = Flask(__name__)
app.config['SECRET_KEY'] = 'hello'
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///drug1.sqlite'
app.config['SQLALCHEMY_TRACK_MODIFICATIONS'] = False
db = SQLAlchemy(app)
med_list = []
timestr = time.strftime("%Y%m%d-%H%M%S")
cam = cv2.VideoCapture(0)
video_stream = VideoCamera()
#app.route('/')
def index():
return render_template('vid.html')
def gen(camera):
while True:
frame = camera.get_frame()
yield (b'--frame\r\n'
b'Content-Type: image/jpeg\r\n\r\n' + frame + b'\r\n\r\n')
#app.route('/video_feed')
def video_feed():
#app.route("/scan", methods =["POST","GET"])
def scan():
drug_list = []
if request.method == 'POST':
bc = request.form['barcode']
print(bc)
if request.form['submit_button'] == 'Next':
return redirect(url_for('scan2',image=image_link,drug=drug,strength=strength,med_list=med_list))
return render_template("scan.html")
#app.route("/scan2", methods =["POST","GET"])
def scan2():
drug = session.get("drug",None)
image_link = session.get("image_link",None)
strength = session.get("strength",None)
if request.method == 'POST':
if request.form['submit_button'] == 'Next':
retval, frame = cam.read()
cv2.imwrite('img{}.png'.format(timestr), frame)
return redirect(url_for('scan'))
return render_template("scan2.html",image=image_link,drug=drug,strength=strength)
If you want to take a picture using built-in camera in user's laptop then you have to use JavaScript because only web browser has access to user's camera - server can't access user's computer.
Here is example which displays stream from user's camera and it can take screenshot. But it still need JavaScript to send it to server.
from flask import Flask, render_template_string
app = Flask(__name__)
#app.route('/')
def index():
return render_template_string('''
<video id="video" width="640" height="480" autoplay style="background-color: grey"></video>
<button id="snap">Take Photo</button>
<canvas id="canvas" width="640" height="480" style="background-color: grey"></canvas>
<script>
// Elements for taking the snapshot
var video = document.getElementById('video');
var canvas = document.getElementById('canvas');
var context = canvas.getContext('2d');
// Get access to the camera!
if(navigator.mediaDevices && navigator.mediaDevices.getUserMedia) {
// Not adding `{ audio: true }` since we only want video now
navigator.mediaDevices.getUserMedia({ video: true }).then(function(stream) {
//video.src = window.URL.createObjectURL(stream);
video.srcObject = stream; // assing stream to <video>
video.play(); // play stream
});
}
// Trigger photo take
document.getElementById("snap").addEventListener("click", function() {
context.drawImage(video, 0, 0, 640, 480); // copy video frame to canvas
});
</script>
''')
if __name__ == '__main__':
app.run(debug=True)
EDIT:
Here is example which can send image on server.
And few useful links which I had with this code
https://developers.google.com/web/fundamentals/media/capturing-images
https://github.com/jhuckaby/webcamjs
https://developer.mozilla.org/en-US/docs/Web/API/HTMLCanvasElement/toBlob
from flask import Flask, render_template_string, request
app = Flask(__name__)
#app.route('/')
def index():
return render_template_string('''
<video id="video" width="640" height="480" autoplay style="background-color: grey"></video>
<button id="send">Take & Send Photo</button>
<canvas id="canvas" width="640" height="480" style="background-color: grey"></canvas>
<script>
// Elements for taking the snapshot
var video = document.getElementById('video');
var canvas = document.getElementById('canvas');
var context = canvas.getContext('2d');
// Get access to the camera!
if(navigator.mediaDevices && navigator.mediaDevices.getUserMedia) {
// Not adding `{ audio: true }` since we only want video now
navigator.mediaDevices.getUserMedia({ video: true }).then(function(stream) {
//video.src = window.URL.createObjectURL(stream);
video.srcObject = stream;
video.play();
});
}
// Trigger photo take
document.getElementById("send").addEventListener("click", function() {
context.drawImage(video, 0, 0, 640, 480); // copy frame from <video>
canvas.toBlob(upload, "image/jpeg"); // convert to file and execute function `upload`
});
function upload(file) {
// create form and append file
var formdata = new FormData();
formdata.append("snap", file);
// create AJAX requests POST with file
var xhr = new XMLHttpRequest();
xhr.open("POST", "{{ url_for('upload') }}", true);
xhr.onload = function() {
if(this.status = 200) {
console.log(this.response);
} else {
console.error(xhr);
}
alert(this.response);
};
xhr.send(formdata);
}
</script>
''')
#app.route('/upload', methods=['GET', 'POST'])
def upload():
if request.method == 'POST':
#fs = request.files['snap'] # it raise error when there is no `snap` in form
fs = request.files.get('snap')
if fs:
print('FileStorage:', fs)
print('filename:', fs.filename)
fs.save('image.jpg')
return 'Got Snap!'
else:
return 'You forgot Snap!'
return 'Hello World!'
if __name__ == '__main__':
app.run(debug=True, port=5000)
EDIT:
I found example which sends stream to server, it draws red border and text with current time and it sends it back to browser.
# https://developers.google.com/web/fundamentals/media/capturing-images
# https://github.com/jhuckaby/webcamjs
# https://developer.mozilla.org/en-US/docs/Web/API/HTMLCanvasElement/toBlob
# https://developer.mozilla.org/en-US/docs/Web/API/HTMLCanvasElement/toDataURL
# https://developer.mozilla.org/en-US/docs/Web/API/FileReader/readAsDataURL
from flask import Flask, render_template_string, request, make_response
import cv2
import numpy as np
import datetime
app = Flask(__name__)
#app.route('/')
def index():
return render_template_string('''
<video id="video" width="320" height="240" autoplay style="background-color: grey"></video>
<button id="send">Take & Send Photo</button>
<canvas id="canvas" width="320" height="240" style="background-color: grey"></canvas>
<img id="image" src="" width="320" height="240" style="background-color: grey"></img>
<img id="image64" src="" width="320" height="240" style="background-color: grey"></img>
<script>
// Elements for taking the snapshot
var video = document.getElementById('video');
// Element to display snapshot
// you need canvas to get image. canvas can be hidden using `createElement("canvas")`
// var canvas = document.createElement("canvas");
var canvas = document.getElementById('canvas');
var context = canvas.getContext('2d');
var image = document.getElementById('image');
var image64 = document.getElementById('image64');
// Get access to the camera!
if(navigator.mediaDevices && navigator.mediaDevices.getUserMedia) {
// Not adding `{ audio: true }` since we only want video now
navigator.mediaDevices.getUserMedia({ video: true }).then(function(stream) {
//video.src = window.URL.createObjectURL(stream);
video.srcObject = stream;
video.play();
//console.log('setInterval')
window.setInterval(function() {
//context.drawImage(video, 0, 0);
context.drawImage(video, 0, 0, 320, 240); // better use size because camera may gives data in different size then <video> is displaying
image64.src = canvas.toDataURL();
canvas.toBlob(upload, "image/jpeg");
}, 100);
});
}
// Trigger photo take
document.getElementById("send").addEventListener("click", function() {
//context.drawImage(video, 0, 0);
context.drawImage(video, 0, 0, 320, 240); // better use size because camera may gives data in different size then <video> is displaying
image64.src = canvas.toDataURL();
canvas.toBlob(upload, "image/jpeg");
});
function upload(file) {
// create form
var formdata = new FormData();
// add file to form
formdata.append("snap", file);
// create AJAX connection
var xhr = new XMLHttpRequest();
xhr.open("POST", "{{ url_for('upload') }}", true);
xhr.responseType = 'blob';
// define function which get response
xhr.onload = function() {
if(this.status = 200) {
//console.log(this.response);
} else {
console.error(xhr);
}
//alert(this.response);
//img.onload = function(){
// ctx.drawImage(img, 0, 0)
//}
image.src = URL.createObjectURL(this.response); // blob
};
// send form in AJAX
xhr.send(formdata);
//image.src = URL.createObjectURL(file);
}
</script>
''')
def send_file_data(data, mimetype='image/jpeg', filename='output.jpg'):
# https://stackoverflow.com/questions/11017466/flask-to-return-image-stored-in-database/11017839
response = make_response(data)
response.headers.set('Content-Type', mimetype)
response.headers.set('Content-Disposition', 'attachment', filename=filename)
return response
#app.route('/upload', methods=['GET', 'POST'])
def upload():
if request.method == 'POST':
#fs = request.files['snap'] # it raise error when there is no `snap` in form
fs = request.files.get('snap')
if fs:
#print('FileStorage:', fs)
#print('filename:', fs.filename)
# https://stackoverflow.com/questions/27517688/can-an-uploaded-image-be-loaded-directly-by-cv2
# https://stackoverflow.com/a/11017839/1832058
img = cv2.imdecode(np.frombuffer(fs.read(), np.uint8), cv2.IMREAD_UNCHANGED)
#print('Shape:', img.shape)
# rectangle(image, start_point, end_point, color, thickness)
img = cv2.rectangle(img, (20, 20), (300, 220), (0, 0, 255), 2)
text = datetime.datetime.now().strftime('%Y.%m.%d %H.%M.%S.%f')
img = cv2.putText(img, text, (5, 15), cv2.FONT_HERSHEY_SIMPLEX, 0.5, (255, 255, 255), 1, cv2.LINE_AA)
#cv2.imshow('image', img)
#cv2.waitKey(1)
# https://jdhao.github.io/2019/07/06/python_opencv_pil_image_to_bytes/
ret, buf = cv2.imencode('.jpg', img)
#return f'Got Snap! {img.shape}'
return send_file_data(buf.tobytes())
else:
return 'You forgot Snap!'
return 'Hello World!'
if __name__ == '__main__':
app.run(debug=True, port=5000)
Camera works with HTTP only on address 127.0.0.1
On 0.0.0.0 it needs HTTPS but it needs cert. For test you can use ssl_context='adhoc' but browser will warn you that it is insecure connection and you will have to accept it.
app.run(host='0.0.0.0', port=5000, ssl_context='adhoc')
I hope the title is enough to understand my problem, as you can see in the image below, i can get the pciture from my database, the problem is when I update the data and I didnt change the picture displayed, it makes an error, the cause of the error is I didnt get any data from html
<label for="myfile3">
<img id="output3" src="{{selectbanner.image.url}}" style="height:225px;width:250px;" class="subimage"/><br>
<input type="file" accept="myfile" id="myfile3" name="image" value="{{selectbanner.image.url}}" onchange="loadFile3(event)" >
</label>
<script>
var loadFile3 = function(event) {
var reader = new FileReader();
reader.onload = function(){
var output3 = document.getElementById('output3');
output3.src = reader.result;
};
reader.readAsDataURL(event.target.files[0]);
};
</script>
this is my views.py
image = request.FILES.get('image')
print(image)
update = Banner.objects.get(id=banner_id)
update.image = image
update.title = Title
update.sub_title = Sub
update.description = Description
update.save()
return redirect('Banners')
Firstly I would say you should refer to previously asked related questions.
Refer to these:
This
This
And this
I'm writing flask api using keras. However I get a lot of errors. One of them is Error 405 - method not allowed.
POST http://0.0.0.0:5000/static/predict 405 (METHOD NOT ALLOWED) jquery-3.3.1.min.js
I'm trying to get predictions written on the page, but they didn't show even before that error 405.
I don't know which place can lead to that error.
Here is code:
predict.html
<body>
<input id="image-selector" type="file">
<button id="predict-button"> Predict</button>
<p style="font-weight:bold">Predictions</p>
<p> Jablko <span id="apple-prediction"></span></p>
<p> Banan <span id="banana-prediction"></span></p>
<img id="selected-image" src=""/>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
<script>
let base64Image;
$("#image-selector").change(function(){
let reader = new FileReader();
reader.onload = function(e){
let dataURL = reader.result;
$('#selected-image').attr("src", dataURL);
base64Image = dataURL.replace("data:image/jpg;base64,", "");
//console.log(base64Image);
}
reader.readAsDataURL($("#image-selector")[0].files[0]);
$("#apple-prediction").text("");
$("#banana-prediction").text("");
});
$("#predict-button").click(function(event){
let message = {
image:base64Image
}
//console.log(message);
$.post("http://0.0.0.0:5000/static/predict", function(response){
$("#apple-prediction").text(response.prediction.apple.toFixed(6));
$("#banana-prediction").text(response.prediction.banana.toFixed(6));
console.log(response);
});
});
</script>
</body>
predict.py
app = Flask(__name__)
def get_model():
global model
model=load_model('fc_model1.h5')
#model.load_weights('model_grocery.h5')
#graph = tf.get_default_graph
print("** Model loaded!")
def preprocess_image(image, target_size):
image = image.resize(target_size)
image = image.img_to_array(image)
image = np.expand_dims(image, axis=0)
return image
print("**Loading model**")
get_model()
#app.route("/predict", methods=["POST"])
def predict():
message = request.get_json(force=True)
encoded = message['image']
decoded = base64.b64decode(encoded)
image = Image.open(io.BytesIO(decoded))
processed_image = preprocess_image(image, target_size=(224, 224))
#bt_prediction = vgg16.predict(processed_image)
prediction = model.predict(processed_image).tolist()
response = {
'prediction': {
'apple': prediction[0][0],
'banana': prediction[0][1]
}
}
return jsonify(response)
The error shows in google-chrome.
Your JS code has
$.post("http://0.0.0.0:5000/static/predict")
but your Flask route is
#app.route("/predict", methods=["POST"])
def predict():
Because the snippet you posted doesn't show that you're prepending /static/ to all routes, it looks like that's a mistake.
You specified methods=['POST'] correctly, so visiting 127.0.0.1:5000/predict should yield the expected result.
If you wanted to check 0.0.0.0:5000/predict, you need to add app.run(host='0.0.0.0')(See: Configure Flask dev server to be visible across the network).
I want to upload image with ajax, crop the uploaded image and save the image.
I uses pillow 5.1.0., django 2.0.5.
models.py:
class TestPhoto(models.Model):
file = models.ImageField()
forms.py:
class TestPhotoFrom(forms.ModelForm):
# this is not necessary part, you can ignore it.
x = forms.FloatField(widget=forms.HiddenInput())
y = forms.FloatField(widget=forms.HiddenInput())
class Meta:
model = TestPhoto
fields = ('file', 'x', 'y',)
template.html:
<form method="post" enctype="multipart/form-data" id="formUpload">
{% csrf_token %}
{{ form }}
</form>
<button class="js-crop-and-upload">button</button>
<script>
$(function () {
$(".js-crop-and-upload").click(function () {
//Get file from form.
var form_upload = $("#formUpload")[0];
var form_data = new FormData(form_upload);
//Send file with ajax.
$.ajax({
url:'/crop/',
type:'post',
dataType:'json',
cache:false,
processData: false,
contentType: false,
data:{
'file': form_data,
'value': 'test_value',
},
success:function (data) {
console.log(data)
}
});
});
});
</script>
views.py:
def crop(request):
if request.method == "GET":
form = TestPhotoFrom()
return render(request, 'authapp/crop.html', {'form': form})
else:
if request.is_ajax():
# get file from request.
file = request.FILES
image = Image.open(file)
# cropping image
cropped_image = image.crop((0, 0, 200, 200))
resized_image = cropped_image.resize((200, 200), Image.ANTIALIAS)
# save cropped image
resized_image.save()
return JsonResponse({'success': 'file_uploaded'})
I read this: https://simpleisbetterthancomplex.com/tutorial/2017/03/02/how-to-crop-images-in-a-django-application.html
And now I need to do that with jquery-ajax.
But when I click button to do ajax request, server console is printing this error:
'MultiValueDict' object has no attribute 'read'
How can I do that?
Sorry, I don't know also whether these part on views.py is correct or not:
image = Image.open(file)
cropped_image = image.crop((0, 0, 200, 200))
resized_image = cropped_image.resize((200, 200), Image.ANTIALIAS)
resized_image.save()
But before checking it, I cannot solve this: 'MultiValueDict' object has no attribute 'read'
Question.1:
How can I solve 'MultiValueDict' object has no attribute 'read'?
Question.2:
Is this part correct? Or will it be working well?
image = Image.open(file)
cropped_image = image.crop((0, 0, 200, 200))
resized_image = cropped_image.resize((200, 200), Image.ANTIALIAS)
resized_image.save()
Because I'm very newbie in uploading image with ajax on django very little, I want your explanation or modification.
Thanks for reading poor question.
I can only give you an answer for the ajax side
When using FormData, you have to pass it as the data parameter.
If you want to add other fields you will use append()
#formUpload would be the form with the file input used to select the image.
$(".js-crop-and-upload").click(function () {
//Get file from form.
var form_upload = $("#formUpload")[0];
var form_data = new FormData(form_upload);
form_data.append('value', 'test_value');
//Send file with ajax.
$.ajax({
url:'/crop/',
type:'post',
dataType:'json',
cache:false,
processData: false,
contentType: false,
data:form_data,
success:function (data) {
console.log(data)
}
});
});