How can I delete file with particular extension from s3 bucket using pycharm boto3 library.
For example I have an s3 bucket having multiple files with different extension like '.txt' , '.csv' etc.
I want to create python script which will delete file from s3 having ".csv" extension only
Please help
You can add a trigger on your S3 bucket with a suffix value as ".csv" to invoke a lambda where you can read the bucket and key from the event and use boto3's delete() method to delete the CSV file.
`import boto3
s3 = boto3.resource('s3')
s3.Object('your-bucket', 'your-key').delete()`
Related
I'm trying to read a file content's (not to download it) from an S3 bucket. The problem is that the file is located under a multi-level folder. For instance, the full path could be s3://s3-bucket/folder-1/folder-2/my_file.json. How can I get that specific file instead of using my iterative approach that lists all objects?
Here is the code that I want to change:
import boto3
s3 = boto3.resource('s3')
bucket = s3.Bucket('s3-bucket')
for obj in my_bucket.objects.all():
key = obj.key
if key == 'folder-1/folder-2/my_file.json':
return obj.get()['Body'].read()
Can it be done in a simpler, more direct way?
Yes - there is no need to enumerate the bucket.
Read the file directly using s3.Object, providing the bucket name as the 1st parameter & the object key as the 2nd parameter.
"Folders" don't really exist in S3 - Amazon S3 doesn't use hierarchy to organize its objects and files. For the sake of organizational simplicity, the Amazon S3 console shows "folders" as a means of grouping objects but they are ultimately baked into your object key.
This should work:
import boto3
s3 = boto3.resource('s3')
obj = s3.Object("s3-bucket", "folder-1/folder-2/my_file.json")
body = obj.get()['Body'].read()
I have boto code that collects S3 sub-folders in levelOne folder:
import boto
s3 = boto.connect_s3()
bucket = s3.get_bucket("MyBucket")
for level2 in bucket.list(prefix="levelOne/", delimiter="/"):
print(level2.name)
Please help to discover similar functionality in boto3. The code should not iterate through all S3 objects because the bucket has a very big number of objects.
If you are simply seeking a list of folders, then use CommonPrefixes returned when listing objects. Note that a Delimiter must be specified to obtain the CommonPrefixes:
import boto3
s3_client = boto3.client('s3')
response = s3_client.list_objects_v2(Bucket='BUCKET-NAME', Delimiter = '/')
for prefix in response['CommonPrefixes']:
print(prefix['Prefix'][:-1])
If your bucket has a HUGE number of folders and objects, you might consider using Amazon S3 Inventory, which can provide a daily or weekly CSV file listing all objects.
I think the following should be equivalent:
import boto3
s3 = boto3.resource('s3')
bucket = s3.Bucket('MyBucket')
for object in bucket.objects.filter(Prefix="levelOne/", Delimiter="/"):
print(object.key)
I extracted an Excel file with multiple sheets from S3 and I am turning each sheet into csv format and doing a simple cleansing before uploading it to another S3 bucket.
This is my code so far for my Lambda function but I have no idea how to upload the csv file for each sheet to S3.
Also I want to change the empty cells in the excel files with Nan but I don't know how.
Update: I tried the solution from the answer below. I am getting "errorMessage": "'Records'", "errorType": "KeyError". My lambda function is also not getting triggered by s3.
You can store files in Lambda's local file system within the /tmp/ directory. There is a limit of 500MB, so delete those files once you have finished with them.
Therefore, when you are creating a file, put it in that directory:
with open("/tmp/data%s.csv" %(sheet6.name.replace(" ","")), "w", encoding='utf-8') as file:
You can then upload it to Amazon S3 by using upload_file(file, bucket, key):
s3.upload_file('/tmp/data1.csv', 'mybucket', 'data1.csv')
Here's some code I have for extracting the Bucket and Key that triggered a Lambda function:
import urllib
def lambda_handler(event, context):
bucket = event['Records'][0]['s3']['bucket']['name']
key = urllib.parse.unquote_plus(event['Records'][0]['s3']['object']['key'])
...
I am coding in Python Lang. in AWS Lambda and I need to write the output which shows in output logs in a folder of S3 bucket. The code is,
client = boto3.client('s3')
ouput_data = b'Checksums are matching for file'
client.put_object(Body=ouput_data, Bucket='bucket', Key='key')
And now I want to add Checksums are matching for file and then I will need to add the file names. How can I add
I have written a code to delete older files and and keep the latest one. My code is working in local but wanted to apply the same code when accessing AWS s3 bucket folder to perform the similar operation.
The code working fine when providing local path.
import os
import glob
path = r'C:\Desktop\MyFolder'
allfiles =[os.path.basename(file) for file in glob.glob(path + '\*.*')]
diff_pattern=set()
deletefile=[]
for file in allfiles:
diff_pattern.add('_'.join(file.split('_',2)[:2]))
print('Pattern Found - ',diff_pattern)
for pattern in diff_pattern:
patternfiles=[os.path.basename(file) for file in glob.glob(path + '\\'+pattern+'_*.*')]
patternfiles.sort()
if len(patternfiles)>1:
deletefile=deletefile+patternfiles[:len(patternfiles)-1]
print('Files Need to Delete - ',deletefile)
for file in deletefile:
os.remove(path+'\\'+file)
print('File Deleted')
I expect the same code to work for AWS s3 buckets. Below is the files format and example with there status(keep/delete) that I'm working with.
file format: file_name_yyyyMMdd.txt
v_xyz_20190501.txt Delete
v_xyz_20190502.txt keep
v_xyz_20190430.txt Delete
v_abc_20190505.txt Keep
v_abc_20190504.txt Delete
I don't think you can access S3 files like local path.
You may need to use boto3 library in python to access s3 folders.
Here is a sample for you to see how it works..
https://dluo.me/s3databoto3