how can i get the file name without its root and path. only a name so i can save the images i want to convert with the same original name?
import sys
import os,glob
from PIL import Image, ImageFilter
path = os.getcwd()
if not os.path.exists('converted'):
save_to = os.makedirs('converted')
for i in glob.glob(f'{path}/*.jpg'):
img = Image.open(i)
img.save(???????) ######## <---------?????????
#i want to save the imege whith its original name,
# but with a different extention, and i want to save it to a different folder then cwd
Use os.path.basename to get filename without path.
Use os.path.splitext to split filename into stem and suffix.
Did you wanted something like this?
for i in glob.glob(f'{path}/*.png'):
img = Image.open(i)
basename = os.path.basename(i)
root_ext = os.path.splitext(basename)[0]
ext = ".png"
img.save(path+"/converted/" + root_ext + ext)
Related
Can anyone show me how i can convert all png images in my local folder to jpg images? I've tried using the following code
path1 = r'C:\Users\david.han\Desktop\COPY_images_files'
path2 = r'C:\Users\david.han\Desktop\JPG converter'
files_to_convert = (f for f in os.listdir(path1) if f.endswith(".png"))
for filename in files_to_convert:
im = Image.open(os.path.join(path1, filename))
root, _ = os.path.splitext(filename)
jpg_file = os.path.join(path2, f'{root}.jpg')
im.save(jpg_file)
I keep getting this error "OSError: cannot write mode P as JPEG"
I've decided to keep JPG but in case anyone wants to know how to change png to jpg
enter code here
from PIL import Image
import os
path = r'C:\Users\david.han\Desktop\COPY_images_files'
for file in os.listdir(path):
if file.endswith(".jpg"):
img = Image.open(file)
file_name, file_ext = os.path.splitext(file)
img.save('/png/{}.png'.format(file_name))
Correction to David's code:
from PIL import Image
import os
path = r'enter_path_to_images'
for file in os.listdir(path):
if not file.endswith(".jpg"):
img = Image.open("{path}/{file}")
file_name, file_ext = os.path.splitext(file)
img.save('/png/{}.png'.format(file_name))
In this case, we also need to add the correct path not to get any errors.
I'm trying to convert all files from a directory from .jpg to .png. The name should remain the same, just the format would change.
I've been doing some researches and came to this:
from PIL import Image
import os
directory = r'D:\PATH'
for filename in os.listdir(directory):
if filename.endswith(".jpg"):
im = Image.open(filename)
im.save('img11.png')
print(os.path.join(directory, filename))
continue
else:
continue
I was expecting the loop to go through all my .jpg files and convert them to .png files. So far I was doing only with 1 name: 'img11.png', I haven't succed to build something able to write the adequate names.
The print(os.path.join(directory, filename)) works, it prints all my files but concerning the converting part, it only works for 1 file.
Do you guys have any idea for helping me going through the process?
You can convert the opened image as RGB and then you can save it in any format.
You can try the following code :
from PIL import Image
import os
directory = r'D:\PATH'
c=1
for filename in os.listdir(directory):
if filename.endswith(".jpg"):
im = Image.open(filename)
name='img'+str(c)+'.png'
rgb_im = im.convert('RGB')
rgb_im.save(name)
c+=1
print(os.path.join(directory, filename))
continue
else:
continue
You're explicitly saving every file as img11.png.
You should get the name of your jpg file and then use that to name and save the png file.
name = filename[:-4]
im.save(name + '.png')
I would have used os.rename() function like below.
import os
directory = r'D:\PATH'
for filename in os.listdir(directory):
prefix = filename.split(".jpg")[0]
os.rename(filename, prefix+".png")
Please let me know if this is what you wanted. Try the code with some copied images inside a test folder, before applying to the intended folder. All the best.
from PIL import Image
import os
directory = r'D:\PATH'
for filename in os.listdir(directory):
if filename.endswith(".jpg"):
prefix = filename.split(".jpg")[0]
im = Image.open(filename)
im.save(prefix+'.png')
else:
continue
Please try this one and let me know.
I want to copy all the pictures from one folder to another folder. I tried to run this code again and again but it returns me False only instead of saving pictures to other folder.
import cv2
import glob
input_path = 'C:\\Users\\Kazmi-PC\\OneDrive\\Pictures\\1\\*.*'
output_path = 'C:\\Users\\Kazmi-PC\\OneDrive\\Pictures\\2\\*.jpg'
for file in glob.glob(input_path):
print("printing.....")
print(file)
a= cv2.imread(file)
cv2.imwrite(output_path, a)
You can't use * in output filename. You would have to use imwrite inside for loop and use unique filenames in output.
You can use shutil.copy(file, directory) to copy. So you can use output without *.jpg and you don't have to add filename in output.
But you still need to copy every file separatelly.
import glob
import shutil
input_path = 'C:\\Users\\Kazmi-PC\\OneDrive\\Pictures\\1\\*.*'
output_dir = 'C:\\Users\\Kazmi-PC\\OneDrive\\Pictures\\2\\'
for file in glob.glob(input_path):
shutil.copy(file, output_dir)
I have this code, it origionally comes from here: renaming files base on the file structure
I added a thumbnail save as to the function from here: Create thumbnail images for jpegs with python
I'm trying to select all files from a directory structure, rename them based on the file structure. I've added a filter using 'in', but I can't get the resize as thumbnail bit to work.
Name Image is not defined.
import os
import shutil
#testing
import sys
import image
def image_thumb_filter():
size = 128, 128
for path, dirs, files in os.walk(wd):
for file in files:
if file.endswith(".jpg"):
src = os.path.join(path, file)
#print(src)
dst = os.path.join(os.getcwd(), "Photo_selection")
if not os.path.exists(dst): #Checks 'Photos_mirror' folder exists
otherwise creates
os.makedirs(dst)
new_name = src.replace(wd+'\\', '').replace('\\', '_')
new_dst = os.path.join(dst, new_name + "_thumb")
if not os.path.isfile(new_dst):
if "99\\526" in src:
try:
im = image.open(src)
im.thumbnail(size)
im.save(new_dst, "JPEG")
except IOError:
print ("cannot create thumbnail for", infile)
shutil.copy(src, dst)
old_dst = os.path.join(dst, file)
#Assuming your /dir/dir/... structure is inside of your working
directory (wd)
os.rename(old_dst, new_dst)
else: # it doesn't like this else statement
continue
image_thumb_filter()
You have not defined the object "Image" specifically anywhere in your code. Remember that Python and many other languages are case sensitive. Maybe you meant "image?"
I have a zipfile object:
docx_zip = zipfile.ZipFile(path)
I want to access the full path of that zip file in order to pass that path to ImageTk Image object, so I need the path to that file.
image = Image.open(PATH_TO_IMAGE)
photo = ImageTk.PhotoImage(image)
So I ask: How can I get PATH_TO_IMAGE ?
One method optional is to extract it to the current working directory and give it the new path (the file name), but I was wondering if there is an option to get the full path straight from the zip archive.
Can you try
import os.path
docx_zip = zipfile.ZipFile(path)
print os.path.dirname(path)
I don't think that zipfile allows for this. At least I can't find anything in the docs, but there is a workaround. You can create a ZipInfo object from your ZipFile, which will hold the information you want:
import zipfile
import os
docx_zip = zipfile.ZipFile(zip_path)
docx_info = docx_zip.getinfo(name_of_image_in_zip)
path_to_image = os.path.abspath(docx_info.filename)
# or get all paths:
docx_name_list = docx_zip.infolist()
paths_to_images = [os.path.abspath(x.filename) for x in docx_name_list]
I hope this helps.