I am working on a project which is tenant based project means for every client creating a new database. For now, to create a new database I am using mongo compass and manually creating database on clicking new or plus sign.
But I want to create a new database in mongodb using the pyspark. I have a mongo connection string. Please suggest me to how to create?
Thank You.
I don't know pyspark but typical mongo workflow to create db is to run any write operation. If you want to create a db before any using of it, you can run a simple insert operation or, for example, create a collection inside this db
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I'm new to using Postgres, so I'm not sure if this is a basic question. I obtain a Postgres dump from my company that I load as a Postgres schema using Pgadmin. I then use the psycopg2 package in python to load the various tables of this schema into pandas dataframes and do whatever processing I need.
Every time I get a new version of the data, I have to go through a 3-step process in pgadmin to update the schema before I work with it in python:
"Drop cascade" the existing public schema
Create a new public schema
Restore the public schema by pointing it to the new pgdump file
Rather than doing these three using pgadmin, can this be done programatically from within a python script?
I'm running a simple Flask app with Heroku, and I can run the following command to create all the tables:
db.create_all()
However, I ship new stuff frequently and I often need to add new columns to existing tables. Is there an easy way to do this?
If I need to manually create a new column with Postgres, how would I access the repl for Heroku's Postgres database?
You should be using migrations.
This is a great plugin for that: https://flask-migrate.readthedocs.io/en/latest/
and this is a good explanation about how to get going with that: https://realpython.com/flask-by-example-part-2-postgres-sqlalchemy-and-alembic/
I am trying to enter about 1 millions records to PostgreSql since I create table dynamically I don't have any models associated with it so I cant perform bulk_insert of django
How is there any method of inserting data in a efficient manner.
I am trying using single insert statement but this is very time consuming and too slow
Your problem is not about django. You better carry the data(not necesarry but could be good) to the server that you want to insert and create a simple python program or sth. else to insert the data.
Avoid to insert a data at this size by using an http server.
I am facing a strange problem right now. I am using pypyodbc to insert data into a test database hosted by AWS. This database that I created was by hand and did not imitate all relations and whatnot between tables. All I did was create a table with the same columns and the same datatypes as the original (let's call it master) database. When I run my code and insert the data it works in the test environment. Then I change it over to the master database and the code runs all the way through but no data is actually inputted. Is there any chance that there are security protocols in place which prevent me from inputting data in through the Python script rather than through a normal SQL query? Is there something I am missing?
It sounds like it's not pointing to the correct database. Have you made sure the connection information changes to point to the correct DB? So the server name is correct, the login credentials are good, etc.?
I'm making an application that will fetch data from a/n (external) postgreSQL database with multiple tables.
Any idea how I can use inspectdb only on a SINGLE table? (I only need that table)
Also, the data in the database would by changing continuously. How do I manage that? Do I have to continuously run inspectdb? But what will happen to junk values then?
I think you have misunderstood what inspectdb does. It creates a model for an existing database table. It doesn't copy or replicate that table; it simply allows Django to talk to that table, exactly as it talks to any other table. There's no copying or auto-fetching of data; the data stays where it is, and Django reads it as normal.