When I try to build a simple UI, everything works well, except the tkinter function I used always repeats twice, I am not sure why this happens and how to deal with it. Here is an example code:
import tkinter as tk
root = tk.Tk()
dirname = tk.filedialog.askdirectory(parent=root, initialdir="/",title='Please select a directory')
print(dirname)
When I run this code, the function works well, it will let me select a folder, but after I select the folder, it asks me to select it again. And from the print(), it outputs both the folders I have selected.
What should I do to make it only run one time?
Hi can you try with below script, I tried running below script and it does not ask for second selection and dont print second selection as well;
import tkinter as tk
from tkinter import filedialog as fd
root = tk.Tk()
dirname = fd.askdirectory(parent=root, initialdir="/",title='Please select a
directory')
print(dirname)
Related
I am trying to make a Tkinter script to select files through Windows File Explorer. I don't need the Tkinter window to show, just the File Explorer interface.
import tkinter
from tkinter import filedialog
import os
window = tkinter.Tk()
#window.geometry("1x1")
window.withdraw()
def open_files():
files = filedialog.askopenfiles(mode='r')
global filenames
filenames = [os.path.abspath(file.name) for file in files]
window.destroy() # analysis:ignore #says "window" is undefined becasue of "del window" below
window.after(0, open_files)
window.mainloop()
del window
The first time I run this in Spyder, if window.withdraw() is not commented out, the console just shows runfile(*my_file_name*) and the code does... something... in the background, but nothing seems to actually happen. Nothing changes on-screen, but I cannot type in the console so I know the code is running.
If I open a new console tab and run the code with window.withdraw() commented out, everything works, and the Tkinter GUI is visible. If I then run this code again in the same tab, with window.withdraw() not commented out, then the code works as intended, with only the File Explorer window opening up, and the Tkinter GUI staying hidden. This is the case even if I click the "Remove all variables" button in Spyder, so as far as I understand the code is not saving any variables that allow it to run properly after the first time.
My question is, why does this code work the 2nd, 3rd, 4th, etc. time I run it, but not the first time?
I kept playing around, and changed -alpha to alpha and got this error:
TclError: wrong # args: should be "wm attributes window ?-alpha ?double?? ?-transparentcolor ?color?? ?-disabled ?bool?? ?-fullscreen ?bool?? ?-toolwindow ?bool?? ?-topmost ?bool??"
So I ended up changing window.attributes('-alpha',0) to window.attributes('-topmost',True, '-alpha',0), and this works! It brings up File Explorer on the first run without showing the Tkinter window. Thank you #Thingamabobs for your help.
My final code is:
import tkinter
from tkinter import filedialog
import os
window = tkinter.Tk()
window.attributes('-topmost',True, '-alpha',0)
filenames = [os.path.abspath(file.name) for file in filedialog.askopenfiles(mode='r')]
window.destroy()
del window
I am running my performance test on python and I want to call some Tcl commands using Tkinter inside my python script.
Can somebody please help me to write the code,
import Tkinter
root = Tkinter.Tk()
root.tk.eval('puts {printed by tcl}')
I tried simply above example, here when I do root=tkinter.tk() it opens up a window, I just want to execute my command and get the result
The code you have tried will not show any window until you put the root.mainloop(),but you can try something like this,
import tkinter
root = tkinter.Tk()
root.withdraw()
root.tk.eval('puts {printed by tcl}')
root.destroy()
root.mainloop()
here withdraw() will remove the window from the screen without destroying it and then you can perform your tasks and then destroy it at the end of code.
I have a problem that annoys me. I am currently building a small app with a Tkinter GUI.
On the front page, I want some introductory text in either a text or a scrolledtext widget. The code examples I've come across uses keywords such as INSERT, CURRENT and END for indexation inside the widget.
I have literally copy pasted the below code into my editor, but it doesn't recognise INSERT (throws error: "NameError: name 'INSERT' is not defined"):
import tkinter as tk
from tkinter import scrolledtext
window = tk.Tk()
window.title("test of scrolledtext and INSERT method")
window.geometry('350x200')
txt = scrolledtext.ScrolledText(window,width=40,height=10)
txt.insert(INSERT,'You text goes here')
txt.grid(column=0,row=0)
window.mainloop()
I can get the code to work if I change [INSERT] with [1.0], but it is very frustrating that I cannot get INSERT to work, as I've seen it in every example code I've come across
Use tk.INSERT instead of only INSERT. Full code is shown.
import tkinter as tk
from tkinter import scrolledtext
window = tk.Tk()
window.title("test of scrolledtext and INSERT method")
window.geometry('350x200')
txt = scrolledtext.ScrolledText(window,width=40,height=10)
txt.insert(tk.INSERT,'You text goes here')
txt.grid(column=0,row=0)
window.mainloop()
You don't need to use the tkinter constants. I personally think it's better to use the raw strings "insert", "end", etc. They are more flexible.
However, the reason the constants don't work for you is that you're not directly importing them. The way you're importing tkinter, you need to use tk.INSERT, etc.
INSERT could not be used directly.
You can use it in the past just because you used this in the past:
from tkinter import * # this is not a good practice
INSERT,CURRENT and END are in tkinter.constants.Now in your code,you even didn't import them.
If you want to use them,you can use
from tkinter.constants import * # not recommended
...
txt.insert(INSERT,'You text goes here')
Or
from tkinter import constants
...
txt.insert(constants.INSERT,'You text goes here') # recommend
If didn't want to import them,you can also use:
txt.insert("insert",'You text goes here')
Edit:I found in the source code of tkinter,it had import them,reboot's answer is also OK.
I have a selection of excel data that I am analyzing, and have just recently added the ability for the user to open the file explorer and locate the file visually, as opposed to entering the file location on the command line. I found this question (and answer) to make the window appear, which worked for a while.
I am still using the command line for everything except locating the file. Currently, this is a skeleton of what I have to open the window (nearly identical to the answer of the question linked above)
Tk().withdraw()
data_file_path = askopenfilename()
# other code with prompts, mostly print statements
Tk().withdraw()
drug_library_path = askopenfilename()
Once the code reaches the first two lines of code, the command line just sits with a blinking cursor, like it's waiting for input (my guess, for askopenfilename() to return a file location), but nothing happens. I can't ctrl+C to get out of the program, either.
I have found this question, which is close to what I'm looking for, but I'm on Windows, not Mac, and I can't even get the window to open -- most questions I see talk about not being able to close the window.
Thanks for any help!
Note: At this point in the program, no data from excel has been loaded. This is one of the first lines that is ran.
Try easygui instead. It's also built on tkinter, but unlike filedialog it's made to run without a full GUI.
Since you are using Windows, use this command in the command line (not in python) to install easygui:
py -m pip install easygui
then try this code:
import easygui
data_file_path = easygui.fileopenbox()
# other code with prompts, mostly print statements
drug_library_path = easygui.fileopenbox()
If you want to use an internal module, you can import tkFileDialog, and call:
filename = tkFileDialog.askopenfilename(title="Open Filename",filetypes=(("TXT Files","*.txt"),("All Files","*.*")))
I use this in many projects, you can add arguments such as initialdir, and you can specify allowable filetypes!
I had the same problem, but I found that the issue was that I was getting input with input() before I called askopenfilename() or fileopenbox().
from tkinter import Tk
from tkinter.filedialog import askopenfilename
var = input()
Tk().withdraw()
filepath = askopenfilename()
I simply switched the positions of askopenfilename() (or fileopenbox()) and input(), and it worked as usual.
Tk().withdraw()
filepath = askopenfilename()
var = input()
I want my script should work in such a way that, close all the previous windows in tkinter.
If I minimise the existing pop up window and again I will run same script, it will again pop up new window. How can I close the already existing window, when i run script again?
Simple code:
import Tkinter as tk
root = tk.Tk()
root.mainloop()
Maybe if you check all variable in locals and see if you have tk type in it?
import tkinter as tk
root = tk.Tk()
tk_type = type(root)
print(tk_type)
var=0
for var in locals().items():
if type(var[1]) == tk_type:
print(var, 'to be deleted')
root.mainloop()
something like this where you can put the test at the begining of the class to see if it exists other TK window object.
I'm sure it should exist a better solution though.