Develop Reference

Pywinauto don't return to me all identifiers with print_control_identifiers()

I have some trouble when I use pywinauto with python
Input code
app = Application(backend="uia").start("F:\\ROKLauncher\\launcher.exe")
app = Application(backend="uia").connect(path="F:\\ROKLauncher\\launcher.exe", timeout=10)
app.LauncherDialog.print_control_identifiers()
Console is printing:
Control Identifiers:
Dialog - 'Launcher' (L276, T131, R1644, B909)
['Dialog', 'Launcher', 'LauncherDialog']
child_window(title="Launcher", control_type="Window")
Here is an image of the window that I want to automate and I just want to check all identifiers and click the yellow button after:

Handling Context Menu of the taskbar icon with pywinauto

I am trying to automate the exiting operation on one of the apps. The app's icon is located in the taskbar. I was successfull in opening that icon's context menu with the modified code that I have found on stackoverflow:
import pywinauto
from pywinauto.application import Application
import time
app= "Service is enabled."
app = Application(backend="uia").connect(path="explorer.exe")
st = app.window(class_name="Shell_TrayWnd")
t = st.child_window(title="Notification Chevron").wrapper_object()
t.click()
time.sleep(1)
list_box = Application(backend="uia").connect(class_name="NotifyIconOverflowWindow")
list_box_win = list_box.window(class_name="NotifyIconOverflowWindow")
list_box_win.wait('visible', timeout=30, retry_interval=3)
# time.sleep(1)
appOpened= list_box_win.child_window(title = app)
appOpened.click_input(button = "right")
After the execution of the code above I get to the point when the context menu is opened:
The next thing that I want to do is to click on Exit, I have tried doing it by specifying the mouse click coordinates, but I have noticed that the position of the parent icon is changing from time to time.
What I would like to do is to get the handle on the Exit button and send click automatically.
------Edit-------
The icon is located in the hidden icons

So you want to access to the right click context menu. As said in this answer, you can do something like :
listbox.PopupMenu["Exit"].set_focus().click_input()

Right click on taskbar icon then select on popupmenu

This is my code to right click on the app selected :
import pywinauto
#import time
from pywinauto.application import Application
app = Application(backend="uia").connect(path="explorer.exe")
taskbar = app.window(class_name="Shell_TrayWnd")
taskbar.child_window(title="myApp").click_input(button='right')
app.PopupMenu.MenuClick("Open")
But then I can't choose "Open" on the popupmenu, which is Open or Exit.
Everything work until the MenuClick().
How can I do that ?

How to get count of icons in tray using pywinauto

I have an app which sits in tray when I click on .exe file.
I am unable click on my app which sit in system tray. Because it doesn't have class_name or id or anything when I inspect using inspector.exe. So I decided to click this using index of icon. As I am not sure how many icons sit in tray when I run this particular program. So I wanted to get the count of the icon before I click the .exe file. If the count is x then I can click index x icon after clicking the .exe which actually clicks on my desired icon.
Can any one help me in getting the count of the icons. I tried multiple times using child_window(class_name="") but it returned just an object instead of list.
Below is my code:
from pywinauto.application import Application
import time
app = Application(backend="uia").connect(path="explorer.exe")
st = app.window(class_name="Shell_TrayWnd")
t = st.child_window(title="Notification Chevron").wrapper_object()
t.click()
time.sleep(1)
list_box = Application(backend="uia").connect(class_name="NotifyIconOverflowWindow")
list_box_win = list_box.window(class_name="NotifyIconOverflowWindow")
list_box_win.wait('visible', timeout=30, retry_interval=3)
list_box_win.child_window(class_name="", found_index=x).click_input()
Your help will be much appreciated :)

This is not giving the count and do the required job.
The following code will loop through the apps available in the system tray and clicks on the desired app by checking its name.
from pywinauto.application import Application
import time
app = Application(backend="uia").connect(path="explorer.exe")
taskBar = app.window(class_name='Shell_TrayWnd')
trayIcon = taskBar["Notification Chevron"].wrapper_object()
trayIcon.click()
time.sleep(0.25)
trayWindowContainer = Application(backend="uia").connect(class_name="NotifyIconOverflowWindow")
trayWindow = trayWindowContainer.window(class_name="NotifyIconOverflowWindow")
trayWindow.wait('visible', timeout=30, retry_interval=3)
breakLoop: bool = False
for notification_area in trayWindow.children():
for app_in_tray in notification_area.children():
if "<App_name>" in str(app_in_tray):
app_in_tray.click_input()
breakLoop = True
break
if breakLoop:
break

How to automate pop up window click OK button?

How to automate pop up window click button? I combine SWAPY and coding, but can not find necessary coding. I automate Speech Filing System Tools for Speech Research
from pywinauto.application import Application
app = Application().Start(cmd_line=u'"C:\\Program Files\\SFS\\Program\\sfswin.exe"')
afxab = app[u'sfswin - Unknown1']
afxab.Wait('ready')
afxbfdb = afxab.Unknown1
afxbfdb.Maximize()
toolbarwindow = afxab[u'5']
toolbar_button = toolbarwindow.Button(1)
toolbar_button.Click()
app.OpenDialog.Edit.set_text(ur'C:\Program Files\SFS\six.wav')
app.OpenDialog.Open.click_input()
app.OpenDialog.wait_not('visible')
afxab = app.window_(title_re="Open Audio File")
afxabButton1 = ButtonWrapper(afxab.Button.WrapperObject("OK")).Click