How to change list of list to a string - python

I need to get:
'W1NaCl U1NaCl V1NaCl'
from:
[['W1NaCl'], ['U1NaCl'], ['V1NaCl']]
How to get required output in pythonic way


items = [['W1NaCl'], ['U1NaCl'], ['V1NaCl']]
res = " ".join([item[0] for item in items])
Which yields: W1NaCl U1NaCl V1NaCl


You can do:
[[i] for i in 'W1NaCl U1NaCl V1NaCl'.split()]
Split will chop it into words, and the list comprehension will make the inner-arrays

Related

convert list of integers in string format to list of integers in python

I have a list which looks like below
lis = '[-3.56568247e-02 -3.31957154e-02\n 7.04742894e-02\n 7.32413381e-02\n 1.74463019e-02]' (string type)
'\n' is also there in the list.
I need to convert this to actual list of integers
lis = [-3.56568247e-02,-3.31957154e-02 ,7.04742894e-02 ,7.32413381e-02, 1.74463019e-02] (list of integers)
I am doing the functionality, but it is failing
import as
res = ast.literal_eval(lis)
Can anyone tell me how to resolve this?

We can use re.findall along with a list comprehension:
lis = '[-3.56568247e-02 -3.31957154e-02 7.04742894e-02 7.32413381e-02\n 1.74463019e-02]'
output = [float(x) for x in re.findall(r'\d+(?:\.\d+)?(?:e[+-]\d+)?', lis)]
print(output)
# [0.0356568247, 0.0331957154, 0.0704742894, 0.0732413381, 0.0174463019]

You can try
[int(i) for i in lis.strip("[]").split(" ")]

You risk getting 1000 ways to do this.
This is a quick and easy way using only basic methods:
lis = '[1 2 3 4 5 77]'
elements = lis.replace('[','').replace(']','').split(' ')
my_ints = [int(e) for e in elements]
print(my_ints)

Converting a list with multiple values into a dictionary

I have the following list and am wanting to convert it into a dictionary where the 4 digit value at the start of each item becomes the id.
['3574,A+,2021-03-24', '3575,O+,2021-04-03', '3576,AB-,2021-04-09', '3580,AB+,2021-04-27', '3589,A+,2021-05-08', '3590,B-,2021-05-11']
I have tried many different methods but it doesn't seem to work.

You can use str.split, map and dictionary comprehension
# data holds the list you have provided
{splitted[0]:splitted[1:] for splitted in map(lambda item:item.split(','), data)}
OUTPUT:
Out[35]:
{'3574': ['A+', '2021-03-24'],
'3575': ['O+', '2021-04-03'],
'3576': ['AB-', '2021-04-09'],
'3580': ['AB+', '2021-04-27'],
'3589': ['A+', '2021-05-08'],
'3590': ['B-', '2021-05-11']}

You can use dictionary comprehension with str.split:
lst = [
"3574,A+,2021-03-24",
"3575,O+,2021-04-03",
"3576,AB-,2021-04-09",
"3580,AB+,2021-04-27",
"3589,A+,2021-05-08",
"3590,B-,2021-05-11",
]
out = {int(v.split(",")[0]): v.split(",")[1:] for v in lst}
print(out)
Prints:
{
3574: ["A+", "2021-03-24"],
3575: ["O+", "2021-04-03"],
3576: ["AB-", "2021-04-09"],
3580: ["AB+", "2021-04-27"],
3589: ["A+", "2021-05-08"],
3590: ["B-", "2021-05-11"],
}

Here is the code to do what I believe you asked for. I have also added comments in the code for a bit more clarification.
my_list = ['3574,A+,2021-03-24',
'3575,O+,2021-04-03',
'3576,AB-,2021-04-09',
'3580,AB+,2021-04-27',
'3589,A+,2021-05-08',
'3590,B-,2021-05-11']#your list
my_dict = {}#The dictionary you want to put the list into
print("Your list:", my_list, "\n")
for item in my_list:#cycles through every item in your list
ID, value = item.split(",", 1)#Splits the item in your list only once (when it sees the first comma)
print(ID + ": " + value)
my_dict[ID] = value#Add the ID and value to your dictionary
print("\n" + "Your desired dictionary:", my_dict)
Which outputs this:
Your list: ['3574,A+,2021-03-24', '3575,O+,2021-04-03', '3576,AB-,2021-04-09', '3580,AB+,2021-04-27', '3589,A+,2021-05-08', '3590,B-,2021-05-11']
3574: A+,2021-03-24
3575: O+,2021-04-03
3576: AB-,2021-04-09
3580: AB+,2021-04-27
3589: A+,2021-05-08
3590: B-,2021-05-11
Your desired dictionary: {'3574': 'A+,2021-03-24', '3575': 'O+,2021-04-03', '3576': 'AB-,2021-04-09', '3580': 'AB+,2021-04-27', '3589': 'A+,2021-05-08', '3590': 'B-,2021-05-11'}
Enjoy!

TRY:
result = dict(i.split(',', 1) for i in lst)
OUTPUT:
{'3574': 'A+,2021-03-24',
'3575': 'O+,2021-04-03',
'3576': 'AB-,2021-04-09',
'3580': 'AB+,2021-04-27',
'3589': 'A+,2021-05-08',
'3590': 'B-,2021-05-11'}

How to append pipe delimiter in string array in python

I've array of string in python, I'm iterating over the loop each value and trying to append ('|') symbol using below code. But its not appending as expected
result_list = []
new_value = 'iek,33833,,sdfd,lope'
my_list = ['abc,1234,,ickd,sold', 'yeje,38393,,dkdi,eole', 'euei,38393,,idkd,dikd']
for val in my_list:
result_list.append(val + '|')
res = result_list.append(new_value) + '|')
print res
I'm trying to print the list of string including new string at last. But its giving me below error:
TypeError: can only concatenate list (not "str") to list
Sample output:
abc,1234,,ickd,sold|yeje,38393,,dkdi,eole|euei,38393,,idkd,dikd|iek,33833,,sdfd,lope|
Thanks a lot for your help!

Use a list comprehension to add |, then join():
''.join([x+'|' for x in my_list])
# abc,1234,,ickd,sold|yeje,38393,,dkdi,eole|euei,38393,,idkd,dikd|
Simply using '|'.join() won't get you the final | you require.

This will directly give you the result.
'|'.join(my_list) + '|'

No need to iterate, you can use join() to achieve this.
my_list = ['abc,1234,,ickd,sold', 'yeje,38393,,dkdi,eole', 'euei,38393,,idkd,dikd']
print '|'.join(my_list)
output:
abc,1234,,ickd,sold|yeje,38393,,dkdi,eole|euei,38393,,idkd,dikd

result_list = []
my_list = ['abc,1234,,ickd,sold', 'yeje,38393,,dkdi,eole', 'euei,38393,,idkd,dikd']
for val in my_list:
result_list.append(str(val)+"|")
# result_list.append()
print ''.join(result_list)

Spliting string into two by comma using python

I have following data in a list and it is a hex number,
['aaaaa955554e']
I would like to split this into ['aaaaa9,55554e'] with a comma.
I know how to split this when there are some delimiters between but how should i do for this case?
Thanks

This will do what I think you are looking for:
yourlist = ['aaaaa955554e']
new_list = [','.join([x[i:i+6] for i in range(0, len(x), 6)]) for x in yourlist]
It will put a comma at every sixth character in each item in your list. (I am assuming you will have more than just one item in the list, and that the items are of unknown length. Not that it matters.)

i assume you wanna split into every 6th character
using regex
import re
lst = ['aaaaa955554e']
newlst = re.findall('\w{6}', lst[0])
# ['aaaaa9', '55554e']
Using list comprehension, this works for multiple items in lst
lst = ['aaaaa955554e']
newlst = [item[i:i+6] for i in range(0,len(a[0]),6) for item in lst]
# ['aaaaa9', '55554e']

This could be done using a regular expression substitution as follows:
import re
print re.sub(r'([a-zA-Z]+\d)(.*?)', r'\1,\2', 'aaaaa955554e', count=1)
Giving you:
aaaaa9,55554e
This splits after seeing the first digit.

concatenating selected elements in a list of lists in python

I have a (python) list of lists as below
biglist=[ ['1','123-456','hello','there'],['2','987-456','program'],['1','123-456','list','of','lists'] ]
I need to get this in the following format
biglist_modified=[ ['1','123-456','hello there'],['2','987-456','program'],['1','123-456','list of lists'] ]
I need to concatenate the third element onwards in each inner list.I tried to do this by using list comprehensions,
def modify_biglist(bigl):
ret =[]
for alist in bigl:
alist[2] = ' '.join(alist[2:])
del alist[3:]
ret.append(alist)
return ret
This does the job..but it looks a bit convoluted -having a local variable ret and using del? Can someone suggest something better

[[x[0], x[1], " ".join(x[2:])] for x in biglist]
or, in-place:
for x in biglist:
x[2:] = [" ".join(x[2:])]

To modify your list in place, you could use the following simplification of your code:
for a in big_list:
a[2:] = [" ".join(a[2:])]

This ought to do it:
[x[:2] + [" ".join(x[2:])] for x in biglist]
Slightly shorter.

Categories

Resources