I am a total newbie with GUIs and also tkinter.
I am trying to get 2 inputs from user through a GUI which I implemented with tkinter. After the user give inputs and press the button, I want to return to these 2 inputs and keep doing something else with these 2 inputs. I have checked Return values of Tkinter text entry, close GUI but it did not work for my case.
What I have tried is this:
_Gui.py
import tkinter as tk
def get_input():
entry1 = entry1.get()
entry2 = entry2.get()
return entry1, entry2
root = tk.Tk()
root.geometry("320x240+800+300")
label1 = tk.Label(text="Label1")
label1.config(font=('Helvetica bold',16))
label1.pack()
entry1 = tk.Entry(root)
entry1.config(font=('Helvetica bold',16))
entry1.pack()
label2 = tk.Label(text="Label2")
label2.config(font=('Helvetica bold',16))
label2.pack()
entry2 = tk.Entry(root)
entry2.config(font=('Helvetica bold',16))
entry2.pack()
button = tk.Button(root, text="Start", command=get_input)
button.config(font=('Helvetica bold',16))
button.pack()
root.mainloop()
And in main.py:
import _Gui as gui
if __name__ == "__main__":
a, b = gui.get_input()
something_else(a, b)
But it also did not work.
Thanks for your help in advance!
You can use root.destroy() to destroy the window, but the function get_input() will execute twice after you pressed the button (the other is after the window is destroyed, in your "main.py"), so if you destroyed the window in the first execution, you can't use entry1.get().
I suggest you use this:
(_Gui.py)
import tkinter as tk
root = tk.Tk()
root.geometry("320x240+800+300")
def get_input():
global a, b
a = entry1.get()
b = entry2.get()
root.destroy()
label1 = tk.Label(text="Label1")
label1.config(font=('Helvetica bold',16))
label1.pack()
entry1 = tk.Entry(root)
entry1.config(font=('Helvetica bold',16))
entry1.pack()
label2 = tk.Label(text="Label2")
label2.config(font=('Helvetica bold',16))
label2.pack()
entry2 = tk.Entry(root)
entry2.config(font=('Helvetica bold',16))
entry2.pack()
button = tk.Button(root, text="Start", command=get_input)
button.config(font=('Helvetica bold',16))
button.pack()
(main.py)
import _Gui as gui
if __name__ == "__main__":
gui.root.mainloop()
something_else(gui.a, gui.b)
(Sorry, my English is not very well.)
Related
I am attempting to open a new window when the New Window button is pressed in the main "root" window. This currently works and does indeed open a second window. In the second window I want to ask the user for an input and then this input will be turned into a list of strings.
An example input would be "Amy, Bob, Carl". The expected output would be ['Amy', 'Bob', 'Carl'] but currently the program just returns [''].
My current code is:
from tkinter import *
root = Tk()
root.title("Welcome screen")
root.geometry("300x300")
def open_new_window():
top = Toplevel()
top.title("second window")
entities = Entry(top)
entries = entities.get().split(", ")
entities.pack()
entities.focus_set()
print(entries)
sub_button = Button(top, text="Submit", command= ?)
sub_button.pack(pady=20)
close_btn = Button(top, text="Close", command=top.destroy)
close_btn.pack()
open_button = Button(root, text="New Window", command=open_new_window)
open_button.pack(pady=20)
exit_button = Button(root, text="Close", command=root.destroy)
exit_button.pack(pady=20)
root.mainloop()
I am new to Tkinter and I am unsure why this is happening. I'm sure it's a simple silly mistake but I can't find where I am going wrong. I also am unsure as to whether I need a Submit button as I don't know what command should be passed to it.
Any advice is appreciated. Please let me know if any additional information is required.
First, we will understand why you got a empty list: your code is executed sequentially, so when you do the entities.get() you haven't yet written anything nor pressed "Submit", i.e., you want to read the entry box once you press the "Submit", not earlier, for that reason, you have the command = ?.
As I am aware, you have mainly 2 options:
Get the text from the button itself
Create a variable linked to the entry box and read this
Method 1: read the data from the entry
from tkinter import *
root = Tk()
root.title("Welcome screen")
root.geometry("300x300")
def do_stuff(entry):
print(entry.get())
def open_new_window():
top = Toplevel()
top.title("second window")
entities = Entry(top)
entities.pack()
entities.focus_set()
sub_button = Button(top, text="Submit", command= lambda: do_stuff(entities))
sub_button.pack(pady=20)
close_btn = Button(top, text="Close", command=top.destroy)
close_btn.pack()
open_button = Button(root, text="New Window", command=open_new_window)
open_button.pack(pady=20)
exit_button = Button(root, text="Close", command=root.destroy)
exit_button.pack(pady=20)
root.mainloop()
Method 2: link a variable
from tkinter import *
root = Tk()
root.title("Welcome screen")
root.geometry("300x300")
def do_stuff(text_entry):
print(text_entry.get())
def open_new_window():
top = Toplevel()
top.title("second window")
text_entry = StringVar()
entities = Entry(top, textvariable = text_entry)
entities.pack()
entities.focus_set()
sub_button = Button(top, text="Submit", command= lambda: do_stuff(text_entry))
sub_button.pack(pady=20)
close_btn = Button(top, text="Close", command=top.destroy)
close_btn.pack()
open_button = Button(root, text="New Window", command=open_new_window)
open_button.pack(pady=20)
exit_button = Button(root, text="Close", command=root.destroy)
exit_button.pack(pady=20)
root.mainloop()
The main advantage in this last approach is that you can play with the text before and after the entry is built.
I'm trying to build a very simple program in Python and Tkinter that allows the user to input people's names by keyboard and then a button is commanded to select a person from the list at random and show it in a tk.Label object.
My problem is once I run the root.mainloop(), I can add names to the list but the list does not update with the new names.
This is the main code for the Tkinter to initialize
import tkinter as tk
from tkinter import filedialog, Text
import random
root = tk.Tk()
root.title('Millor persona del moment')
root.geometry("500x200")
root.configure(bg='black')
peopleList = []
tk.Label(root, text="Insertar participante: ",fg="#ff007f", bg='black').grid(row=0)
e1 = tk.Entry(root)
e1.grid(row=0, column=1)
addButton = tk.Button(root, text='AƱadir', padx=10, pady=5, fg="#ff007f", bg='black', command=addPerson)
addButton.grid(row=0, column=2)
while peopleList:
turnButton = tk.Button(root, text='Saca Tema', padx=10, pady=5, fg="#ff007f", bg='black', command=wordTurn(peopleList))
turnButton.grid(row=1, column=0)
nom = tk.StringVar()
nom.set('Comencem')
personSpeaking = tk.Label(root, textvariable=nom,fg="#ff007f", bg='black')
personSpeaking.grid(row=1, column=1)
root.mainloop()
And these are the functions I use
def addPerson():
peopleList.append(e1.get())
e1.delete(0,'end')
def wordTurn(peopleList):
person = random.choice(peopleList)
peopleList.remove(person)
nom.set(person)
command=wordTurn(peopleList)) calls the return value of wordTurn when the button is pressed, which is None and should raise an error. Use command=lambda peopleList=peopleList: wordTurn(peopleList)) instead.
I been searching for methods to copy text to clipboard or copy the results from Tkinter gui but idk if there is a command or something
here is my code for now here the result comes in a messagebox can i copy it to clipboard
import tkinter.messagebox
import string
import random
def qs_msgbbox(): # qs_msgbbox
tkinter.messagebox.showinfo("Info", "For customer support or tip or rating contact:"
"dghaily725#gmail.com\npress the button for generated pass\nmsg will appear then copy\nthe generated password")
def gen_pass(k=9): # gen_pass
char = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890!##$%^&*"
password = ''
for i in range(9):
password += random.choice(char)
tkinter.messagebox.showinfo("Password", password)
root = Tk()
root.title("Password Generator")
lbl1 = Label(root, text="Generate Password", bd=2, relief=SUNKEN, height=5, width=50, bg='black', fg='white')
lbl1.configure(font=(70))
lbl1.grid(row=0, column=2)
lbl2 = Label(root, text='For more information press the Question mark', bd=2, relief=SUNKEN, fg='red')
lbl2.configure(font=(70))
lbl2.grid(row=0, column=0, pady=10)
btn1 = Button(root, text='Press to Generate', height=5, width=50, bg='grey', command=gen_pass)
btn1.configure(font=(70))
btn1.grid(row=1, column=2, padx=460, pady=50)
btn2photo = PhotoImage(file='question.png')
btn2 = Button(root, image=btn2photo, width=30, height=30, command= qs_msgbbox)
btn2.grid(row=0, column=1)
root.mainloop()
and also just a quick small question is it better to use classes or this form
Tkinter does have a function for that, simply just
from tkinter import Tk
root = Tk()
root.clipboard_clear()
root.clipboard_append("Something to the clipboard")
root.update() # the text will stay there after the window is closed
Hope I could help
Greets
The above answer is perfectly fine. Infact its the method to do it. I read the comments, He had mentioned that it could only take in string. That is completely false. It can also take in functions. For example..
import tkinter as tk
root = tk.Tk()
#creating a entry Widget.(Labels are fine as well)
entry = tk.Entry(root)
entry.pack()
#NOW if you want to copy the whole string inside the above entry box after you
typed in #
def copy ():#assign this function to any button or any actions
root.clipboard_clear()
root.clipboard_append(entry.get()) #get anything from the entry widget.
root.mainloop()
Hoping this was helpful
I have a GUI using Tkinter, it has a main screen and then when you press a button a popup window appears, where you select a checkbutton and then a email will get sent to you.
Not matter what I do, I cannot read the value of the checkbutton as 1 or True it always = 0 or False.
This is my code:
import tkinter as tk
from tkinter import *
import time
root = tk.Tk()
root.title('Status')
CheckVar1 = IntVar()
def email():
class PopUp(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
popup = tk.Toplevel(self, background='gray20')
popup.wm_title("EMAIL")
self.withdraw()
popup.tkraise(self)
topframe = Frame(popup, background='gray20')
topframe.grid(column=0, row=0)
bottomframe = Frame(popup, background='gray20')
bottomframe.grid(column=0, row=1)
self.c1 = tk.Checkbutton(topframe, text="Current", variable=CheckVar1, onvalue=1, offvalue=0, height=2, width=15, background='gray20', foreground='snow', selectcolor='gray35', activebackground='gray23', activeforeground='snow')
self.c1.pack(side="left", fill="x", anchor=NW)
label = tk.Label(bottomframe, text="Please Enter Email Address", background='gray20', foreground='snow')
label.pack(side="left", anchor=SW, fill="x", pady=10, padx=10)
self.entry = tk.Entry(bottomframe, bd=5, width=35, background='gray35', foreground='snow')
self.entry.pack(side="left", anchor=S, fill="x", pady=10, padx=10)
self.button = tk.Button(bottomframe, text="OK", command=self.on_button, background='gray20', foreground='snow')
self.button.pack(side="left", anchor=SE, padx=10, pady=10, fill="x")
def on_button(self):
address = self.entry.get()
print(address)
state = CheckVar1.get()
print (state)
time.sleep(2)
self.destroy()
app = PopUp()
app.update()
tk.Button(root,
text="EMAIL",
command=email,
background='gray15',
foreground='snow').pack(side=tk.BOTTOM, fill="both", anchor=N)
screen = tk.Canvas(root, width=400, height=475, background='gray15')
screen.pack(side = tk.BOTTOM, fill="both", expand=True)
def latest():
#Other code
root.after(300000, latest)
root.mainloop()
The popup works perfectly, and the email will print when entered but the value of checkbox is always 0.
I have tried:
CheckVar1 = tk.IntVar() - No success
self.CheckVar1 & self.CheckVar1.get() - No success
Removing self.withdraw() - No success
I only have one root.mainloop() in the script, I am using app.update() for the popup window because without this it will not open.
I have checked these existing questions for solution and none have helped:
Self.withdraw - Can't make tkinter checkbutton work normally when running as script
Self.CheckVar1 - TKInter checkbox variable is always 0
Only one instance of mainloop() - Python tkinter checkbutton value always equal to 0
I have also checked very similar questions but I wasn't going to post them all.
Any help is appreciated.
The problem is that you have two root windows. Each root window gets its own internal tcl interpreter, and the widgets and tkinter variables in one are completely invisible to the other. You're creating the IntVar in the first root window, and then trying to associate it with a checkbutton in a second root window. This cannot work. You should always only have a single instance of Tk in a tkinter program.
because of variable scope
try to put CheckVar1 = IntVar() inside the class
use it with self like this
self.CheckVar1 = tk.IntVar() # object of int
self.CheckVar1.set(1) # set value
variable=self.CheckVar1 # passing to the checkbutton as parameter
state = self.CheckVar1.get() # getting value
I have a bit of difficulty with the code below. Basically, I want the code to, when I press the Enter button, to open the window2 but also close window1 simultaneously so that there is only one window and not two of them.
The code is...
from tkinter import *
def window1():
window = Tk()
window.title("Welcome")
f = Frame()
f.pack()
label1 = Label(window, text = "Welcome to the random window")
label1.pack()
button1 = Button(window, text = "Enter...", command = window2)
button1.pack()
def window2():
screen = Tk()
screen.title("Pop-Up!")
fr = Frame()
fr.pack()
label2 = Label(screen, text = "This is a pop-up screen!")
label2.pack()
button2 = Button(screen, text = "Return", command = window1)
button2.pack()
window1()
This is "Bad" because you're using two instances of Tk. Try instead using TopLevels.
import tkinter as tk
def window1():
window = tk.Toplevel(root)
window.title("Welcome")
# etc etc ...
tk.Button(window,text="Enter...",command=lambda: window2(window)).pack()
def window2(old_window):
old_window.destroy()
# window2 stuff
root = tk.Tk()
root.iconify() # to minimize it, since we're just using Toplevels on top of it
window1()
root.mainloop()
When you are using the Tk() function, you are creating a new instance of the Tcl/tkinter interpreter. Instead use Toplevel() which will make a new window in the current interpreter.