how to create a loop and save the data array variable individually? - python

I write a helper function read_xyT to read all .csv files in a directory and output them into a pandas DataFrame. Since there are lots for such directories and I want to save them into individual variables (or maybe some better solutions?)
what I do now is
path = r'./data/T-600s'
df33 = read_xyT(path,33)
df34 = read_xyT(path,34)
df35 = read_xyT(path,35)
df36 = read_xyT(path,36)
...
There is in total 60 folders... I wonder if there is a smarter way to do it more efficiently? i.e.
subdirectoynames = np.arange(34,50) # the helper function take 'path' as input
variablenames = alistforfilenames
for v,f in (variablenames, subdirectorynames):
dfxx = read_xyT(path,yy)
then I'll have the saved individual variables such as df37, df38, df39, ...
Or is there a better way to do it?
Thank you in advance!

You can use a dict comprehension:
df_dict = {f'df{idx}': read_xyT(path, idx) for idx in subdirectorynames}
This creates a dictionary where you can access the dataframes using e.g. df_dict['df33']

Related

Why are multiple values incorrectly updated in my dynamically created nested dicts?

Dfs is a dict with dataframes and the keys are named like this: 'datav1_135_gl_b17'
We would like to calculate a matrix with constants. It should be possible to assign the values in the matrix according to the attributes from the df name. In this example '135' and 'b17'.
If you want code to create an example dfs, let me know, I've cut it out to more clearly state the problem.
We create a nested dict dynamically with the following function:
def ex_calc_time(dfs):
formats = []
grammaturs = []
for i in dfs:
# (...)
# format
split1 = i.split('_')
format = split1[-1]
format.replace(" ", "")
formats.append(format)
formats = list(set(formats))
# grammatur
# split1 = i.split('_')
grammatur = split1[-3]
grammatur.replace(" ", "")
grammaturs.append(grammatur)
grammaturs = list(set(grammaturs))
# END FLOOP
dict_mean_time = dict.fromkeys(formats, dict.fromkeys(grammaturs, ''))
return dfs, dict_mean_time
Then we try to fill the nested dict and change the values like this (which should be working according to similiar nested dict questions, but it doesn't). 'Nope' is updated for both keys:
ex_dict_mean_time['b17']['170'] = 'nope'
ex_dict_mean_time
{'a18': {'135': '', '170': 'nope', '250': ''},
'b17': {'135': '', '170': 'nope', '250': ''}}
I also tried creating a dataframe from ex_dict_mean_time and filling it with .loc, but that didn't work either (df remains empty). Moreover I tried this method, but I always end up with the same problem and the values are overwritten. I appreciate any help. If you have any improvements for my code please let me know, I welcome any opportunity to improve.

Apply function to each group where the group are splitted in multiple files without concatenating all the files

My data come from BigQuery exported to GCS bucket as CSV file and if the file size is quite massive, BigQuery will automatically split the data into several chunk. With time series in mind, the time series might be scattered across different files. I have a custom function that I want to applied to each TimeseriesID.
Here's some constraint of the data:
The data is sorted by TimeseriesID and TimeID
The number of row of each files is may vary, but at minimum 1 row (which is very unlikely)
The starting of TimeID is not always 0
The length of each time series may vary but at maximum it will only scattered across 2 files. No time series scatter in 3 different files.
Here's the initial setup to illustrate the problem:
# Please take note this is just for simplicity. The actual goal is not to calculate mean for all group, but to apply a custom_func to each Timeseries ID
def custom_func(x):
return np.mean(x)
# Please take note this is just for simplicity. In actual, I read the file one by one since reading all the data is not possible
df1 = pd.DataFrame({"TimeseriesID":['A','A','A','B'],"TimeID":[0,1,2,4],"value":[10,20,5,30]})
df2 = pd.DataFrame({"TimeseriesID":['B','B','B','C'],"TimeID":[5,6,7,8],"value":[10,20,5,30]})
df3 = pd.DataFrame({"TimeseriesID":['C','D','D','D'],"TimeID":[9,1,2,3],"value":[10,20,5,30]})
This should be pretty trivial if I can just concat all the files but the problem is if I concat all the dataframe then it won't fit in the memory.
The output I desired is should be similar to this but without concat all the files.
pd.concat([df1,df2,df3],axis=0).groupby('TimeseriesID').agg({"value":simple_func})
I'm also aware about vaex and dask but I want to stick with simple pandas for time being.
I'm also open to solution which involve modifying the BigQuery to split the files better.
Approach presented by op to use concat with million of records would be overkill for memories/other resources.
I have tested OP code using Google Colab Nootebooks and this was a bad approach
import pandas as pd
import numpy as np
import time
# Please take note this is just for simplicity. The actual goal is not to calculate mean for all group, but to apply a custom_func to each Timeseries ID
def custom_func(x):
return np.mean(x)
# Please take note this is just for simplicity. In actual, I read the file one by one since reading all the data is not possible
df1 = pd.DataFrame({"TimeseriesID":['A','A','A','B'],"TimeID":[0,1,2,4],"value":[10,20,5,30]})
df2 = pd.DataFrame({"TimeseriesID":['B','B','B','C'],"TimeID":[5,6,7,8],"value":[10,20,5,30]})
df3 = pd.DataFrame({"TimeseriesID":['C','D','D','D'],"TimeID":[9,1,2,3],"value":[10,20,5,30]})
start = time.time()
df = pd.concat([df1,df2,df3]).groupby('TimeseriesID').agg({"value":custom_func})
elapsed = (time.time() - start)
print(elapsed)
print(df.head())
output will be:
0.023952960968017578
value
TimeseriesID A 11.666667
B 16.250000
C 20.000000
D 18.333333
As you can see, 'concat' takes time to process. Due to few records this is not perceived.
The approach should be as follow:
Get files with data that you are going to process. ie: only workable columns.
Create a dictionary from the processed files key and values. if necessary, obtain values per key in a necessary file. You can store the results in a 'results' directory as json/csv:
A.csv will have all key 'A' values
...
n.csv will have all key 'n' values
Iterate trough results directory and start building your final output inside a dictionary.
{'A': [10, 20, 5], 'B': [30, 10, 20, 5], 'C': [30, 10], 'D': [20, 5, 30]}
apply custom function to each key value list.
{'A': 11.666666666666666, 'B': 16.25, 'C': 20.0, 'D': 18.333333333333332}
You can check the logic using below code, I use json to store the data:
from google.colab import files
import json
import pandas as pd
#initial dataset
df1 = pd.DataFrame({"TimeseriesID":['A','A','A','B'],"TimeID":[0,1,2,4],"value":[10,20,5,30]})
df2 = pd.DataFrame({"TimeseriesID":['B','B','B','C'],"TimeID":[5,6,7,8],"value":[10,20,5,30]})
df3 = pd.DataFrame({"TimeseriesID":['C','D','D','D'],"TimeID":[9,1,2,3],"value":[10,20,5,30]})
#get unique keys and its values
df1.groupby('TimeseriesID')['value'].apply(list).to_json('df1.json')
df2.groupby('TimeseriesID')['value'].apply(list).to_json('df2.json')
df3.groupby('TimeseriesID')['value'].apply(list).to_json('df3.json')
#as this is an example you can download the output as jsons
files.download('df1.json')
files.download('df2.json')
files.download('df3.json')
Update 06/10/2021
I have tuned code for OPs needs. This part creates refined files.
from google.colab import files
import json
#you should use your own function to get the data from the file
def retrieve_data(uploaded,file):
return json.loads(uploaded[file].decode('utf-8'))
#you should use your own function to get a list of files to process
def retrieve_files():
return files.upload()
key_list =[]
#call a function that gets a list of files to process
file_to_process = retrieve_files()
#read every raw file:
for file in file_to_process:
file_data = retrieve_data(file_to_process,file)
for key,value in file_data.items():
if key not in key_list:
key_list.append(key)
with open(f'{key}.json','w') as new_key_file:
new_json = json.dumps({key:value})
new_key_file.write(new_json)
else:
with open(f'{key}.json','r+') as key_file:
raw_json = key_file.read()
old_json = json.loads(raw_json)
new_json = json.dumps({key:old_json[key]+value})
key_file.seek(0)
key_file.write(new_json)
for key in key_list:
files.download(f'{key}.json')
print(key_list)
Update 07/10/2021
I have updated code to avoid confusion. This part process refined files.
import time
import numpy as np
#Once we get the refined values we can use it to apply custom functions
def custom_func(x):
return np.mean(x)
#Get key and data content from single json
def get_data(file_data):
content = file_data.popitem()
return content[0],content[1]
#load key list and build our refined dictionary
refined_values = []
#call a function that gets a list of files to process
file_to_process = retrieve_files()
start = time.time()
#read every refined file:
for file in file_to_process:
#read content of file n
file_data = retrieve_data(file_to_process,file)
#parse and apply function per file read
key,data = get_data(file_data)
func_output = custom_func(data)
#start building refined list
refined_values.append([key,func_output])
elapsed = (time.time() - start)
print(elapsed)
df = pd.DataFrame.from_records(refined_values,columns=['TimerSeriesID','value']).sort_values(by=['TimerSeriesID'])
df = df.reset_index(drop=True)
print(df.head())
output will be:
0.00045609474182128906
TimerSeriesID value
0 A 11.666667
1 B 16.250000
2 C 20.000000
3 D 18.333333
summarize:
When handling large datasets, you should always need to focus on the data that you are going to use and keep it minimal. Only using the workable values.
Processing times are faster when operations are performed by basic operators or python native libraries.

for loop with same dataframe on both side of the operator

I have defined 10 different DataFrames A06_df, A07_df , etc, which picks up six different data point inputs in a daily time series for a number of years. To be able to work with them I need to do some formatting operations such as
A07_df=A07_df.fillna(0)
A07_df[A07_df < 0] = 0
A07_df.columns = col # col is defined
A07_df['oil']=A07_df['oil']*24
A07_df['water']=A07_df['water']*24
A07_df['gas']=A07_df['gas']*24
A07_df['water_inj']=0
A07_df['gas_inj']=0
A07_df=A07_df[['oil', 'water', 'gas','gaslift', 'water_inj', 'gas_inj', 'bhp', 'whp']]
etc for a few more formatting operations
Is there a nice way to have a for loop or something so I don’t have to write each operation for each dataframe A06_df, A07_df, A08.... etc?
As an example, I have tried
list=[A06_df, A07_df, A08_df, A10_df, A11_df, A12_df, A13_df, A15_df, A18_df, A19_df]
for i in list:
i=i.fillna(0)
But this does not do the trick.
Any help is appreciated
As i.fillna() returns a new object (an updated copy of your original dataframe), i=i.fillna(0) will update the content of ibut not of the list content A06_df, A07_df,....
I suggest you copy the updated content in a new list like this:
list_raw = [A06_df, A07_df, A08_df, A10_df, A11_df, A12_df, A13_df, A15_df, A18_df, A19_df]
list_updated = []
for i in list_raw:
i=i.fillna(0)
# More code here
list_updated.append(i)
To simplify your future processes I would recommend to use a dictionary of dataframes instead of a list of named variables.
dfs = {}
dfs['A0'] = ...
dfs['A1'] = ...
dfs_updated = {}
for k,i in dfs.items():
i=i.fillna(0)
# More code here
dfs_updated[k] = i

Python, loops with changeable parts of filenames

I have a bunch of very similar commands which all look like this (df means pandas dataframe):
df1_part1=...
df1_part2=...
...
df1_part5=...
df2_part1=...
I would like to make a loop for it, as follows:
for i in range(1,5):
for j in range(1,5):
df%i_part%j=...
Of course, it doesn't work with %. But is has to be some easy way to do it, I suppose.
Could You help me please?
You can try one of the following options:
Create a dictionary which maps the your df and access it by the name of the dataframe:
mapping = {"df1_part1": df1_part1, "df1_part2": df1_part2}
for i in range(1,5):
for j in range(1,5):
mapping[f"df{i}_part{j}"] = ...
Use globals to access dynamically your variables:
df1_part1=...
df1_part2=...
...
df1_part5=...
df2_part1=...
for i in range(1,5):
for j in range(1,5):
globals()[f"df{i}_part{j}"] = ...
One way would be to collect your pandas dataframes in a list of lists and iterate over that list instead of trying dynamically parse your python code.
df1_part1=...
df1_part2=...
...
df1_part5=...
df2_part1=...
dflist = [[df1_part1, df1_part2, df1_part3, df1_part4, df1_part5],
[df2_part1, df2_part2, df2_part3, df2_part4, df2_part5]]
for df in dflist:
for df_part in df:
# do something with df_part
Assuming that this process is part of data preparation, I would like to mention that you should try to work with "data preparation pipelines" whenever it is possible. Otherwise, the code will be a huge mess to read after a couple of months.
There are several ways to deal with this problem.
A dictionary is the most straightforward way to deal with this.
df_parts = {
'df1' : {'part1': df1_part1, 'part2': df1_part2,...,'partN': df1_partN},
'df2' : {'part1': df1_part1, 'part2': df1_part2,...,'partN': df2_partN},
'...' : {'part1': ..._part1, 'part2': ..._part2,...,'partN': ..._partN},
'dfN' : {'part1': dfN_part1, 'part2': dfN_part2,...,'partN': dfN_partN},
}
# print parts from `dfN`
for val in for df_parts['dfN'].values():
print(val)
# print part1 for all dfs
for df in df_parts.values():
print(df['part1'])
# print everything
for df in df_parts:
for val in df_parts[df].values():
print(val)
The good thing with this approach is that you can iterate through the whole dictionary, but you don't include range which may be confusing later. Also, it is better to assign every df_part directly to a dict instead of assigning N*N variables which may be used once or twice. In this case you can just use 1 variable and re-assign it as you progress:
# code using df1_partN
df1 = df_parts['df1']['partN']
# stuff to do
# happy? checkpoint
df_parts['df1']['partN'] = df1

How to increase multi dimension of array in tensorflow?

I have a txt file which has 8 columns and I am selecting 1 column for my feature extraction which gives me 13 features values, the shape of output array will be [1x13].
Similarly I have 5 txt files in a folder I want to run a loop so that the returned variable will have 5x13 data.
def loadinfofromfile(directory,sd,channel):
# subdir selection and read file names in it for particular crack type.
subdir, filenames = loadfilenamesindirectory(directory,sd)
for i in range(5):
# join the directory sub directory and the filename
loadfile = os.path.join(directory,subdir,filenames[i])
# load the values of that paticular file into tensor
fileinfo = tf.constant(np.loadtxt(loadfile),tf.float32)
# select the particular column data ( choosen from crack type, channel no)
fileinfo_trans = tf.transpose(fileinfo)
fileinfo_back = tf.gather(fileinfo_trans,channel)
# extracting features from selected column data gives [1x13]
pool = features.pooldata(fileinfo_back)
poolfinal = tf.concat_v2([tf.expand_dims(pool,0)],axis=0)
return poolfinal
In the above function I am able to get [1x13] to the variable 'pool' and I am expecting the size of the variable poolfinal as [5x13] but i get it as [1x13].
how to concat in vertical direction ?
What is the mistake i did in the loop ?
each loop creates pool and poolfinal from sctratch. That's why you see only one data in poolfinal.
instead please try following:
pools = []
for ...:
pools.append(...)
poolfinal = tf.concat_v2(pools, axis=0)

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