I want to create a dictionary with Key value pairs which are filled via an for Loop
The dictionary I want to achive
[
{
"timestamp": 123123123,
"image": "image/test1.png"
},
{
"timestamp": 0384030434,
"image": "image/test2.png"
}
]
My code does not work and I´m new to the datatypes of python.
images_dict = []
for i in images:
time = Image.open(i)._getexif()[36867]
images_dict = {"timestamp": time, "image": i}
What am I missing?
First, you seem to be confusing the definition of a list and a dictionary in python. Dictionaries use curly brackets {} and lists use regular brackets []. So in your first example, you are describing a list with a single element, which is a dictionary.
As for your code example, you are creating an empty list, and then iterating over images which I assume is a list of images, and then redefining the variable images_dict to be a dictionary with two key: value pairs for every iteration.
It seems like what you want is this:
images_dict = []
for image in images:
time = Image.open(1)._getexif()[36867]
images_dict.append({'timestamp': time, 'image': image})
The answer from Tom McLean worked for me, I´m a little bit confused with the dataypes of python
images_dict.append({"timestamp": time, "image": i})
Related
I am getting data from an API and storing it in json format. The data I pull is in a list of dictionaries. I am using Python. My task is to only grab the information from the dictionary that matches the ticker symbol.
This is the short version of my data printing using json dumps
[
{
"ticker": "BYDDF.US",
"name": "BYD Co Ltd-H",
"price": 25.635,
"change_1d_prc": 9.927101200686117
},
{
"ticker": "BYDDY.US",
"name": "BYD Co Ltd ADR",
"price": 51.22,
"change_1d_prc": 9.843448423761526
},
{
"ticker": "TSLA.US",
"name": "Tesla Inc",
"price": 194.7,
"change_1d_prc": 7.67018746889343
}
]
Task only gets the dictionary for ticker = TSLA.US. If possible, only get the price associated with this ticker.
I am unaware of how to reference "ticker" or loop through all of them to get the one I need.
I tried the following, but it says that its a string, so it doesn't work:
if "ticker" == "TESLA.US":
print(i)
Try (mylist is your list of dictionaries)
for entry in mylist:
print(entry['ticker'])
Then try this to get what you want:
for entry in mylist:
if entry['ticker'] == 'TSLA.US':
print(entry)
This is a solution that I've seen divide the python community. Some say that it's a feature and "very pythonic"; others say that it's a bad design choice we're stuck with now, and bad practice. I'm personally not a fan, but it is a way to solve this problem, so do with it what you will. :)
Python function loops aren't a new scope; the loop variable persists even after the loop. So, either of these are a solution. Assuming that your list of dictionaries is stored as json_dict:
for target_dict in json_dict:
if target_dict["ticker"] == "TESLA.US":
break
At this point, target_dict will be the dictionary you want.
It is possible to iterate through a list of dictionaries using a for loop.
for stock in list:
if stock["ticker"] == "TSLA.US":
return stock["price"]
This essentially loops through every item in the list, and for each item (which is a dictionary) looks for the key "ticker" and checks if its value is equal to "TSLA.US". If it is, then it returns the value associated with the "price" key.
I have a JSON file that looks like this:
{
"returnCode": 200,
"message": "OK",
“people”: [
{
“details: {
"first": “joe”,
“last”: doe,
“id”: 1234567,
},
“otheDetails”: {
“employeeNum”: “0000111222”,
“res”: “USA”,
“address”: “123 main street”,
},
“moreDetails”: {
“family”: “yes”,
“siblings”: “no”,
“home”: “USA”,
},
},
{
“details: {
"first": “jane”,
“last”: doe,
“id”: 987654321,
},
“otheDetails”: {
“employeeNum”: “222333444”,
“res”: “UK”,
“address”: “321 nottingham dr”,
},
“moreDetails”: {
“family”: “yes”,
“siblings”: “yes”,
“home”: “UK,
},
}
This shows two entries, but really there are hundreds or more. I do not know the number of entries at the time the code is run.
My goal is to iterate through each entry and get the 'id' under "details". I load the JSON into a python dict named 'data' and am able to get the first 'id' by:
data['people'][0]['details']['id']
I can then get the second 'id' by incrementing the '0' to '1'. I know I can set i = 0 and then increment i, but since I do not know the number of entries, this does not work. Is there a better way?
Less pythonic then a list comprehension, but a simple for loop will work here.
You can first calculate the number of people in the people list and then loop over the list, pulling out each id at each iteration:
id_list = []
for i in range(len(data['people'])):
id_list.append(data['people'][i]['details']['id'])
You can use dict.get method in a list comprehension to avoid getting a KeyError on id. This way, you can fill dictionaries without ids with None:
ids = [dct['details'].get('id') for dct in data['people']]
If you still get KeyError, then that probably means some dcts in data['people'] don't have details key. In that case, it might be better to wrap this exercise in try/except. You may also want to identify which dcts don't have details key, which can be gathered using error_dct list (which you can uncomment out from below).
ids = []
#error_dct = []
for dct in data['people']:
try:
ids.append(dct['details']['id'])
except KeyError:
ids.append(None)
#error_dct.append(dct)
Output:
1234567
987654321
I've got this discord.py command that makes a leaderboard from a json
cogs/coins.json (the dictionary) looks like this:
{
"781524858026590218": {
"name": "kvbot test platform",
"total_coins": 129,
"data": {
"564050979079585803": {
"name": "Bluesheep33",
"coins": 127
},
"528647474596937733": {
"name": "ACAT_",
"coins": 2
}
}
(The green strings with numbers in the json files are discord guild/member ids)
How do I make the code shorter and clearer?
Thanks for helping in advance, because I really don't know the solution
When it comes to finding (sorting) the first ten items within a dict, then the way is much easier than repeatedly going through the dict and doing different things there.
And little better code, like Dict.get for safety access.
Based on a sample of JSON data.
with open('cogs/coins.json', 'r') as f:
coins_data = json.load(f)
# Get is safefy access to dict
# Dict.items() returns pairs of (Key, Val)
members_coins = list(coins_data.get(str(ctx.guild.id), None)['data'].items())
if members_coins is None: # If data not found
await ctx.send('Not data')
return
# Sort list by Val part of pair, and `coins` key, reverse for descending
members_coins.sort(key=lambda x: x[1]['coins'], reverse=True)
output = ''
# list[:10] for first 10 items (if list is smaller, thats okay, python don't mind)
for member_id, vals in members_coins[:10]:
output += f'{vals["name"]}: {vals["coins"]}'
# output += f'<#{member_id}>: {vals["coins"]}' # If you want "mention" display of user
await ctx.send(output)
I am brand new to python and have hit a roadblock I can't seem to figure out.
I have a list of values. This list could have 1 value or many.
['9589503164607', '9589503197375']
I need to output this in a json format. My current output looks like this:
"line_items": {"id": ["9589503164607", "9589503197375"]}
I need this:
{"line_items":[{"id":9589503164607},{"id":9589503197375}]}
Currently, I am using a dictionary for this value and the rest that go with this line. However, due to having duplicate keys ("id"), I feel this may be the wrong approach.
shop_data = {
"fulfillment": {
"location_id": cleanslid,
"tracking_number": trackingnumber,
"line_items": {
"id": iteminvids,
}
}
}
iteminvids is the list I referenced.
If anyone could point me in the right direction I would be so grateful!
Use a list comprehension to create a list of dictionaries.
"line_items": [{"id": item} for item in list_of_values]
If your original list is in lst, you can do
json.dumps({"line_items": [{"id": i} for i in lst}]})
This question already has answers here:
Getting a list of values from a list of dicts
(10 answers)
Closed 5 years ago.
I have this JSON file where the amount of id's sometimes changes (more id's will be added):
{
"maps": [
{
"id": "blabla1",
"iscategorical": "0"
},
{
"id": "blabla2",
"iscategorical": "0"
},
{
"id": "blabla3",
"iscategorical": "0"
},
{
"id": "blabla4",
"iscategorical": "0"
}
]
}
I have this python code that has to print all the values of ids:
import json
data = json.load(open('data.json'))
variable1 = data["maps"][0]["id"]
print(variable1)
variable2 = data["maps"][1]["id"]
print(variable2)
variable3 = data["maps"][2]["id"]
print(variable3)
variable4 = data["maps"][3]["id"]
print(variable4)
I have to use variables, because i want to show the values in a dropdown menu. Is it possible to save the values of the id's in a more efficient way? How do you know the max amount of id's of this json file (in de example 4)?
You can get the number of id (which is the number of elements) by checking the length of data['maps']:
number_of_ids = len(data['maps'])
A clean way to get all the id values is storing them in a list.
You can achieve this in a pythonic way like this:
list_of_ids = [map['id'] for map in data['maps']]
Using this approach you don't even need to store the number of elements in the original json, because you iterate through all of them using a foreach approach, essentially.
If the pythonic approach troubles you, you can achieve the same thing with a classic foreach approach doing so:
list_of_ids = []
for map in data['maps']:
list_of_ids.append(map['id'])
Or you can do with a classic for loop, and here is where you really need the length:
number_of_ids = len(data['maps'])
list_of_ids = []
for i in range(0,number_of_ids):
list_of_ids.append(data['maps'][i]['id'])
This last is the classic way, but I suggest you to take the others approaches in order to leverage the advantages python offers to you!
You can find more on this stuff here!
Happy coding!
data['maps'] is a simple list, so you can iterate over it as such:
for map in data['maps']:
print(map['id'])
To store them in a variable, you'll need to output them to a list. Storing them each in a separate variable is not a good idea, because like you said, you don't have a way to know how many there are.
ids = []
for map in data['maps']:
ids.append(map['id'])