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Failed to locate the webdriver element using Selenium |

Using selenium automation webdriver i'm unable to locate the text box element on a travel website using python. Using locator present in the webdriver such as Id/name/css_selector/class_name or xpath/full xpath.
Below is the screenshot of the python code:
[Code_1][1]
While the first one is located the second one isn't. The corresponding HTML code is
[text_box2][2]
How can i fill(automate) both fileds corresponding flight destinations i.e leaving and going
[1]: https://i.stack.imgur.com/gpoIr.jpg
[2]: https://i.stack.imgur.com/Q7mGs.jpg

Here is a slightly different approach for locating things. I am using waits borrowed from CruisePandey in this thread. I used firefox, but that is adaptable. Some notes of what was hard:
I had to make sure to be on the Flights tab.
I had to click in the from and to fields, which were buttons after all, and then wait to be able to type into the revealed input fields.
Finally, I had to choose the first element from the dropdown list that resulted.
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Firefox(executable_path='/usr/bin/geckodriver')
driver.maximize_window()
driver.get('https://www.expedia.co.in')
wait = WebDriverWait(driver, 15)
wait.until(EC.presence_of_element_located((By.LINK_TEXT, "Flights")))
driver.find_element_by_link_text('Flights').click()
wait.until(EC.presence_of_element_located((By.ID, "location-field-leg1-origin")))
driver.find_element(By.CLASS_NAME,'uitk-faux-input').click()
fieldInput = driver.find_element_by_id('location-field-leg1-origin')
wait.until(EC.visibility_of(fieldInput))
fieldInput.send_keys("SFO")
wait.until(EC.presence_of_element_located((By.TAG_NAME, "strong")))
driver.find_element_by_tag_name('strong').click()
driver.find_elements(By.CLASS_NAME,'uitk-faux-input')[1].click()
fieldInput = driver.find_element_by_id('location-field-leg1-destination')
wait.until(EC.visibility_of(fieldInput))
fieldInput.send_keys("BOS")
wait.until(EC.presence_of_element_located((By.XPATH,"//strong[contains(text(), 'Boston')]")))
driver.find_element_by_xpath("//strong[contains(text(), 'Boston')]").click()

You may want to use the below xpath for going To input field :
//label[text()='Going to']//following-sibling::input[#name]
Code :
wait = WebDriverWait(driver, 10)
wait.until(EC.element_to_be_clickable((By.XPATH, "//label[text()='Going to']//following-sibling::input[#name]"))).send_keys('something')
Imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

if you want to automate from 1 place holder to another, i have use this set of code & it works for me
wait.until(EC.element_to_be_clickable((By.XPATH,"//*[#id='location-field-leg1-origin-menu']/div[2]/ul/li[1]/button"))).click()
b = wait.until(EC.element_to_be_clickable((By.XPATH, ".//*[#id='location-field-leg1-destination-menu']/div[1]/button"))).send_keys("NYC")
b = wait.until(EC.element_to_be_clickable((By.XPATH,".//*[#id='location-field-leg1-destination-menu']/div[2]/ul/li[1]/button"))).click()
c = wait.until(EC.element_to_be_clickable((By.XPATH, ".//*[#id='d1-btn']"))).click()

How to select a textbox using selenium in python

HTMLI want to select a textbox using XPath or any other locator, but I am unable to do so. The code is working fine for one part of the page, while it is not working using any locator for the other half of the page. I am not sure if my code is wrong or if something else is the problem.
I have attached the HTML part.
Here is my code:
import selenium
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
driver = webdriver.Chrome()
driver.get('Website')
driver.implicitly_wait(50)
driver.find_element_by_xpath('//*[#id="j_username"]').send_keys("Username")
driver.find_element_by_xpath('//*[#id="j_password"]').send_keys("Password")
driver.find_element_by_xpath('//*[#id="b_submit"]').click()
driver.find_element_by_xpath('//*[#id="15301"]/div[1]/a/span').click()
driver.find_element_by_xpath('//*[#id="22261"]/a').click()
driver.find_element_by_xpath('//*[#id="22323"]/a').click()
driver.implicitly_wait(50)
driver.find_element_by_xpath('//*[#id="filterRow"]').clear()
The last line is where I am getting the following error:
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[#id="filterRow"]"}

Page may have not finished rendering when you try to find the element. So it will give NoSuchElementException
Try the following method
elem = driver.find_element_by_xpath('//*[#id="filterRow"]')
if len(elem) > 0
elem[0].clear()
Hope this will help you

You can wait till the elements loads using wait -
from selenium.webdriver.support import expected_conditions as EC
wait = WebDriverWait(driver, 20)
Filter_Row = wait.until(EC.visibility_of_element_located((By.XPATH, '//*[#id="filterRow"]')))
Filter_Row.clear()
Try the above code and see what happens.

Try below solution
wait = WebDriverWait(driver, 20)
wait.until(EC.element_to_be_clickable((By.XPATH, "//*[#id='filterRow']"))).clear()
Note: add below imports to your solution :
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

As in one of comments, you mentioned upon clicking tab a new page is opening. Can you please check if its opening in a new frame. Is so please switch to frame first where your element is using below statement:
driver.switch_to.frame(driver.find_element_by_name(name))
To navigate back to original frame you can use:
driver.switch_to.default_content()

using 'find_element_by_css_selector'
driver.find_element_by_css_selector("input")

How do I find an element by its id in Selenium?

This is my code:
I have used the find element by id RESULT_RadioButton-7_0, but I am getting the following error:
from selenium import webdriver
from selenium.webdriver.common.by import By
driver = webdriver.Chrome(executable_path="/home/real/Desktop/Selenium_with_python/SeleniumProjects/chromedriver_linux64/chromedriver")
driver.get("https://fs2.formsite.com/meherpavan/form2/index.html?153770259640")
radiostatus = driver.find_element(By.ID, "RESULT_RadioButton-7_0").click()
My error is this:
elementClickInterceptedException: element click intercepted: Element is not clickable at point (40, 567). Other element would receive the click: <label for="RESULT_RadioButton-7_0">...</label> (Session info: chrome=78.0.3904.70)

Based on the page link you provided, it looks like your locator strategy is correct here. If you are getting an error—most likely NoSuchElementException, I am assuming it might have something to do with waiting for the page to load before attempting to find the element. Let's use the ExpectedConditions class to wait on the element to exist before locating it:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
# Add the above references to your .py file
# Wait on the element to exist, and store its reference in radiostatus
radiostatus = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.ID, "RESULT_RadioButton-7_0")))
# Click the element
#radiostatus.click()
# Click intercepted workaround: JavaScript click
driver.execute_script("arguments[0].click();", radiostatus)
This will tick the radio button next to "Male" on the form.

Please find the below answer which will help you to click on the "Male" radio button from your link.
from selenium.webdriver.common.by import By
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains
driver = webdriver.Chrome(executable_path=r"C:\New folder\chromedriver.exe")
driver.maximize_window()
driver.get('https://fs2.formsite.com/meherpavan/form2/index.html?153770259640')
# Clicking on the "Male" checkbox button
maleRadioButton = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.ID, "RESULT_RadioButton-7_0")))
ActionChains(driver).move_to_element(maleRadioButton).click().perform()

Unless you need to wait on the element (which doesn't seem necessary), you should be able to do the following:
element_to_click_or_whatever = driver.find_element_by_id('RESULT_RadioButton-7_0')
If you look at the source for find_element_by_id, it calls find_element with By.ID as an argument:
def find_element_by_id(self, id_):
return self.find_element(by=By.ID, value=id_)
IMO: find_element_by_id reads better, and it's one less package to import.
I don't think your issue is finding the element; there's an ElementClickInterceptedException when trying to click on the element. For example, the radio button is located, but (strangely) Selenium doesn't think it's displayed.
from selenium import webdriver
driver = webdriver.Chrome()
driver.maximize_window()
driver.get("https://fs2.formsite.com/meherpavan/form2/index.html?153770259640")
radiostatus = driver.find_element_by_id('RESULT_RadioButton-7_0')
if radiostatus:
print('found')
# Found
print(radiostatus.is_displayed())
# False

Login Button can not be found with selenium

https://www.sevenonemedia.de/tv/programm/programmwochen
Here I want to login:
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
import time
options = Options()
chrome_path = "T:/Markus/WebScrapingExample/Chromedriver/chromedriver.exe"
driver = webdriver.Chrome(executable_path=chrome_path,chrome_options=options)
driver.set_window_size(1280, 720)
time.sleep(5)
driver.get("https://www.sevenonemedia.de/tv/programm/programmwochen")
driver.find_element_by_id("_58_login").send_keys("name")
driver.find_element_by_id("_58_password").send_keys("pw")
driver.find_element_by_xpath('//*[#id="sign-in-button"]').click()
ElementNotInteractableException: element not interactable
(Session info: chrome=78.0.3904.97)
This is my error
Id is there. Why does this happen?

This page contains duplicate of element with ID sign-in-button. If your selector points to more than one element, driver always takes the first from the top of the DOM one which is not interactable in this case. You must refer to the second element with this id. Try this selector for "Sign in" button:
//*[#id="aheadcustom_p_p_id_58"]//button

hi first things you should not give your password to all of the stackoverflow community :)
you can't click on the button because there is a popup at the bottom of the page and you have to click on it first for selenium it's hidding your button
last is that the totality of your code ?
if yes you forgot
driver = webdriver.Firefox() #or any other webdriver
you have not create driver without this line
EDIT !!
it wasn't working with only the modification above but with this one its good
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
import time
time.sleep(5)
driver = webdriver.Firefox()
driver.get("https://www.sevenonemedia.de/tv/programm/programmwochen")
driver.find_element_by_id("_58_login").send_keys("login")
driver.find_element_by_id("_58_password").send_keys("pssd")
driver.find_element_by_xpath("/html/body/div[1]/div/div/div[2]/a").click()
driver.find_element_by_css_selector("#_58_fm > fieldset:nth-child(1) > div:nth-child(6) > button:nth-child(1)").click()
this work :)
sometime css selector a safer and work better

To click on the Login button you have to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following solutions:
Using XPATH:
driver.get("https://www.sevenonemedia.de/tv/programm/programmwochen")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#title='Anmelden' and not(contains(#name,'INSTANCE'))]"))).send_keys("a.mai#mediaplus.com")
driver.find_element_by_xpath("//input[#title='Passwort' and not(contains(#name,'INSTANCE'))]").send_keys("Edidaten17")
driver.find_element_by_xpath("//input[#title='Passwort' and not(contains(#name,'INSTANCE'))]//following::button[1]").click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Browser Snapshot:

The problem is that your button locator isn't unique on the page. It finds two buttons, the first of which is not visible which causes the ElementNotInteractableException.
The simple fix is to use the CSS selector below
#main-content #sign-in-button
That will find only the button you want. So your last few lines of code would be
driver.find_element_by_id("_58_login").send_keys("name")
driver.find_element_by_id("_58_password").send_keys("pw")
driver.find_element_by_css_selector('#main-content #sign-in-button').click()

sleep(1)
login_box = driver.find_element_by_name('login')
login_box.click()
this is for facebook login button, just inspect the website and see the id/name/type to make your code automate to work properly

Selenium webdriver: Click not working in python

I want to click first on the link of the table with text A218012216.
It seems that table/links code are hidden inside JS.
I tried several ways, but without success.
This is my code so far:
import time
from selenium import webdriver
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
url0 ="https://ccrecordse.tarrantcounty.com/AssumedNames/SearchEntry.aspx"
driver = webdriver.Chrome(executable_path="D:\Python\chromedriver.exe")
driver.get(url0)
time.sleep(3)
#fill the form # select by visible text
selectStart = driver.find_element_by_id('x:11265151.0:mkr:3')
selectStart.send_keys('09/05/2019')
selectEnd = driver.find_element_by_id('x:1246303050.0:mkr:3')
selectEnd.send_keys('09/05/2019')
#submit the form
driver.find_element_by_id("cphNoMargin_SearchButtons2_btnSearch__5").click()
time.sleep(3)
driver.find_element_by_link_text('A218012216').click()
How can I get that information?

The problem is that you are trying to use find_element_by_link_text on an element that is not an <a> tag link_text is only for <a> tags...
In my solution, you will see I am using WebDriverWait this is best practice in selenium...
Also, I used the XPath locator with text()=the_text note that the the_text will need to change as the date changes (you are searching for the future date 09/05/2019 so it shows the current date therefor the text will change...)
The Solution:
import time
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
url0 ="https://ccrecordse.tarrantcounty.com/AssumedNames/SearchEntry.aspx"
driver = webdriver.Chrome(executable_path=r"D:\Python\chromedriver.exe")
driver.get(url0)
time.sleep(3)
#fill the form # select by visible text
selectStart = driver.find_element_by_id('x:11265151.0:mkr:3')
selectStart.send_keys('02/19/2019')
selectEnd = driver.find_element_by_id('x:1246303050.0:mkr:3')
selectEnd.send_keys('02/19/2019')
#submit the form
driver.find_element_by_id("cphNoMargin_SearchButtons2_btnSearch__5").click()
the_text = "A219002410"
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//*[text()='"+the_text +"']"))).click()
Hope this helps you!