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Essentially, I was wondering if you could merge these 2 lines:
items = ["cat","apple","taco"]
def change(x):
return(items[x-1])
temp = change(2) # THIS ONE AND
temp = "orange" # THIS ONE
It's difficult for me to explain, my apologies. I essentially just want to be able to get rid of that temp variable or a least only have to use it once.
Why not just something like:
items = ["cat","apple","taco"]
def change(ind, tx):
items[ind-1] = tx
change(2, "orange")
print(items)
# >>> ['cat', 'orange', 'taco']
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I have a list like below
l1 = ['a10','b2','a2','c1','b4','c5']
and I want to sum of numeric and output like below
l2 = ['a12','b6','c7'].
Note: do not use in-built function
from collections import Counter
l1 = ['a10','b2','a2','c1','b4','c5']
l2 = [f'{k}{v}' for (k, v) in Counter(''.join(i[0]*int(i[1:]) for i in l1)).items()]
# ['a12', 'b6', 'c6']
Figuring this out is left as an exercise to the reader.
It also assumes the alpha part is always just the first character.
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I want to give the values in all_X_H in there normal indices order a to variables in ring[corrector_indexes[m]].KickAngle which doesn't have the same order as a.
This is a simple example:
all_X_H = [
0,-0.000009
1,-0.000018
2,-0.000010
3,-0.000007]
corrector_indexes = [1,2,3,4]
final_corr_order_H = [3,2,1,0]
for m in final_corr_order_H:
for a in range(len(all_X_H)):
ring[corrector_indexes[m]].KickAngle = [all_X_H[a],0]
The result i want to see is
ring[corrector_indexes[3]].KickAngle = [all_X_H[0],0]
ring[corrector_indexes[2]].KickAngle = [all_X_H[1],0]
ring[corrector_indexes[1]].KickAngle = [all_X_H[2],0]
ring[corrector_indexes[0]].KickAngle = [all_X_H[3],0]
How can i define two different indices in one for loop to implement this?
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x=0
for x in range(0,k):
if(x>list_length):
x=0
#adding value of list in position 'x' to concat list
concat_list.append(l[x])
x+=1
I want to edit the real value(defined outside the for loop) of x in "if statement". How can I do that?
Well, if you want to redefine the original value x, then redefine your for loop variable (i.e. for x in range(0, k) to for i in range(0, k)).
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I have a list of strings L.
I need to check, whether a string is either directly an element of L or is in this format: "foo-element_of_L"
Is there a better way to do this in python than adding "foo-X" to L for all X in L?
I would do two lookups:
if x in L or f'foo-{x}' in L:
which may be significantly faster than
if any(x == y or f'foo-{x}' == y for x in L):
which is essentially what you were proposing.
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I have a list of lists of strings such that:
decipher = [['###>>?', '######', '*&*...', '##&#&#'], ['###>>?', '######', '*&*...', '######'], ['###>>?', '######', '*&*...', '######'], ['###>>?', '######', '*&*...', '######']]
I need to concatenate items with the same indeces from each list to print on the same line, each subsequent set of identically indexed items have to print on a new line:
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###&#&###&#&###&#&#
How can I accomplish that? Thanks!
A simple one line solution would be:
>>> print '\n'.join(''.join(i) for i in zip(*decipher))
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###################
Here is another solution:
for col in range(len(decipher[0])):
out = ''
for row in range(len(decipher)):
out += decipher[row][col]
print(out)
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###################