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FileNotFoundError: [Errno 2] No such file or directory: 'codedata.pkl'

This is a school program to learn how to use file and directory in Python. So to do my best I create a function to open, set it as a variable and close properly my file.
But I got the error of the title:
FileNotFoundError: [Errno 2] No such file or directory: 'codedata.pkl'
def load_db():
""" load data base properly
And get ready for later use
Return:
-------
cd : (list) list of tuples
"""
file = open('codedata.pkl', 'rb')
codedata = pickle.loads(file)
file.close()
return codedata
From the interpreter, this is the line
file = open('codedata.pkl', 'rb')
Which is the problem, but I don't see where is the source of the problem.
Can anyone help me?

Can you check what is the location of the file?
If your file is located at /Users/abc/Desktop/, then the code to open the file on python would be as shown below
file = open('/Users/abc/Desktop/codedata.pkl', 'rb')
codedata = pickle.load(file)
file.close()
You can also check if the file exists at the desired path by doing something like this
import os
filepath = '/Users/abc/Desktop/codedata.pkl'
if os.path.exists(filepath):
file = open('/Users/abc/Desktop/codedata.pkl', 'rb')
codedata = pickle.load(file)
file.close()
else:
print("File not present at desired location")

it happens when you run the script without determining it's the current working directory (example in vs code if you go to Explorer Tape )
You do not work from the same directory that your data.pkl in that's why No file exists
You can know the current directory from getcwd() usually it will be the C/User/.
print(os.getcwd())
filepath=""
if os.path.exists(r"D:\research\StleGAN\karras2019stylegan-ffhq-1024x1024.pkl"):
print("yes")
else:
print("no")
The solution is to open a directory that contains the script or to add the full path.

Renaming a single file in python

I'm trying to rename an audio file but I keep getting OSError: [Errno 2] No such file or directory.
In my program, each user has a directory that holds the users files. I obtain the path for each user by doing the following:
current_user_path = os.path.join(current_app.config['UPLOAD_FOLDER'], user.username)
/Users/johnsmith/Documents/pythonprojects/project/files/john
Now I want to obtain the path for the existing file I want to rename:
current_file_path = os.path.join(current_user_path,form.currentTitle.data)
/Users/johnsmith/Documents/pythonprojects/project/files/john/File1
The path for the rename file will be:
new_file_path = os.path.join(current_user_path, form.newTitle.data)
/Users/johnsmith/Documents/pythonprojects/project/files/john/One
Now I'm just running the rename command:
os.rename(current_file_path, new_file_path)

you can use os.rename for rename single file.
to avoid
OSError: [Errno 2] No such file or directory.
check if file exist or not.
here is the working example:
import os
src = "D:/test/Untitled003.wav"
dst = "D:/test/Audio001.wav"
if os.path.isfile(src):
os.rename(src, dst)

If the OS says there's no such file or directory, that's the gospel truth. You're making a lot of assumptions about where the file is, constructing a path to it, and renaming it. It's a safe bet there's no such file as the one named by current_file_path, or no directory to new_file_path.
Try os.stat(current_file_path), and similarly double-check the new file path with os.stat(os.posixpath.dirname(new_file_path)). Once you've got them right, os.rename will work if you've got permissions.

Try changing the current working directory to the one you want to work with. This code below should give you a simple walk through of how you should go about it:
import os
print (os.getcwd())
os.chdir(r"D:\Python\Example")
print (os.getcwd())
print ("start")
def rename_files():
file_list= os.listdir(r"D:\Python\Example")
print(file_list)
for file_name in file_list:
os.rename(file_name,file_name.translate(None,"0123456789")) rename_files()
print("stop")
print (os.getcwd())

Recovering filenames from a folder in linux using python

I am trying to use the listdir function from the os module in python to recover a list of filenames from a particular folder.
here's the code:
import os
def rename_file():
# extract filenames from a folder
#for each filename, rename filename
list_of_files = os.listdir("/home/admin-pc/Downloads/prank/prank")
print (list_of_files)
I am getting the following error:
OSError: [Errno 2] No such file or directory:
it seems to give no trouble in windows, where you start your directory structure from the c drive.
how do i modify the code to work in linux?

The code is correct. There should be some error with the path you provided.
You could open a terminal and enter into the folder first. In the terminal, just key in pwd, then you could get the correct path.
Hope that works.

You could modify your function to exclude that error with check of existence of file/directory:
import os
def rename_file():
# extract filenames from a folder
#for each filename, rename filename
path_to_file = "/home/admin-pc/Downloads/prank/prank"
if os.exists(path_to_file):
list_of_files = os.listdir(path_to_file)
print (list_of_files)

How to copy a folder (divide into sub folders) using Python?

i try to copy a directory (divided into folders and subfolders) to a new folder that will be created.i work with python 2.7.
dir_src = an exist folder
dir_dst = a new folder (not exist) that all the folders will be copied to
I read https://docs.python.org/2/library/shutil.html and tried this code:
import os,shutil
dir_src = r"C:\Project\layers"
dir_dst = r"C:\Project\new"
for file in os.listdir(dir_src):
print file
src_file = os.path.join(dir_src, file)
dst_file = os.path.join(dir_dst, file)
shutil.copytree(src_file, dst_file,symlinks=False, ignore=None)
print 'copytree'
But i get an error:
WindowsError: [Error 267] : 'C:\\Project\\layers\\abc.cpg/*.*'
Thank you very much for any help.

The error you are getting (Permission denied) should tell you what is the problem - you don't have rights to read or copy the files. Running the program as administrator should fix it.

About edited question and error:
WindowsError: [Error 267] : 'C:\\Project\\layers\\abc.cpg/*.*'
Please carefully read docs
import shutil
dir_src = r"C:\Project\layers"
dir_dst = r"C:\Project\new"
shutil.copytree(dir_src, dir_dst)
you not need any for.
Note:
Please keep in mind, that destination path shouldn't be existed.

How to correctly move Files with Python

I already read some useful infos here about moving files with Python. But those are not working on my machine. I use eclipse to run python and the program should move files within windows.
I used os.rename, shutil.move, shutil.copy and so on....
Here is my simple code.
import os
import shutil
source = os.listdir("C:/test/")
dest_dkfrontend = "C:/test1/"
for files in source:
if files.startswith("Detail"):
print('Files found ' + files)
shutil.copy(files, dest_dkfrontend)
else:
print('File name not matching')
I receive an error like:
with open(src, 'rb') as fsrc:
IOError: [Errno 2] No such file or directory:
Could you please help to address this?

first you have to check if your destination directory exists or not.
and shutil.copy requires 1st parameter as source of file with file name and 2nd parameter as destination of file where to copy with new file name.
try this.
import os
import shutil
source = os.listdir("C:/test/")
dest_dkfrontend = "C:/test1/"
if not os.path.exists(dest_dkfrontend):
os.makedirs(dest_dkfrontend)
for files in source:
if files.startswith("Detail"):
print('Files found ' + files)
shutil.copy(source+files, dest_dkfrontend+files)
else:
print('File name not matching')