Let's say I have something like this:
expr="
def something():
return True
something()"
somevar=compile(expr, "","eval")
This throws a syntax error on "def". I've also tried wrapping the compile() with an eval(), no use. I basically want the result of the function call. Is this possible with eval or compile? Is there any library that would achieve this? I want somevar to be False.
Thanks in advance
According to the docs:
The mode argument specifies what kind of code must be compiled; it can be 'exec' if source consists of a sequence of statements, 'eval' if it consists of a single expression, or 'single' if it consists of a single interactive statement
So there's a couple of things here:
You should use multi-line strings in Python (three """)
You shouldn't use "eval" but "exec"
The returned object is not executed. You have to explicitly call it once created.
With all that in mind:
expr = """
def something():
print('hi')
return "done"
something()
"""
somevar = compile(expr, "", "exec")
exec(somevar)
This does print "hi". However, that code itself doesn't return anything. You run the function something() which yes: returns "done" but after running something()? Where would you return the return?
One option, as explained in this other SO thread would be assigning the return value to what would become a sort of "global" variable:
expr = """
def something():
return "done"
retval = something()
"""
somevar = compile(expr, "", "exec")
exec(somevar)
print(retval)
I can't help but saying that this sort of convoluted coding, that runs code stored in strings is probably a bad idea. It's insecure, hard to track, debug, refactor... So if this is going to be used for something besides learning purposes... Well... I would invite you to try and think if there's another way of achieving what you want.
Related
I am used to vb.net. I am learning python 3.6/7, as I understand it code writing is in either:
functions that return a result
functions that return a None
In a modules (no functions), ie run the module.py
In a class ie run the class.ID.function (ref (1) and (2))
In .Net you can run code in a function and a sub routine, so python has no sub routines, just functions returning None.
Is this correct?
Every function in python return some value, if you don't specify the return value then it will implicitly return None. So there is no distinction like sub or function in python.
Like other programming languages, in Python:
To let a function return a value, you have to use the return statement.
But if you don't specify the return value then it will simply return Nothing.
According to Wikipedia, In computer programming, a subroutine is a sequence of program instructions that performs a specific task, packaged as a unit. This unit can then be used in programs wherever that particular task should be performed.
So, in python a function can return any kind of value, objects or even None. A function returns None in two cases :
You write return None or return at the end of the function.
def some_func():
#do anything and return None
#you can write "return" instead "return None"
return None
some_var = some_func()
#There is no output to the above line of code
print(some_var)
#There is no output to the above line of code
print(type(some_var))
#Output: NoneType
You don't return anything at all and every function by default returns a None if nothing specified. For example:
def some_func():
print ("I print and return nothing")
some_var = some_func()
#Output : I print and return nothing
print(some_var)
#There is no output to the above line of code
print(type(some_var))
#Output: NoneType
Hope it helps.
I am trying to make a function's output behave as if it's my input. The goal is to make a new output from the old output.
I have some code that looks like this:
def func():
BLOCK OF CODE
func()
There is no return statement in the function and no parameters within the parenthesis.
When I type func() to call my function as shown above, I get the desired output, which is a bunch of printed statements. Now I want to do something with that output to get another output.
All I'm trying to do is effectively "pipe" the output of one function into the input of another function (or, if possible, not even worry about creating another function at all, and instead doing something more direct). I looked into Python 3 writing to a pipe
but it did not help me. I also tried defining another function and using the preceding function as a parameter, which did not work either:
def another_func(func):
print another_statement
another_func(func)
I also tried making a closure (which "kind" of worked because at least it printed the same thing that func() would print, but still not very encouraging):
def func():
def another_func():
print another_statement
BLOCK OF CODE
another_func()
Finally, I tried designing both a decorator and a nested function to accomplish this, but I have no parameters in my function, which really threw off my code (didn't print anything at all).
Any advice on how to manipulate a function's output like as if it is your input so that it's possible to create a new output?
You could achieve this by redirecting stdout using a decorator:
from StringIO import StringIO
import sys
def pipe(f):
def decorated(*args, **kwargs):
old,sys.stdout = sys.stdout,StringIO()
try:
result = f(*args, **kwargs)
output = sys.stdout.getvalue()
finally:
sys.stdout = old
return result, output
return decorated
You could then get the result, output pair from any decorated function, eg:
#pipe
def test(x):
print x
return 0
test(3) -> (0, '3\n')
However, I can't think of a good reason why you'd want to do this.
(Actually, that's not quite true; it is handy when writing unit tests for user IO, such as when testing student assignments in a software engineering course. I seriously doubt that that's what the OP is trying to do, though.)
Return the desired value(s) from the function - instead of printing the values on the console, return them as strings, numbers, lists or any other type that makes sense. Otherwise, how do you expect to "connect" the output of a function as the input to another, if there is no output to begin with?
Of course, printing on the console doesn't count as output unless you're planning to eventually use OS pipes or a similar mechanism to connect two programs on the console, but keep things simple! just use the function's return values and worry about pipes later if and only if that's necessary for your problem in particular.
After reading the comments: "connecting" two functions by printing on the console from one and reading from the console from the other would be a really bad idea in this case, first you have to grasp the way functions return values to each other, trust me on this one: you have to rethink your program! even though other answers (strictly speaking) answer your original question, that's absolutely not what you should do.
just for fun ... because OP asked for it
import StringIO
import sys
def func1():
for i in range(1,10):
print "some stuff %d"%i
def func2(func):
old_std = sys.stdout
sys.stdout = StringIO.StringIO()
try:
func()
return sys.stdout.getvalue().splitlines()
finally:
sys.stdout = old_std
print func2(func1)
You need to return a value from your function. This can be used to assign the value into another variable.
Say I define some function doubleThis that will double the input
def doubleThis(x):
print 'this is x :', x
return x * 2 # note the return keyword
Now I can call the function with 3, and it returns 6 as expected
>>> doubleThis(3)
this is x : 3
6
Now I have another function subtractOne that returns the input value, minus 1.
def subtractOne(i):
print 'this is i :', i
return i - 1
Now comes the answer to your question. Note that we can call the first function as the input to the second, due to the fact that it has a return value.
>>> subtractOne(doubleThis(3))
this is x : 3
this is i : 6
5
I have been working at learning Python over the last week and it has been going really well, however I have now been introduced to custom functions and I sort of hit a wall. While I understand the basics of it, such as:
def helloworld():
print("Hello World!")
helloworld()
I know this will print "Hello World!".
However, when it comes to getting information from one function to another, I find that confusing. ie: function1 and function2 have to work together to perform a task. Also, when to use the return command.
Lastly, when I have a list or a dictionary inside of a function. I'll make something up just as an example.
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
How would I access the key/value and be able to change them from outside of the function? ie: If I had a program that let you input/output player stats or a character attributes in a video game.
I understand bits and pieces of this, it just confuses me when they have different functions calling on each other.
Also, since this was my first encounter with the custom functions. Is this really ambitious to pursue and this could be the reason for all of my confusion? Since this is the most complex program I have seen yet.
Functions in python can be both, a regular procedure and a function with a return value. Actually, every Python's function will return a value, which might be None.
If a return statement is not present, then your function will be executed completely and leave normally following the code flow, yielding None as a return value.
def foo():
pass
foo() == None
>>> True
If you have a return statement inside your function. The return value will be the return value of the expression following it. For example you may have return None and you'll be explicitly returning None. You can also have return without anything else and there you'll be implicitly returning None, or, you can have return 3 and you'll be returning value 3. This may grow in complexity.
def foo():
print('hello')
return
print('world')
foo()
>>>'hello'
def add(a,b):
return a + b
add(3,4)
>>>7
If you want a dictionary (or any object) you created inside a function, just return it:
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
return my_dict
d = my_function()
d['Key1']
>>> Value1
Those are the basics of function calling. There's even more. There are functions that return functions (also treated as decorators. You can even return multiple values (not really, you'll be just returning a tuple) and a lot a fun stuff :)
def two_values():
return 3,4
a,b = two_values()
print(a)
>>>3
print(b)
>>>4
Hope this helps!
The primary way to pass information between functions is with arguments and return values. Functions can't see each other's variables. You might think that after
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
my_function()
my_dict would have a value that other functions would be able to see, but it turns out that's a really brittle way to design a language. Every time you call my_function, my_dict would lose its old value, even if you were still using it. Also, you'd have to know all the names used by every function in the system when picking the names to use when writing a new function, and the whole thing would rapidly become unmanageable. Python doesn't work that way; I can't think of any languages that do.
Instead, if a function needs to make information available to its caller, return the thing its caller needs to see:
def my_function():
return {"Key1":"Value1",
"Key2":"Value2",
"Key3":"Value3",
"Key4":"Value4",}
print(my_function()['Key1']) # Prints Value1
Note that a function ends when its execution hits a return statement (even if it's in the middle of a loop); you can't execute one return now, one return later, keep going, and return two things when you hit the end of the function. If you want to do that, keep a list of things you want to return and return the list when you're done.
You send information into and out of functions with arguments and return values, respectively. This function, for example:
def square(number):
"""Return the square of a number."""
return number * number
... recieves information through the number argument, and sends information back with the return ... statement. You can use it like this:
>>> x = square(7)
>>> print(x)
49
As you can see, we passed the value 7 to the function, and it returned the value 49 (which we stored in the variable x).
Now, lets say we have another function:
def halve(number):
"""Return half of a number."""
return number / 2.0
We can send information between two functions in a couple of different ways.
Use a temporary variable:
>>> tmp = square(6)
>>> halve(tmp)
18.0
use the first function directly as an argument to the second:
>>> halve(square(8))
32.0
Which of those you use will depend partly on personal taste, and partly on how complicated the thing you're trying to do is.
Even though they have the same name, the number variables inside square() and halve() are completely separate from each other, and they're invisible outside those functions:
>>> number
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'number' is not defined
So, it's actually impossible to "see" the variable my_dict in your example function. What you would normally do is something like this:
def my_function(my_dict):
# do something with my_dict
return my_dict
... and define my_dict outside the function.
(It's actually a little bit more complicated than that - dict objects are mutable (which just means they can change), so often you don't actually need to return them. However, for the time being it's probably best to get used to returning everything, just to be safe).
I wonder how to correctly use python 2.7 callback functions.
I have some callback functions from Cherrypy auth examples in my code.
(These callbacks return a function that can evaluate to True or False, depending on the logged in user being in a group or not.)
I wonder if a callback is executed or not if I write a piece of code like this:
Given the definition from the library is:
def member_of(groupname):
def check():
if groupname == 'admin':
if cherrypy.request.login == 'joe':
return True
if cherrypy.request.login == 'toni':
return True
return False
return False
# .... (other groups checked in the same way)
return check # returns a callback function from my understanding?
How can I apply and execute the callback in my code?
If I put it like this:
if member_of('admin'):
do_something()
else:
do_something_else()
Will this execute the calllback and check for the admin group? Or will it find out if the value of "member_of" is a function definition and a function definition is probably always a "True" value (or maybe a False value) but both are wrong, because it needs to be executed
Can you enlighten me on this? How can I make sure a callback is executed? An how can I pass it around as it is?
In python, like in many other languages, a variable can also contain a function and you can pass them around like other variables that contain e.g. numbers or strings.
CherryPy's member_of function itself does return a function in your example.
I am explaining it in simple steps:
If you write member_of() it returns the result of the function member_of() which is the function with the name check in this case.
cb_function = member_of('admin')
At this point the variable cb_function holds the result of calling the function member_of, and in the last line member_of returns check, which was defined within the function member_of as another function!
You have to call the first result again, because you can and you have to treat it in almost the same way as a local function, that you defined in the current context, to get the final result, by doing something like:
my_result = cb_function()
And then you would continue and use the result. For example you could check its boolean value:
if my_result:
# do something
...
The 3 steps from above together can be written shorter:
cb_function = member_of('admin')
if cb_function():
# do something
...
Or even shorter:
if member_of('admin')():
# do something
...
At first it may appear a little strange in python to have the double ()(), but if you think about it for a while it makes sense.
If you execute it, it is plain simple.
member_of() will return method object check.
you have to execute to get result by doing something like if member_of('admin')():
or,
k=member_of('admin')
if k():
To do your task.
I'm wondering if anyone can think up a way to check if a function needs to return a meaningful value in Python. That is, to check whether the return value will be used for anything. I'm guessing the answer is no, and it is better to restructure my program flow. The function in question pulls its return values from a network socket. If the return value is not going to get used, I don't want to waste the resources fetching the result.
I tried already to use tracebacks to discover the calling line, but that didn't work. Here's an example of what I had in mind:
>>> def func():
... print should_return()
...
>>> func()
False
>>> ret = func()
True
The function "knows" that its return value is being assigned.
Here is my current workaround:
>>> def func(**kwargs):
... should_return = kwargs.pop('_wait', False)
... print should_return
...
>>> func()
False
>>> ret = func(_wait=True)
True
The very second line of the body of import this says it all: "explicit is better than implicit". In this case, if you provide an optional argument, the code will be more obvious (and thus easier to understand), simpler, faster and safer. Keep it as a separate argument with a name like wait.
While with difficulty you could implement it magically, it would be nasty code, prone to breaking in new versions of Python and not obvious. Avoid that route; there lieth the path unto madness.
All functions return a value when they complete.
If you're asking if they should return at all, then you are actually asking about The Halting Problem
One approach might be to return an object with a __del__ method that relies on the garbage collector removing the unused value some time in the future.
Note that it won't happen immediately; it might not even happen at all :)
You might consider returning a future, or 'promise'. That is, return another function that, when executed, performs the necessary work to actually determine the result. I seem to be thinking that you want lazy evaluation, which is "evaluate only what you need" (more or less), rather than your question, which confusingly asks: "Evaluate only if it returns a value, which might be needed".
i have some code that kinda works using inspect module, but it might be prone to break like others mention.
inspect.stack()[1].frame.f_code.co_names[-1]
will be holding the function name when user didn't assign return value to anything, when user assign to var with name XXX, this var will hold XXX. Code comparing this vs the function name to decide whether user assign the return value to any var
import inspect
def func():
tmp = inspect.stack()[1].frame.f_code.co_names[-1]
should_return = tmp != 'func'
print("execute") # execute something
# if should_return False, end here without fetching result
if should_return:
print("fetching result, user assign to {}".format(tmp))
# fetching result and return the result here
>>> func()
execute
>>>
>>> xxx=func()
execute
fetching result, user assign to xxx
>>>
All functions in Python always return. If you don't explicitly return, functions return None.
===========
def func():
while True:
pass
This function does not return.
There is no way of determining if an arbitrary function will return. If you can, you have solved the Turing problem.