Develop Reference

Verifying if user input is in multiple zero values

How can we check if a user enters the value 0 multiple times in a row?
I have tried below code- here I have tried to define multiple value in list, but if the user enters 000000000 or more, I have to define till 000000000 in list is there any other way to achieve this
list = [0,00,000,0000]
num = int(input("Enter a number: "))
if num in list:
print("Zero")
elif :
print(" None ")

You need to take the input as a string. And you can check if the user has entered a string that will have all zeros in it as follows
def all_zeros(string):
return all(ch == '0' for ch in string)

This worked for me
num = input("Enter: ")
if num.count('0') > 0 and num.startswith('0'):
print("0")
else:
print("none")

Since you asked in this way
How can we check if a user enters the value 0 multiple times in a row?
But, other answers were checking whether more than one 0's are present in the string or not. I assume you want to check continuous zero's only,
num = input("Enter Number: ") # returns string
if "00" in num: #checking substring
print("Found continuous zeros")
else:
print("Entered no continous zeros!")
value = int(num) # convert it to int if needed
It doesn't matter how many zeros in the string, all these [00,000,0000,00000...] belong to the same category.
Output:
>>> num = input("Enter Number: ")
Enter Number: 0008
>>> num
'0008'
>>> "00" in num
True
>>>

num = input("Enter: ")
if num.count("0") > 1 and int(num) == 0:
print("0")
else:
print("none")
don't change num to int it will remove all the trailing zeroes

Need help understanding while-loops and what it is doing

I am learning Python, and currently I am learning about sentinel loops. I have this piece of code that I need help understanding. What exactly is the while-loop doing? I did some research and I know it is looping through the if-statement (correct me if I am wrong); but is it looping through a specific equation until the user stops inputting their integers? Thank you in advanced.
(Please no hate comments I am still learning as a developer. & this is my first post Thanks)
even = 0 odd = 0
string_value = input("Please enter an int. value: ")
while string_value !="":
int_value = int(string_value)
if int_value % 2 == 0:
even += 1
else:
odd += 1
string_value = input("Please enter an int. value: ")
if even + odd == 0:
print("No values were found. Try again...") else:
print("Number of evens is: ", str(even)+".")
print("Number of odd is: ", str(odd)+".")
---Updated Code:
def main():
print("Process a series of ints enter at console \n")
count_even = 0
count_odd = 0
num_str = input("Please enter an int. value or press <Enter> to stop: ")
#Process with loop
while num_str !="":
num_int = int(num_str)
if num_int % 2 == 0:
count_even += 1
else:
count_odd += 1
num_str = input("Please enter an int. value: ")
if count_even + count_odd == 0:
print("No values were found. Try again...")
else:
print("Number of evens is: ", str(count_even)+".")
print("Number of odd is: ", str(count_odd)+".")
main()

First thing the while loop does is check if the user input is emptywhile string_value !="", if it is not empty than it will start the loop. The != means not equals and the "" is empty so not equals empty. Next it sets the variable int_value as the integer of the user input(will error if user inputs anything other than whole number). Next it checks if the variable int_value % 2(remainder of division by 2) is 0, so pretty much it checks if the number is divisible by 2, if it is divisible by two it will add 1 to the even variable. Otherwise it will add 1 to the odd variable

It will be very helpful if you go through python doc https://docs.python.org/3/tutorial/index.html
even = 0 odd = 0
The above line even and odd are variables keeping count of even number and odd number.
string_value = input("Please enter an int. value: ")
The above line prompt the user to input an integer
while string_value !="":
int_value = int(string_value)
if int_value % 2 == 0:
even += 1
else:
odd += 1
string_value = input("Please enter an int. value: ")
The above while loop check firstly, if the input is not empty, int() Return an integer object constructed from a number or string x, or return 0 if no arguments are given https://docs.python.org/3/library/functions.html#int. The if statement takes the modulus of the integer value, and then increases the counter for either odd or even.
Finally, the count of odd and even are printed.

the input() function waits until the user enters a string so unless the user enters an empty string the while loop will keep asking the user for strings in this line:
string_value = input("Please enter an int. value: ")
and check if its an empty string in this line:
while string_value !="":

How do I sum numbers from user input in python?(only if they are even numbers)

I am new to programming, and I'm trying to make a code to get six numbers from a user and sum only even numbers but it keeps error like, "unsupported operand type(s) for %: 'list' and 'int' How can I do with it?
Also, I want to make like this,
Enter a value: 1
Is it even number?:no
Enter a value: 2
Is it even number?:yes
Enter a value: 3
Is it even number?:no
Enter a value: 6
Is it even number?:yes
but it keeps like this,
Enter a value: 1
Enter a value: 2
Enter a value: 3
Enter a value: 4
Enter a value: 5
Is it even number?:
Is it even number?:
Is it even number?:
Is it even number?:
Is it even number?:
How can I fix this?
anyone who can fix this problem please let me know
Python 3.7
numbers = [int(input('Enter a value: ')) for i in range(6)]
question = [input('Is it even number?: ') for i in range(6)]
list1 = [] #evens
list2 = [] #odds
if numbers % 2 ==0:
list1.append
else:
list2.append
sum = sum(list1)
print(sum)
And I'd appreciate it if you could let me know if you knew the better code

This should do it. Note that there is no real need to ask the user if the number is even, but if you do want to ask, you can just add question = input('Is it even number?: ').lower() in the loop and then do if question=='yes'. Moreover, note that you cannot perform % on a list; it has to be on a single number.
evens = []
odds = []
for i in range(6):
number = int(input('Enter a value: '))
if number%2==0:
evens.append(number)
else:
odds.append(number)
print(sum(evens))

you are running the first two input statements in for loops and print at the same time.
You can just take inputs first 6 times and store them in a list. After that you can check each input and store in even and odd lists while printing if its even or odd. and print the sum at last.

Your if condition makes no sense:
if numbers % 2 == 0:
What is the value of [1, 2, 3, 6] % 2? There is no such thing as "a list, modulo 2". Modulus is defined between two scalar numbers.
Instead, you have to consider each integer in turn. This is not an operation you get to vectorize; that is a capability of NumPy, once you get that far.
for i in range(6):
num = int(input('Enter a value: '))
# From here, handle the *one* number before you loop back for the next.

If you want to show running sum. You can do something like :
import sys
sum_so_far = 0
while True:
raw_input = input('Enter an integer: ')
try:
input_int = int(raw_input)
if input_int == 0:
sys.exit(0)
elif input_int % 2 == 0:
sum_so_far = sum_so_far + input_int
print("Sum of Even integers is {}. Enter another integer er or 0 to exit".format(sum_so_far))
else:
print("You entered an Odd integer. Enter another integer or 0 to exit")
except ValueError:
print("You entered wrong value. Enter an integer or 0 to exit!!!")

Using += in a while loop but need to exclude highest number

I was tasked with creating a program that takes all the inputted numbers and adds them together except the highest integer out of that list. I am suppose to use while and if then logic but I cannot figure out how to exclude the highest number. I also had to make the program break when the string "end" was put into the console. So far I have,
total = 0
while 1 >= 1 :
value = input("Enter the next number: ")
if value != "end":
num = float(value)
total += num
if value == 'end':
print("The sum of all values except for the maximum value is: ",total)
return total
break
I just have no idea how to make it disregard the highest inputted number. Thanks in advance! I am using python 3 fyi.

Is this what you're trying to do?
total = 0
maxValue = None
while True:
value = input("Enter the next number: ")
if value != "end":
num = float(value)
maxValue = num if maxValue and num > maxValue else num
total += num
else:
print("The sum of all values except for the maximum value is: ",total-maxValue )
# return outside a function is SyntaxError
break

Here you go in regards to keeping it close to your original. Using lists is great in python for this sort of thing.
list = []
while True:
num = input("Please enter value")
if num == "end":
list.remove(max(list))
return sum(list)
else:
list.append(int(num))
if you input 1,2 and 3 this would output 3 - it adds the 1 and 2 and discards the original 3.
You've said it's an assignment so if lists aren't allowed then you could use
max = 0
total = 0
while True:
num = input("Please enter value")
if str(num) == "end":
return total - max
if max < int(num):
max = int(num)
total += int(num)

the easiest way to achieve the result you want is to use python's builtin max function (that is if you don't care about performance, because this way you are actually iterating over the list 2 times instead of one).
a = [1, 2, 3, 4]
sum(a) - max(a)
This not exactly the same as you want it to do, but the result is going to be the same (Since instead of not adding the largest item you can just subtract it in the end).

This should work for you.
total = 0
highest = None
while True:
value = input("Enter the next number: ")
if value != 'end':
num = float(value)
if highest is None or num > highest:
highest = num
total += num
else:
break
print("The sum of all values except for the maximum value is: ",total-highest )
print(total-highest)

Python3x Integer and String Input

I want the user to input a number
Give a number : he types "10" -but...
Give a number : he types "I want to type 10"
i want the program to just "count" the integer. Because if he types a string the program will stop
import random
goal = random.randrange(1,10)
n = 1
tries = 0
name = input("Dose to onoma sou ")
print("A game in Python")
while n != 0 :
value = int(input("madepse poio einai to noumero:"))
n = abs(value - goal)
print(value,n)
tries = tries + 1
if n >= 4 :
print("den eisai koda")
elif n > 0 and n <= 3 :
print("eisai koda")
else :
print("to vrikes")
print ("to score sou einai: ",tries)
skoros = str(tries)
score = open('score.txt', 'a')
score.write(name)
score.write(' ')
score.write(skoros)
score.write("\n")
score.close

This will take any input and pull the first number out of it. \d matches any digit 0-9, and + means "one or more".
import re
while True:
user = input('Enter a number: ')
match = re.search(r'\d+',user)
if match:
value = int(match.group(0))
break
else:
print("I didn't see a number in that response.")
print(value)

Well, you could just manually loop through the string and store the position of the number using isdigit().
The following approach expects the number to be the only one in the string (multi digit allowed):
start = None
stop = None
for i in range(len(input)):
c = input[i]
if c.isdigit():
if start == None:
start = i
stop = i
try:
number = int(input[start:stop])
catch:
print("invalid input")
EDIT:
I guess there would be some nice and easy Regex solution, but I'll leave my hands off of it, as I am not too experienced with it...