Im trying to scrape the information of all the player names and player rating from this website:
https://www.fifaindex.com/players/?gender=0&league=1&order=desc
But i only get the information from the first player on the page.
The code im using:
from bs4 import BeautifulSoup
import requests
url = "https://www.fifaindex.com/players/?gender=0&league=1&order=desc"
page = requests.get(url)
soup = BeautifulSoup(page.content, 'html.parser')
results = soup.find_all('div', class_="responsive-table table-rounded")
for result in results:
rating = result.find("span", class_="badge badge-dark rating r3").text
name = result.find("a", class_="link-player")
info = [rating, name]
print(info)
The HTML parsed is attached in the picture
I tinkered around a little bit and I think I got a version that does what you want
from bs4 import BeautifulSoup
import requests
page = requests.get("https://www.fifaindex.com/players/?
gender=0&league=1&order=desc")
soup = BeautifulSoup(page.content, "html.parser")
results = soup.find_all("tr")
for result in results:
try:
result["data-playerid"]
except KeyError:
continue
rating = result.find("span", class_="badge badge-dark rating r3").text
name = result.find("a", class_="link-player")
info = [rating, name]
print(info)
Get all table lines with a data-playerid attribute will fix it:
#!/usr/bin/env python3
from bs4 import BeautifulSoup
import requests
url = "https://www.fifaindex.com/players/?gender=0&league=1&order=desc"
r = requests.get(url)
soup = BeautifulSoup(r.content, 'html.parser')
results = soup.find_all('tr', {'data-playerid': True})
for res in results:
rating = res.find("span", class_="badge badge-dark rating r3").text
name = res.find("a", class_="link-player")
info = [rating, name]
print(info)
Related
This is the link url
url = 'https://www.booking.com/searchresults.html?label=gen173nr-1FCAEoggI46AdIM1gEaGyIAQGYATG4ARfIAQzYAQHoAQH4AQKIAgGoAgO4AuS4sJ4GwAIB0gIkYWJlYmZiMWItNWJjMi00M2Y2LTk3MGUtMzI2ZGZmMmIyNzMz2AIF4AIB&aid=304142&dest_id=-2092174&dest_type=city&group_adults=2&req_adults=2&no_rooms=1&group_children=0&req_c
Hotel_name = doc.find_all("div",{'class' : "fcab3ed991 a23c043802"})
this gives me the result of all hotel names in page number, 1, but how can I get the hotel names of all the pages?
I've tried this
import requests
from bs4 import BeautifulSoup
# Initialize the page number
page_number = 0
while True:
# Increment the page number
page_number += 1
# Make the GET request to the URL
url = f"https://www.booking.com/searchresults.html?label=gen173nr-1FCAEoggI46AdIM1gEaGyIAQGYATG4ARfIAQzYAQHoAQH4AQKIAgGoAgO4AuS4sJ4GwAIB0gIkYWJlYmZiMWItNWJjMi00M2Y2LTk3MGUtMzI2ZGZmMmIyNzMz2AIF4AIB&aid=304142&dest_id=-2092174&dest_type=city&group_adults=2&req_adults=2&no_rooms=1&group_children=0&req_children=0&nflt=ht_id%3D204&rows=15&offset={page_number*15}"
response = requests.get(url)
# Parse the HTML content
soup = BeautifulSoup(response.content, 'html.parser')
# Extract the hotel information
hotels = soup.find_all('div', {'class' : "fcab3ed991 a23c043802"})
if not hotels:
break
for hotel in hotels:
price = hotel.find('div', {' data-testid="title'}).text
print(f"{price}")
but it gives me an empty list as an output.
Avoid selecting elements by classes that looks highly dynamic and use HTML structure instead. Check the number of total results and use it in range() to iterate the results.
Example
import requests, re
from bs4 import BeautifulSoup
data = []
soup = BeautifulSoup(
requests.get('https://www.booking.com/searchresults.html?label=gen173nr-1FCAEoggI46AdIM1gEaGyIAQGYATG4ARfIAQzYAQHoAQH4AQKIAgGoAgO4AuS4sJ4GwAIB0gIkYWJlYmZiMWItNWJjMi00M2Y2LTk3MGUtMzI2ZGZmMmIyNzMz2AIF4AIB&aid=304142&dest_id=-2092174&dest_type=city&group_adults=2&req_adults=2&no_rooms=1&group_children=0&req_children=0&nflt=ht_id%3D204&rows=15',
headers={'user-agent':'some agent'}
).text)
num_results = int(re.search(r'\d+',soup.select_one('div:has(+[data-testid="pagination"])').text).group(0))
for i in range(0,int(num_results/25)):
soup = BeautifulSoup(
requests.get(f'https://www.booking.com/searchresults.html?label=gen173nr-1FCAEoggI46AdIM1gEaGyIAQGYATG4ARfIAQzYAQHoAQH4AQKIAgGoAgO4AuS4sJ4GwAIB0gIkYWJlYmZiMWItNWJjMi00M2Y2LTk3MGUtMzI2ZGZmMmIyNzMz2AIF4AIB&aid=304142&dest_id=-2092174&dest_type=city&group_adults=2&req_adults=2&no_rooms=1&group_children=0&req_children=0&nflt=ht_id%3D204&rows=15&offset={int(i*25)}',
headers={'user-agent':'some agent'}
).text
)
data.extend([e.select_one('[data-testid="title"]').text for e in soup.select('[data-testid="property-card"]')])
data
import requests
from bs4 import BeautifulSoup
r = requests.get("https://gaana.com/playlist/gaana-dj-hindi-top-50-1")
soup = BeautifulSoup(r.text, "html.parser")
result = soup.find("div", {"class": "s_c"})
print(result.class)
From the above code, I am able to scrape this data
https://www.pastiebin.com/5f08080b8db82
Now I would like to scrape only the title of the songs and then make a list out of them like the below:
Meri Aashiqui
Genda Phool
Any suggestions are much appreciated!
Try this :
import requests
from bs4 import BeautifulSoup
r = requests.get("https://gaana.com/playlist/gaana-dj-hindi-top-50-1")
soup = BeautifulSoup(r.text, "html.parser")
result = soup.find("div", {"class": "s_c"})
#print(result)
div = result.find_all('div', class_='track_npqitemdetail')
name_list = []
for x in div:
span = x.find('span').text
name_list.append(span)
print(name_list)
this code will return all song name in name_list list.
Hey guess so I got as far as being able to add the a class to a list. The problem is I just want the href link to be added to the links_with_text list and not the entire a class. What am I doing wrong?
from bs4 import BeautifulSoup
from requests import get
import requests
URL = "https://news.ycombinator.com"
page = requests.get(URL)
soup = BeautifulSoup(page.content, 'html.parser')
results = soup.find(id = 'hnmain')
articles = results.find_all(class_="title")
links_with_text = []
for article in articles:
link = article.find('a', href=True)
links_with_text.append(link)
print('\n'.join(map(str, links_with_text)))
This prints exactly how I want the list to print but I just want the href from every a class not the entire a class. Thank you
To get all links from the https://news.ycombinator.com, you can use CSS selector 'a.storylink'.
For example:
from bs4 import BeautifulSoup
from requests import get
import requests
URL = "https://news.ycombinator.com"
page = requests.get(URL)
soup = BeautifulSoup(page.content, 'html.parser')
links_with_text = []
for a in soup.select('a.storylink'): # <-- find all <a> with class="storylink"
links_with_text.append(a['href']) # <-- note the ['href']
print(*links_with_text, sep='\n')
Prints:
https://blog.mozilla.org/futurereleases/2020/06/18/introducing-firefox-private-network-vpns-official-product-the-mozilla-vpn/
https://mxb.dev/blog/the-return-of-the-90s-web/
https://github.blog/2020-06-18-introducing-github-super-linter-one-linter-to-rule-them-all/
https://www.sciencemag.org/news/2018/11/why-536-was-worst-year-be-alive
https://www.strongtowns.org/journal/2020/6/16/do-the-math-small-projects
https://devblogs.nvidia.com/announcing-cuda-on-windows-subsystem-for-linux-2/
https://lwn.net/SubscriberLink/822568/61d29096a4012e06/
https://imil.net/blog/posts/2020/fakecracker-netbsd-as-a-function-based-microvm/
https://jepsen.io/consistency
https://tumblr.beesbuzz.biz/post/621010836277837824/advice-to-young-web-developers
https://archive.org/search.php?query=subject%3A%22The+Navy+Electricity+and+Electronics+Training+Series%22&sort=publicdate
https://googleprojectzero.blogspot.com/2020/06/ff-sandbox-escape-cve-2020-12388.html?m=1
https://apnews.com/1da061ce00eb531291b143ace0eed1c9
https://support.apple.com/library/content/dam/edam/applecare/images/en_US/appleid/android-apple-music-account-payment-none.jpg
https://standpointmag.co.uk/issues/may-june-2020/the-healing-power-of-birdsong/
https://steveblank.com/2020/06/18/the-coming-chip-wars-of-the-21st-century/
https://www.videolan.org/security/sb-vlc3011.html
https://onesignal.com/careers/2023b71d-2f44-4934-a33c-647855816903
https://www.bbc.com/news/world-europe-53006790
https://github.com/efficient/HOPE
https://everytwoyears.org/
https://www.historytoday.com/archive/natural-histories/intelligence-earthworms
https://cr.yp.to/2005-590/powerpc-cwg.pdf
https://quantum.country/
http://www.crystallography.net/cod/
https://parkinsonsnewstoday.com/2020/06/17/tiny-magnetically-powered-implant-may-be-future-of-deep-brain-stimulation/
https://spark.apache.org/releases/spark-release-3-0-0.html
https://arxiv.org/abs/1712.09624
https://www.washingtonpost.com/technology/2020/06/18/data-privacy-law-sherrod-brown/
https://blog.chromium.org/2020/06/improving-chromiums-browser.html
I am trying to get top movies name by genre. I couldn't get complete href links for that, I stuck by getting half href links
By the following code I got,
https://www.imdb.com/search/title?genres=action&sort=user_rating,desc&title_type=feature&num_votes=25000,
https://www.imdb.com/search/title?genres=adventure&sort=user_rating,desc&title_type=feature&num_votes=25000,
https://www.imdb.com/search/title?genres=animation&sort=user_rating,desc&title_type=feature&num_votes=25000,
https://www.imdb.com/search/title?genres=biography&sort=user_rating,desc&title_type=feature&num_votes=25000,
.........
Like that but i want to all top 100 movies name by its genre like action, Adventure, Animation, Biography.......
I tried the following code:
from bs4 import BeautifulSoup
import requests
url = 'https://www.imdb.com'
main_url = url + '/chart/top'
res = requests.get(main_url)
soup = BeautifulSoup(res.text, 'html.parser')
for href in soup.find_all(class_='subnav_item_main'):
# print(href)
all_links = url + href.find('a').get('href')
print(all_links)
I want complete link as shown bellow from a link
/search/title?genres=action&sort=user_rating,desc&title_type=feature&num_votes=25000,&pf_rd_m=A2FGELUUNOQJNL&pf_rd_p=5aab685f-35eb-40f3-95f7-c53f09d542c3&pf_rd_r=FM1ZEBQ7E9KGQSDD441H&pf_rd_s=right-6&pf_rd_t=15506&pf_rd_i=top&ref_=chttp_gnr_1"
You need another loop over those urls and a limit to only get 100. I store in a dictionary with keys being genre and values being a list of films. Note original titles may appear e.g. The Mountain II (2016) is Dag II (original title).
links is a list of tuples where I keep the genre as first item and url as second.
import requests, pprint
from bs4 import BeautifulSoup as bs
from urllib.parse import urljoin
url = 'https://www.imdb.com/chart/top'
genres = {}
with requests.Session() as s:
r = s.get(url)
soup = bs(r.content, 'lxml')
links = [(i.text, urljoin(url,i['href'])) for i in soup.select('.subnav_item_main a')]
for link in links:
r = s.get(link[1])
soup = bs(r.content, 'lxml')
genres[link[0].strip()] = [i['alt'] for i in soup.select('.loadlate', limit = 100)]
pprint.pprint(genres)
Sample output:
I need to access the following website: http://mothoq.com/store/22
scroll down till i see the phone icon.
click on it, and scrape the phone number.
I have successfully connected to the website, and able to scrape all data needed, except of the phone number.
I have tried to use
soup.find_all('p',attrs={"align":"center"})
my code is:
import requests
import pandas as pd
from bs4 import BeautifulSoup
records = []
storeId = 22
url = "http://mothoq.com/store/" + str(storeId)
r = requests.get(url)
content = r.text
soup = BeautifulSoup(content, "html5lib")
results = soup.find('div', attrs={'id': 'subtitle'})
for storeData in results:
storeName = soup.find('h1')
url = soup.find('font').text
contacts = soup.find_all('p', attrs={"class":"store_connect_details"})
for storeContact in contacts:
storePhone = soup.find_all('p', attrs={"align":"center"})
storeTwitter = soup.find('a', attrs={"class":"connect_icon_twitter"})['href']
storeFacebook = soup.find('a', attrs={"class":"connect_icon_facebook"})['href']
storeLinkedin = soup.find('a', attrs={"class":"connect_icon_linkedin"})['href']
print(storePhone)
Thanks!
You should search for hidden div with id="store-telephone-form" and take second
<p> tag from it.
import requests
import pandas as pd
from bs4 import BeautifulSoup
records = []
storeId = 22
url = "http://mothoq.com/store/" + str(storeId)
r = requests.get(url)
content = r.text
soup = BeautifulSoup(content, "lxml")
results = soup.find('div', attrs={'id': 'subtitle'})
storeName = soup.find('h1')
url = soup.find('font').text
contacts = soup.find_all('p', attrs={"class":"store_connect_details"})
try:
storePhone = soup.find('div', attrs={"id":"store-telephone-form"}).select('p')[1].text
storeTwitter = soup.find('a', attrs={"class":"connect_icon_twitter"}).get('href')
storeFacebook = soup.find('a', attrs={"class":"connect_icon_facebook"}).get('href')
storeLinkedin = soup.find('a', attrs={"class":"connect_icon_linkedin"}).get('href')
except:
pass
print(storePhone)