how to take list as a input in python in a single line.
enter image description hereI tried following thing but it didn't worked
You need to take input separated by space:
input_string = input("Enter a list element separated by space ")
lst = input_string.split()
You can also take input separated by any other character as well.
You can do so by accepting the numbers on a single line separated by spaces and then split it to get all the numbers as a list, then map it to an integer value to produce the required integer list.
numList = list(map(int, input("Enter a list of numbers separated by spaces: ").split()))
print(numList)
You can make use of eval function.
_list = eval(input("enter the list:"))
When prompted you pass the list as follow: [1, 2, 3]
Your _list variable will be a list structure containing 1, 2 and 3 as elements.
Edit: this, of course, does not guarantee that only lists will be accepted on the input, so have this in mind.
list1 = input("data with spaces: ").split(" ")
list2 = input("data with commas: ")split(",")
Related
I have written a code that should input numbers from the user and report back the numbers from 1 to 100 that are missing from their input.
My code is below which doesn't work:
num_list = []
number = input('Enter numbers (remember a space): ')
number.split()
num_list.append(number)
for i in range(1, 101):
if i in num_list:
continue
else:
print(i, end =', ')
The code outputs all the numbers from 1 to 100 but doesn't exclude the numbers.
Note: The code has to exclude all the numbers entered not only one number.
E.g. if the user inputted 1 2 3 4 the output should start from 5 and list the numbers through to 100.
There are three of problems
1) your are not saving the returned list from split method
result = number.split()
2) Use extend instead of append
num_list.extend(result)
3) By default input will read everything as string, you need to convert them into int from string after splitting, below is example using List Comprehensions
result = [int(x) for x in number.split()]
append : Will just add an item to the end of the list
So in you case after appending user input your list will be
num_list.append(number) #[[1,2,3,4,5]] so use extend
extend : Extend the list by appending all the items from the iterable.
num_list.append(number) #[1,2,3,4,5]
Note : If the num_list empty you can directly use result from split method, no need of extend
Usually, we input() a list in Python 3.X like this:
x = list(map(int, input()))
print (x)
But here let's say we give an input of 1234 then it prints:`
[1, 2, 3, 4]
Is there a way that I can print it like:
[12, 34]
Thanks in Advance!
Let's say you want the numbers to be entered separated by spaces. First get the entire line as input:
line = input()
Now parse the input. In this case, split on spaces:
words = line.split(' ')
Finally, convert each "word" to an int:
numbers = [int(i) for i in words]
Of course you can use map() instead of a list comprehension.
Note that this requires input such as
12 34
You can do this all in one line, but it is better to use variables to store each intermediate step. When you get it wrong, you can debug much more easily this way.
In my opinion, I would not complicate things :
I would declare an empty list :
l = []
Then I would simply append the input :
for i in range(0, n):
print("l[", i, "] : ")
p = int(input())
l.append(p)
You can notice here the "n",it's the size for the list,in your case it would be:
for i in range(0, 1):
print("l[", i, "] : ")
p = int(input())
l.append(p)
We always start from 0,so range(0,1) would count 0, then 1 and so on with other cases.
Hope this would help.
Hi im trying to write a program which uses a repetition statement to allow users to enter 5 numbers and stores them in a list.Then allow the user to search the list for a number entered by the user and indicate whether the number has been found or not. Im quite stuck on this one, I've made as much of an effort as i can
data =raw_input('Please input 5 numbers: ')
print data
search =raw_input('Search for the numer: ')
for sublist in data:
if sublist[1] == search:
print "Found it!", sublist
break
data is a string, the for loop will loop over every character in this string. That's probably not what you want.
If you want to find an integer in a list of integers, split the input on whitespace and convert each to an integer using int.
ints = [int(x) for x in data.split()]
if int(search) in ints:
print "Found it"
You might try something like this
numbers = []
while len(numbers) < 5:
number = raw_input('Please input 5 numbers: ')
if number.isdigit():
numbers.append(int(number)) #may want to use float here instead of int
else:
print "You entered something that isn't a number"
search = raw_input('Search for the numer: ')
if int(search) in numbers:
print "Found it!"
your code indicates that you may be using sublists but it is unclear how you are creating them.
Issue 1: This line stores the input as a string in the variable data.
data =raw_input('Please input 5 numbers: ')
At this point it is necessary to split the string into a list, and converting the elements to integers.
If the user inputs numbers separated by a space, you can do:
data_list = data.split() # if the numbers are comma-separated do .split(',') instead
int_list = [int(element) for element in data_list]
Issue 2: The users search input should be converted to an integer
search =raw_input('Search for the numer: ')
search_int = int(search)
Issue 3: There is no need for indexing the sublist as you've attempted sublist[1].
The for-loop should then be:
for sublist in int_list:
if sublist == search_int:
print "Found it!", sublist
break
I'm new to python (PYTHON 3.4.2) and I'm trying to make a program that adds and divides to find the average or the mean of a user's input, but I can't figure out how to add the numbers I receive.
When I open the program at the command prompt it accepts the numbers I input and would print it also if I use a print function, but it will not sum the numbers up.
I receive this error:
TypeError: unsupported operand type(s) for +: 'int' and 'str'
My code is below:
#Take the user's input
numbers = input("Enter your numbers followed by commas: ")
sum([numbers])
Any help would be deeply appreciated.
input takes a input as string
>>> numbers = input("Enter your numbers followed by commas: ")
Enter your numbers followed by commas: 1,2,5,8
>>> sum(map(int,numbers.split(',')))
16
you are telling user to give input saperated by comma, so you need to split the string with comma, then convert them to int then sum it
demo:
>>> numbers = input("Enter your numbers followed by commas: ")
Enter your numbers followed by commas: 1,3,5,6
>>> numbers
'1,3,5,6' # you can see its string
# you need to split it
>>> numbers = numbers.split(',')
>>> numbers
['1', '3', '5', '6']
# now you need to convert each element to integer
>>> numbers = [ x for x in map(int,numbers) ]
or
# if you are confused with map function use this:
>>> numbers = [ int(x) for x in numbers ]
>>> numbers
[1, 3, 5, 6]
#now you can use sum function
>>>sum(numbers)
15
input will give you string, and you are trying to concat string with int.
First you need to convert elements of "numbers" to int, no need to strip the comma or whitespaces. This code is pretty straight forward and works fine.
numbers = input("Enter your numbers followed by commas: ")
numbers_int = [int(x) for x in numbers]
numbers_sum = sum(numbers_int)
print numbers_sum
Try the following code. It works for me. Actually input() tries to run the input as a Python expression. But the raw_input() takes the input as string. input() exists in Python 3.x.You can find more details here
numbers = input("Enter your numbers followed by commas: ") ## takes numbers as input as expression
print sum([i for i in numbers]) ## list comprehension to convert the numbers into invisible list. This is done because `sum()` runs only on iterable and list is iterable.
Output:
Enter your numbers followed by commas: 1,2,3,4
10
Simple: the list elements are stored as string :) So you have to convert all of them to int
I have a function here and I want it to count the length of list like 1,2,3,4,5 =5
but the function only counts numbers 1234=4
how can i fix this
def mylen(alist):
if alist:
return 1 + mylen(alist[1:])
return 0
def main():
alist=input("Enter a list of number :")
print(mylen(alist))
main()
fyi i cannot use len
I'm assuming you want mylen('1234') to be = 1. Take your input and split up the numbers by the comma separator.
def mylen(alist):
if alist:
return 1 + mylen(alist[1:])
return 0
def main():
alist=input("Enter a number :")
print(mylen(alist.split(','))
main()
There is no need for the computer to do so much processing for something that is built into the language. This will work just fine:
alist=input("Enter a number :")
print(len(alist.split(','))
In Python 3:
alist=input("Enter a list of number :")
alist will now be a string. If you enter "1,2,3,4,5", a list will be the string "1,2,3,4,5", not a list of numbers [1,2,3,4,5].
A string is a sequence type, just like a list, so your code works with the string as well, and counts the number of elements (characters) in it.
You can use split to convert the input in a list:
userinput = input("Enter a list of number :")
alist = userinput.split(",")
(Note that this is still a list of strings, not numbers, but this doesn't matter for this exercise.)