Develop Reference

Tkinter toplevel window is not defined

I wonder if someone could tell me if its possible to update toplevel windows using external functions. I've replicated my issue below what I need to do is update the Toplevel(master) using the function updatelabel(). I have used similar external function to update items in root which works like a dream. However, with the top level window I always get the
NameError: name 'newWindow' is not defined
The only work around I found was to kill the newWindow using newWindow.destroy() on each load but this method makes the screen pop up and then close again which doesn't look pretty. Any help most welcome thanks.
from tkinter import *
from tkinter.ttk import *
master = Tk()
master.geometry("200x200")
def updatelabel():
Label(newWindow,
text="I changed").pack()
def openNewWindow():
# Toplevel object which will
# be treated as a new window
newWindow = Toplevel(master)
# sets the title of the
# Toplevel widget
newWindow.title("New Window")
# sets the geometry of toplevel
newWindow.geometry("200x200")
# A Label widget to show in toplevel
Label(newWindow,
text="I want to change").pack()
button1 = Button(newWindow,
text="Click me to change label", command=updatelabel).pack()
btn = Button(master,
text="open a new window",
command=openNewWindow)
btn.pack(pady=10)
mainloop()

Your “newWindow” is defined in your “openNewWindow” function and so it basically only exists in there, you could probably fix this by either defining “newWindow” outside of the function, or by using it as an argument(just add it to the brackets and give it a name in the function itself’s brackets) calling “updateLabel”
I think this should work, though I haven’t worked with tkinter in a bit so don’t blame me if it doesn’t
from tkinter import *
from tkinter.ttk import *
master = Tk()
master.geometry("200x200")
def updatelabel(newWindow):
Label(newWindow,
text="I changed").pack()
def openNewWindow():
# Toplevel object which will
# be treated as a new window
newWindow = Toplevel(master)
# sets the title of the
# Toplevel widget
newWindow.title("New Window")
# sets the geometry of toplevel
newWindow.geometry("200x200")
# A Label widget to show in toplevel
Label(newWindow,
text="I want to change").pack()
button1 = Button(newWindow,
text="Click me to change label", command= lambda: updatelabel(newWindow)).pack()
btn = Button(master,
text="open a new window",
command=openNewWindow)
btn.pack(pady=10)
mainloop()

How to make tkinter right click menu work on one widget only?

Is there a simple way to get the right click menu to open on texty only and not the whole window?
This was a quick mashup to illustrate my question. Inheriting from texty on line 25 was a shot in the dark, which didnt work, but it's close to a simple solution, like I am seeking. I was hoping to avoid programming a whole class each time I want to set a right click menu.
from tkinter import *
from tkinter import ttk
def menu_popup(event):
try:
popup.tk_popup(event.x_root, event.y_root, 0)
finally:
popup.grab_release()
win = Tk()
win.geometry("600x550+125+125")
e = Entry(win, width=50, font=('Helvetica', 11))
e.pack()
e.insert(0, "Some text....")
label = Label(win, text="Right-click to see a menu", font= ('Helvetica 18'))
label.pack(pady= 40)
texty=Text(win, height=10)
texty.pack()
popup = Menu(texty, tearoff=0)
popup.add_command(label="New")
popup.add_separator()
popup.add_command(label="Open")
popup.add_separator()
popup.add_command(label="Close")
win.bind("<Button-3>", menu_popup)
button = ttk.Button(win, text="Quit", command=win.destroy)
button.pack()
mainloop()

The widget on which the callback should be executed for the respective event is determined by the widget you call bind on(and the level of bind too*). So if you want the event to be identified within texty, then apply binding to it.
texty.bind("<Button-3>", menu_popup)
* There is bind_all which executes no matter which widget has focus or is called upon. Read 54.1. Levels of binding for more info.

How to start a second tkinter program from another and then close first?

I'm creating a tkinter gui that I would like to run. This app will do some house cleaning of sorts. It would check files, check for updates, give the user some information etc. Then I would like it to start another tkinter application and then close it self.
import tkinter as tk
import os
def StartProgram():
os.startfile("C:/WINDOWS/system32/notepad.exe")
root = tk.Tk()
frame = tk.Frame(root)
frame.pack()
button = tk.Button(frame, text="QUIT", fg="red", command= lambda: quit())
button.pack( side=tk.LEFT)
button2 = tk.Button(frame,text="Start my exe", command=lambda: StartProgram())
button2.pack(side=tk.LEFT)
root.maxsize(200,200)
root.minsize(200,200)
root.mainloop()
The problem I have so far is when I attempt to close the original app it closes the one it started as well.
EDIT: I also tried root.destroy(), root.quit()
Any suggestion how I might correct this?

Placing Tkinter Frame in another Frame

I am trying to experiment and get the button to only display the label when the button is clicked instead it is opening up another GUI window. The main frame is called secret message. Within this when i click onto the button it should then replace the empty place with the label in row=2.
Could someone explain to me how i can raise the label rather than just opening up a new window. All code is functional but i want another way around this, i am new to python.
from tkinter import *
def topLevel():
top=Toplevel()
top.geometry("300x200")
root=Tk()
root.title("Secret Message")
button1 = Button(text="Push this button to see hidden message!", width =60, command=topLevel)
button1.grid(row=1, column=0)
label1 = Label(width=50, height=10, background="WHITE", text= "There is no secret!")
label1.grid(row=2, column=0)
root.mainloop()

You question title has nothing to do with your question.
To update the geometry of your label you simple need to tell the function where you want the label on the container you set up your label in. In this case you do not define the container so the widgets default to the root window.
Here is a working example that will update the label geometry when you press the button.
from tkinter import *
root=Tk()
root.title("Secret Message")
def grid_label():
label1.config(text="There is no secret!")
Button(root, text="Push this button to see hidden message!", width=60, command=grid_label).grid(row=1, column=0)
label1 = Label(root, width=50, height=10, background="WHITE")
label1.grid(row=2, column=0)
root.mainloop()

How to close other window by python Tkinter?

I have following python code in Tkinter.
import tkinter as tk
def main_gui(login, s):
login.quit() # close login window
win = tk.Tk()
win.geometry('300x150')
name = tk.Label(win, text='Hello' + s.get()) # Hello David
name.pack()
win.mainloop()
# initial Tkinter frame
login = tk.Tk()
login.title('Login')
login.geometry('300x150')
# input user name
user_name_var = tk.StringVar()
user_name_var.set('David')
tk.Label(login, text='User name').place(x=10, y=50)
user_name = tk.Entry(login, textvariable=user_name_var)
user_name.place(x=100, y=50)
input_ok = tk.Button(win_login, command=lambda: main_gui(login, user_name), text='OK', width=15)
input_ok.place(x=100, y=90)
win_login.mainloop()
I want to close login window, but my code can not close it. How to solve it.

You are almost there - only two details you have to adapt:
The method to remove a widget in Tkinter is destroy, so login.quit() should be login.destroy().
Once login is destroyed, the user_name Entry will also be destroyed, and you will not be able to get the name from it anymore. You should get the name earlier, e.g., directly in the lambda:
... lambda: main_gui(login, user_name.get()), ...

you can use the
root.withdraw()
function, this will close the window without completely destroying all of the root.after functions