Develop Reference

Export quiz result to a text file in Python

Is it possible to have questions and answers exported to a text file such as result.txt?
I answer all the questions and at the end - all the information is saved in a txt file as a list, that can be viewed later.
Example:
Question 1
Answer 1
Question 2
Answer 2
...
I was wondering about file=open, but would that be right?
And how do I export input questions with file open?
I hope you can help.
from datetime import date
today = date.today()
date = today.strftime("%d.may, %Y.year\n")
print("Today is:", date)
print("Greeting text 1")
print("Greeting text 2\n")
def Vide():
while True:
name = input("Let's see!\nWhat is your name? ")
description = input("Enter a description of the environmental pollution: ")
city = input("In which city is environmental pollution observed? ")
address = input("Enter your residential address: ")
try:
question = int(input("Do you have any additional complaints?\nAnswer with: 1 = Yes, 2 = No\n" ))
except ValueError:
print("Answer with numbers - 1 or 2!")
continue
if question == 1:
print("\nJYou noted that there are additional complaints, fill in the questions again!\n")
continue
elif question == 2:
print("Thank you for your complaint, it will be resolved! 💜")
break
else:
print("Only numbers 1 and 2 are allowed!")
Vide()

As you wanted the file content as a key-value pair, initialize a dictionary and add the corresponding values, instead of using separate variables for names, descriptions, etc. use them as dictionary keys.
First, initialize a global dictionary
global mydict
Initialize it in Vide() function. (use of global keyword because mydict is being modified in a function)
global mydict
mydict = {}
Store question and answer as a key-value pair
mydict["name"] = input("Let's see!\nWhat is your name? ")
mydict["description"] = input("Enter a description of the environmental pollution: ")
mydict["city"] = input("In which city is environmental pollution observed? ")
mydict["address"] = input("Enter your residential address: ")
In try block:
mydict["question"] = int(input("Do you have any additional complaints?\nAnswer with: 1 = Yes, 2 = No\n"))
Now the if-else statements:
if mydict["question"] == 1:
print("\nJYou noted that there are additional complaints, fill in the questions again!\n")
continue
elif mydict["question"] == 2:
print("Thank you for your complaint, it will be resolved! 💜")
break
else:
print("Only numbers 1 and 2 are allowed!")
After calling the function Vide(), write your dictionary to a file
with open("qna.txt", "w") as f:
f.write(str(mydict))
f.close()
Whole code
global mydict
print("Greeting text 1")
print("Greeting text 2\n")
def Vide():
global mydict
mydict = {}
while True:
mydict["name"] = input("Let's see!\nWhat is your name? ")
mydict["description"] = input("Enter a description of the environmental pollution: ")
mydict["city"] = input("In which city is environmental pollution observed? ")
mydict["address"] = input("Enter your residential address: ")
try:
mydict["question"] = int(input("Do you have any additional complaints?\nAnswer with: 1 = Yes, 2 = No\n"))
except ValueError:
print("Answer with numbers - 1 or 2!")
continue
if mydict["question"] == 1:
print("\nJYou noted that there are additional complaints, fill in the questions again!\n")
continue
elif mydict["question"] == 2:
print("Thank you for your complaint, it will be resolved! 💜")
break
else:
print("Only numbers 1 and 2 are allowed!")
Vide()
with open("qna.txt", "w") as f:
f.write(str(mydict))
f.close()

This can be done by writing or appending to a text file. You are correct, we can use the file = open structure to achieve this. I suggest writing something like the following:
file = open('results.txt', 'w')
Then use the following to write to the file once it has been opened.
file.write("Use your variables and questions from before to print user entered data")
Don't forget to close the file once you're done!
file.close()

I'm Having Trouble checking two values are equal in python

finishgame = "n"
counter = 0
#the song randomizer
num = random.randint(0,50)
f = open("songs.txt","r")
lines = f.readlines()
#first letter only system
song = str(lines[num])
firstl = song[0]
print(firstl)
#the artist generator
g = open("artists.txt","r")
line = g.readlines()
print(line[num])
#guess system
while finishgame == "n":
guess = str(input("Enter your guess"))
if guess == song:
counter = counter+5
print("Correct!")
finishgame = "y"
elif counter == 2:
print("Out of guesses, sorry :(")
print("The Correct Answer was:",song)
finishgame = "y"
else:
counter = counter+1
print("Try Again")
First time asking so apologizes for any errors. I have create a song guessing game where it takes a song from an external file, and displays the first letter of the title. It then takes the artist from a separate file (where it is in the same line as the song in the other file) and displays that too. Then you should guess the song. However, my code is having trouble recognizing when a 'guess' is correct, please can anyone tell me why? I've tried using different methods of identification such as the id() function but so far have not got any results. I'm probably missing something simple but any help would be much appreciated.

I get very strange error while im trying to finish my project

This code is meant to pick an artist from internal file (text file), read it and pick randomly from the internal file the artist (that are in the text file in array style, e.g., "carrot apple banana"), therefore I added .txt to the chosen artist so the program will open artist's file with songs and pick a random song.
import random
loop = False
counter = 0
points = 0
max_level = 10
while loop == False:
for lines in open("pick.txt").readlines():
art = lines.split()
artist = random.choice(art)
for i in open((artist) + ".txt"):
song = i.split()
song_name = random.choice(song)
print("the song begins with :" , song_name , "this song is by :" , artist)
answer = input("Enter full name of the song : ")
if answer == song_name:
points = points +3
print("correct")
counter = counter +1
print(counter)
elif answer != song_name:
print("WRONG !!! \n try again")
dec = input("Please enter the full name of the song :")
if dec == song_name:
points = points +2
print("correct")
counter = counter +1
print(counter)
elif dec != song_name:
print("smh \n WRONG")
counter = counter +1
print(counter)
elif counter >= max_level:
print("The End")
quit()
else:
print("error")
input()
Afterwards when I run the code in python shell, there is a random chance that I get this error, either straight away or later on:
raise IndexError('Cannot choose from an empty sequence') from None
IndexError: Cannot choose from an empty sequence

That error is from the random module by the looks of it. This is probably when you’re reading the file and there is a line that is blank.
A cause is usually the last line of the file which is often a blank newline/EOF.
Just add a check when reading your file(s):
for line in open(artist + '.txt', 'r'):
if line.strip():
song = line.strip().split()
song_name = random.choice(song)
An empty line will have a ‘truthiness’ value of 0 or False so a line with content returnsTrue.

Your error probably arises from an empty line in one of your text-files.
I was able to duplicate your error with your exact code and the following text-files:
pick.txt with only the word adele,
and adele.txt with hello-from-the-other-side and two new lines.
You can test this in prelude:
>>> for i in open("adele.txt"):
... song = i.split()
...
>>> song
[]
On another note, you seem to be iterating throughout the lines in a textfile before you do anything with the data in the lines. That can't possibly make sense. I would advice you to add things in a list as you go, and then select from this list instead.

Quiz from external text file Python

I am trying to create a quiz where I have questions and answers from an external text file to import into Python so that the user can input a selection.
The problem is that my code only prints "Correct" at the end of the quiz once, and doesn't say after each question answered if the user got the question correct or incorrect.
The first column (detail[0]) is where the question is and the correct answer is in the fourth column (detail[4]))
Thanks
Here is what is in the text file:
What is 1+1,1,2,2
What is 2+2,4,2,4
Here is the source code below:
def quiz():
file = open("quiz.txt","r")
right = False
for line in file:
detail = line.split(",")
print(detail[0])
select = input("Select 1 or 2: ")
if select == detail[3]:
right = True
break
if right == True:
print("Correct")
else:
print("Incorrect")

Just modify the main for-loop to print the result there and then:
for line in file:
detail = line.split(",")
print(detail[0])
select = input("Select 1 or 2: ")
if select == detail[3]:
print("correct!")
else:
print("incorrect :(")

Python - Word Scramble Game

While this assignment is past due (I joined the class late unfortunately) I still need to figure it out. I have the following list of words:
abhor:hate
bigot:narrow-minded, prejudiced person
counterfeit:fake; false
enfranchise:give voting rights
hamper:hinder; obstruct
kindle:to start a fire
noxious:harmful; poisonous; lethal
placid:calm; peaceful
remuneration:payment for work done
talisman:lucky charm
abrasive:rough; coarse; harsh
bilk:cheat; defraud
I need to read this file into a dictionary, pick a random key, scramble it, then ask the user to solve it. Unlike other solutions on here, it does not iterate three times, but runs until the user enters 'n'. The code will ask the user after each round if the user wants to continue the game. The user can also type 'hint' to get the definition of the word.
There is a similar question here: (http://www.dreamincode.net/forums/topic/302146-python-school-project-write-a-word-scramble-game-status-complete/) or rather the result of a question, but I am not knowledgeable enough to bridge the gaps and make it work for my purposes. None of the variation on this that I have seen on stack overflow come close enough for me to bridge the gap either, likely because I just don't know enough yet. Before we even start, this code does not yet work at all really, I am pretty lost at this point, so please be gentle. My code so far is below:
import random
from random import shuffle
#Reads the words.txt file into a dictionary with keys and definitions
myfile = open("words.txt", "r")
wordDict = dict([(line[:line.index(":")], line[line.index(":") +1 : -1])
for line in myfile.readlines()])
#print (b)
def intro():
print('Welcome to the scramble game\n')
print('I will show you a scrambled word, and you will have to guess the word\n')
print('If you need a hint, type "Hint"\n')
#Picks a random key from the dictionary b
def shuffle_word():
wordKey = random.choice(list(wordDict.keys()))
return wordKey
#Gives a hint to the user
def giveHint(wordKey):
hint = wordDict[wordKey]
return hint
#Below - Retrieves answer from user, rejects it if the answer is not alpha
def getAnswer():
answer = input('\nEnter your first guess: ')
while True:
if answer.isalpha():
return answer
else:
answer = input('\nPlease enter a letter: ')
def keepPlaying():
iContinue = input("\nWould you like to continue? ")
return iContinue
def scramble():
theList = list(shuffle_word())
random.shuffle(theList)
return(''.join(theList))
#Main Program
if keepPlaying() == 'y':
intro()
shuffle_word()
randomW = shuffle_word()
#scramKey = list(randomW)
thisWord = scramble()
print ("\nThe scrambled word is " +thisWord)
solution = getAnswer()
if solution == thisWord:
print("\nCongratulations")
if solution == 'Hint' or solution == 'hint':
myHint = giveHint(wordKey)
print(myHint)
else:
print("\nThanks for playing")
I have edited this post to ask for new information, though I am not sure if that ishow its properly done. Thanks to the help of those below, I have made progress, but am stuck not on a specific piece.
I have two questions. 1: How can I get the giveHint() function to return the definition of the random key selected by the shuffle_wprd() function. I know what I have above will not work because it is simply returning a string, but it seems like just using a dict.get() function would not get the correct definition for the random word chosen.
2: How can I get the program not to ask the user to continue on the first pass, but to then ask from then on. I thought about using a while loop and redefining the variable during the iteration, but I don't know enough to get it to work properly.
regardless, thank you to those people who have already helped me.

This should help you out a bit, the length seems to be of no benefit as a hint as you can see the length of the scrambled word so I used the definition as the hint,I think you also want to ask the user to guess the word not individual letters:
from random import shuffle, choice
#Reads the words.txt file into a dictionary with keys and definitions
with open("words.txt") as f:
word_dict = {}
for line in f:
# split into two parts, word and description
word, hint = line.split(":")
word_dict[word] = hint
def intro():
print('Welcome to the scramble game\n')
print('I will show you a scrambled word, and you will have to guess the word\n')
#Picks a random key from the dictionary b
def pick_word():
word = choice(list(word_dict.keys()))
return word
#Gives a hint to the user
def give_hint(word):
# return the definition of the word
descrip = word_dict[word]
return descrip
#Below - Retrieves answer from user, rejects it if the answer is not alpha
def get_answer():
while True:
answer = input('Please enter a guess: ')
if answer.isalpha():
return answer
else:
print("Only letters in the word")
def main():
intro()
word = pick_word()
# give user lives/tries
tries = 3
shffled_word = list(word)
# shuffle the word
shuffle(shffled_word)
# rejoin shuffled word
shffled_word = "".join(shffled_word)
# keep going for three tries as most
while tries > 0:
inp = input("Your scrambled word is {}\nEnter h if you want to see your hint or any key to continue".format(shffled_word))
if inp == "h":
print("The word definition is {}".format(give_hint(word)))
ans = get_answer()
if ans == word:
print("Congratulations you win!")
break
tries -= 1
# ask user if they want to play again, restarting main if they do
play_again = input("Press 'y' to play again or any key to exit")
if play_again == "y":
main()
# else the user did not press y so say goodbye
print("Goodbye")
main()
There are a few more bits to be added but I will leave that up to you.

Thank you to all those who helped. For any who come along later, the final product is here. Similar to what Padraic Cunningham put, but without the three answer limit, and without his more elegant solution of wrapping the main program into a called function.
import random
from random import shuffle, choice
#Reads the words.txt file into a dictionary with keys and definitions
with open("words.txt") as f:
wordDict = {}
for line in f:
# split into two parts, word and description
word, hint = line.split(":")
wordDict[word] = hint
#print (b)
def intro():
print('Welcome to the scramble game\n')
print('I will show you a scrambled word, and you will have to guess the word\n')
print('If you need a hint, type "Hint"\n')
#Picks a random key from the dictionary b
def shuffle_word():
wordKey = choice(list(wordDict.keys()))
return wordKey
#Gives a hint to the user
def giveHint(wordKey):
descrip = wordDict[word]
return descrip
#Below - Retrieves answer from user, rejects it if the answer is not alpha
def getAnswer():
answer = input('\nEnter a guess: ')
while True:
if answer.isalpha():
return answer
else:
answer = input('\nPlease enter a letter: ')
def getAnswer2():
answer2 = input('\nEnter another guess: ')
while True:
if answer2.isalpha():
return answer2
else:
answer2 = input('\nPlease enter a letter: ')
def keepPlaying():
iContinue = input("\nWould you like to continue? ")
return iContinue
#def scramble():
# theList = list(shuffle_word())
# random.shuffle(theList)
# return(''.join(theList))
#Main Program
while keepPlaying() == 'y':
intro()
#shuffle_word()
randomW = shuffle_word()
cheatCode = giveHint(randomW)
#scramKey = list(randomW)
thisWord = list(randomW)
print(thisWord)
random.shuffle(thisWord)
print(thisWord)
thisRWord = ''.join(thisWord)
print ("\nThe scrambled word is " +thisRWord)
solution = getAnswer()
loopMe = False
while loopMe == False:
if solution == randomW:
print("\nCongratulations")
loopMe = True
if solution == 'Hint' or solution == 'hint':
print(cheatCode)
if solution != randomW:
loopMe = False
solution = getAnswer2()