How to draw a player sprite on the screen [duplicate] - python

This question already has answers here:
How to draw images and sprites in pygame?
(4 answers)
Closed 7 days ago.
The code sample below does not work as intended.
import pygame as pg
import time as t
import math as m
import random as r
import os # this efficiently imports the necessary modules
pg.init()
screen = pg.display.set_mode((500, 500))
pg.display.set_caption("bullet hell")
clock = pg.time.Clock()
clock.tick(60)
player = pg.image.load("player.png")
def loopkill():
if event.type == pg.QUIT:
running = False
def loop(): # this is the mainloop for pygame
running = True
while running:
for event in pg.event.get():
t.sleep(100)
if event.type == pg.QUIT:
running = False
if event.type == pg.KEYDOWN:
print("ready")
pg.surface.blit(player, (250, 250))
g.draw(screen)
g.update()
pg.display.flip()
# Quit Pygame
pg.quit()
loop()
Expected a player sprite, however got a blank screen instead.

I'm suspicious of the t.sleep(100) that would make your program stop for 100 seconds every time there is an event. Also, the functions which draw the screen are within the event loop, so they are only called when there are events.

Related

Keep getting an error about pygame not being initialised

I keep getting an error about system not being initialised. The error is about the pygame.display.update()
Where is this meant to go?
import pygame #IMPORTS THE PYGAME CLASSES, METHODS AND ATTRIBUTES
from pygame.locals import * #IMPORTING ALL PYGAME MODULES
pygame.init() #INITIALISING PYGAME
WIDTH, HEIGHT = 1000, 600
WINDOW = pygame.display.set_mode((WIDTH,HEIGHT))
pygame.display.set_caption("On The Run")
blue = 146,244,255 #BACKGROUND COLOUR
width = 80
height = 60
x = 200 #X-POSITION OF THE CHARACTER
y = 100 #Y-POSITION OF THE CHARACTER
player1 = pygame.image.load('assets/characterMove3.jpg') #DISPLAYING THE IMAGE ONTO THE SCREEN
player1 = pygame.transform.scale(player1,(width,height)) #SCALING THE IMAGE TO SUITABLE DIMENSIONS
WINDOW.blit(player1,(x,y))
def game_loop(): #WHERE THE WINDOW IS CREATED
run = True
while run:
WINDOW.fill(blue)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False #WE WILL QUIT THE GAME AS THE VARIABLE run IS NOW FALSE
pygame.quit() #IT WON'T SHOW THE MOST RECENT THING I DREW UNLESS I MANUALLY UPDATE IT
pygame.display.update()
game_loop()
The problem is that pygame.quit() is called in the application loop. pygame.quit() deinitializes all Pygame modules and crashes all subsequent Pygame API calls. pygame.quit() must be the very last Pygame API call. Call pygame.quit() after the application loop:
def game_loop(): #WHERE THE WINDOW IS CREATED
run = True
while run:
WINDOW.fill(blue)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
#pygame.quit() <-- DELETE
pygame.display.update()
pygame.quit() # <-- INSERT
game_loop()

Doing something after a period of time: Pygame

I wanted to do something after a period of time. On stack overflow I found a question that helps solve that, (Link) but when I run the program the code works, however it goes away after a millisecond. Whereas I want it to stay there after the amount of time I want it to wait. In this case for a test run I am blitting some text onto the screen. Here is the code:
import pygame
# Importing the modules module.
pygame.init()
# Initializes Pygame
SCREEN_WIDTH = 800
SCREEN_HEIGHT = 600
screen = pygame.display.set_mode((800, 600))
# Sets the screen to pygame looks and not normal python looks.
pygame.display.set_caption("Test Run")
# Changes the title
# Heading
headingfont = pygame.font.Font('Bouncy-PERSONAL_USE_ONLY.otf', 45)
headingX = 230
headingY = 10
class Other():
def show_heading():
Heading = headingfont.render("Health Run!", True, (255, 255, 255))
screen.blit(Heading, (headingX, headingY))
pygame.time.set_timer(pygame.USEREVENT, 100)
running = True
while running:
screen.fill((0,0,0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.USEREVENT:
Other.show_heading()
#Update Display
pygame.display.update()
If you want to draw the text permanently, you need to draw it in the application loop. Set a Boolean variable "draw_text" when the timer event occurs. Draw the text depending on draw_text in the application loop:
draw_text = False
running = True
while running:
screen.fill((0,0,0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.USEREVENT:
draw_text = True
if draw_text:
Other.show_heading()
#Update Display
pygame.display.update()
For more information about timers and timer events, see Spawning multiple instances of the same object concurrently in python, How can I show explosion image when collision happens? or Adding a particle effect to my clicker game and many more.

How do i use Xbox 360 controller with pygame?

This code goes into infinite loop. I cant use A button on xbox 360 controller
import pygame
from pygame import joystick
pygame.init()
joystick = pygame.joystick.Joystick(0)
pygame.joystick.init()
print("start")
while True:
if joystick.get_button(0) == 1 :
print("stoped")
break
I cant use A button on xbox 360 controller
Personnaly, I can, so this seems to be possible. You are just missing that pretty much every user input needs to be updated by pygame through pygame.event.get().
From the pygame documentation:
Once the device is initialized the pygame event queue will start receiving events about its input.
So, apparently you need to get the events in the while loop like such to make the joystick work:
import pygame
from pygame.locals import *
pygame.init()
joystick = pygame.joystick.Joystick(0)
while True:
for event in pygame.event.get(): # get the events (update the joystick)
if event.type == QUIT: # allow to click on the X button to close the window
pygame.quit()
exit()
if joystick.get_button(0):
print("stopped")
break
Also,
In the line if joystick.get_button(0) == 1, you don't need to type == 1 because the statement is already True.
You are initializing pygame.joystick twice: through the line pygame.init() and pygame.joystick.init().
You don't need to type from pygame import joystick because you already already have it in the line import pygame.
You can take this as reference and use it in your own way.
import pygame
import sys
pygame.init()
pygame.joystick.init()
clock = pygame.time.Clock()
WIDTH,HEIGHT = 500,500
WHITE = (255,255,255)
BLUE = (0,0,255)
BLUISH = (75,75,255)
YELLOW =(255,255,0)
screen = pygame.display.set_mode((WIDTH,HEIGHT))
smile = pygame.image.load("smile.jpg")
smile = pygame.transform.scale(smile,(WIDTH,HEIGHT))
idle = pygame.image.load("idle.jpg")
idle = pygame.transform.scale(idle,(WIDTH,HEIGHT))
joysticks = [pygame.joystick.Joystick(x) for x in range(pygame.joystick.get_count())]
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
sys.exit()
elif event.type == pygame.JOYBUTTONDOWN:
if event.button == 0: #press A button to smile
screen.fill(WHITE)
screen.blit(smile,(0,0))
pygame.display.update()
clock.tick(10)
elif event.type == pygame.JOYBUTTONUP:
if event.button == 0:
screen.fill(WHITE)
screen.blit(idle,(0,0))
pygame.display.update()
clock.tick(10)

Pygame used in VS Code with Pygame Snippets [duplicate]

This question already has answers here:
How to get keyboard input in pygame?
(11 answers)
What all things happens inside pygame when I press a key? When to use pygame.event==KEYDOWN
(1 answer)
Closed 2 years ago.
I have installed vs code and added pygame snippets to use pygame library. My big problem is, every time I try to use any key option of pygame, like pygame.KEYDOWN or pygame.QUIT it tells me that QUIT is not a function of pygame. Can someone help me?
Everything else seems to work, like display or surface
even pygame.key.get_pressed() don’t make problems.
import pygame, random, sys
from pygame.locals import *
from pygame.key import *
def set_Background():
screen = pygame.display.set_mode((500,500))
surface = pygame.image.load('Background.png')
surface = pygame.transform.scale(surface, (500, 500))
screen.blit(surface, (0,0))
pygame.display.update()
return screen
def set_Enemy():
enemy = pygame.image.load('Enemy.png')
enemy = pygame.transform.scale(enemy, (50, 50))
return enemy
def set_Player():
player = pygame.image.load('Player.png')
player = pygame.transform.scale(player, (70, 70))
return player
RUNNING = True
while RUNNING:
background = set_Background()
enemy = set_Enemy()
player = set_Player()
enemy_rect = enemy.get_rect()
player_rect = player.get_rect()
e_x = random.randint(10,450)
e_y = random.randint(10,450)
background.blit(enemy, (e_x, e_y))
pygame.display.update()
for event in pygame.event.get():
key = pygame.key.get_pressed()
if event.type == key[pygame.K_ESCAPE]:
#module pygame has no K_ESCAPE member
sys.exit()
if event.type == pygame.QUIT:
#says module pygame has no QUIT member
sys.exit()
pygame.key.get_pressed() shouldn't be in the event loop, but in the main while loop. In the event loop you need to check if the event type is pygame.QUIT and then set the running flag to False.
Here's a fixed version:
import pygame
pygame.init()
screen = pygame.display.set_mode((500,500))
clock = pygame.time.Clock()
running = True # Uppercase names are for constants not variables.
while running:
# The event loop.
for event in pygame.event.get():
# If a pygame.QUIT event is in the queue.
if event.type == pygame.QUIT:
running = False
# To check if it was a `KEYDOWN` event.
elif event.type == pygame.KEYDOWN:
# If the escape key was pressed.
if event.key == pygame.K_ESCAPE:
running = False
# Use pygame.key.get_pressed to see if a key is held down.
# This should not be in the event loop.
key = pygame.key.get_pressed()
if key[pygame.K_UP]:
print('up arrow pressed')
screen.fill((30, 30, 30))
pygame.display.flip()
clock.tick(60)
Add from pygame.locals import * at the top of your code.
You are mixing two types of key presses in one go. You should instead either
for event in pygame.event.get():
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_SOMEKEY:
do_something()
or
keys = pygame.key.get_pressed()
if keys[pygame.K_somekey]:
do_something()
so the code above with the pygame.key.get_pressed() should not be in the event loop

clearing the screen with a key press in pygame [duplicate]

This question already has answers here:
Why is my PyGame application not running at all?
(2 answers)
Pygame level/menu states
(2 answers)
Closed 2 years ago.
this code is supposed to go to a different function which clears the screen when you hit z, and it does do that, but whenever I let go of z it switches back to the title function and redraws everything.
I'm trying to use it as a "hit this key to go to a new window" type thing and the screenfill is just a fill-in for now, so you can see why that's a problem. for the record I'm using python 3.6.
I've also already tried putting global start in the top of the title function, but then the z key does nothing. please and thanks!
import pygame
from pygame.locals import *
import random
pygame.init()
LOGO = pygame.image.load("kelogo.png")
savannah = pygame.image.load("savannah.png")
hitkey = pygame.image.load("hitkey.png")
display_width = 800
display_height = 600
white = (255, 255, 255)
game_display = pygame.display.set_mode((display_width, display_height))
start = False
def main_game():
while start:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
game_display.fill(white)
pygame.display.update()
def title():
intro = False
while not intro:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
game_display.blit(savannah, ((0),(0)))
game_display.blit(LOGO, ((0),(100)))
game_display.blit(hitkey, ((130),(100)))
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_z:
start = True
main_game()
pygame.display.update()
title()
main_game()
pygame.quit()
quit()

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