I have integrated the chatgpt into my mobile application. Problem I am facing chatgpt api give response like a paragraph.
In my application how I can structure the paragraph you can say how I can set the format like chatgot does in their own website.
I attached the picture. How I can structure this paragraph?
I did no find the answer yet
Related
I've been dealing with this issue for weeks. Does anyone know how to create column tags in Data Catalog from DLP results? I wanted to run inspection job on DLP and then tag the inspected tables with the infoTypes that I've inspected. I only found Java codes regarding this problem but I appreciate if anyone can help me with Python.
I was unable to find a sample Python code that would implement column level tags. This Tag() function from the Python Client Library could be useful. The complete Data Catalog Python Client Library documentation can be found here.
Feature Request
However, you can let Google know that this is a feature that is important for access through their client libraries, and that you would like to request they provide a sample code for it.
Google's Issue Tracker is a place for developers to report issues and make feature requests for their development services. I'd suggest you make a feature request there. The best component to file this under would be the Big Data, with the Feature Request template.
Some website uses google sign in, I am not able to parse such website. Help me with your valuable suggestion.
I am using python library utillib2, BeautifulSoup.
If some uses google sing in to login Quora, than I want to parse his details like what question he put up on the site and what is the response on the question.
You've gotta be specific, post code links anything that can explain your question.
We're not mind readers, so please when you post a question make your request detailed.
I am trying to access a 3rd party ticketing site via API through a web scraper.
I know this is vague but I am new to python and I am not exactly sure how to figure out my error below:
My code breaks on this line:
roken_response =r.json
I get this error
Can anyone tell why exactly my code is breaking?
Using the requests library (which you seem to be using), .json is a convenience method that decodes the response as JSON. If your response was not JSON, then you will get a JSONDecodeError, as you show in your screenshot.
So the webserver probably answered your request with some HTML or something instead of JSON.
Also it sounds like you are violating the ToS of that poor ticketing site :(
My question may look silly but I am asking this after too much search on Google, yet not have any clue.
I am using iCloud web services. For that I have converted this Python code to PHP. https://github.com/picklepete/pyicloud
Up to this, everything is working good. When authenticate using icloud username,password I am getting a list of web service URLs as part of response. Now for example to use Contacts web service, I need to use Contact web service URL and add a part to that URL to fetch contacts.
https://p45-contactsws.icloud.com:443/co/startup with some parameters.
The webservice URL https://p45-contactsws.icloud.com:443 is coming in response while authenticating. But the later part, 'co/startup' is there in the python code. I don't know how they found that part. So for some services which is there in Python code, they are working good. But I want to use few other service like https://p45-settingsws.icloud.com:443, https://p45-keyvalueservice.icloud.com:443 etc. and when I try to send request with correct parameters to this other services, I am getting errors like 404 not found or unauthorized access. So I believe that some URL part must be added to this just like contacts. If someone knows how or where can I get correct URL part, I will be really thankful.
Thanks to all in advance for their time reading/answering my question.
I am afraid there doesn't seem to be an official source for these API endpoints, since they seem to be discovered through sniffing the network calls rather than a proper guide from Apple. For example, this presentation, which comes from a forensic tools company, is from 2013 and covers some of the relevant endpoints. Note that iOS was still at versions 5 & 6 then (vs. the current v9.3).
All other code samples on the net basically are using the same set of API endpoints that were originally observed in 2012-2013. (Here's a snippet from another python module with additional URLs you may use.) However, all of them pretty much point to each other as the source.
If you'd like to pursue a different path, Apple now promotes the CloudKit and CloudKit JS solutions for registered apps working with iCloud data.
Using the examples Google provides there they often encode the html responses by using:
self.response.write( "<html><p>Some stuff!</p></html>" )
This is a terrible way to hardcode html and in cases where I want to send back a nice looking page or a prefab, nicely designed response page it seems there ought to be a way to redirect the user directly to an actual nice_response.html.
I can't seem to find any example or docs on how to do this. Am I approaching it wrong or is there a simple way to direct a request to a real HTML page without hardcoding the response html?
Thanks
What you need is templating. Take a look at this page https://cloud.google.com/appengine/docs/python/gettingstartedpython27/templates?hl=fr