Pyside6 - How to call parent method in child method class - python

I want to call a father method inside a child class method but I'm having some trouble and missing some points.
I'm able to call parent's method just inside def__init__(self)
How to solve?
I tried:
class MainWindow(QMainWindow):
ws = websocket.WebSocket()
threadpool = QThreadPool()
pippo = "pippo"
def __init__(self):
super().__init__()
tabs = QTabWidget()
tabs.setTabPosition(QTabWidget.North)
tabs.setMovable(False)
tabs.setDocumentMode(True)
self.voices = Widget("Voices", self)
tabs.addTab(self.voices, "Voices")
self.setCentralWidget(tabs)
def do_something(self):
print ('doing something!')
class Widget(QWidget):
def __init__(self, name, parent=None):
super().__init__(parent)
self.ui = Ui_Widget()
self.ui.setupUi(self)
self.name=name
self.lan = str(config_ini("language"))
self.username = str(config_ini("user"))
print(self.parent().pippo) #HERE MY CODE WORKS
self.parent().do_something() #HERE MY CODE WORKS
self.ui.InitializeButton.clicked.connect(self.clickedInitialize)
#Pressione tasto Initialize
def clickedInitialize(self):
self.parent().do_something() #HERE MY CODE ___DON'T___ WORKS
and I receive this error:
Traceback (most recent call last):
File "C:\Users\IENOGIUS\Documents\Cefla\VoiceCommands\VoiceChecker\voicechecker.py", line 294, in clickedInitialize
self.parent().do_something()
AttributeError: 'PySide6.QtWidgets.QStackedWidget' object has no attribute 'do_something'

As the addTab() documentation explains:
Ownership of page is passed on to the QTabWidget.
This would be true anyway whenever you add a widget to another, making it a child of that new parent.
In this case, it happens when tabs.addTab(self.voices, "Voices"), which reparents the widget to the tab widget (actually, its internal QStackedWidget): the window becomes the ancestor of the Widget instance, the actual parent is the stacked widget.
The structure will be the following:
MainWindow
QTabWidget
QStackedWidget (internally used by QTabWidget to display pages)
Widget
If you want to keep a reference to the main window, just use an instance attribute in the __init__ (eg. self.mainWindow = parent).
Note, though, that child objects should never directly call methods of their ancestors (see "separation of concerns"), and signals also exist for this very reason.
What you should actually do is to connect the signal from the window:
class MainWindow(QMainWindow):
def __init__(self):
# ...
self.voices = Widget("Voices", self)
self.voices.ui.InitializeButton.clicked.connect(self.do_something)
And obviously remove that connection from Widget.
Alternatively, a better approach should use a custom signal instead:
class Widget(QWidget):
do_something_signal = Signal()
# ...
def clickedInitialize(self):
# do whatever you need, then:
self.do_something_signal.emit()
class MainWindow(QMainWindow):
def __init__(self):
# ...
self.voices.do_something_signal.connect(self.do_something)
I suggest you to read more about the Qt object trees and ownerships and also possible proper usage of signals in complex object structures in this related question.
Note: please avoid using code comments that are not necessary for the understanding of the code, especially if in languages that are not English. And, really, don't use "pippo".

Related

Access items and attributes across multiple windows

i have a main GUI-Window from which i open a new Window (FCT-popup) with a buttonclick:
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
self.ui = Ui_MainWindow() # sets ui = to the main window from the ui-file
self.ui.setupUi(self)
[...]
def enter_fct_results(self):
self.FCTpopup = FCT_Window()
self.FCTpopup.show()
In the Window i have a QTable to fill and a button to submit the data and close the window:
class FCT_Window(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
self.ui = Ui_FCT_Window()
self.ui.setupUi(self)
[...]
self.ui.pushButton_submitFCT.clicked.connect(lambda: MainWindow.store_fct_data(MainWindow, self.on_submit()[0]))
def on_submit(self): # event when user clicks
fct_nparray = np.zeros((self.ui.tableFCTinputs.rowCount(), self.ui.tableFCTinputs.columnCount()))
for j in range(self.ui.tableFCTinputs.columnCount()):
for i in range(self.ui.tableFCTinputs.rowCount()):
fct_nparray[i, j] = float(self.ui.tableFCTinputs.item(i, j).text())
return fct_nparray, lambda: self.close()
self.ui.pushButton_submitFCT.clicked.connect(lambda: MainWindow.store_fct_data(MainWindow, self.on_submit()[0]))
The receiving function iin the main window looks like ths:
def store_fct_data(self, data):
self.fct_data = data
Now i just want to understand how i can make either the mainwindow or the pushbutton which opens the 2nd window disabled. Disabling inside enter_fct_results() works, but if i want to enable it again with either store_fct_data or on_submit provides errors like this:
self.ui.pushButton_FCTresults.setEnabled(1)
self.ui.pushButton_submitFCT.clicked.connect(lambda: MainWindow.store_fct_data(MainWindow, self.on_submit()[0]))
AttributeError: type object 'MainWindow' has no attribute 'ui'
I dont think i have understood it here how to deal with multiple windows and stuff. For example how would i change a the color of a button in the main window by using a button in window2. How do i access the widgets? if i am inside the same Window i do that easily by
self.ui.pushbutton.setText("New Text")
I dont get how to access items and attributes across Windows :( Can you help me?
Access to attributes of another instance
There is a fundamental difference between disabling the button of the second window in enter_fct_results and what you tried in the lambda: in the first case, you're accessing an instance attribute (for instance, self.FCTpopup.ui.pushButton), while in the second you're trying to access a class attribute.
The self.ui object is created in the __init__ (when the class instance is created), so the instance will have an ui attribute, not the class:
class Test:
def __init__(self):
self.value = True
test = Test()
print(test.value)
>>> True
print(Test.value)
>>> AttributeError: type object 'Test' has no attribute 'value'
Provide a reference
The simple solution is to create a reference of the instance of the first window for the second:
def enter_fct_results(self):
self.FCTpopup = FCT_Window(self)
self.FCTpopup.show()
class FCT_Window(QMainWindow):
def __init__(self, mainWindow):
QMainWindow.__init__(self)
self.mainWindow = mainWindow
self.ui.pushButton_submitFCT.clicked.connect(self.doSomething)
def doSomething(self):
# ...
self.mainWindow.ui.pushButton.setEnabled(True)
Using modal windows (aka, dialogs)
Whenever a window is required for some temporary interaction (data input, document preview, etc), a dialog is preferred: the main benefit of using dialogs is that they are modal to the parent, preventing interaction on that parent until the dialog is closed; another benefit is that (at least on Qt) they also have a blocking event loop within their exec() function, which will only return as soon as the dialog is closed. Both of these aspects also make unnecessary disabling any button in the parent window. Another important reason is that QMainWindow is not intended for this kind of operation, also because it has features that generally unnecessary for that (toolbars, statusbars, menus, etc).
def enter_fct_results(self):
self.FCTpopup = FCT_Window(self)
self.FCTpopup.exec_()
class FCT_Window(QDialog):
def __init__(self, parent):
QMainWindow.__init__(self, parent)
self.ui.pushButton_submitFCT.clicked.connect(self.doSomething)
def doSomething(self):
# ...
self.accept()
The above makes mandatory to recreate the ui in designer using a QDialog (and not a QMainWindow) instead. You can just create a new one and drag&drop widgets from the original one.
i finally found my mistake: It was the place of the signal connection. It has to be right before the 2nd window is opened:
def enter_fct_results(self):
self.FCTpopup = Dialog(self.fct_data)
self.FCTpopup.submitted.connect(self.store_fct_data)
self.FCTpopup.exec_()
With this now i can send the stored data from the mainwindow to the opened window, import into the table, edit it and send it back to the main window on submit.

How to properly design a multi-window application in Qt (PyQt)?

The most obvious approach for me is to declare each window (window, dialog or widget) in the constructor and call the show() method when needed. Something like this:
class MultiWindowApp():
def __init__(self):
self.window_1 = self.init_window_1()
self.window_2 = self.init_window_2()
def init_window_1(self):
gui = uic.loadUi(...)
# other settings
return gui
def init_window_2(self):
gui = uic.loadUi(...)
# other settings
return gui
def show_window_1(self):
self.window_1.show()
def show_window_2(self):
self.window_2.show()
Nevertheless, it does not seem to be memory efficient, because I store the windows in the memory all the time, even when I am not showing it.
Alternative solution that comes to my mind is to create a separate class for each window (or other widget) and have one placeholder for all in the main class. Assign an instance of the respective class and delete on closing the window. A minimal example below:
class Window_1(QWidget):
def __init__(self):
QWidget.__init__(self)
uic.loadUi(...)
# other settings
self.show()
class Window_2(QWidget):
def __init__(self):
QWidget.__init__(self)
uic.loadUi(...)
# other settings
self.show()
class MultiWindowApp():
def __init__(self):
self.widget_placeholder = None
def show_window_1(self):
self.widget_placeholder = Window_1()
def show_window_2(self):
self.widget_placeholder = Window_1()
This would be a bit slower, but I would avoid keeping in memory unnecessary stuff. Nevertheless, I still have a feeling that there is a better way. What is the proper way of designing such an application?
I didn't run the examples above, so there can be some errors, but I think that the concepts behind them are clear.

AttributeError: "Dialog" object has no attribute 'setupUi'

I made two forms on pyqt5 - qt-designer. One is the Main Form and the second is a Dialog which I will use for user input. I converted both to py code.
First of all I should inform you that I do not modify the converted Ui.py files. I prefer to have an extra "Main" file where I set each modification. I do this so that I won't have to make the extra changes each time I modify with the Ui files.
So, I added a second class on my Main file and tried to call it from my MainForm Class through a menu item. Here is some example code:
class MainForm(QMainWindow):
def __init__(self, parent=None):
super(MainForm, self).__init__(parent)
self.ui = Ui_MainForm()
self.ui.setupUi(self)
self.ui.actionMenu1.triggered.connect(self.open_my_dialog)
def open_my_dialog(self):
my_dialog = QDialog()
my_dialog.ui = MyDialog()
my_dialog.ui.setupUi(my_dialog)
# MainForm.hide(self)
my_dialog.exec_()
my_dialog.show()
class MyDialog(QDialog):
def __init__(self, parent=None):
super(MyDialog, self).__init__(parent)
self.ui = Ui_MyDialog()
self.ui.setupUi(self)
self.ui.pushButton_cancel.clicked.connect(self.cancel_dialog)
def cancel_dialog(self):
print("Closing Dialog Window...")
sys.exit()
When I run this and click the respective menu button I get the following error:
AttributeError: 'MyDialog' object has no attribute 'setupUi'
the Error is at this line:
self.ui.setupUi(self) # this is under MyDialog Class
I can get the code working if I reference it to the external (Ui_MyDialog) file directly without using the second class here. But as I stated at the beginning I want to control this from within this file, make the modifications directly here so that I won't have the keep track of the modifications to the Ui files in the future.
Given that the error occurs at this line
self.ui.setupUi(self)
and you assigned an Ui_MyDialog instance to self.ui, before
self.ui = Ui_MyDialog()
the error message should be mentioning class Ui_MyDialog and not MyDialog.
So, either you misreported the error message or the error does not occur 'under MyDialog Class'.
I also would point out: QWidget and derived classes have no setupUi method, themselves. Such method belongs to Ui_* classes, generated by uic, and is typically called from the constructor of a widget that inherits from a Ui_* class.
So, if you want to call setupUi on MyDialog instances, MyDialog must inherit from Ui_MyDialog, in the first place.
And you do call it in open_my_dialog:
my_dialog.ui = MyDialog()
my_dialog.ui.setupUi(my_dialog)
Finally I got it to work. But before I provide the answer, I would like to thank
#p-a-o-l-o and #LoïcG.. the latter helping me out all the way. Thanks!
The code worked when I changed it to the following:
class MainForm(QMainWindow):
def __init__(self, parent=None):
super(MainForm, self).__init__(parent)
self.ui = Ui_MainForm()
self.ui.setupUi(self)
self.ui.actionMenu1.triggered.connect(self.open_my_dialog)
def open_my_dialog(self):
my_dialog = MyDialog()
# my_dialog.show() <-- seems this line is not necessary either
my_dialog.exec_() # this alone was enough for the code to work
class MyDialog(QDialog):
def __init__(self, parent=None):
super(MyDialog, self).__init__(parent)
self.ui = Ui_MyDialog()
self.ui.setupUi(self)
self.ui.pushButton_cancel.clicked.connect(self.cancel_dialog)
def cancel_dialog(self):
print("Closing Dialog Window...")
self.close() # not important but corrected this also.
I hope this helps!
Edit: I corrected some lines and made the answer more simple thanks to
#LoïcG. !

findChild on object created within pyqt designer

I have the following problem with my pyqt:
Assuming i create an object within the Qt Designer and save it as an .ui file. Then i use pyuic to convert it to an .py file. Because i want to integrate a new module into a given program, this is the favorite way to go (because later the .ui files will be converted automatically at startup to .py files).
If i have a look at my .py file i see the following for the window:
class Ui_SubWindow(object):
def setupUi(self, SubWindow):
SubWindow.setObjectName(_fromUtf8("SubWindow"))
....
i have a RemoteWindow class as MainWindow where the SubWindow is initiated:
class RemoteWindow(QtGui.QMainWindow):
def __init__(self, subcore):
super(RemoteWindow, self).__init__(subcore.core.gui)
self.subcore = subcore
self.ui = Ui_SubWindow()
Now i have a core program:
class SubCore(object):
def __init__(self, core, identity, number):
...
self.gui = RemoteWindow(self)
self.newController = NewController(self.gui)
and the new controller class:
class NewController(object):
def __init__(self, subwindow):
self.subwindow = subwindow
self.ui = subwindow.ui
from my controller i want to call a .findChild() on that window
submitFrame = self.ui.findChild(QtGui.QFrame, "frameSubmit")
, but all i get is an:
AttributeError: 'Ui_SubWindow' object has no attribute 'findChild'
I assume this is, because the class Ui_SubWindow is not a child class of some QObject but of an object, am i right?
self.ui is the same as subwindow.ui, where subwindow is an instance of RemoteWindow which has as .ui argument the Ui_SubWindow Class.
Is there any chance to make the pyuic or the Qt Designer to make this SubWindow a child of QObject, without manipulating the automatically generated .py file?
You don't need to use findChild at all, because pyuic will automatically create attributes in the ui object for all the widgets defined in Qt Designer. The attribute names are taken from the objectName. So all you need is:
submitFrame = self.ui.frameSubmit
Qt Designer creates a design, that is, a class that serves to fill the main widget so the internal widgets are not children of this class, if you want to use findChild you must do it to the widget that returns this class after calling the method setupUi.
class RemoteWindow(QtGui.QMainWindow):
def __init__(self, subcore):
super(RemoteWindow, self).__init__(subcore.core.gui)
self.subcore = subcore
self.ui = Ui_SubWindow()
self.ui.setupUi(self) # Here the widget is filled
[...]
And then you should use it in the following way:
class NewController(object):
def __init__(self, subwindow):
self.subwindow = subwindow
submitFrame = self.subwindow.findChild(QtGui.QFrame, "frameSubmit")
[...]
I recently had to do this same thing and leaving this here in case someone sees this link vs the other related one.
https://stackoverflow.com/a/62340205/1621381
for name, obj in dict(self.__dict__).items():
# print(str(name) + str(obj))
obj_type = str(obj).strip("<PyQt5").rsplit(" ")[0].replace(".", '', 1)
# obj_type = str(obj).strip("<").rsplit(" ")[0]
# print(obj_type)
# obj_type = obj_str.strip("<PyQt5").rsplit(" ")[0].replace(".", '', 1)
label_name = "self." + str(name)
try:
label_name = self.findChild(eval(obj_type), name)
print(str(label_name) + ' created')
except:
pass
if not isinstance(obj_type, QObject):
continue

PyQt - open only one child window and minimize it with parent window

The idea is to open a child window from parent window menu and when I minimize the parent window, the child window must be minimized also and only one child window can be opened.
I have the solution for minimizing the child when parent is minimized, but I can open child window multiple-times (although the child is already opened) and I would like to disable opening of multiple child windows.
The parent window is MainWindow.py:
class MainWindow(QtGui.QMainWindow):
def __init__(self):
super(MainWindow, self).__init__()
self.setWindowTitle('Parent window')
self.flags = QtCore.Qt.Window
self.ControlPanel = Control_panel_window()
self.createActions()
self.createMenus()
def createActions(self):
# window - menu
self.windowShowControlPanelAction = QtGui.QAction(self.tr("&Control panel"), self, statusTip='Control panel')
self.connect(self.windowShowControlPanelAction, QtCore.SIGNAL("triggered()"), self.ShowControlPanel)
def createMenus(self):
# window
self.windowMenu = QtGui.QMenu(self.tr("&Window"), self)
self.windowMenu.addAction(self.windowShowControlPanelAction)
self.menuBar().addMenu(self.windowMenu)
def ShowControlPanel(self):
self.ControlPanel = Control_panel_window(self)
self.ControlPanel.setWindowFlags(QtCore.Qt.Window)
self.ControlPanel.show()
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
win = MainWindow()
win.setContextMenuPolicy(QtCore.Qt.CustomContextMenu)
win.show()
sys.exit(app.exec_())
The child window is ChildWindow.py:
class Control_panel_window(QWidget):
def __init__(self, parent = None):
super(Control_panel_window, self).__init__(parent)
self.setFixedSize(200, 300)
def setWindowFlags(self, flags):
print "flags value in setWindowFlags"
print flags
super(Control_panel_window, self).setWindowFlags(flags)
The problem is: how can I set that only one child window is opened?
In your ShowControlPanel function you are creating a new control panel each time the signal is triggered. Since you already have an instance available why don't you use that instead?
class MainWindow(QtGui.QMainWindow):
def __init__(self):
super(MainWindow, self).__init__()
self.setWindowTitle('Parent window')
self.flags = QtCore.Qt.Window
self.control_panel = ControlPanelWindow(self)
self.control_panel.setWindowFlags(self.flags)
#...
def create_actions(self):
self.show_control_panel_action = QtGui.QAction(
self.tr("&Control panel"),
self,
statusTip='Control panel'
)
self.show_control_panel_action.triggered.connect(self.show_control_panel)
#...
def show_control_panel(self):
self.control_panel.show()
Some stylistic notes:
Try to follow PEP8 official python coding-style guide. This include using CamelCase for classes, lowercase_with_underscore for almost everything else. In this case, since Qt uses halfCamelCase for methods etc you may use it too for consistency.
Use the new-style signal syntax:
the_object.signal_name.connect(function)
instead of:
self.connect(the_object, QtCore.SIGNAL('signal_name'), function)
not only it reads nicer, but it also provides better debugging information. Using QtCore.SIGNAL you will not receive an error if the signal doesn't exist (e.g. you wrote a typo like trigered() instead of triggered()). The new-style syntax does raise an exception in that case you will be able to correct the mistake earlier, without having to guess why something is not working right and searching the whole codebase for the typo.

Categories

Resources