While learning the os module in Python and I've come across a problem.
Let's pretend my current working directory is: C:\Users\Москва\Desktop\Coding\Project 1.
I'd like to change the cwd to Desktop but since the path contains some Russian letters (Москва) it throws a Syntax error:
print(os.getcwd()) # C:\Users\Москва\Desktop\Coding\Project 1
os.chdir('C:\Users\Москва\Desktop')
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes...
How shall I usually treat non-standard characters in paths and change the directory in my case?
It isn't about the russian, it's about the backslash with u: \U.
When you print os.getcwd, escaped backslashes goes away:
os.getcwd()
# 'C:\\Users\\chris\\Documents\\Москва\\test'
print(os.getcwd())
C:\Users\chris\Documents\Москва\test
And now if you try to use the printed one by copy-paste, python will understand \Users part as a unicode but of course fail. You can simply reproduce by executing
"\Uaaaa"
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-1: truncated \UXXXXXXXX escape
You can either use raw string, or use escaped backslashes:
os.chdir(r'C:\Users\sjysk\Documents\Москва')
# ^ note `r` here
os.getcwd()
# 'C:\\Users\\chris\\Documents\\Москва'
os.chdir('C:\\Users\\sjysk\\Documents\\Москва')
os.getcwd()
# 'C:\\Users\\chris\\Documents\\Москва'
when I run this code on pycharm using python:
import great_expectations as ge
df=ge.read_csv("C:\Users\TasbeehJ\data\yellow_tripdata_2019-02.csv")
it gave me this error:
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
how to solve it?
The esiast way whould be to add an r to use the \as a sign and not an escape value.
import great_expectations as ge
df=ge.read_csv(r"C:\Users\TasbeehJ\data\yellow_tripdata_2019-02.csv")
You can try by looking here, https://docs.python.org/3.7/library/csv.html?highlight=csv#module-csv
Maybe you can try writing:
>>> import csv
>>> with open('yellow_tripdata_2019-02.csv', newline='') as csvfile:
from PIL import Image
import os
for f in os.listdir('C:\Users\diodi\Pictures'):
if f.endswith('.jpg'):
print(f)
i get the error
for f in os.listdir('C:\Users\diodi\Pictures'):
^
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
if someone can edit the error message please do.
i want to print the names of the pictures(jpg) i have in
('C:\Users\diodi\Pictures')
i am using python 3.7,i know i didn't use the pillow library yet.
The backslashes are being parsed as escape characters, use r to denote raw string
os.listdir(r"C:\Users\diodi\Pictures"):
Or escape them with more backslashes
os.listdir('C:\\Users\\diodi\\Pictures'):
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How should I write a Windows path in a Python string literal?
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I am using Python 3.1 on a Windows 7 machine. Russian is the default system language, and utf-8 is the default encoding.
Looking at the answer to a previous question, I have attempting using the "codecs" module to give me a little luck. Here's a few examples:
>>> g = codecs.open("C:\Users\Eric\Desktop\beeline.txt", "r", encoding="utf-8")
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-4: truncated \UXXXXXXXX escape (<pyshell#39>, line 1)
>>> g = codecs.open("C:\Users\Eric\Desktop\Site.txt", "r", encoding="utf-8")
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-4: truncated \UXXXXXXXX escape (<pyshell#40>, line 1)
>>> g = codecs.open("C:\Python31\Notes.txt", "r", encoding="utf-8")
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 11-12: malformed \N character escape (<pyshell#41>, line 1)
>>> g = codecs.open("C:\Users\Eric\Desktop\Site.txt", "r", encoding="utf-8")
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-4: truncated \UXXXXXXXX escape (<pyshell#44>, line 1)
My last idea was, I thought it might have been the fact that Windows "translates" a few folders, such as the "users" folder, into Russian (though typing "users" is still the correct path), so I tried it in the Python31 folder. Still, no luck. Any ideas?
The problem is with the string
"C:\Users\Eric\Desktop\beeline.txt"
Here, \U in "C:\Users... starts an eight-character Unicode escape, such as \U00014321. In your code, the escape is followed by the character 's', which is invalid.
You either need to duplicate all backslashes:
"C:\\Users\\Eric\\Desktop\\beeline.txt"
Or prefix the string with r (to produce a raw string):
r"C:\Users\Eric\Desktop\beeline.txt"
Typical error on Windows because the default user directory is C:\user\<your_user>, so when you want to pass this path as a string argument into a Python function, you get a Unicode error, just because the \u is a Unicode escape. If the next 8 characters after the \u are not numeric this produces an error.
To solve it, just double the backslashes: C:\\user\\<\your_user>...
This will ensure that Python treats the single backslashes as single backslashes.
Prefixing with 'r' works very well, but it needs to be in the correct syntax. For example:
passwordFile = open(r'''C:\Users\Bob\SecretPasswordFile.txt''')
No need for \\ here - maintains readability and works well.
With Python 3 I had this problem:
self.path = 'T:\PythonScripts\Projects\Utilities'
produced this error:
self.path = 'T:\PythonScripts\Projects\Utilities'
^
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in
position 25-26: truncated \UXXXXXXXX escape
the fix that worked is:
self.path = r'T:\PythonScripts\Projects\Utilities'
It seems the '\U' was producing an error and the 'r' preceding the string turns off the eight-character Unicode escape (for a raw string) which was failing. (This is a bit of an over-simplification, but it works if you don't care about unicode)
Hope this helps someone
Or you could replace '\' with '/' in the path.
path = pd.read_csv(**'C:\Users\mravi\Desktop\filename'**)
The error is because of the path that is mentioned
Add 'r' before the path
path = pd.read_csv(**r'C:\Users\mravi\Desktop\filename'**)
This would work fine.
I had this same error in python 3.2.
I have script for email sending and:
csv.reader(open('work_dir\uslugi1.csv', newline='', encoding='utf-8'))
when I remove first char in file uslugi1.csv works fine.
Refer to openpyxl document, you can do changes as followings.
from openpyxl import Workbook
from openpyxl.drawing.image import Image
wb = Workbook()
ws = wb.active
ws['A1'] = 'Insert a xxx.PNG'
# Reload an image
img = Image(**r**'x:\xxx\xxx\xxx.png')
# Insert to worksheet and anchor next to cells
ws.add_image(img, 'A2')
wb.save(**r**'x:\xxx\xxx.xlsx')
I had same error, just uninstalled and installed again the numpy package, that worked!
I had this error.
I have a main python script which calls in functions from another, 2nd, python script.
At the end of the first script I had a comment block designated with ''' '''.
I was getting this error because of this commenting code block.
I repeated the error multiple times once I found it to ensure this was the error, & it was.
I am still unsure why.
I am running the following code in python and it's giving me this error:
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
def filePro(filename):
f=open(filename,'r')
wordcount=0
for lines in f:
f1=lines.split()
wordcount=wordcount+len(f1)
f.close()
print ('word count:'), str(wordcount)
Please help me.
Unicode literals (String literals in Python 3.x) with \U or \u escape sequence should be one of following forms:
>>> u'\U00000061' # 8 hexadecimals
'a'
>>> u'\u0061' # 4 hexadecimals
'a'
If there's not enough escape sequence, you get a SyntaxError.
>>> u'\u61'
File "<stdin>", line 1
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-3: truncated \uXXXX escape
>>> u'\U000061'
File "<stdin>", line 1
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-7: truncated \UXXXXXXXX escape
If you mean literal \ and U. You'd better to use raw string:
>>> r'\u0061'
'\\u0061'
>>> print(r'\u0061')
\u0061
In the code you posted, there's no unicode escape sequence. You should Check other part of your code.
Not sure, not much information provided here, but I guess python is trying to open the file with wrong encoding, you could open the file with the codecs library, use the correct codec to open the file, if I don't know or if it comes from windows I usually use 'cp1252' as this can open most types.
import codecs
def filePro(filename):
f = codecs.open(filename, 'r', 'cp1252'):
wordcount=0
for lines in f:
f1=lines.split()
wordcount=wordcount+len(f1)
f.close()
print ('word count:'), str(wordcount)
Another possibillity is that you have a filename that python translates to code, for example a file name like 'c:\Users\something' here the \U will be interpret. See this answer