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Python: How to make this code look more beautiful ,elegant ,Pythonic ,simple ,shorter? [closed]

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This is my code ,it is extremely big for something this simple ,how should i make it better?
import numpy
charStats = {'health': 50 ,'damage': 10.1}
charList = []
numbyO = -1
for x in charStats:
numbyO += 1
charList.append(charStats[x])
print(int(numpy.mean(charList)))

You don't need to create charList; just use dict.values():
from statistics import mean
char_stats = {'health': 50 ,'damage': 10.1}
print(int(mean(char_stats.values())))

You can creat a class object and reuse this code,,,
import numpy
class GetMean:
"""make a class object that takes a dict. argument"""
def __init__(self, dict_argument):
#creat dict. attribute
self.dict_argument = dict_argument
#creat list attribute
self.char_list = []
#creat numby_0 attribute
self.numby_0 = -1
def return_mean(self):
#method that returns mean
for x in self.dict_argument:
self.numby_0 +=1
self.char_list.append(self.dict_argument[x])
mean = (int(numpy.mean(self.char_list)))
return mean
charStats = {'health': 50 ,'damage': 10.1}
get_mean = GetMean(charStats)
#instanting GetMean object
mean = get_mean.return_mean()
#using return mean method
print(mean) #showing result

How to split a list's value into two lists [closed]

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How can I split a 'time' value into two 'day' 'time' lists?
See attached image:

If you have it as datetimeobject:
datos['day'] = dados['time'].dt.date
datos['time'] = dados['time'].dt.time
If you have it as string object:
datos['day'] = dados['time'].str[:11]
datos['time'] = dados['time'].str[11:]
Or
data[['day', 'time']] = data['time'].str.split(' ').apply(pd.Series)
data[['day', 'time']] = data['time'].str.split(' ', expand=True)
Or using regex
data[['day', 'time']] = data['time'].str.extract('(.*) (.*)')
To convert it to string:
datos['time'] = dados['time'].astype(str)
It is better then converting to normal list [str(x) ...]
To convert it to datetime
datos['time'] = pd.to_datetime(dados['time'])
It may use options - ie. yearfirst=True, dayfirst=True, format="%Y-%m-%d %H:%I:%S"

I use this for resolve the problem, is there any cleaner way?
dia = [str(x) for x in dados.time]
hora = [str(x) for x in dados.time]
for x in range(len(dia)):
dia [x]=dia [x][0:11]
hora[x]=hora[x][11:20]
dados.insert(0, 'dia', dia)
dados.insert(1, 'hora', hora)
dados.drop(columns='time',inplace=True)

How to remove double quotes from a nested list [closed]

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I have a list Let's say
m = [["'ghvghvgh hgdghdh', 'hxjhsdhb.com - Error 404:validation', 'jhhscbhjbcsd', 'hghs'"],["'ghvh', 'hxjhsdhb', 'jhhcsd', 'hs'"]]
and I want my output something like this (removing the double quotes).
m = [['ghvghvgh hgdghdh', 'hxjhsdhb.com - Error 404:validation', 'jhhscbhjbcsd', 'hghs'],['ghvh', 'hxjhsdhb', 'jhhcsd', 'hs']] ```
m[0][0].replace('"', '') # I have tried this

To normalise the data, you need to replace the single quotes and not the double-ones the trim away extra spaces.
lst = [
i[0].replace("'", '').strip().split(', ')
for i in m
]

import re
a=re.compile('[a-zA-Z]+')
m = [["'ghvghvgh', 'hxjhsdhb', 'jhhscbhjbcsd', 'hghs' "],[" 'ghvh', 'hxjhsdhb', 'jhhcsd', 'hs'"]]
res= [[a.findall(i) for i in j][0] for j in m]
print(res)
output
[['ghvghvgh', 'hxjhsdhb', 'jhhscbhjbcsd', 'hghs'], ['ghvh', 'hxjhsdhb', 'jhhcsd', 'hs']]

How to get number form multi text files name and use it? [closed]

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I'm a new python user. I try to write a script to deal with multiple text files all of them the same name and indexed like
sample1_freq780Hz_accRate600Hz_V3Volt_1_.txt
sample1_freq780Hz_accRate600Hz_V3Volt_2_.txt
sample1_freq780Hz_accRate600Hz_V3Volt_3_.txt
I used this code:
def get_numbers_from_filename(filename):
result = re.search(r'\d+', filename).group(0)
return result for filename in os.listdir('input/'):
print(get_numbers_from_filename(filename))
but it didn't give me the wanted results
I need a code to get the numbers as follow:
freq: 780 Hz
accRate: 600 Hz
V: 3 Volt
and how to deal and use these numbers as parameters inside the full script?

You can use regex:
import re
import os
new_s = [dict(zip(['freq', 'accRate', 'V'], ['{} {}'.format(c, a) for a, c in zip(['Hz', 'Hz', 'Volt'], re.findall('(?<=freq)\d+|(?<=accRate)\d+|(?<=V)\d+', i))])) for i in os.listdir('input/')]
print(new_s[0])
Output:
{'freq': '780 Hz', 'accRate': '600 Hz', 'V': '3 Volt'}
To access the values in the list, iterate over new_s:
values = [new_s[0][i] for i in ['freq', 'accRate', 'V']]
Output:
['780 Hz', '600 Hz', '3 Volt']

How to split data into train,test and validation sets? [closed]

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Following is my code:
Here is the main function
trainingSet=[]
testSet=[]
validationSet=[]
loadDataset('iris.data.txt', trainingSet, testSet,validationSet)
And this is the loadDataset function
def loadDataset(filename, trainingSet=[] ,testSet=[],validationSet=[]):
with open(filename, 'rb') as csvfile:
lines = csv.reader(csvfile)
dataset = list(lines)
for x in range(len(dataset)-1):
for y in range(4):
dataset[x][y] = float(dataset[x][y])
random.shuffle(dataset)
trainingSet .append(dataset[:106])
testSet.append(dataset[106:128])
validationSet.append(dataset[128:150])
"loadDataset gets wine data set csv and converts it into a list of floats. Then it splits the data."
I am trying to split my data into 70-15-15. But when I print the lengths of each list it gives 1.

Simply using .extend instead of .append should solve your issue. .append adds the slice dataset[xxx] as a single element to the list. .extend, on the other hand, adds all the elements in dataset[xxx] to the list.
However, if you only call loadDataSet once, as in your example, there is no need to initialize empty datasets, and you can return the ranges directly.
main function:
trainingSet, testSet, validationSet = loadDataset('iris.data.txt')
loadDataset function:
def loadDataset(filename):
with open(filename, 'rb') as csvfile:
lines = csv.reader(csvfile)
dataset = list(lines)
for x in range(len(dataset)-1):
for y in range(4):
dataset[x][y] = float(dataset[x][y])
random.shuffle(dataset)
trainingSet = dataset[:106]
testSet = dataset[106:128]
validationSet = dataset[128:150]
return trainingSet, testSet, validationSet