I need to stop an infinite while loop - python

while the script is running, it needs to be outside the input to catch the keyword and break the loop, I need to break the loop instantly with the 'esc' word, while the script waits for input by the user
¿how do i that?
import time ; import keyboard as kb
while (True):
if kb.is_pressed('esc'):
break
n = str(input('f(x) = '))
print(n)
time.sleep(1)
its a bit whim but the only way to stop the loop is to hold the 'esc' keyword and it would be more comfortable to press the key and instantly break the loop, i tried a few methods but they all lead to the same thing and this one is the most efficient

If you are fine with using Ctrl+C instead of esc, you can just catch the KeyboardInterrupt error.
import time
while True:
try:
n = str(input('f(x) = '))
time.sleep(1)
except KeyboardInterrupt:
print("\nBreaking from the infinite loop")
break
SIGINT is the signal sent when we press Ctrl+C. The default action is to terminate the process. However in Python, a KeyboardInterrupt error is raised.
It can be difficult to trigger a SIGINT when the escape key is pressed, since the interrupt process is hardware and OS dependent.

Related

Is there a way to break out of the time.sleep() method? [duplicate]

I need to break from time.sleep() using ctrl c.
While 1:
time.sleep(60)
In the above code when the control enters time.sleep function an entire 60 seconds needs to elapsed for python to handled the CTRL C
Is there any elegant way to do it. such that I can interrupt even when the control is in time.sleep function
edit
I was testing it on a legacy implementation which uses python 2.2 on windows 2000 which caused all the trouble . If I had used a higher version of python CTRL C would have interrupted the sleep() . I did a quick hack by calling sleep(1) inside a for loop . which temporarily fixed my issue
The correct answer is to use python stdlib's threading.Event
Sure you can tune down your sleep interval so you sleep for very short periods, but what if you actually want to run your loop once every 60s? Then you need to do more work to determine if it's time to run or just keep sleeping. Furthermore, you're still technically blocking but for only a short period of time. Contrast to threading.Event:
from threading import Event
exit = Event()
def main():
while not exit.is_set():
do_my_thing()
exit.wait(60)
print("All done!")
# perform any cleanup here
def quit(signo, _frame):
print("Interrupted by %d, shutting down" % signo)
exit.set()
if __name__ == '__main__':
import signal
for sig in ('TERM', 'HUP', 'INT'):
signal.signal(getattr(signal, 'SIG'+sig), quit);
main()
When the signal handler calls exit.set(), the main thread's wait() call will immediately be interrupted.
Now, you could use an Event to signal that there's more work to do, etc. But in this case it does double duty as a convenient indicator that we want to quit (e.g. the while not exit.is_set() part.)
You also have the option to put any cleanup code after your while loop.
Not sure what the sense of this code is - but if necessary use a shorter sleep() interval and put a for loop around it:
for i in range(60):
sleep(1)
Catching the KeyboardInterrupt exception using try..except is straight-forward
The KeyboardInterrupt exception is raised when a user hits the interrupt key, Ctrl-C. In python this is translated from a SIGINT signal. That means, you can get handle it however you want using the signal module:
import signal
def handler(signum, frame):
print("do whatever, like call thread.interrupt_main()")
signal.signal(signal.SIGINT, handler)
print("Waiting for SIGINT...")
signal.pause()
That way, you can do whatever you want at the receipt of a keyboard interrupt.
The most elegant solution is certainly threading.Event, though if you only need a quick hack, this code works well :
import time
def main():
print("It’s time !")
if __name__ == "__main__":
print("press ctrl-c to stop")
loop_forever = True
while loop_forever:
main()
try:
time.sleep(60)
except KeyboardInterrupt:
loop_forever = False
I tried your code with python versions 2.5, 2.6, 3 under Linux and all throw "KeyboardInterrupt" exception when hitting CTRL-C.
Maybe some exception handling catches the Interrupt or your problem is like this:
Why is KeyboardInterrupt not working in python?
Based on #Andreas Jung answer
for i in range(360):
try:
sleep(1)
except KeyboardInterrupt:
sys.exit(0)
Figured I'd throw this in.
import time
def sleep(seconds):
for i in range(seconds):
try:
time.sleep(1)
except KeyboardInterrupt:
print("Oh! You have sent a Keyboard Interrupt to me.\nBye, Bye")
break
sleep(60)

How to exit a Python program or loop via keybind or macro? Keyboardinterrupt not working

I am trying to complete a simple GUI automation program that merely opens a web page and then clicks on a specific spot on the page every 0.2 seconds until I tell it to stop. I want my code to run and have its loop run infinitely until a keybind I specify breaks the loop (or entire program). I started out with the classic, KeyboardInterrupt, which enables CTRL+C to exit a program. Here is what I thought my final code would look like:
import webbrowser, pyautogui, time
webbrowser.open('https://example.com/')
print('Press Ctrl-C to quit.')
time.sleep(5)
#pyautogui.moveTo(1061, 881)
try:
while True:
time.sleep(0.2)
pyautogui.click(1061,881)
except KeyboardInterrupt:
print('\nDone.')
Everything about the code works, except the fact that I can't exit it once the clicking loop starts. Keyboard interrupt and using CTRL-C to exit do not work at all for this script, for whatever reason.
I merely want to be able to press "escape" (or any other key) to exit the loop (or the program altogether) - just any way to make the loop exit and stop. Right now it runs ad infinitum, but I want a simple keybind macro to be able to stop/break it.
I've tried using getch to keybind the escape key to cause a break, but to no avail:
import webbrowser, pyautogui, time, msvcrt
webbrowser.open('https://example.com')
print('Press Ctrl-C to quit.')
time.sleep(5)
#pyautogui.moveTo(1061, 881)
try:
while True:
time.sleep(0.2)
pyautogui.click(1061,881)
if msvcrt.kbhit():
key = ord(readch())
if key == 27:
break
I'm surprised it's been so hard to do this in Python. I've checked out a lot of similar problems across Stackoverflow, but with unsatisfactory answers, and none that solve my problem, unfortunately. I've been able to do things like this in simpler coding languages like AuotHotKeys with ease. I feel like I'm dancing around the solution. Any and all help would be wonderfully appreciated! Thanks in advance.
If I understood correctly, you want to be able to stop your program by pressing a key on your keyboard.
To make you create a thread that will check in background if you press the key in question.
A little example:
import threading, time
from msvcrt import getch
key = "lol"
def thread1():
global key
lock = threading.Lock()
while True:
with lock:
key = getch()
threading.Thread(target = thread1).start() # start the background task
while True:
time.sleep(1)
if key == "the key choosen":
# break the loop or quit your program
Hope its help.

Python Curses: Exiting a program fast

What is the best way to quickly exit a Python program with an infinite loop that uses curses module?
I've tried adding nodelay() method coupled with this at the end of the loop:
if screen.getch() == ord('q'):
break
However, it takes 2-3 seconds to make all the function calls on one iteration of the loop. And because of the application, it doesn't make sense to run the loop more often than every 5 second. This means that in order for my way of exiting the program to work, I sometimes have to press and hold 'q' for 2-8 seconds.
My code looks like this:
import curses
import time
def main(screen):
refresh_rate = 5
screen.nodelay(1)
# Infinite loop. Displays information and updates it
# every (refresh_rate) # of seconds
while True:
# Makes several http requests
# and passes responses through multiple functions
# Escape infinite loop
if screen.getch() == ord('q'):
break
# Wait before going through the loop again
time.sleep(refresh_rate)
if __name__ == "__main__":
curses.wrapper(main)
My other solution was to replace while True with:
loop = 1
while loop:
#Loop code
if screen.getch() == ord('q'):
loop = -1
This way, there is no need to press and hold 'q' to exit the program. But it can still take up to 8 seconds to exit after pressing 'q' once.
For obvious reasons, this doesn't seem to be the best way of exiting the program. I am pretty sure there should be a better (faster) solution.
Other than that, the program works fine. It's 2 files with more than 300 lines, so I am posting just the relevant parts of the code with my attempted solutions.
Given that you have nodelay already, the usual approach is to use napms with a small (20-50 milliseconds) time, and addressing your 5-seconds goal, to run the functions after several (10-25) repetitions of the getch/napms loop.
Mixing curses and standard I/O doesn't really work well unless you take care to flush things when switching between the two.
What's probably happening is that your 'q' is coming in between the getch() and the sleep calls. Given that getch() takes a fraction of a second to execute and sleep locks the program for 5 seconds, it's very likely that any time you press a key you're going to wait.
The easiest way to exit any python script is to press Ctrl-C - it spawns a KeyBoardInterrupt exception that can be handled like:
try:
while True:
do_something()
except KeyboardInterrupt:
pass
Granted, if this is meant to be a user-facing application, that might not be sufficient. But it's also unlikely that any production application would operate without a full event loop and a UI that would allow them to exit.
Last, if you want another way of doing what you're already doing, you can use:
import sys
sys.stdin.read(1)
To read 1 bye of user input at a time. I'd go for the Ctrl-C route, if I were you.

Ending an infinite while loop

I currently have code that basically runs an infinite while loop to collect data from users. Constantly updating dictionaries/lists based on the contents of a text file. For reference:
while (True):
IDs2=UpdatePoints(value,IDs2)
time.sleep(10)
Basically, my problem is that I do not know when I want this to end, but after this while loop runs I want to use the information collected, not lose it by crashing my program. Is there a simple, elegant way to simply exit out of the while loop whenever I want? Something like pressing a certain key on my keyboard would be awesome.
You can try wrapping that code in a try/except block, because keyboard interrupts are just exceptions:
try:
while True:
IDs2=UpdatePoints(value,IDs2)
time.sleep(10)
except KeyboardInterrupt:
print('interrupted!')
Then you can exit the loop with CTRL-C.
You could use exceptions. But you only should use exceptions for stuff that isn't supposed to happen. So not for this.
That is why I recommand signals:
import sys, signal
def signal_handler(signal, frame):
print("\nprogram exiting gracefully")
sys.exit(0)
signal.signal(signal.SIGINT, signal_handler)
you should put this on the beginning of your program and when you press ctrl+c wherever in your program it will shut down gracefully
Code explanation:
You import sys and signals.
Then you make a function that executes on exit. sys.exit(0) stops the programming with exit code 0 (the code that says, everything went good).
When the program get the SIGINT either by ctrl-c or by a kill command in the terminal you program will shutdown gracefully.
I think the easiest solution would be to catch the KeyboardInterrupt when the interrupt key is pressed, and use that to determine when to stop the loop.
except KeyboardInterrupt:
break
The disadvantage of looking for this exception is that it may prevent the user from terminating the program while the loop is still running.
I use python to track stock prices and submit automated buy/sell commands on my portfolio. Long story short, I wanted my tracking program to ping the data server for info, and place trades off of the information gathered, but I also wanted to save the stock data for future reference, on top of being able to start/stop the program whenever I wanted.
What ended up working for me was the following:
trigger = True
while trigger == True:
try:
(tracking program and purchasing program conditions here)
except:
trigger = False
print('shutdown initialized')
df = pd.DataFrame...
save all the datas
print('shutdown complete')
etc.
From here, while the program is in the forever loop spamming away requests for data from my broker's API, using the CTRL-C keyboard interrupt function toggles the exception to the try loop, which nullifies the while loop, allowing the script to finalize the data saving protocol without bringing the entire script to an abrupt halt.
Hope this helps!
Resultant
I would suggest using the try, except syntax within a loop if you are running on an IPYNB file in Google Colab or Jupyter, like:
while True:
try:
IDs2=UpdatePoints(value,IDs2)
time.sleep(10)
except KeyboardInterrupt:
break
except:
continue
the last except is for any other error if occurs the loop will resume
You can catch the KeyboardInterrupt error in Python:
try:
while 1>0:
IDs2=UpdatePoints(value,IDs2)
time.sleep(10)
except KeyboardInterrupt:
print('While loop ended!')
Also, instead of saying:
while True:
It looks more professional to use:
while 1>0:
To read more about Python Error handling (try, except, etc.):
https://www.w3schools.com/python/python_try_except.asp
or:
https://www.w3schools.com/python/gloss_python_try_finally.asp

Scanning Keypress in Python

I have paused a script for lets say 3500 seconds by using time module for ex time.sleep(3500).
Now, my aim is to scan for keypresses while the script is on sleep, i mean its on this line.
Its like I want to restart the script if a "keypress Ctrl+R" is pressed.
For ex.. consider
#!/usr/bin/python
import time
print "Hello.. again"
while True:
time.sleep(3500)
Now while the code is at last line, If i press Ctrl+R, i want to re-print "Hello.. again" line.
I am aware that this does not fully answer your question, but you could do the following:
Put the program logic code in a function, say perform_actions. Call it when the program starts.
After the code has been run, start listening for an interrupt.
That is, the user must press ctrl+c instead of ctrl+r.
On receiving an interrupt, wait half a second; if ctrl+c is pressed again, then exit.
Otherwise, restart the code.
Thus one interrupt behaves as you want ctrl+r to behave. Two quick interrupts quit the program.
import time
def perform_actions():
print("Hello.. again")
try:
while True:
perform_actions()
try:
while True: time.sleep(3600)
except KeyboardInterrupt:
time.sleep(0.5)
except KeyboardInterrupt:
pass
A nice side-effect of using a signal (in this case SIGINT) is that you also restart the script through other means, e.g. by running kill -int <pid>.
You may want to use Tkinter {needs X :(}
#!/usr/bin/env python
from Tkinter import * # needs python-tk
root = Tk()
def hello(*ignore):
print 'Hello World'
root.bind('<Control-r>', hello)
root.mainloop() # starts an X widget
This script prints Hello World to the console if you press ctrl+r
See also Tkinter keybindings. Another solution uses GTK can be found here
in a for loop sleep 3500 times for 1 second checking if a key was pressed each time
# sleep for 3500 seconds unless ctrl+r is pressed
for i in range(3500):
time.sleep(1)
# check if ctrl+r is pressed
# if pressed -> do something
# otherwise go back to sleep

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