How to switch to the new opened window ?
I tried window name= but I don't know how to get the window name or switch auto to the new opened window cause the previous one closed automatically
try: #after first login, popup disapears
wait = WebDriverWait(driver, 100)
wait.until(EC.visibility_of_element_located((By.XPATH, '//*[#id="chakra-modal--header-1"]/button/svg/path')))
driver.find_element(by = By.XPATH, value = '//*[#id="chakra-modal--header-1"]/button/svg/path').click() #exit pop-up
except:
pass
#once in page
#HERE I GOT THE ERROR
wait = WebDriverWait(driver, 100)
wait.until(EC.visibility_of_element_located((By.XPATH, '//*[#id="root"]/div[1]/div[1]/p')))
elem = driver.find_element(by = By.XPATH, value = '//*[#id="root"]/div[1]/div[1]/p') #find balance element
You can find all opened windows/tabs:
all_windows = driver.window_handles
print(all_windows) #to find windows IDs
you can number of opened windows/tabs:
len(driver.window_handles)
To switch:
driver.switch_to.window(window_handle ID)
driver.switch_to.window(window_handle ID)
worked just fine thank u
Related
For Example: Get icon of google
try:
element = WebDriverWait(driver, 10).until(
EC.presence_of_element_located((By.TAG_NAME,'body'))
)
gmail = driver.find_element(By.LINK_TEXT, 'Gmail')
google_icon = driver.find_element(By.CLASS_NAME, "lnXdpd")
action = ActionChains(driver)
action.context_click(google_icon)
finally:
pass
the context_click don't work.so I try
# test second
action.move_to_element(google_icon)
# action.context_click(on_element=None)
action.context_click(google_icon)
It's don't work too. but
gmail.click()
this is can work.what should i do.
I'm trying to click on a div to get to the next page of a table (the url does not change when the page changes). The go to the next page div has the same class as the go to the previous page's.
ive used:
elem = driver.find_element_by_class_name('cXQSjq')
elem.click()
timeout = 30
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, "gxzFwa")))
except TimeoutException:
driver.quit()
names = driver.find_elements_by_class_name('iBSZGH')
for company in names[1:]:
name.append(company.text)
mostdata = driver.find_elements_by_class_name('gvgMSe.gJYnHB')
for most in mostdata:
most = most.text
most = most.replace(',','')
data.append(most)
last7dsales = driver.find_elements_by_class_name('fGpHsy.kpsxyE')
for last in last7dsales:
last = last.text
last = last.replace(',','')
last7day.append(last)
#loop for the other pages:
for i in range(6):
elem.click()
timeout = 30
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, "gxzFwa")))
except TimeoutException:
driver.quit()
names = driver.find_elements_by_class_name('iBSZGH')
for company in names[1:]:
name.append(company.text)
mostdata = driver.find_elements_by_class_name('gvgMSe.gJYnHB')
for most in mostdata:
most = most.text.replace(',','')
most = most.text.replace(',','')
data.append(most)
last7dsales = driver.find_elements_by_class_name('fGpHsy.kpsxyE')
for last in last7dsales:
last = last.text.replace(',','')
last7day.append(last)
and it worked to get me to page 2, but after page 2 it gives me the error:
selenium.common.exceptions.ElementClickInterceptedException: Message: element click
intercepted: Element <div class="styles__Chevron-sc-1buchb9-1 cXQSjq">...</div> is
not clickable at point (702, 656). Other element would receive the click: <div
id="hs-eu-cookie-confirmation-inner">...</div>
(Session info: chrome=92.0.4515.107)
Do you know if there is an issue that i am able to call elem.click() after using selenium to find other parts of the page. I'm scraping data from
https://nonfungible.com/market/history
I guess the issue here is that the next page button appears on the bottom of the page, so to click on it you should first scroll this element into the view.
See if this will work now:
from selenium.webdriver.common.action_chains import ActionChains
actions = ActionChains(driver)
elem = driver.find_element_by_class_name('cXQSjq')
actions.move_to_element(elem).perform()
time.sleep(0.3)
elem.click()
timeout = 30
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, "gxzFwa")))
except TimeoutException:
driver.quit()
names = driver.find_elements_by_class_name('iBSZGH')
for company in names[1:]:
name.append(company.text)
mostdata = driver.find_elements_by_class_name('gvgMSe.gJYnHB')
for most in mostdata:
most = most.text
most = most.replace(',','')
data.append(most)
last7dsales = driver.find_elements_by_class_name('fGpHsy.kpsxyE')
for last in last7dsales:
last = last.text
last = last.replace(',','')
last7day.append(last)
#loop for the other pages:
for i in range(6):
actions.move_to_element(elem).perform()
time.sleep(0.3)
elem.click()
timeout = 30
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, "gxzFwa")))
except TimeoutException:
driver.quit()
names = driver.find_elements_by_class_name('iBSZGH')
for company in names[1:]:
name.append(company.text)
mostdata = driver.find_elements_by_class_name('gvgMSe.gJYnHB')
for most in mostdata:
most = most.text.replace(',','')
most = most.text.replace(',','')
data.append(most)
last7dsales = driver.find_elements_by_class_name('fGpHsy.kpsxyE')
for last in last7dsales:
last = last.text.replace(',','')
last7day.append(last)
I didn't check correctness of the rest of your code, but clicking the next button should work now
Im so embarrassed because i doesn't scroll on a modal in instagram. Instead of that it scrolling the page on the back :(
i already try with browser.execute_script("arguments[0].scrollTop = arguments[0].scrollHeight", modalDiv) ...i try with any thing i founded but still not work.
My code :
browser.get('https://www.instagram.com/%s' % account)
sleep(2)
clickToFollowing= browser.find_element_by_xpath("/html/body/div[1]/section/main/div/header/section/ul/li[3]/a/span")
clickToFollowing.click()
actionChain = webdriver.ActionChains(browser)
time.sleep(2)
modalDiv= browser.find_elements_by_xpath("//html/body/div[5]/div/div/div[2]/div/div/div[4]/div[2]/div[2]")
browser.execute_script("window.scrollBy(0, 660);")
You need to scroll multiple time in follower list section to grab everything you need.
Code :
options = webdriver.ChromeOptions()
options.add_argument('start-maximized')
driver = webdriver.Chrome("C:\\Users\\etc\\Desktop\\Selenium+Python\\chromedriver.exe", options=options)
wait = WebDriverWait(driver, 30)
driver.get("https://www.instagram.com")
wait.until(EC.element_to_be_clickable((By.NAME,"username"))).send_keys('your username')
wait.until(EC.element_to_be_clickable((By.NAME,"password"))).send_keys('your password')
wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR,"button[type='submit']"))).click()
wait.until(EC.element_to_be_clickable((By.XPATH,"//button[text()='Not Now']"))).click()
sleep(3)
wait.until(EC.element_to_be_clickable((By.XPATH,"//button[text()='Not Now']"))).click()
wait.until(EC.element_to_be_clickable((By.XPATH,"//*[name()='svg' and #aria-label='Activity Feed']/../../following-sibling::div/span"))).click()
wait.until(EC.element_to_be_clickable((By.XPATH, "//div[text()='Profile']"))).click()
sleep(3)
wait.until(EC.element_to_be_clickable((By.XPATH, "//button[#title='Change Profile Photo']/../../../following-sibling::section/descendant::li[3]/a"))).click()
sleep(3)
fBody = driver.find_element_by_xpath("//div[#class='isgrP']")
scroll = 0
while scroll < 5: # scroll 5 times
driver.execute_script('arguments[0].scrollTop = arguments[0].scrollTop + arguments[0].offsetHeight;', fBody)
sleep(2)
scroll += 1
fList = driver.find_elements_by_xpath("//div[#class='isgrP']//li")
print("fList len is {}".format(len(fList)))
print("ended")
I'm using selenium with python to test my web server. Here is my test code:
i = 0
msg = 'abc'
while i < 10:
driver = webdriver.Chrome()
driver.get("http://www.example.com")
txt = driver.find_element_by_id('input-text')
txt.clear()
txt.send_keys(msg)
btn = driver.find_element_by_id('input-search')
btn.click()
driver.quit()
i += 1
The code works well except only one thing: it executes Chrome, do the test and close it for each time of loop. Obviously it's not necessary. What I need is simply to execute Chrome only one time and do many requests. I've tried as below but it doesn't work:
i = 0
msg = 'abc'
driver = webdriver.Chrome()
while i < 10:
driver.get("http://www.example.com")
txt = driver.find_element_by_id('input-text')
txt.clear()
txt.send_keys(msg)
btn = driver.find_element_by_id('input-search')
btn.click()
i += 1
driver.quit()
I think it's because in my test, there are two things:
1) fill abc in input-text;
2) click a button, submit the abc and open a new web page.
On the new page, there is also an input-text and a button input-search, so it will fill the abc and click the button on the new page, which is not what I want.
At btn.click(), it doesn't wait for page loaded because it is not a hyperlink and it doesn't submit a webform. So your script might be failed. You should fix it by waiting for some elements to determine if it should reload page or not. See code below.
try:
driver.get('http://www.example.com')
txt = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.ID, "input-text")))
txt.clear()
txt.send_keys(msg)
btn = driver.find_element_by_id('input-search')
btn.click()
countryDescriptionElement = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.ID, "country-description")))
#print(driver.page_source.encode('utf-8'))
except WebDriverException as ex:
print("Enter: " + msg + ", Error: " + str(ex) + ", Found: " + driver.page_source)
Prerequisites.
You need an account at Instagram to use this script.
Setup a test environment:
Log in, open the needed list(works correctly):
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from time import sleep
driver = webdriver.Chrome(
# driver = webdriver.Firefox(
# driver = webdriver.PhantomJS(
service_args=['--ignore-ssl-errors=true', '--ssl-protocol=any'])
driver.get("https://instagram.com/accounts/login")
username = driver.find_element_by_name("username")
password = driver.find_element_by_name("password")
username1 = 'instagram' # change it!
password1 = 'instagrampassword1' # change it!
username.send_keys(username1)
password.send_keys(password1)
submit_button = driver.find_element_by_css_selector(
'#react-root > div > article > div > div:nth-child(1) > div > form > span > button')
submit_button.click()
sleep(2)
link = 'https://www.instagram.com/youtube/'
driver.get(link)
driver.implicitly_wait(2)
driver.find_elements_by_class_name("_218yx")[2].click()
Wrong scroll.
How to fix this block?
How to focus and scroll correctly on this page?
My attempts:
driver.find_element_by_class_name("_cx1ua").send_keys(Keys.NULL) # focus
#The element has been deleted entirely or
#The element is no longer attached to the DOM.
driver.find_element_by_class_name("_q44m8").send_keys(Keys.NULL)
# cannot focus element
driver.find_element_by_class_name("_qjr85").send_keys(Keys.NULL)
# cannot focus element
for i in range(5):
driver.find_element_by_class_name("_cx1ua").send_keys(Keys.END)
=============================================================
to #Moshisho :
We need to focus on some element to activate it.
The question is what the element we need to choose to focus and how?
This is not a "body":
something like that, but not this:
background = driver.find_element_by_css_selector("body")
# background = driver.find_element_by_css_selector("div._2uju6")
for i in range(5):
background.send_keys(Keys.SPACE)
time.sleep(1)
Without it this command do not work.
to #Naveen :
print(driver.find_element_by_css_selector("div._a1rcs").location_once_scrolled_into_view) # {'x': 0, 'y': 0}
print(driver.find_element_by_class_name("_cx1ua").location_once_scrolled_into_view) # {'x': 376, 'y': 229}
print(driver.find_element_by_class_name("_q44m8").location_once_scrolled_into_view) # {'x': 376, 'y': 180}
print(driver.find_element_by_class_name("_qjr85").location_once_scrolled_into_view) # {'x': 376, 'y': 180}
And what's next?
driver.execute_script("window.scrollTo(0, 3000);") # do not working
Try the following code:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from time import sleep
from selenium.webdriver.support.ui import Select
driver = webdriver.Chrome(
# driver = webdriver.Firefox(
# driver = webdriver.PhantomJS(
service_args=['--ignore-ssl-errors=true', '--ssl-protocol=any'])
driver.maximize_window()
driver.get("https://instagram.com/accounts/login")
username = driver.find_element_by_name("username")
password = driver.find_element_by_name("password")
username1 = 'instagramlogin1' # change it!
password1 = 'instagrampassword1' # change it!
username.send_keys(username1)
password.send_keys(password1)
submit_button = driver.find_element_by_css_selector(
'#react-root > div > article > div > div:nth-child(1) > div > form > span > button')
submit_button.click()
sleep(2)
link = 'https://www.instagram.com/youtube/'
driver.get(link)
driver.implicitly_wait(2)
following = driver.find_element_by_xpath("//a[#href='/youtube/following/']/span")
total_following = int(following.text)
print "total no. of users following: ", total_following
# click on 239 following, displays 10 users
following.click()
loaded_following = driver.find_elements_by_xpath("//ul[#class='_539vh _4j13h']/li")
loaded_till_now = len(loaded_following)
while(loaded_till_now<total_following):
print "following users loaded till now: ", loaded_till_now
print loaded_following[loaded_till_now-1]
loaded_following[loaded_till_now-1].location_once_scrolled_into_view
# driver.execute_script("arguments[0].focus();", loaded_following[loaded_till_now-1])
driver.find_element_by_tag_name('body').send_keys(Keys.END) # triggers AJAX request to load more users. observed that loading 10 users at a time.
sleep(1) # tried wihtout sleep but throws StaleElementReferenceException. As it takes time to get the resposne and update the DOM
loaded_following = driver.find_elements_by_xpath("//ul[#class='_539vh _4j13h']/li")
loaded_till_now = len(loaded_following)
# All 239 users are loaded.
driver.quit()
Observed that browser is sending AJAX request to load more users. this action is triggered when you scroll using mouse or enter Space or End keys
In order to scroll in the window, you need to execute JavaScript, try this:
driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
EDIT: in order to focus an element (it needs to be able to get the focus e.g. an anchor, input, button etc...) you also need to use JavaScript executor:
elementToFocus = driver.find_element_by_id("yourID")
driver.execute_script("arguments[0].focus();", elementToFocus)
I'm working with a dynamic React app, I need to scroll to the pages bottom to make react render all the data.
For unknown reasons, solutions based on JS execute_script didn't work. However I got send_keys solution working:
# scroll to bottom to load all
WebDriverWait(driver, 5).until(
EC.presence_of_element_located((By.XPATH, "//body"))
)
attempt_num = 2
while attempt_num > 0:
try:
elem = driver.find_element_by_xpath("//body")
elem.click()
elem.send_keys(Keys.END)
except StaleElementReferenceException as e:
print(e)
attempt_num = attempt_num - 1
The click() on body and the retry for StaleElementReferenceException are crucial. I haven't found a more elegant way than to retry.
See top answer of How to avoid "StaleElementReferenceException" in Selenium?