This question already has answers here:
Is False == 0 and True == 1 an implementation detail or is it guaranteed by the language?
(3 answers)
Why is bool a subclass of int?
(3 answers)
Closed 13 days ago.
a = True
match a:
case False:
print("It is false")
case 2:
print('It is 2 true.')
case 1:
print('It is 1 true.')
>>> It is 1 true.
Why does the program execute the last case statement?
Related
This question already has answers here:
How to test multiple variables for equality against a single value?
(31 answers)
Why does "a == x or y or z" always evaluate to True? How can I compare "a" to all of those?
(8 answers)
Closed 7 months ago.
what will be the output of this code and why
options = "year2"
options1 = "semester1"
if (options == "year1") and (options1 == "semester1"):
print("a")
elif (options == "year1" or "year3" or "year4") and (options1 == "semester2" or "semester3"):
print("b")
elif (options == "year2" or "year3" or "year4") and (options1 == "semester1"):
print("c")
else:
print("d")
You are looking for something like
options in ("year1", "year2", ...)
The Misunderstanding here is, that you connect with or
<options == "year1"> or <"year3"> ...
<options == "year1"> might or migth not be true
<"year3"> is equivalent to bool("year3") which will be always true
This question already has answers here:
Why does "a == x or y or z" always evaluate to True? How can I compare "a" to all of those?
(8 answers)
Closed 1 year ago.
I have tried to write a recursive version of the Palindrome function. But it is giving me True in all the cases. why?
def isPalindrome(inputString):
if len(inputString)==0 or 1:
return True
elif inputString[0]==inputString[-1]:
return isPalindrome(inputString[1:-1])
else:
return False
Why False is not working for non Palindrome Text.
Short circuit evaluation.
def is_palindrome(input_string):
if len(input_string) == 0 or len(input_string) == 1:
return True
elif input_string[0] == input_string[-1]:
return is_palindrome(input_string[1:-1])
else:
return False
print(is_palindrome('your_string')) # False
This question already has answers here:
Python: Problem with raw_input reading a number [duplicate]
(6 answers)
Python: not all arguments converted during string formatting
(3 answers)
Python TypeError: not all arguments converted during string formatting
(1 answer)
'%' python is giving me a "not all arguments converted during string formatting"
(1 answer)
Closed 4 years ago.
I searched about it and the other person who posted a similar issue had a typo error but I can't find that in mine.strong text
here's the code -
num = raw_input("Enter any number: ")
def is_even(x):
if x % 2 == 0:
return True
else:
return False
print is_even(num)
Convert your raw_input to int
Ex:
num = int(raw_input("Enter any number: "))
def is_even(x):
if x % 2 == 0:
return True
else:
return False
print is_even(num)
This question already has answers here:
How do I check if raw input is integer in python 2.7?
(5 answers)
Closed 6 years ago.
# Validating for only numbers in python one after another(in sequence)
a = raw_input()
#if a is a number then it should take next raw_input i.e., 'b' else it should ask for 'a' again
b = raw_input()
#if b is a number then it should take next raw_input i.e., 'c' else it should ask for 'b' again
c = raw_input()
#if c is a number then it should take next raw_input i.e., 'd' else it should ask for 'c' again
## This should be done upto 'e'
use a.isdigit() to validate string a is digit or not
str.isdigit()
Return true if all characters in the string are digits and there is at least one character, false otherwise.
Make use of if..else construct for the conditional checks and refer this post for the integer check.
Edit 1
I have not executed it,but you could try the following and see if it works-
def ask(text):
temp = raw_input(text)
try:
retVal = int(temp)
return retVal
except ValueError:
return False
a = False
b = False
c = False
while not a:
a = ask("Enter A:")
if a == False:
continue
while not b:
b = ask("ENter B:")
if b == False:
continue
while not c:
c = ask("Enter C:")
This question already has answers here:
Python: False vs 0
(3 answers)
Closed 6 years ago.
I'm trying to configure the following if else :
Basically 0 is equals to False in Python...
I would like to understand why this happens and how I can workaround in this case :
x=0
if x==False:
print "x == False" #always prints this line
elif x == 0:
print "x == 0"
Appreciate the help:
EDIT:
already tried x = int(0)
You should use x is False to check whether x is exactly False.
I doubt you really need it though.
if x is False:
print "x is False" #always prints this line
elif x is 0:
print "x is 0"
Because 0 == False but 0 is not False.