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I follow cs50 by D.Malan and he presented:
CS50 2022 - Lecture 6 - Python
Time: 1:39:12
from cs50 import get_int
# Get scores
scores = []
for i in range(3):
score = get_int("Score: ")
scores += [score]
# Print average
average = sum(scores) / len(scores)
print(f"Average: {average}")
It loops endlessly without asking for an integer and not returning any result.
I work with VSCode jupyter notebook file.
Code available as well here:
https://cdn.cs50.net/2021/fall/lectures/6/src6.pdf
Why is that ? But during the lecture it quickly returns a value.
I expect the same result like on the lecture YT.
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I'm new to python. For a project at school, I have to make a sort of card game.
here is the code that I use:
playersDeckSize = deckSize / 2
i = 0
for i in range(int(playersDeckSize)):
playerDeck[i] = cards[random.randint(0, len(cards - 1))]
computerDeck[i] = cards[random.randint(0, len(cards - 1))]
i = i + 1
Your problem is in this expression:
len(cards - 1)
cards appears to be a list; you can't subtract 1 from a list. I suspect that you mean
len(cards) - 1
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The result of one of my web scrapes produces the following:
price = ['$1049.98']
which is type list, and I am trying to convert this to float.
Take the first and only element in the list, strip off the $ sign and convert it to a float:
parsed_price = float(price[0].lstrip('$'))
import re
price = ['$1049.98']
get_values = [float(re.search(r'(\d+\.\d+)+',cost).group()) for cost in price]
print(get_values)
>>>[1049.98]
Here is my simple solution. Hope that helps.
price = ['$1049.98']
result = [float(i[1:]) for i in price][0]
print(result)
You can change the index(I mean, replace 0 with other numbers) or loop though the list(result).
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I'm working with big multidimensional arrays. I want to know after x loops the values S,S2,E,E2
I want to find all the solutions of a loop.
I have a code that iterates with a greedy. My output is a list of numers. I want to save the arrays that generate those numbers. My code:
while True:
if f2<f:
f,S,S2=f2,E,E2 # f is a value and S and E are arrays
......
print f2-f
else:
break
If i run this code I have a list of f2-f but I need also to save the f,S,S2,f2,E,E2 created in each passage of the while.. Thank you
results = []
while True:
if f2<f:
f,S,S2=f2,E,E2 # f is a value and S and E are arrays
......
results.append((f,S,S2,E,E2))
print f2-f
print "intermediate result:", results[-1]
else:
break
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Can someone please explain how this works? Like, how does it count?
for a in range(2,5):
for b in range(1,2):
print (a+b,end=" ")
print("---",end=" ")
the output is: 3 --- 4 --- 5 ---
It just adds 2, 3, 4 with 1 and prints the result.
In Python-3.x, print() is a function and the argument end in it means
string appended after the last value, default a newline
Values returned by range(x, y) are [x, y-1]
If you don't know the usage of a function, you could open ipython and type something like the following:
help(print)
help(range)
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def distinct(y):
s = str(y)
for digit in s:
if s.count(digit) > 1:
return False
return True
f = open("s1.15.in", 'r')
year = int(f.readline()) + 1
while not distinct(year):
year = year + 1
print (year)
I'm receiving the syntax error on the "f" variable and I'm not sure why. I'm super new to Python.
IDLE's shell is not meant for pasting code. Create a new script file (File → New Window) and run that script (Run → Run Module); it'll work fine.