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Does this program need to be cleaned up or does it look ok? [closed]

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I have an autistic neighbour who counts words and sentences. For example he'll say a word like "River" and say it has 5 letters and lands on the right. I wrote a python program I was going to install it on his windows tablet. This is what I have my question is do you see anything that could be streamlined or changed to make it simpler?
def foo():
while True:
print("\nEnter a word or sentance to see if its")
print("even, odds and which side it lands on")
a = input("")
b = len(a) - a.count(' ')
print(b)
if (b % 2) == 0:
print("{0} is even\nTo the left ".format(a))
else:
print("{0} is odd\nTo the right ".format(a))
foo()

The number % by 3 and 5 are reapiting [closed]

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print(i)
if i % 3 == 0:
print("cot")
elif i%5 == 0:
print("cot")
the code will output number from 1 to 100 and if the number between 1 and 100 is % by 3 or 5 it will be replace with cot,but if the number is cot the number will be put again,without the :cot

If i understand you correctly, what you are trying to do is to change the number to cot if it's divisible by 3 or 5.
So if any of those restrictions is accomplish, you need to assign 'cot' to the variable.
Like this:
i = <some number>
if i%3 == 0:
i = "cot"
elif i%5 == 0:
i = "cot"
print(i)

Create a function that takes a number num and returns each place value in the number [closed]

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Create a function that takes a number num and returns each place value in the number.
Eg num_split(-434) ➞ [-400, -30, -4], num_split[59]->[50,9]

Try this:
def num_split(num):
num = str(num)
num = [c for c in num]
num = num[::-1]
num_lis = []
f = 1
for i in range(len(num)):
num_lis.append(int(num[i])*f)
f *= 10
return num_lis
print(num_split(59))

how can i know how often (if statment are True) in my code? [closed]

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Let's assume:
for a in range(10):
if a == 2 or a == 5:
print (how often this condition was True)
of course will be two, in my code i want to know when my condition be True , thanks

count = 0 # set a variable for counting
for a in range(10):
if a == 2 or a == 5: # for each entry that meets the condition
count += 1 # add 1 to count
print(count) # 2

Understanding how to use conditional statements with python [closed]

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def greater_less_equal_5(answer):
if ___ :
return 1
elif ___:
return -1
else:
return 0
print greater_less_equal_5(4)
print greater_less_equal_5(5)
print greater_less_equal_5(6)
(On line 2, fill in the if statement to check if answer is greater than 5.
On line 4, fill in the elif so that the function outputs -1 if answer is less than 5.)

def greater_less_equal_5(answer):
if answer>5 :
return 1
elif answer<5:
return -1
else:
return 0
print greater_less_equal_5(4)
print greater_less_equal_5(5)
print greater_less_equal_5(6)
Try this